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Radioactive decay and the Bateman equation
Introduction to Nuclear Science
Simon Fraser UniversitySpring 2011
NUCS 342 January 19, 2011
NUCS 342 (Lecture 4) January 19, 2011 1 / 34
Outline
1 Natural radioactivity
2 Nuclear decay
3 Independent decay of radioactive mixture
4 The Bateman equation
5 Decay branches
NUCS 342 (Lecture 4) January 19, 2011 2 / 34
Outline
1 Natural radioactivity
2 Nuclear decay
3 Independent decay of radioactive mixture
4 The Bateman equation
5 Decay branches
NUCS 342 (Lecture 4) January 19, 2011 2 / 34
Outline
1 Natural radioactivity
2 Nuclear decay
3 Independent decay of radioactive mixture
4 The Bateman equation
5 Decay branches
NUCS 342 (Lecture 4) January 19, 2011 2 / 34
Outline
1 Natural radioactivity
2 Nuclear decay
3 Independent decay of radioactive mixture
4 The Bateman equation
5 Decay branches
NUCS 342 (Lecture 4) January 19, 2011 2 / 34
Outline
1 Natural radioactivity
2 Nuclear decay
3 Independent decay of radioactive mixture
4 The Bateman equation
5 Decay branches
NUCS 342 (Lecture 4) January 19, 2011 2 / 34
Natural radioactivity
Natural radioactivity
Natural radioactivity has been discovered by Henri Becquerel andMarie Sk lodowska-Curie in late 1890s.
Radioactive polonium and radium elements were isolated by Marieand Pierre Curie in 1898.
The process involves spontaneous disintegration of the parent elementand a formation of a daughter element.
A number of long-lifetime processes were identified since then:
-decay : emission of 4He-decay: emission of an electron and electron anti neutrinoelectron capture: capture of an electron from an atomic orbit by aproton+-decay: emission of a positron and electron neutrinoheavy fragment emission: for example 12C or 16Ofission: split of a nucleus into two fragments of comparable mass andcharge
NUCS 342 (Lecture 4) January 19, 2011 3 / 34
Natural radioactivity
Natural radioactivity
To quantify the decay process several measures can be introduced:
Activity A: number of disintegration per second
half-life T 12
: time after which the number of radioactive nuclei in asample is reduced to half of its initial value
lifetime : time after which the number of radioactive nuclei in asample is reduced by a factor of e 2.718 of its initial value.
NUCS 342 (Lecture 4) January 19, 2011 4 / 34
Natural radioactivity
Units
Lifetimes and half-lives are measured in units of time.
Nuclear lifetimes span broad range from 1020 s up to infinity (forstable nuclei).
The SI unit for activity is 1 Becquerel, abbreviated as [Bq],
1 [Bq] = 1 [dps] (decay/disintegration per second). (1)
An often used non-SI unit is 1 Curie, abbreviated [Ci].
1 [Ci] = 3.7 1010 [Bq] (2)
1 [Ci] corresponds to activity of 1 g of Radium and is a sizable unit.
Typical environmental levels of radioactivity are pico-nano Curie(0.01-10 [Bq]), research calibration sources are typically of microCurie (10 [kBq]) activity, a reactor upon a shutdown have activity inthe range of giga Curie ( 109 Ci or 1019 [Bq]).
NUCS 342 (Lecture 4) January 19, 2011 5 / 34
Natural radioactivity
Natural radioactivity
Some naturally occurring long-lived radioactive isotopes
Nuclide Half-life [years] Natural abundance4019K 1.28109 0.01%8737Rb 4.81010 27.8%11348Cd 91015 12.2%11549In 5.51014 95.7%
12852Te 7.71024 31.7%
13052Te 2.71021 33.8%
13857La 1.11011 0.09%
14460Nd 2.31015 23.8%
14762Sm 1.11011 15%
14862Sm 71015 11.3%
NUCS 342 (Lecture 4) January 19, 2011 6 / 34
Nuclear decay
Nuclear decay
One can show experimentally that the sample activity A isproportional to the number N of nuclei in the sample(decay is the first-order reaction).
Denoting the proportionality constant by and calling it the decayrate one obtains
A = N
Activity is the number of disintegration per second,
At = N(t) N(t + t) = (N(t + t) N(t))
A = N(t + t) N(t)t
= dNdt
Above equations when combined give
dNdt
= N
N(t) = N(0) exp(t)NUCS 342 (Lecture 4) January 19, 2011 7 / 34
Nuclear decay
Nuclear decay
Defining lifetime as
=1
the nuclear decay law can be written as
N(t) = N(0) exp( t
)It is easy to note that after time t = the number of radioactivenuclei in the samples is reduced by the factor of e
N() = N(0) exp(
)= N(0) exp1 =
1
eN(0)
NUCS 342 (Lecture 4) January 19, 2011 8 / 34
Nuclear decay
Nuclear decay
The half-life is
N(t = T 12) = N(0) exp
(T 1
2
)=
1
2N(0)
exp(T 1
2
)=
1
2
T 12
= ln
(1
2
)= ln(2)
T 12
=ln(2)
= ln(2) = 0.693
NUCS 342 (Lecture 4) January 19, 2011 9 / 34
Nuclear decay
Nuclear decay
T1/2 = 1.5, = T1/2/ ln(2) = 2.16
0
20
40
60
80
100
0 2 4 6 8 10
Num
ber
of a
tom
s [%
]
Time [arb.]
T1/2
2T1/2
3T1/2
NUCS 342 (Lecture 4) January 19, 2011 10 / 34
Nuclear decay
Nuclear decay
T1/2 = 1.5, = T1/2/ ln(2) = 2.16
1
10
100
0 2 4 6 8 10
Num
ber
of a
tom
s [%
]
Time [arb.]
T1/2
2T1/23T1/2
NUCS 342 (Lecture 4) January 19, 2011 11 / 34
Nuclear decay
Decay rate measurements
For large range of lifetimes measurements of the decay curves shownon the graphs above can be carried out and lifetimes/decay rates canbe fitted.
However, for lifetimes comparable or longer than the span of a humanlife there are no measurable changes in the activity of a sample whichprohibits direct decay curve measurements.
In these cases the decay rates are deduce from the ratio of observedactivity A to the absolute number of radioactive atoms N in a sample.
A = N = = 1
=N
A(3)
The absolute number of atoms can be established based on the totalmass of the sample and its isotopic composition.
Isotopic composition can be established using mass spectroscopy.
NUCS 342 (Lecture 4) January 19, 2011 12 / 34
Nuclear decay
Activity
It should be stressed that the activity of a sample depends on its massm (number of radioactive atoms) and the decay rate. Denoting themolar mass by and the Avogadro number by NA one gets
A = N = m
NA =
1
m
NA (4)
This implies that small mass of short-lived isotopes may have thesame activity as a large mass of long-lived isotopes.
For example 1 MBq of tritium (T1/2=12.33 y) corresponds to5.59 1014 or 1.1 [nmole] of atoms or 2.78 [ng] of mass
1 MBq of 14C (T1/2=5730 [y]) corresponds to 2.61017 or0.43 [mole] of atoms or mass of 6 [g].
NUCS 342 (Lecture 4) January 19, 2011 13 / 34
Nuclear decay
Detection efficiency
Radiation detectors are built to detect decay products.
As such detectors respond to activity.
In a typical experiments number of counts NC corresponding todetection of radiation of interest in a detector is recorded per unit oftime. The units of NC are counts per second.
This number of counts is related to the activity by the responsefunction of a detector called efficiency
NC = A (5)
Efficiency depends on the type and geometry of the detector, as wellas type and energy of detected radiation.
NUCS 342 (Lecture 4) January 19, 2011 14 / 34
Nuclear decay
Activation analysis
Tritium is produced in atmosphere by reaction of fast neutronsgenerated by cosmic rays with 14N
n +14 N 12 C +3 H (6)
Tritium is then incorporated into water and remove from atmosphereas rain and snow.
A 50 ml sample of water typically show 1 [dpm] (disintegration perminute) associated with the decay of tritium to 3He. Based onthat let us estimate number ratio of tritium to hydrogen in water.
The number of tritium atoms in the sample is
N3H =1
A = A = 12.33 [y]1 [1/min] = 6.5106 = 1.081017 [mole]
(7)
NUCS 342 (Lecture 4) January 19, 2011 15 / 34
Nuclear decay
Activation analysis
The number of tritium atoms in the sample is
N3H =1
A = A = 12.33 [y]1 [1/min] = 6.5106 = 1.081017 [mole]
The mass of the 50 ml sample is 50 g.
The number of water molecules in the sample is
NH2O =m
=
50
18.02= 2.77 [mole] = 16.7 1023 (8)
There are two hydrogen atoms per molecule, thus the tritium tohydrogen number ratio is
N3HN1H
=1.08 1017
5.54= 2 1018 (9)
NUCS 342 (Lecture 4) January 19, 2011 16 / 34
Independent decay of radioactive mixture
Independent decay of radioactive mixture
Quite often radioactive samples are mixtures of radioactivitiesdecaying at different rates.
If the decay products from both samples are the same (for exampleelectrons from decay) a detector will see the combined decay ofthe mixture.
In such cases a special care has to be taken if lifetimes are extracted.A common procedure is to extract parameters for the longest-livedactivity first, subtract it from the data, analyze the next longest lived,etc.
Currently this is done using computer fits.
An example for a two-component mixture is analyzed below.
NUCS 342 (Lecture 4) January 19, 2011 17 / 34
Independent decay of radioactive mixture
Independent decay of two radioactivities
N(t)=70 exp( t
ln(2)1.5
)+30 exp
( t
ln(2)15
)
0
20
40
60
80
100
0 5 10 15 20 25 30 35 40
Num
ber
of a
tom
s [%
]
Time [arb.]
NUCS 342 (Lecture 4) January 19, 2011 18 / 34
Independent decay of radioactive mixture
Independent decay of two radioactivities
N(t)=70 exp( t
ln(2)1.5
)+30 exp
( t
ln(2)15
)
10
100
0 5 10 15 20 25 30 35 40
Num
ber
of a
tom
s [%
]
Time [arb.]
NUCS 342 (Lecture 4) January 19, 2011 19 / 34
The Bateman equation
Decay chains
Decay chains in which radioactive decay of an unstable isotope feedsradioactive decay of another unstable isotope are commonlyencountered in nature and experimental nuclear science.
For example, there are three naturally occurring, long-lived chains of and decays originating in the long-lived isotopes of 232Th(T1/2=14.1 Gy),
235U (T1/2=0.7 Gy) and238U (T1/2=4.5 Gy).
Another example is a sequence of decay of unstable isotopes alongthe mass parabolas for a fixed mass number until the most stableisotope is reached.
In case of the decay chain activities and abundances of radioactiveisotopes are not independent. Rather, they are determined by thehistory of the decay: the decay rates and abundances in the precedingpart of the chain.
Thus the chain decay is different then independent decay of a mixtureconsidered so far.
NUCS 342 (Lecture 4) January 19, 2011 20 / 34
The Bateman equation
235U and 238U chains
NUCS 342 (Lecture 4) January 19, 2011 21 / 34
The Bateman equation
The Bateman equation
The Bateman equation is a mathematical model describingabundances and activities in a decay chain as a function of time,based on the decay rates and initial abundances.
The Bateman equation is not a single equation, rather it is a methodof setting up differential equations describing the chain of interestbased on its known properties.
We are going to consider the simplest case with a parent feedingsingle daughter.
Then by varying the parameters such as the decay rates and relativeinitial abundances we will investigate the chain evolution as a functionof time.
NUCS 342 (Lecture 4) January 19, 2011 22 / 34
The Bateman equation
Two-decay chain
Let us denote
Initial number of parent and daughter atoms as N1(0) and N2(0)Number of parent and daughter atoms in time as N1(t) and N2(t)Parent and daughter activities in time as A1(t) and A2(t)Parent and daughter decay rates by 1 and 2
The equation for the time evolution of the parent is the same as for asingle step decay
dN1(t)
dt= 1N1(t) (10)
The equation for the time evolution of the daughter, however,includes a term describing daughter decay but also daughter feedingby the parent
dN2(t)
dt= 2N2(t) + 1N1(t) (11)
NUCS 342 (Lecture 4) January 19, 2011 23 / 34
The Bateman equation
Two-decay chain
The solution of Eq. 10 is
N1(t) = N1(0) exp (1t) (12)
Taking this into account Eq. 11 become
dN2(t)
dt= 2N2(t) + N1(0) exp (1t) (13)
The solution for N2(t) is
N2(t) = N2(0) exp (2t) +
N1(0)1
2 1(exp (2t) exp (1t)) (14)
NUCS 342 (Lecture 4) January 19, 2011 24 / 34
The Bateman equation
Two-decay chain: abundance for a special case
Blue: parent T1/2=1.5, N1(0) = 100%Red: daughter T1/2=3, N2(0) = 0%
20
40
60
80
100
0 2 4 6 8 10 12 14
Num
ber
of a
tom
s [%
]
Time [arb.]
NUCS 342 (Lecture 4) January 19, 2011 25 / 34
The Bateman equation
Two-decay chain: abundances for a special case
Blue: parent T1/2=1.5, N1(0) = 100%Red: daughter T1/2=3, N2(0) = 0%
1
10
100
0 2 4 6 8 10 12 14
Num
ber
of a
tom
s [%
]
Time [arb.]
NUCS 342 (Lecture 4) January 19, 2011 26 / 34
The Bateman equation
Two-decay chain: activities
Eqs 12 and 14 define abundances
Activities of the parent and the daughter can be calculated from
A1(t) = 1N1(t) = 1N1(0) exp (1t)A2(t) = 2N2(t) = 2N2(0) exp (2t) + (15)
N1(0)122 1
(exp (2t) exp (1t))
NUCS 342 (Lecture 4) January 19, 2011 27 / 34
The Bateman equation
Two-decay chain: activities for a special case
Blue: parent T1/2=1.5, N1(0) = 100%Red: daughter T1/2=3, N2(0) = 0%
10
20
30
40
50
60
70
0 2 4 6 8 10 12 14
Dec
ay p
er u
nit t
ime
Time [arb.]
NUCS 342 (Lecture 4) January 19, 2011 28 / 34
The Bateman equation
Two-decay chain: activities for a special case
Blue: parent T1/2=1.5, N1(0) = 100%Red: daughter T1/2=3, N2(0) = 0%
1
10
100
0 2 4 6 8 10 12 14
Dec
ay p
er u
nit t
ime
Time [arb.]
NUCS 342 (Lecture 4) January 19, 2011 29 / 34
Decay branches
Decay branches
Decay branches are observed when there is more than a single processfor disintegration of the parent nucleus.
For example, in the decay chain of 238U 218Po can -decay to 214Pbor decay to 218At.
Another example is in the decay chain of 235U with 227Ac having an branch to 223Fr and a decay branch to 227Th.
Yet another example are decays of 235U and 238U by spontaneousfission which is a tiny, however, existing branch as compared to thedominating decay.
NUCS 342 (Lecture 4) January 19, 2011 30 / 34
Decay branches
235U and 238U chains
NUCS 342 (Lecture 4) January 19, 2011 31 / 34
Decay branches
Total decay rate and branching ratios
For clarity, let us consider two competing branches in the decayingparent: an and a branch.
The decay rates and define probability per unit time fordisintegration by the respective process. The total probability fordisintegration is
= + (16)
Relative probability for each branch decay, called the branching ratio,is the ratio of the respective decay rate to the total decay rate
br =
=
+
br =
=
+ (17)
NUCS 342 (Lecture 4) January 19, 2011 32 / 34
Decay branches
Lifetime and partial lifetimes
The decay (without feeding) is defined by the total rate
dN(t)
dt= N(t) = ( + )N(t) =
N(t) = N(0) exp (t)) = N(0) exp (( + )t) =N(0) exp (t) exp (t) (18)
Lifetime of the parent is defined by the total rate
=1
(19)
Partial lifetimes for the decays are defined as
=1
, =
1
(20)
NUCS 342 (Lecture 4) January 19, 2011 33 / 34
Decay branches
Lifetime and partial lifetimes
Note that while = + (21)
and the total rate is dominated by the larger of , partial rates.
For the lifetime and partial lifetimes this implies
1
=
1
+
1
(22)
and the lifetime of the parent is dominated by the shorter partiallifetime.
It should be stressed that
6= +
and that there is only one lifetime defining decay of the parent.Partial lifetimes can be extracted from measured branching ratios.
NUCS 342 (Lecture 4) January 19, 2011 34 / 34
Natural radioactivityNuclear decayIndependent decay of radioactive mixtureThe Bateman equationDecay branches