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Inverse Kinematics

Inverse Kinematics. Inverse Kinematics (IK) T q1q1 q2q2 q3q3 q4q4 q5q5 Given a kinematic chain (serial linkage), the position/orientation of one end relative

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Page 1: Inverse Kinematics. Inverse Kinematics (IK) T q1q1 q2q2 q3q3 q4q4 q5q5 Given a kinematic chain (serial linkage), the position/orientation of one end relative

Inverse Kinematics

Page 2: Inverse Kinematics. Inverse Kinematics (IK) T q1q1 q2q2 q3q3 q4q4 q5q5 Given a kinematic chain (serial linkage), the position/orientation of one end relative

Inverse Kinematics (IK)

T

q1

q2 q3

q4q5

Given a kinematic chain (serial linkage),the position/orientation of oneend relative to the other (closed chain), find the values of the joint parameters

rigid groupsof atoms

Page 3: Inverse Kinematics. Inverse Kinematics (IK) T q1q1 q2q2 q3q3 q4q4 q5q5 Given a kinematic chain (serial linkage), the position/orientation of one end relative

Why is IK useful for proteins?

Filling gaps in structure determination by X-ray crystallography

Page 4: Inverse Kinematics. Inverse Kinematics (IK) T q1q1 q2q2 q3q3 q4q4 q5q5 Given a kinematic chain (serial linkage), the position/orientation of one end relative

Structure DeterminationX-Ray Crystallography

Page 5: Inverse Kinematics. Inverse Kinematics (IK) T q1q1 q2q2 q3q3 q4q4 q5q5 Given a kinematic chain (serial linkage), the position/orientation of one end relative

Automated Model Building Software systems: RESOLVE, TEXTAL, ARP/wARP,

MAID

• 1.0Å < d < 2.3Å ~ 90% completeness• 2.3Å ≤ d < 3.0Å ~ 67% completeness (varies

widely)1

Manually completing a model:

• Labor intensive, time consuming• Existing tools are highly interactive

JCSG: 43% of data sets 2.3Å

1Badger (2003) Acta Cryst. D59

Model completion is high-throughput bottleneck

1.0Å 3.0Å

Page 6: Inverse Kinematics. Inverse Kinematics (IK) T q1q1 q2q2 q3q3 q4q4 q5q5 Given a kinematic chain (serial linkage), the position/orientation of one end relative

The Completion Problem

Input:• Electron-density map• Partial structure•Two anchor residues•Amino-acid sequence of missing fragment (typically 4 – 15 residues long)

Output: • Few candidate conformation(s) of fragment that

- Respect the closure constraint (IK)- Maximize match with electron-density map

Main part of protein (f olded)

Protein f ragment (f uzzy map)

Anchor 1(3 atoms)

Anchor 2(3 atoms)

Main part of protein (f olded)

Protein f ragment (f uzzy map)

Anchor 1(3 atoms)

Anchor 2(3 atoms)

Page 7: Inverse Kinematics. Inverse Kinematics (IK) T q1q1 q2q2 q3q3 q4q4 q5q5 Given a kinematic chain (serial linkage), the position/orientation of one end relative

Example: TM0813

GLU-77

GLY-90

PDB: 1J5X, 342 res.2.8Å resolution12 residue gapBest: 0.6Å aaRMSD

Page 8: Inverse Kinematics. Inverse Kinematics (IK) T q1q1 q2q2 q3q3 q4q4 q5q5 Given a kinematic chain (serial linkage), the position/orientation of one end relative

Example: TM0813

GLU-77

GLY-90

PDB: 1J5X, 342 res.2.8Å resolution12 residue gapBest 0.6Å aaRMSD

Page 9: Inverse Kinematics. Inverse Kinematics (IK) T q1q1 q2q2 q3q3 q4q4 q5q5 Given a kinematic chain (serial linkage), the position/orientation of one end relative

Why is IK useful for proteins?

Filling gaps in structure determination by X-ray crystallography

Studying the motion space of “loops” (secondary structure elements connecting helices and strands), which often play a key role in:• enzyme catalysis, • ligand binding (induced fit), • protein – protein interactions

Page 10: Inverse Kinematics. Inverse Kinematics (IK) T q1q1 q2q2 q3q3 q4q4 q5q5 Given a kinematic chain (serial linkage), the position/orientation of one end relative

Loop motion in Amylosucrase

17-residue loop that plays important role in protein’s activity

Page 11: Inverse Kinematics. Inverse Kinematics (IK) T q1q1 q2q2 q3q3 q4q4 q5q5 Given a kinematic chain (serial linkage), the position/orientation of one end relative

Loop 7 of 1G5A

Conformations obtained by deformation sampling

Page 12: Inverse Kinematics. Inverse Kinematics (IK) T q1q1 q2q2 q3q3 q4q4 q5q5 Given a kinematic chain (serial linkage), the position/orientation of one end relative

1K96

Page 13: Inverse Kinematics. Inverse Kinematics (IK) T q1q1 q2q2 q3q3 q4q4 q5q5 Given a kinematic chain (serial linkage), the position/orientation of one end relative

Why is IK useful for proteins?

Filling gaps in structure determination by X-ray crystallography

Studying the motion space of “loops” (secondary structure elements connecting helices and strands), which often play a key role in:• enzyme catalysis, • ligand binding (induced fit), • protein – protein interactions

Sampling conformations using homology modeling Chain tweaking for better prediction of folded state R.

[Singh and B. Berger. ChainTweak: Sampling from the Neighbourhood of a Protein Conformation. Proc. Pacific Symposium on Biocomputing, 10:52-63, 2005.]

Page 14: Inverse Kinematics. Inverse Kinematics (IK) T q1q1 q2q2 q3q3 q4q4 q5q5 Given a kinematic chain (serial linkage), the position/orientation of one end relative

Generic Problem Definition

Inputs: Protein structure with missing fragment(s) (typically 4 – 15 residues long, each)

Amino-acid sequence of each missing fragment

Outputs: Conformation of fragment or distribution of conformations that

• Respect the closure constraint (IK)•Avoid atomic clashes• Satisfy other constraints, e.g., maximize match with

electron density map, minimize energy function, etc

Page 15: Inverse Kinematics. Inverse Kinematics (IK) T q1q1 q2q2 q3q3 q4q4 q5q5 Given a kinematic chain (serial linkage), the position/orientation of one end relative

Inputs: Closed kinematic chain with n degrees of freedom

Relative positions/orientations X of end frames Target function T(Q) →

Outputs: Conformation(s) that

• Achieve closure• Optimize T

IK Problem

T

Page 16: Inverse Kinematics. Inverse Kinematics (IK) T q1q1 q2q2 q3q3 q4q4 q5q5 Given a kinematic chain (serial linkage), the position/orientation of one end relative

Relation to Robotics

Page 17: Inverse Kinematics. Inverse Kinematics (IK) T q1q1 q2q2 q3q3 q4q4 q5q5 Given a kinematic chain (serial linkage), the position/orientation of one end relative

Some Bibliographical References

Robotics/Computer Science

• Exact IK solvers– Manocha & Canny ’94– Manocha et al. ’95

• Optimization IK solvers– Wang & Chen ’91

• Redundant manipulators– Khatib ’87 – Burdick ’89

• Motion planning for closed loops– Han & Amato ’00 – Yakey et al. ’01– Cortes et al. ’02, ’04

Biology/Crystallography• Exact IK solvers

– Wedemeyer & Scheraga ’99– Coutsias et al. ’04

• Optimization IK solvers– Fine et al. ’86– Canutescu & Dunbrack Jr. ’03

• Ab-initio loop closure– Fiser et al. ’00 – Kolodny et al. ’03

• Database search loop closure– Jones & Thirup ’86– Van Vlijman & Karplus ’97

• Semi-automatic tools– Jones & Kjeldgaard ’97– Oldfield ’01

Page 18: Inverse Kinematics. Inverse Kinematics (IK) T q1q1 q2q2 q3q3 q4q4 q5q5 Given a kinematic chain (serial linkage), the position/orientation of one end relative

Forward Kinematics

d1

d2

1

2

(x,y)

x = d1 cos 1 + d2 cos(1+2)y = d1 sin 1 + d2 sin(1+2)

Page 19: Inverse Kinematics. Inverse Kinematics (IK) T q1q1 q2q2 q3q3 q4q4 q5q5 Given a kinematic chain (serial linkage), the position/orientation of one end relative

Inverse Kinematics

d1

d2

1

2

(x,y)

2 = cos-1x2 + y2 – d1

2 – d22

2d1d2

-x(d2sin2) + y(d1 + d2cos2)

y(d2sin2) + x(d1 + d2cos2)1 =

Page 20: Inverse Kinematics. Inverse Kinematics (IK) T q1q1 q2q2 q3q3 q4q4 q5q5 Given a kinematic chain (serial linkage), the position/orientation of one end relative

Inverse Kinematics

d1

d2

(x,y)

2 = cos-1x2 + y2 – d1

2 – d22

2d1d2

-x(d2sin2) + y(d1 + d2cos2)

y(d2sin2) + x(d1 + d2cos2)1 =

Two solutions

Page 21: Inverse Kinematics. Inverse Kinematics (IK) T q1q1 q2q2 q3q3 q4q4 q5q5 Given a kinematic chain (serial linkage), the position/orientation of one end relative

More Complicated Example

d1

d2

1

2

d3

(x,y)

3

Redundant linkage Infinite number of solutions Self-motion space

Page 22: Inverse Kinematics. Inverse Kinematics (IK) T q1q1 q2q2 q3q3 q4q4 q5q5 Given a kinematic chain (serial linkage), the position/orientation of one end relative

More Complicated Example

d1

d2

1

2

d3

(x,y)

3

1-D space(self-motionspace)

d3d2

d1(1,2,3)

Page 23: Inverse Kinematics. Inverse Kinematics (IK) T q1q1 q2q2 q3q3 q4q4 q5q5 Given a kinematic chain (serial linkage), the position/orientation of one end relative

More Complicated Example

d1

d2

1

2

d3

3

No redundancy Finite number of solutions

(x,y,)

d3d2

d1(1,2,3)

Page 24: Inverse Kinematics. Inverse Kinematics (IK) T q1q1 q2q2 q3q3 q4q4 q5q5 Given a kinematic chain (serial linkage), the position/orientation of one end relative

General Results from Kinematics

Number of DOFs of a linkage (dimensionality of velocity space):

NDOF = k(Nlink – 1) – (k–1)Njoint

where k = 3 if the linkage is planar and k = 6 if it is in 3-D space (Grübler formula, 1883).

Examples: - Open chain: Njoint = Nlink – 1 NDOF = Njoint

- Closed chain: Njoint = Nlink NDOF = Njoint – k

Nlink = 4Njoint = 3NDOF = 3(4-1)-(3-1)3 = 3

Nlink = 4Njoint = 4NDOF = 1

Page 25: Inverse Kinematics. Inverse Kinematics (IK) T q1q1 q2q2 q3q3 q4q4 q5q5 Given a kinematic chain (serial linkage), the position/orientation of one end relative

General Results from Kinematics

Number of DOFs of a linkage (dimension of velocity space):

NDOF = k(Nlink – 1) – (k–1)Njoint

where k = 3 if the linkage is planar and k = 6 if it is in 3-D space (Grübler formula, 1883).

Examples: - Open chain: Njoint = Nlink – 1 NDOF = Njoint

- Closed chain: Njoint = Nlink NDOF = Njoint – k

Nlink = 4Njoint = 3NDOF = 3(4-1)-(3-1)3 = 3

Nlink =Njoint = NDOF =

Page 26: Inverse Kinematics. Inverse Kinematics (IK) T q1q1 q2q2 q3q3 q4q4 q5q5 Given a kinematic chain (serial linkage), the position/orientation of one end relative

General Results from Kinematics

Number of DOFs of a linkage (dimension of velocity space):

NDOF = k(Nlink – 1) – (k–1)Njoint

where k = 3 if the linkage is planar and k = 6 if it is in 3-D space (Grübler formula, 1883).

Examples: - Open chain: Njoint = Nlink – 1 NDOF = Njoint

- Closed chain: Njoint = Nlink NDOF = Njoint – k

Nlink = 4Njoint = 3NDOF = 3(4-1)-(3-1)3 = 3

Nlink = 3Njoint = 3NDOF = 0

Page 27: Inverse Kinematics. Inverse Kinematics (IK) T q1q1 q2q2 q3q3 q4q4 q5q5 Given a kinematic chain (serial linkage), the position/orientation of one end relative

General Results from Kinematics

Number of DOFs of a linkage (dimension of velocity space):

NDOF = k(Nlink – 1) – (k–1)Njoint

where k = 3 if the linkage is planar and k = 6 if it is in 3-D space (Grübler formula, 1883).

Examples: - Open chain: Njoint = Nlink – 1 NDOF = Njoint

- Closed chain: Njoint = Nlink NDOF = Njoint – k5 amino-acids10 - joints10 linksNDOF = 4

Page 28: Inverse Kinematics. Inverse Kinematics (IK) T q1q1 q2q2 q3q3 q4q4 q5q5 Given a kinematic chain (serial linkage), the position/orientation of one end relative

General Results from Kinematics

6-joint chain in 3-D space: NDOF=0 At most 16 distinct IK solutions

Page 29: Inverse Kinematics. Inverse Kinematics (IK) T q1q1 q2q2 q3q3 q4q4 q5q5 Given a kinematic chain (serial linkage), the position/orientation of one end relative

IK Methods

Analytical (exact) techniques (only for 6 joints) Write forward kinematics in the form of

polynomial equations (use t = tan(/2) Simplify, e.g., using the fact that two

consecutive torsional angles and have intersecting axes [Coutsias, Seck, Jacobson, Dill, 2004]

Solve

E.A. Coutsias, C. Seok, M.P. Jacobson, and K.A. Dill.A Kinematic View of Loop Closure. J. Comp. Chemistry, 25:510-528, 2004

Page 30: Inverse Kinematics. Inverse Kinematics (IK) T q1q1 q2q2 q3q3 q4q4 q5q5 Given a kinematic chain (serial linkage), the position/orientation of one end relative

Decomposition Method for Randomly Sampling Conformations

of Closed Chains Decompose closed chain into:

• 6 “passive” joints • n-6 “active” joints

Page 31: Inverse Kinematics. Inverse Kinematics (IK) T q1q1 q2q2 q3q3 q4q4 q5q5 Given a kinematic chain (serial linkage), the position/orientation of one end relative

Decompose closed chain into:• 6 “passive” joints • n-6 “active” joints

Sample the active joint parameters

Compute the passive joint parameters using exact IK solver

Decomposition Method for Randomly Sampling Conformations

of Closed Chains

J. Cortés, T. Siméon, M. Renaud-Siméon, and V. Tran. Geometric Algorithms for the Conformational Analysis of Long Protein Loops. J. Comp. Chemistry, 25:956-967, 2004

Page 32: Inverse Kinematics. Inverse Kinematics (IK) T q1q1 q2q2 q3q3 q4q4 q5q5 Given a kinematic chain (serial linkage), the position/orientation of one end relative

Application of Decomposition Method

Amylosucrase

Page 33: Inverse Kinematics. Inverse Kinematics (IK) T q1q1 q2q2 q3q3 q4q4 q5q5 Given a kinematic chain (serial linkage), the position/orientation of one end relative
Page 34: Inverse Kinematics. Inverse Kinematics (IK) T q1q1 q2q2 q3q3 q4q4 q5q5 Given a kinematic chain (serial linkage), the position/orientation of one end relative

IK Methods

Analytical (exact) techniques (only for 6 joints) Write forward kinematics in the form of

polynomial equations (use t = tan(/2) Simplify, e.g., using the fact that two

consecutive torsional angles and have intersecting axes [Coutsias, Seck, Jacobson, Dill, 2004]

Solve Iterative (approximate) techniques

Page 35: Inverse Kinematics. Inverse Kinematics (IK) T q1q1 q2q2 q3q3 q4q4 q5q5 Given a kinematic chain (serial linkage), the position/orientation of one end relative

CCD (Cyclic Coordinate Descent) Method

Generate random conformation with one end of chain at required position/orientation

Repeat until other end is at required position/orientation or algorithm is stuck at local minimum– Pick one DOF– Change to minimize

closure distanceL.T. Wang and C.C. Chen. A Combined Optimization Method for Solving the Inverse Kinematics Problem of Mechanical Manipulators.IEEE Tr. On Robotics and Automation, 7:489-498, 1991.

Page 36: Inverse Kinematics. Inverse Kinematics (IK) T q1q1 q2q2 q3q3 q4q4 q5q5 Given a kinematic chain (serial linkage), the position/orientation of one end relative

fixed end

moving end

Application of CCD to Proteins

Closure Distance: 2 22

S N N C C C C

Compute and move s.t. 0ii

Sq

q

A.A. Canutescu and R.L. Dunbrack Jr.Cyclic coordinate descent: A robotics algorithm for protein loop closure. Prot. Sci. 12:963–972, 2003.

Page 37: Inverse Kinematics. Inverse Kinematics (IK) T q1q1 q2q2 q3q3 q4q4 q5q5 Given a kinematic chain (serial linkage), the position/orientation of one end relative

Example: TM0813

GLU-77

GLY-90

PDB: 1J5X, 342 res.2.8Å resolution12 residue gapBest: 0.6Å aaRMSD

Page 38: Inverse Kinematics. Inverse Kinematics (IK) T q1q1 q2q2 q3q3 q4q4 q5q5 Given a kinematic chain (serial linkage), the position/orientation of one end relative

Example: TM0813

GLU-77

GLY-90

PDB: 1J5X, 342 res.2.8Å resolution12 residue gapBest: 0.6Å aaRMSD

Page 39: Inverse Kinematics. Inverse Kinematics (IK) T q1q1 q2q2 q3q3 q4q4 q5q5 Given a kinematic chain (serial linkage), the position/orientation of one end relative

Advantages of CCD

Simplicity No singularity problem Possibility to constrain each joint independent of all others

But may get stuck at local minima!

Page 40: Inverse Kinematics. Inverse Kinematics (IK) T q1q1 q2q2 q3q3 q4q4 q5q5 Given a kinematic chain (serial linkage), the position/orientation of one end relative

CCD with Ramachandran Maps

Ramachandran maps assign probabilities to φ-ψ pairs

φ

ψ

Page 41: Inverse Kinematics. Inverse Kinematics (IK) T q1q1 q2q2 q3q3 q4q4 q5q5 Given a kinematic chain (serial linkage), the position/orientation of one end relative

CCD with Ramachandran Maps

Ramachandran maps assign probabilities to φ-ψ pairs

Change a pair (φi,ψi) at each iteration: Compute change to φi

Compute change to ψi based on change to φi

Accept with probability min(1,Pnew/Pold)

Page 42: Inverse Kinematics. Inverse Kinematics (IK) T q1q1 q2q2 q3q3 q4q4 q5q5 Given a kinematic chain (serial linkage), the position/orientation of one end relative

IK Methods

Analytical (exact) techniques (only for 6 joints) Write forward kinematics in the form of

polynomial equations (use t = tan(/2) Simplify, e.g., using the fact that two

consecutive torsional angles and have intersecting axes [Coutsias, Seck, Jacobson, Dill, 2004]

Solve Iterative (approximate) techniques

Page 43: Inverse Kinematics. Inverse Kinematics (IK) T q1q1 q2q2 q3q3 q4q4 q5q5 Given a kinematic chain (serial linkage), the position/orientation of one end relative

Jacobian Matrix Q: n-vector of internal coordinates X: 6-vector defining endpoint’s

position/orientation n ≥ 6 Forward kinematics: X = F(Q) dxi = [∂fi(Q)/∂q1] dq1 +…+ [∂fi(Q)/∂qn]

dqn dX = J dQEfficient algorithm to compute Jacobian:

K.S. Chang and O. Khatib. Operational Space Dynamics: Efficient Algorithms for Modeling and Control of Branching Mechanisms. IEEE Int. Conf. on Robotics and Automation (ICRA),pp. 850-856, Sand Francisco, April 2000.

Page 44: Inverse Kinematics. Inverse Kinematics (IK) T q1q1 q2q2 q3q3 q4q4 q5q5 Given a kinematic chain (serial linkage), the position/orientation of one end relative

Jacobian Matrix J

∂f1(Q)/∂q1 ∂f1(Q)/∂q2 … ∂f1(Q)/∂qn

∂f2(Q)/∂q1 ∂f2(Q)/∂q2 … ∂f2(Q)/∂qn

……∂f6(Q)/∂q1 ∂f6(Q)/∂q2 … ∂f6(Q)/∂qn

Page 45: Inverse Kinematics. Inverse Kinematics (IK) T q1q1 q2q2 q3q3 q4q4 q5q5 Given a kinematic chain (serial linkage), the position/orientation of one end relative

Case where n = 6

J is a square 6x6 matrix. Problem: Given X, find Q such that X= F(Q) Start at any X0 = F(Q0) Method:

1. Interpolate linearly between X0 and X sequence X1, X2, …, Xp = X

2.For i = 1,…,p doa) Qi = Qi-1 + J-1(Qi-1)(Xi-Xi-1)

b) Reset Xi to F(Qi)

Page 46: Inverse Kinematics. Inverse Kinematics (IK) T q1q1 q2q2 q3q3 q4q4 q5q5 Given a kinematic chain (serial linkage), the position/orientation of one end relative

Case where n > 6

dX = J dQ J is an 6n matrix. Assume rank(J) = 6. Null space { dQ0 | J dQ0 = 0} has dim = n -

6

Page 47: Inverse Kinematics. Inverse Kinematics (IK) T q1q1 q2q2 q3q3 q4q4 q5q5 Given a kinematic chain (serial linkage), the position/orientation of one end relative

Case where n > 6

dX = J dQ J is an 6n matrix. Assume rank(J) = 6 Find J+ (pseudo-inverse) such that JJ+ = I

dQ = J+dX Null space { dQ0 | J dQ0 = 0} has dim = n -

6 dQ = J+dX + dQ0

arbitrarily chosenin null space

Page 48: Inverse Kinematics. Inverse Kinematics (IK) T q1q1 q2q2 q3q3 q4q4 q5q5 Given a kinematic chain (serial linkage), the position/orientation of one end relative

Computation of J+

1. SVD decomposition J = U VT where: - U in an 66 square orthonormal matrix- V is an n6 square orthonormal matrix- is of the form diag[i]:

2. J+ = V + UT where +=diag[1/i]

12

6

0

Page 49: Inverse Kinematics. Inverse Kinematics (IK) T q1q1 q2q2 q3q3 q4q4 q5q5 Given a kinematic chain (serial linkage), the position/orientation of one end relative

dX U66 VT6n dQ66

=

Getting Null spaceJ

Page 50: Inverse Kinematics. Inverse Kinematics (IK) T q1q1 q2q2 q3q3 q4q4 q5q5 Given a kinematic chain (serial linkage), the position/orientation of one end relative

dX U66 VTnn dQ6n

0=

Getting Null spaceJ

Gram-Schmidt orthogonalization

Page 51: Inverse Kinematics. Inverse Kinematics (IK) T q1q1 q2q2 q3q3 q4q4 q5q5 Given a kinematic chain (serial linkage), the position/orientation of one end relative

dX U66 VTnn dQ6n

0

(n-6) basis N of null space

=

Getting Null spaceJ

NT

Page 52: Inverse Kinematics. Inverse Kinematics (IK) T q1q1 q2q2 q3q3 q4q4 q5q5 Given a kinematic chain (serial linkage), the position/orientation of one end relative

Minimization of Target Function T with Closure

when n > 6Input: Chain with both ends at goal

positions and orientations

Repeat1. Compute Jacobian matrix J at current q2. Compute null-space basis N using SVD of J 3. Compute gradient T(q)4. Move along projection NNTy of y=-T(q) onto

N until minimum is reached or closure is broken New qI. Lotan, H. van den Bedem, A.M. Deacon and J.-C Latombe. Computing Protein Structures from Electron Density Maps: The Missing Loop Problem.

 Proc. 6th Workshop on Algorithmic Foundations of Robotics (WAFR `04)

Page 53: Inverse Kinematics. Inverse Kinematics (IK) T q1q1 q2q2 q3q3 q4q4 q5q5 Given a kinematic chain (serial linkage), the position/orientation of one end relative
Page 54: Inverse Kinematics. Inverse Kinematics (IK) T q1q1 q2q2 q3q3 q4q4 q5q5 Given a kinematic chain (serial linkage), the position/orientation of one end relative

Example: TM0813

GLU-77

GLY-90

PDB: 1J5X, 342 res.2.8Å resolution12 residue gapBest: 0.6Å aaRMSD

Page 55: Inverse Kinematics. Inverse Kinematics (IK) T q1q1 q2q2 q3q3 q4q4 q5q5 Given a kinematic chain (serial linkage), the position/orientation of one end relative

Example: TM0813

GLU-77

GLY-90

PDB: 1J5X, 342 res.2.8Å resolution12 residue gapBest: 0.6Å aaRMSD

Page 56: Inverse Kinematics. Inverse Kinematics (IK) T q1q1 q2q2 q3q3 q4q4 q5q5 Given a kinematic chain (serial linkage), the position/orientation of one end relative

Example: TM0813

GLU-77

GLY-90

PDB: 1J5X, 342 res.2.8Å resolution12 residue gapBest 0.6Å aaRMSD

Page 57: Inverse Kinematics. Inverse Kinematics (IK) T q1q1 q2q2 q3q3 q4q4 q5q5 Given a kinematic chain (serial linkage), the position/orientation of one end relative

TM1621

Green: manually completed conformation

Cyan: conformation computed by stage 1

Magenta: conformation computed by stage 2

The aaRMSD improved by 2.4Å to 0.31Å

Produced by H. van den Bedem

Page 58: Inverse Kinematics. Inverse Kinematics (IK) T q1q1 q2q2 q3q3 q4q4 q5q5 Given a kinematic chain (serial linkage), the position/orientation of one end relative

Multi-Modal Loop

Produced by H. van den Bedem

A323Hist

A316Ser