7/25/2019 Initial Analysis UMPT Load 48 Percent

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Dear all,

Regarding ca

"umber

#

$

4

'

(

8

7/25/2019 Initial Analysis UMPT Load 48 Percent

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Here we ha

!or simulati

*he pre,ict

Cut o3 is sa

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e UMPT load cut off 48%, here is some Q&A that could be initial analsis!

Question

)hat is *"+AP *aabilit defined b -

)hat is the ma. *"+AP *a if /e ha0e onl )MPT -

1o/ if /e al UMPT -

2t is no/ UMPT alread! )h does UMPT board load cut off at 48% -

1o/ does 48% come -

3o, although /e ha0e UMPT but no license then it has no benefit in *"+AP *aabilit -

)hat it is the solution -

)hat is the meaning of (350 excluded)-

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e sample from actual CNBAP usage taken from site 140245

on" # appl$ formula" if CNBAP usage %&1'0 then ()P* +oa, stuck on -1'0./50

e, pattern will e as elow -compare, to actual Boar, loa,

me at level of 4

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Ans/er

2t is combination bet/een te of rocessor module te and number of )++P

2t is #(5, if /e ha0e )++Pb6d 7 , or if /e ha0e at least one )++Pf! 93ee table:!

2t /ill increased the *"+AP *a significantl! 93ee table:!

9: Then actual *"+AP *aabilit stuc; on #(5, e0en alread has UMPT!

)hen *"+AP usage hit 7#(5!

Actual *"+AP *aabilit onl #(5, but sstem calculate as if it has 5! Then the ma.imum UMPT board load is < #(5

3usicousl, es!

These are the susicionust fill the number of desired license out of 5! ?or e.amle, oen the license and gi0e it #5/ill get 5#5545! + doing so /e get 45 in actual, and sol0e the *"+AP issue!

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