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Page 1 of 5
Intelligent Urban Transport Management System
Assignment 1
Name Muhammad bin Ramlan Matrix No. P57600 Subject KA 6423 Session 2012/2013 Lecturer Prof Ir Dr RizaAtiq O.K. Rahmat
Page 2 of 5
Question
Below is an illustration of two signalised intersections which are to be optimised.
Based on the given data, you are required to determine optimum common cycle
time, green time split for each intersection and offset time.
356
521
225
490
95
190
80
18095 152 95 80 180 90
95 204 102 89 200 92
400m
Queue length = 15 cars
Page 3 of 5
Answer
JUNCTION 1
Phase Number Of Lanes
Saturation Flow Per Lane (pcu/Hr)
Saturation Flow (pcu/Hr)
Actual Flows (pcu/Hr)
Flow / Saturation Flow Ration
Green Time Split
1 2 1800 3600 1,005 0.28 0.477 2 2 1800 3600 401 0.11 0.190 3 2 1800 3600 350 0.10 0.166 4 2 1800 3600 350 0.10 0.166
Jumlah, Y 0.59 1.000
Cycle Time
L = 4 * 4 = 16 seconds [lost time per phase 4 seconds]
Co = (1.5 x 16 + 5) / ( 1 - 0.59) = 69.88
Take Co = 70 seconds
Effective Green Time = 70 - L = 54 seconds
Co =
1.5 L + 5 Co =
1.5 L + 5
1 - Y
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Green Time Split
Phase Green Time Round-Up To
1 25.769 26 Take amber time = 3 seconds
2 10.282 11 Take all red time = 1 seconds
3 8.974 9 Total of all amber and red time = 16 sec
4 8.974 9
total 54 55 Actual CycleTime = 71 sec
JUNCTION 2
Phase Number Of Lanes
Saturation Flow Per Lane (pcu/Hr)
Saturation Flow (pcu/Hr)
Actual Flows (pcu/Hr)
Flow / Saturation Flow Ration
Green Time Split
1 2 1800 3600 857 0.24 0.449 2 2 1800 3600 381 0.11 0.200 3 2 1800 3600 327 0.09 0.171 4 2 1800 3600 342 0.10 0.179
Jumlah, Y 0.53 1.000
Cycle Time
L = 4 * 4 = 16 seconds [lost time per phase 4 seconds]
Co = (1.5 x 16 + 5) / ( 1 - 0.59) = 61.67
1 - Y Co =
Co =
1.5 L + 5
1 - Y
Take Co =
Effective Green Time =
Green time split
Phase Green Time Round
1 20.67 212 9.19 103 7.89
4 8.25
total 46 48
OFFSET TIME
= 400/10- (15(2)+2) = 40-32 = 8
# So, Offset Junction
62 seconds
62 - L = 46 seconds
Round-Up To
21 Teke amber time =
10 Take all red time =
8 Total of all amber and red time =
9
48 Actual CycleTime = 64
L=400 meter S=10m/s Q=15 kenderaan Loss time= 2 second
Junction 2 is8 Second
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3 seconds
1 seconds
16 sec
sec