II-C Power & Energy Systems

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    II-C Power & Energy SystemsDennis Buckmaster

    [email protected]://engineering.ecn.purdue.edu/~dbuckmas/

    OUTLINE

    Internal combustion engines

    Hydraulic power circuits Mechanical power transmission

    Electrical circuit analysis (briefly)

    mailto:[email protected]:[email protected]
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    References

    Engineering Principles of

    Agricultural Machinery, 2nd

    ed. 2006. Srivastava,

    Goering, Rohrbach,

    Buckmaster. ASABE.

    Off-Road Vehicle

    Engineering Principles.2003. Goering, Stone, Smith,

    Turnquist. ASABE.

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    Other good sources

    Fluid Power Circuits and

    Controls: Fundamentals

    and Applications. 2002.

    Cundiff. CRC Press.

    Machine Design for

    Mobile and Industrial

    Applications. 1999. Krutz,Schueller, Claar. SAE.

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    Engines

    Power and Efficiencies

    Thermodynamics

    Performance

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    Engine Power Flows

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    Power&

    Efficiencies

    Fuel equivalent

    Pfe,kW = (HgkJ/kgf,kg/h)/3600

    [Hg = 45,000 kJ/kg for No. 2 diesel] Indicated

    Pi,kW = pime,kPaDe,lNe,rpm/120000

    BrakePb,kW = 2TNmNe,rpm/60000

    Friction

    Pf

    = Pi

    -Pb

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    Power &

    Eff iciencies

    Indicated Thermal

    Eit = Pi/Pfe

    MechanicalEm = Pb/Pi

    Overall (brake thermal)

    Ebt = Pb/Pfe = Eit*Em Brake Specific Fuel Consumption

    BSFC= f,kg/h/Pb,kW

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    Dual Cycle

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    Related equations

    Compression ratio = rr = V1/V2

    Displacement

    De,l = (V1-V2)*(# cylinders)= (borecm)

    2(strokecm)*(# cyl)/4000

    Ideal gas

    p1V1/T1 = P2V2/T2 Polytropic compression or expansion

    p2/p1 = rn

    [n = 1 (isothermal) to 1.4 (adiabatic), about 1.3 during

    compression & power strokes]

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    Air intakea,kg/h = .03De,lNe,rpma,kg/cu mv,decimal

    From Stoichiometry (fuel chemistry) A/F = air to fuel mass ratio = 15:1 for cetane

    Related equations

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    What is the displacement of a 6 cylinder

    engine having a 116 mm bore and 120 mm

    stroke?

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    For this same engine (7.6 l displacement, 2200 rpm rated speed), what is the air

    consumption if it is naturally aspirated and has a volumetric efficiency of 85%?

    Assume a typical day with air density of 1.15 kg/m3.

    With a stoichiometric air to fuel ratio based on cetane, at what rate could fuel

    theoretically be burned?

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    Consider the this same (595 Nm, 137 kW @ 2200 rpm) engine which has a high

    idle speed of 2400 rpm and a torque reserve of 30%; peak torque occurs at 1300

    rpm. Sketch the torque and power curves (versus engine speed).

    Torque (Nm)

    Speed (rpm)

    Power (kW)

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    17

    A quick problem

    Diesel engine generating 60 kW at 2300 rpm

    Q: torque available

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    Power Hydraulics

    Principles

    Pumps, motors

    Cylinders

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    About Pressure

    14.7 psia STP (approx __ in Hg)

    Gage is relative to atmospheric

    Absolute is what it says absolute & relative to

    perfect vacuum

    What causes oil to enter a pump?

    Typical pressures: Pneumatic system

    Off-road hydraulic systems

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    20

    Liquids Have no Shape of their own

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    21

    Liquids are

    Practically Incompressible

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    Pascals Law

    Pressure Exerted on a Confined Fluid is

    Transmitted Undiminished in All Directions

    and Acts With Equal Force on Equal Areas

    and at Right Angles to Them.

    22

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    Application Principles

    1 lb (.45kg)Force

    1 sq in (.65cm2)

    Piston Area

    1 psi

    (6.9kpa)

    10 sq in

    (6.5cm2)

    Piston Area

    10 lbs (4.5kg)

    23

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    24

    Hydraulic lever

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    Types of Hydraulic Systems

    Open Center

    Closed Center

    The control valve that regulates the flow from the pump

    determines if system is open or closed.

    Do not confuse Hydraulics with the Closed Loop of thePower Train. (Hydro)

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    Trapped Oil

    Closed Center HydraulicsOpen Center

    Flow in Neutral

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    Extend 27

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    Retract 28

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    Neutral Again 29

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    Pumps

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    Pump Inefficiency

    Leakage: you get less flow from a pump

    than simple theory suggests.

    Increases with larger pressure difference

    Friction: it takes some torque to turn a

    pump even if there is no pressure rise

    Is more of a factor at low pressures

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    Efficiency of pumps & motors

    Em mechanical efficiency < 1 due to

    friction, flow resistance

    Ev

    volumetric efficiency < 1 due to

    leakage

    Eo =overall efficiency = Em * Ev

    Eo

    = Power out/power in

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    Speed

    Flow

    Qgpm = Dcu in/rev Nrpm /231

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    Pressure Rise

    Torque

    Required

    Tinlb = Dcu in/revPpsi /(2)

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    Pressure

    Flow

    Theoretical pump

    Effect of leakage

    Relief valve or pressure

    compensator

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    Pressure

    Flow

    Constant power curve

    Php = Ppsi Qgpm/1714

    1 If t t

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    1a. If a pump turns at

    2000 rpm with a

    displacement of 3

    in3/rev, theoretically,how much flow is

    created?

    1b. If the same pump is

    95% volumetrically

    efficient (5%

    leakage), how muchflow is created?

    Example pump

    problems

    2 If 8 i i d

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    Example pump

    problems

    2a. If 8 gpm is required

    and the pump is to turn

    at 1750 rpm, what

    displacement istheoretically needed?

    2b. If the same pump willreally be is 90%

    volumetrically efficient

    (10% leakage), what is

    the smallest pump tochoose?

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    3a. A 7 in3/rev pump is to

    generate 3000 psi

    pressure rise; how much

    torque will it theoreticallytake to turn the pump?

    3b. If the same pump is91% mechanically

    efficient (9% friction &

    drag), how much torque

    must the prime moverdeliver?

    Example pump

    problems

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    Example motor

    problemIf a motor with 2 in3/rev

    displacement and 90%

    mechanical and 92%volumetric efficiencies

    receives 13 gpm at

    2000 psi

    a. How much fluid poweris received?

    b. What is its overall

    efficiency?c. How fast will it turn?

    d. How much torque will

    be generated?

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    Cylinders

    Force balance on

    piston assembly: FexternalP1 * A1 P2 * A2

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    42

    3000 psi system

    2 bore cylinder

    Extends 24 inches in 10seconds

    Q: max force generated

    max work done

    power used

    flow required

    Example cylinder

    problem

    Tractor source with 2500 psi

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    Tractor source with 2500 psiand 13 gpm available

    Return pressure tax of 500 psi

    Cylinder with 3 bore, 1.5 roddiameters

    Q1: How much force will thecylinder generate?

    Q2: How long will it take to

    extend 12 inches?

    Example cylinder

    problem

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    Power Transmission

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    Transmissions transform power

    a torque for speed torque tradeoff

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    Gears

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    Planetary Gear Sets

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    Belt & Chain Drives

    Speed ratio determined by sprocket teeth

    or belt sheave diameter ratio

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    FIRST GEAR

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    First gear speeds if Input shaft: 1000 rpm

    Main countershaft: 1000 (22/61) = 360 rpm

    Ratio = input speed/output speed = 1000/360 = 2.78

    Ratio = output teeth/input teeth = 61/22 = 2.78Secondary countershaft: 360 rpm (41/42) = 351 rpm

    Output shaft: 351 rpm (14/45) = 109 rpm

    RATIO: input speed/output speed = 1000/109 = 9.2

    Product of output teeth/input teeth = (61/22)(42/41)(45/14) = 9.2

    FIRST GEAR

    If 50 kW @ 2400 d iE l

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    If 50 kW @ 2400 rpm drives a

    pinion gear with 30 teeth and

    the meshing gear has 90

    teeth (assume 98%efficiency)

    Q1: What is the speed of the

    output shaft? Q2: How much power leaves

    the output shaft?

    Q3: How much torque leaves

    the output shaft?

    Example gear

    problem

    If th f l tE l l t

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    If the sun of a planetary gear

    set turns at 1000 rpm, what

    speed of the ring would

    result in a still planetcarrier? Teeth on gears are

    sun: 20 and ring: 100.

    Example planetary

    gear problem

    If a belt dri e from a 1750 rpmE l b lt

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    If a belt drive from a 1750 rpm

    electric motor is to transmit

    5 hp to a driven shaft at 500

    rpm and the small sheavehas a pitch diameter of 4

    Q1: What should the pitch

    diameter of the other pulleybe?

    Q2: Which shaft gets the small

    sheave?

    Q3: How much torque doesthe driven shaft receive?

    Example belt

    problem

    Php = Tft-lbNrpm/5252

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    Electricity

    Voltage = Current * Resistance

    Vvolts = Iamps * Rohms

    Power = voltage times current

    PWatts = Vvolts*Iamps

    VI R

    Th T f Ci it

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    Three Types of Circuits

    SeriesSame current, voltage divided

    +

    -12 v.

    Parallel

    Same voltage, current divided

    Series / Parallel

    A 12 V DC solenoid aE l 12 V DC

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    A 12 V DC solenoid a

    hydraulic valve has a 5 amp

    fuse in its circuit.

    Q1: What resistance would

    you expect to measure as

    you troubleshoot its

    condition?Q2: How much electrical

    power does it consume?

    Example 12 V DC

    problem

    Q1: Identify specifications forE l 12 V DC

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    Q1: Identify specifications for

    a relay of a 12 V DC lighting

    circuit on a mobile machine

    if the circuit has four 60Wlamps.

    Q2: Would the lamps be wiredin series or parallel?

    Example 12 V DC

    problem

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    Good luck on the PE Exam!

    My email address:[email protected]

    My web page:https://engineering.ecn.purdue.edu/~dbuckmas/

    Note ASABE members can access ASABEtexts electronically at:

    http://asae.frymulti.com/toc.asp

    mailto:[email protected]://cobweb.ecn.purdue.edu/~dbuckmas/http://asae.frymulti.com/toc.asphttp://asae.frymulti.com/toc.asphttp://cobweb.ecn.purdue.edu/~dbuckmas/mailto:[email protected]