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Independent Samples: Comparing Proportions. Lecture 42 Section 11.5 Fri, Apr 8, 2005. Confidence Intervals. A confidence interval for p 1 – p 2 is of the form. or. Confidence Intervals. - PowerPoint PPT Presentation
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Independent Independent Samples: Samples:
Comparing Comparing ProportionsProportionsLecture 42Lecture 42
Section 11.5Section 11.5
Fri, Apr 8, 2005Fri, Apr 8, 2005
Confidence IntervalsConfidence Intervals
A confidence interval for A confidence interval for pp11 – – pp22 is of is of the formthe form
21 ˆˆ21 ˆˆ ppzpp
oror
1
22
1
1121
ˆ1ˆˆ1ˆˆˆ
n
pp
n
ppzpp
Confidence IntervalsConfidence Intervals
Since we are trying to estimate the Since we are trying to estimate the difference between difference between pp11 and and pp22, it , it
would not make sense to use the would not make sense to use the pooled estimate ofpooled estimate of..
ExampleExample
Re-do Example 11.8, p. 669, as a Re-do Example 11.8, p. 669, as a confidence interval problem.confidence interval problem.
Confidence Intervals on Confidence Intervals on the TI-83the TI-83
Press STAT.Press STAT. Select 2-PropZInt.Select 2-PropZInt.
A window appears.A window appears.
Enter Enter xx11..
Enter Enter nn11..
Enter Enter xx22..
Enter Enter nn22..
Confidence Intervals on Confidence Intervals on the TI-83the TI-83
Enter the confidence level.Enter the confidence level. Select Calculate.Select Calculate. Press ENTER.Press ENTER.
Confidence Intervals on Confidence Intervals on the TI-83the TI-83
A window appears with the following A window appears with the following information.information. The confidence interval for The confidence interval for pp11 – – pp22..
The value of The value of pp11^̂..
The value of The value of pp22^̂..
nn11..
nn22..
ExampleExample
Re-do Example 11.8, p. 669, using Re-do Example 11.8, p. 669, using the TI-83.the TI-83.
Let’s Do It!Let’s Do It!
Let’s do it! 11.7, p. 671 – HMOs on Let’s do it! 11.7, p. 671 – HMOs on the Rise.the Rise.