Joule Equivalency Lab

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    Jonathan Mills

    Physics 222 Section 003

    Joule Equivalency of Electrical Energy

    October 1, 2010

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    Objective:

    The objectives of this experiment are to understand the equivalence of electrical energy

    and heat energy, to learn techniques of calorimetry, to learn how to measure electrical energy,and to measure the Joule equivalent of electrical energy.

    Theory:

    Electrical and mechanical energy use the same units of energy. This is because both weredeveloped by the same principles of energy and power. Heat energy is measured in quantities

    separately defined from the principles of electricity, magnetism, and mechanics. Due to thisinconvenience, Sir James Joule developed a constant of proportionality between the two forms of

    energy which is now called the Joule equivalent of electrical energy. This constant allows for anunderstand relationship between the two forms of energy.

    Power is defined as the rate of doing work, and electrical power is defined as the amount

    of electrical energy being expended per unit of time. Work is the mechanical energy required tomove an electrical charge through a potential difference (W = Q x V) therefore power, P, is

    given by (P = W / t = V x Q/t) so that power is equal to potential difference times current.

    Heat energy is measured in kilocalories as opposed to mechanical and electrical energywhich is measured in joules. The change in heat energy of a material is directly proportional to

    the change in temperature of the material and depends on the type of material and its mass. Thechange of heat energy for a given change of temperature is equal to mass of the material times

    specific heat of the material times the change in temperature (Q = mcT). When electrical energyis transformed into heat energy, then the equivalence of the electrical energy and heat energy is

    given by multiplying the joule equivalent constant of 4186 Joules/kilocalorie times the change in

    heat energy (W = J x Q). Throughout the experiment a constant current and voltage will bemaintained causing the resistance to increase and therefore the heat energy. This heat energywill increase the temperature of a quantity of water and the container in which it is kept. The

    change in heat energy of the container and water will be the sum of the heat energies of each andwill be given by Q = (mc)(cc)T + (mw)(cw)T. where mc and mw are masses of the

    container and water and cc and cw are specific heats of the material of the container and water.With our previous equations for work and energy, we can deduce that our joule equivalence

    calculated for the experiment will be given by the following equation: J = { (VI) / [ (mc)(cc) +(mw)(cw) ]} x [ 1 / (T/t) ]. In this equation, temperature, T, is a function of time, t.

    Data:

    See attached.

    Conclusions:

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