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- 1 -
JEE-ADVANCEDMODEL GRAND TEST PAPER - I
Time : 3 hrs ] [Number of questions : 60
x − y − y −
A
Y
XQ
PO
V
Vπ 2
Vπ
2
V
1y 5 mm sin t 1S 2y 5 mm sin t / 6
2S ! 1S 2S
" #! $ %
A
1S 2S
5 2 3 mm+ 5 3 mm &!! 5 2 mm
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- 2 -
! "#$
v
Vm
O π 2π 3π(radian)
#$m
mV2
V and2
#%$m mV V
and2
#&$m
mV2
V and2
#'$m mV V
and2 2
( )*+,)))))
#$6
R5
7
R5
9
R5
3
R2
- "./0)123ω 4!))567
#$1 7
cos9
−#%$
1 5cos
9−
#&$1 4
cos9
−#'$
1 1cos
9−
8 ))9:0.5 )""vs ))9)#)9$
LT
A
#$
T
Z
#%$
T
Z
#&$
T
Z
#'$
T
Z
; *))9))2<))5#"99)$
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- 3 -
Magnet(north pole facingthe viewer)
Plane of coil isnearest to you than that of magnet
ω
frame
#$ t
I
#%$ t
I
#&$ t
I
#'$ t
I
= &#$
1
2
3
B
*),! #$a b c> > #%$a c b= > 1#&$a b c= = #'$c b a> >
> )***)******.
) I II IIIC ,C andC *
Gas
Heater
(I)Gas
Heater
(II)fixed
Heater
(III)Gas
#$I II III
C C C> > #%$II I III
C C C> >
#&$III I II
C C C> > #'$I III II
C C C> >
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- 4 -
+ )9),)")ε " #&$
2
EV
#$ t
I
#%$t
I
#&$
t
I
#'$t
I
!"# $ %&
*)%"))?)%)
A B
a b
#$'a to b#%$<%)#&$'9)<#'$')
, "@"#$="A)#$5
#$A R V
6Ω
20 V
#%$
6Ω
20 VA
4Ω
#&$
4Ω
A
20 V
12Ω
6Ω
8Ω
#'$
20 V
A
6Ω
6Ω
6Ω
6Ω
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- 5 -
! B))) 09#$
v v
#$0)),
#%$"))24mv
#&$"2mv
#'$0))@
( P
0?:%0?09
A
B
M
N
P
45°O
y
x
#$ )0?@
#%$ %
#&$ xy 3 z
#'$ xy 3 z
- * f 3 * 9 #$
#$* f 9 I 99
#%$*)
#&$**9 f 9
#'$999
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- 6 -
!
"# $ %&
8 "PQR PQ PR " A
)A")πα < .α
; ) 0P ")
0V ")ρ )
)) ( )0P / 2 C)
)) 01.25V *)
) 0
750P
k9
)9)
6"9
3 30V 8m , 1500kg / m ,m 18kg= ρ = = 7
= "9%3=-/@+4
)1B2<9)9%
)+4
9<)3))/@
6"9!(+47
A B
O
← ←
> "-nRT B9
28.5cm ")
"(,C"
02 C ")( )0 mβα×1
< α +β 6"925
3R = .*
D++9 7
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- 7 -
,+ ")3)) 9")%""%#4$&5Q 1 C, 1.5m= µ = D
A B
C
m
m
mQ Q
!"# $
, )
#$O
2NH#%$
NH
O#&$
O
N #'$2NH
O
,,1.
3 2 22. 3
dry Zether H O
X Mg Y CH CH CH OH++ → → − − −
*EF)3
#$ 3 2CH CH Br and HCHO #%$ 3 2 3CH Br and CH CH CH− −
O
#&$ 3 3 2CH Br and CH CH CHO #'$ 3 3CH Br and CH CHO
,! 32 3 2
FeClCH CH Cl Cl− + → 2 3CH CH−
9)
#$ 3.C H CH− #%$ 3C H CH
⊕−
#&$2 3CH CH−Cl #'$
⊕
2 3CH CH−Cl
,( )
#$
H OH
H OH
H OH
CHO
CH2OH
HHO#%$
O
H OH
H OH
CH2OH
CH2OH
#&$
O
H OH
H OH
CH2OH
CH2OH
H OH
HO H
#'$ H OHH OH
CHO
CH2OH
H OHH OH
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- 8 -
,- "3 2( / ) ( )CP aT V V RT b+ = + )A
")) m nP AV BV= − %
#$m c= − 1n = − #%$m c= 1n = #&$m c= − #'$DG
,8 <#***$<#**$")#$=4> #%$>4= #&$(4! #'$84-
,; :3@B+ H –C 3)2A B C+ −+
3) 3010− /C− 3#
)9)$
#$ 810− #%$ 1510− #&$ 56.023 10× #'$ 512.04 10×
,= * )3
)# A.$
# $")#$ 2GeX #,$ 2SnX #!$ 2PbX
#$#$ 4SnCl #,$ 4PbCl #!$ 4PbI
#A$#$ 2PbO #,$ 2SnO #!$ 2SiO
#.$")#$ 3NH #,$ 3PH #!$ 3AsH
#$!,! #$!! #$!!! #$!
,> ( ) 2
2 6Fe H O
+ 2Fe+
,(94)
)@ 0∆
#$ 17234cm− #%$ 18680cm− #&$ 11808.4cm− #'$ 110850cm−
!+ I 025 C0
0
Ag e Ag ; E 0.800V
AgI e Ag I ; E 0.152V
+ −
− −
+ → = ++ → + = −
splog K *
#$8! #%$J=8, #&$!;=! #'$=,
!"# $ %&
! 5
#$ and
#%$ 3 2 2 3 3 CH CH CH CH and CH CH CH CH
#&$
Br Br
H H
andBr
Br
H
H
#'$OH
and
O
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- 9 -
!, .)O
( )3 2 3 2CH C CH CH OCH− − −
*#$* 2I 3NaOH .#%$*2"#&$B/%
#'$%,(G'?
!! 5#$Si Ge ⇒@#%$&⇒#&$⇒ /2#'$)⇒3
!( *3)&0& #$#%$#&$#'$#)$
!- 5#$/ 4 2NH NO
#%$% 3NH CuO#&$/ 3 2( )Ba N
#'$ Cu 3HNO
$ '"' ' ''
(
!8 " 027 C 300ycalorie 12
!; /)%25'I '< . '): I 0
!= ?)
Cl
+ 3CCl C H− −
O
2 4H SO
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- 10 -
!> "))#D!$
Case – I →
Case – II → EK
Case – III → ))
(+ % ( )n 4B + + "
)9
% % * ( ) ( ) ( )n - 2 n 4 n – 1nB to B and B to B .+ + + ++ 0t =
,-D+!,*
( )n 4nB of B + ++ 2 110 minx − −× ‘ ’x #?)*$
!"# $
( *1
( 1)( 2)( 3)8
n
rr
nt n n n
== + + +∑
1
1n
rrt=
=∑
#$( 1)
( 2)( 3)
n n
n n
++ + #%$
( 1)
2( 2)( 3)
n n
n n
++ + #&$
( 1)
( 1)( 2)
n n
n n
++ + #'$
( 3)
2( 1)( 2)
n n
n n
++ +
(,32 10
1 1
2 2(3 2) sin cos
11 11
p
p r
r rp i
π π
= =
+ − ∑ ∑ D
#$48i #%$16(1 )i− #&$48(1 )i− #'$16( 1)i −
(! *( ) 20 1 21 ........n n
nx C C x C x C x+ = + + + + ( )2
0 i j n
Ci Cj≤ < ≤
+ =∑ ∑
#$( ) 21 2 2 ncnn n− + #%$ ( ) 22 2 n
cnn n +
#&$( )1 2 2ncnn n+ + #'$ ( )2 2n
cnn n +
(( *3)))
#$1
144#%$
7
72#&$
1
72#'$
7
144
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- 11 -
(-3
33
8lim
8
n
n r
r
r→∞ =
− = +
∏
#$1
7#%$
2
7#&$
3
7#'$
4
7
(8 "32
3 200n
na
n=
+
#$ 6a #%$ 7a #&$ 8a #'$ 9a
(; "α 2y gx α= +
2 2 2 2 2 0x y gx gy+ + + − =
#$[1, )∞ #%$[ 1, )− ∞ #&$ (0,1) #'$( ,1]−∞
(= ( 1)( 2) 5x y− − = 2 2 2( 1) ( 2)x y r− + + = %&'
%& 3 4y x= − "'
#$ 3y x= #%$ 2 2 3 1 0x y x+ + + =#&$3 1y x= + #'$ 3 1y x= +
(> "%&
ˆ ˆ ˆˆ ˆ ˆ ˆ ˆ ˆ3 , 2 2 5 2 6i j k i j k and i j k− − + − − + − *) A
ABC∆ %&''
#$1
4#%$
11
2#&$
15
2#'$
3 10
4
-+ ")3 7 4cos sin 1x x+ = ( ),π π−
#$( #%$! #&$, #'$
!"# $ %&
- ( ) 21 1
dx
x x x+ + −∫ D
#$2
1 2 1cos
5( 1)
x xC
x− + − +
+#%$
21 1 1
2 tan2
x xC−
+ − + +
#&$1 3 1
sin5( 1)
xC
x− + + +
#'$1 3 1
sin5( 1)
xC
x− + + +
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- 12 -
-, " E*OAP #B
$ 2a #$3
#$2a
x cyy
= + #%$2a
y cxx
= + #&$2a
x cyy
= − #'$2a
y cxx
= −
-! *3 2 0 ( , )x ax b a b R− − = ∈ )
#$ 1b < #%$ 1a b+ < #&$ 1b a− < #'$ 0a b+ =
-( :%&)3*
A B C AB BC CA+ + = + + &
#$ ABC AC CA= − #$ BCA BA AB= − #$CAB CB BC= −
#$#$#$3 #%$#$#$3
#&$#$#$3 #'$#$#$#$3
-- 4
#$")31 1
2 31 3
41
xTan Tan
x x
π− − + =
− )
#+$,
#%$ 1 1 1 11 1 1 1....
2 8 18 32Tan Tan Tan Tan− − − − + + + +
n 1 1
4 2 1Tan
n
π − − +
#&$*0 1x≤ ≤ 1 1 1sin cos tanx x xθ − − −= + − 4 2
π πθ≤ ≤
#'$"1 14 7
sin3 6
Sin Cos cosπ π− − +
2
π
!"# $ %&
-8 "0B"/LA)
*9M)
-; *%&M:9%%&
: 1: 2AK KB = : 1: 2BL LC = : )AL
CK * BCP∆ ,3%&
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- 13 -
-= * 22 (1 sin )
,1 cos
x xI dx
x
π
π−
+=+
∫ *
-> *2 2
2 21
x y
a b+ = ( )cos , sina bθ θ
%%)
2
1
sinα β θ+ 2( )α β+ =
8+ *%&tan
tan tan
tanA B c b
A B c
− −=+ 22 tan A =
NNN