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TITLE : URBAN TRANSPORTATION ASSIGNMENT 2 NAME : MUHAMMAD BIN RAMLAN MATRIX NO : P 57600 SUBJECT : KKKA 6564 YEAR : 2011/2012 LECTURER : PROF IR DR RIZA ATIQ O.K. RAHMAT

KA6564 Assignment 2

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Page 1: KA6564 Assignment 2

TITLE :

URBAN TRANSPORTATION

ASSIGNMENT 2

NAME : MUHAMMAD BIN RAMLAN

MATRIX NO : P 57600

SUBJECT : KKKA 6564

YEAR : 2011/2012

LECTURER : PROF IR DR RIZA ATIQ O.K. RAHMAT

Page 2: KA6564 Assignment 2

QUESTION ASSIGNMENT 2

In an urban transport study, a city is divided into six zones as shown in Figure 1. The

summarized land use data is given in Table 1.

Figure 1

Table 1

Zone Residential unit Commercial land use

(m2)

1 7,000 6,800,000

2 20,000 370,000

3 31,000 280,000

4 25,000 300,000

5 22,000 360,000

6 35,000 400,000

1 2

3

4

5

6

Page 3: KA6564 Assignment 2

Production rate of the residential unit is 1.9 trips per hour and attraction rate of the commercial

premises is 3.25 trips per 100 sq. meter floor area.

a) Compute the production and attraction of each zone.

b) Balance the production and the attraction.

c) Compute O-D trip matrix for the city.

d) Sketch the trip interchanges

Page 4: KA6564 Assignment 2

SOLUTION ASSIGNMENT 2

a) Compute production and attraction of each zone

Zone Land Use

(Residential Unit)

Production rate

(person-trip / unit / hr)

Production

(person-trip / hr)

1 7,000 1.90 7000 x 1.9 = 13,300

2 20,000 1.90 38,000

3 31,000 1.90 58,900

4 25,000 1.90 47,500

5 22,000 1.90 41,800

6 35,000 1.90 66,500

Total 266,000

Zone Land Use

(Commercial

Premises)

Attraction rate

(person-trip / m2 / hr)

Attraction

(person-trip / hr)

1 6,800,000 3.25 6800000 x (3.25/100)=

221,000

2 370,000 3.25 12,025

3 280,000 3.25 9,100

4 300,000 3.25 9,750

5 360,000 3.25 11,700

6 400,000 3.25 13,000

Total 276,575

b) Balance the production and the attraction.

Zone Production rate Attraction rate Balanced

Production rate Attraction rate

1 13,300 221,000 (13,300/266,000) x

271,288 = 13,564

(221,000/276,575)

x 271,288 =

216,775

2 38,000 12,025 38,755 11,795

3 58,900 9,100 60,071 8,926

4 47,500 9,750 48,444 9,564

5 41,800 11,700 42,631 11,476

6 66,500 13,000 67,822 12,751

Total 266,000 276,575 Nil Nil

Average (266,000 + 276,575) / 2 = 271,288

Page 5: KA6564 Assignment 2

c) Compute O-D trip matrix for the city.

Zone 1 2 3 4 5 6

Value 216,775 11,795 8,926 9,564 11,476 12,751

1 13,564 (13,564/271,288) x

216,775 = 10,838

590 446 478 574 638

2 38,755 30,968 1,685 1,275 1,366 1,639 1,822

3 60,071 48,000 2,612 1,976 2,118 2,541 2,823

4 48,444 38,710 2,106 1,594 1,708 2,049 2,277

5 42,631 34,065 1,854 1,403 1,503 1,803 2,004

6 67,822 54,194 2,949 2,232 2,391 2,869 3,188

The O-D trip matrix value for zone 1 until zone 6 is as per bold in the table above.

Page 6: KA6564 Assignment 2

d) Sketch the trip interchanges.