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Investigative Mathematics Objectives At the end of the lesson, you will be able to : 1. Know the difference between a linear series pattern, non-linear series pattern and triangular series pattern. 2. Recognise the three different types of pattern question. 3. Solve all the three different types of number pattern questions.

Investigative Mathematics

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Investigative Mathematics. Objectives. At the end of the lesson, you will be able to :. Know the difference between a linear series pattern, non-linear series pattern and triangular series pattern. Recognise the three different types of pattern question. - PowerPoint PPT Presentation

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Page 1: Investigative  Mathematics

Investigative Mathematics

Objectives

At the end of the lesson, you will be able to :

1. Know the difference between a linear series pattern, non-linear series

pattern and triangular series pattern.

2. Recognise the three different types of pattern question.

3. Solve all the three different types of number pattern questions.

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Investigative Mathematics

The three different types of pattern questions are :

1. Linear series pattern

2. Non – Linear series pattern

3. Triangular series pattern

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Investigative Mathematics

Linear Series Pattern

Example 1

Look at the number pattern below

4, 10, 16, 22, 28

a)Find the 10th term.b)Find the 55th term.

How do I solve this?

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Now, let us take a look at the number pattern again.

Investigative Mathematics

4, 10, 16, 22, 28

a)Find the 10th term.b)Find the 55th term.

Step 1 – Find the difference between each of the number 10 – 4 = 6, 16 – 10 = 6, 22 – 16 = 6

Looking at it closely, the difference we get is always 6.

Therefore, the first testing formulae we can derive at this stage is +6n where n is just a term.

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Step 2 – testing out the formulae

+6(n) if n = 1 Then, +6(n) = +6(1) = 6

4, 10, 16, 22, 28

a)Find the 10th term.b)Find the 55th term.

Step 3 – adjusting the formulae When n = 1, my answer should be 4, however using the formulae of +6(n) , I got 6 as the answer. Therefore adjustment to the formulae is needed to tally with the answer.

To make the answer to be 4, we need to subtract 2 from the first formulae.

We get+6(n) – 2

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4, 10, 16, 22, 28

a)Find the 10th term.b)Find the 55th term.

Step 4 – testing out the new formulae

+6(n) – 2 if n = 4, my answer would be 22. Let us test +6(n) - 2 = +6(4) - 2 = 24 – 2 = 22. ( correct answer )

Now, if n = 10, then

+6(n) - 2 = +6(10) - 2 = 60 – 2 = 58.

Now, if n = 55, then

+6(n) - 2 = +6(55) - 2 = 330 – 2 = 328.

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Investigative MathematicsNow you try

Example 2

3, 7, 11, 15, 19……

a) Find the 25th term.

b) Find the 100th term.

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Investigative Mathematics

Non-Linear Series Pattern

Example 3

Look at the number pattern below

1, 4, 9, 16, 25 …….

a)Find the 15th term.b)Find the 50th term.

How do I solve this?

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Step 1 – Look at the pattern 4 – 1 = 3, 9 – 4 = 5, 16 – 9 = 7, 25 – 16 = 9

Looking at it closely, is there a pattern?The answer is NO. So…. How?

1, 4, 9, 16, 25 …….

a)Find the 15th term.b)Find the 50th term.

Investigative Mathematics

Step 2 – Look at the pattern again. We realised that 1, 4, 9, 16, 25 is actually…. 1² , 2², 3², 4², 5²

Now, if n = 15, then

15² = 15 x 15 = 225

Now, if n = 50, then

50² = 50 x 50 = 2500

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Investigative Mathematics

Non-Linear Series Pattern

Example 4 …..Now you try.

Look at the number pattern below

2, 5, 10, 17, 26 …….

a)Find the 12th term.b)Find the 48th term.

How do I solve this?

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Investigative Mathematics

Triangular Series Pattern

What is Triangular series?

Look at the pattern in the handout given to you.

Example 5

Look at the number pattern below

3, 9, 18, 30,

a)Find the 12th term.b)Find the 48th term.

How do I solve this?

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Step 1 3 , 9, 18, 30…. Divide all numbers by three

Step 2 1, 3, 6, 10 …. Now, look at the difference between each number.

3 - 1 = 2, 6 - 3 = 3, 10 – 6 = 4 now refer to the handout back. This pattern tells you that it is a triangular series.

Step 3 In a triangular series, there is a general formulae that is n ( n + 1 ) / 2

Example 5

Look at the number pattern below

3, 9, 18, 30,

a)Find the 12th term.b)Find the 48th term.

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Example 5

Look at the number pattern below

3, 9, 18, 30, ( ÷ 3 ) 1, 3, 6, 10

a)Find the 12th term.b)Find the 48th term.

Step 4 test the formulae.If n = 1,

n ( n + 1 ) / 2 = 1 (1 + 1 ) / 2 = 1

If n = 3, n ( n + 1 ) / 2 = 3 (3 + 1 ) / 2 = 6

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Example 5

Look at the number pattern below

3, 9, 18, 30, ( ÷ 3 ) 1, 3, 6, 10

a)Find the 12th term.b)Find the 48th term.

a) If n = 12,

n ( n + 1 ) / 2 = 12 (12 + 1 ) / 2 = 78However, since earlier on we divide it by 3, to get the answer, we have to multiply it by 3 back. Therefore, the answer would be,

78 x 3 = 234

b) If n = 48, n ( n + 1 ) / 2 = 48 (48 + 1 ) / 2 = 1176 1176 x 3 = 3528

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Now take a look at the question that you have in the remediation paper

Investigative Mathematics

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Conclusion

You have learnt

1. the difference between a linear series pattern, non-linear series pattern

and triangular series pattern.

2. to recognise the three different types of pattern question.

3. how to solve all the three different types of number pattern questions.