IES Electronics 2010

8/13/2019 IES Electronics 2010

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DO NOT OPEN Til lS TEST BOOKLET UNTTL YOU ARE ASKED TO DO SO

T.B.C. : Q-GUG-K-FUA Test Booklet Series

Serial062440

TEST OOKLET

ELECTRONICS & T E L E C O M M U N I C T I O N ~ E N G

PAPER ITime Allmved Two Hours

1.

2.

},,,

5.

().

8.

INSTRUCTIONS

IivlivfED. ATELY AFTER THE COivtMENCEMENTOF THEM - 1 > ~N~ l O N ,

YOU SH-OULD.CHECI\ THAT THIS TEST BOOKLET DOES NOT i ~ ~~ NPHINTED OR TOHN) ~ , M I S S I N GPAGES 0.H ITEMS. ETC. IF SO, GE IT I > ,A_CED .llY A COMPLETE

T l < . ~ TBOOKLET.

ENCODE CLEARLY THE TEST BOOKLET SE E , C, OH D AS THE CASE l\1AYBE IN l HE APPROP UATE PLACE IN THE ~ : I B I E E T

You have to enter vour Roll Number on tl ITest Booklel in th; Box provided a l o nr s c '. 0 S I } JDO NOT 11.-Tite anything else on t ' - ~) o ~ c t . .Tim Test Booklet contains 120 l t~ 1:> ( q estions). Each item comprises four respo nse:-:\an ;wersi. 'r'ou will select Lhe .. n. hich vou want to mark on the Answer Sheet. Incase ynu fed thal there is r t r ne cor;ect response, mark ihe response which y ouconsider the best. fn any e~ , clfl os Nl Y ONE response IIH each item.You have lo mark all u-r ;;}o ses ONLY on the separate Answer Sheet provided. Sl'edirection:> in the A~ ~ ' ' S 1 t ' ..All items carry eq . H1 ' sBe (m' you procee n k in the A ~ 1 s w e r~ h e e tthe respor:se lo v a r i o u ~i tems in the TestJ_)O\lklct y o u~ a v eto . u; s


2/44I

L

~ .

:r

'T'Iw nHT\:nt. 1n the above- network is

ra: ' tity l + e LI uiti

i b il

~ ~ t ~ t I u ti

c) I + + e 1 I u t)

i j ) I t - ..... e t I uft.J

When waves travel along a transnw;sion linefrom a generator lo a load, lhrough whichreg1011 is powl'r transmission laking place ?

i ; ~i Only throug-h llw conducting region . ...

i b Only through thercgl(Jns

l e i Both tlll'OIJgh conductingnon-eunducti ng regions

idi

2

mode of lhe above shown

1ai x t l = ui2 + U

lbi x\U :::: uil 2i

i CJ,, XIt i "' \1 ~ U

id x ti = ui t l )

5.

Consider the following statements :

. Power factor will be unity.

2 Current in circuit will b(' maximum.

3. Current in circuit will be minimum.

\Vhich of these statements are correct. \Vilhrespect to resonance in R-L-C parallel circuiL?

la'i L 2 and :

b) 1 and 2 only

c l 2 and 3 only

~ ~ and 3 only

of the following- pair of values of L and

should be used in a tank rircu it lo obtain aeson ant frequency of 8 kHz ? The bandw idth

is 800 Hz and \vinding resistance of the coilis 10 ohms.

al 2 mll and 1 fti'

(bi 10 H and 02pF

{(;) 1 99 mH and 02 )tF\ . ~ ~ . /

ldl 1 99 m and 10 pF

7 An elliptically polarized wave travelling in tlwpositive Z-clirection in air has x and ycomponents

Ex sin \f)l jlz) V m

Ey = 6 sin O)t - f)z + 75" i V/mI f the characteristic impedance oC air is wo 0,the average power per unit area conveved bviliewmcis - - a) 8 \V n 2

tbl 4 W/m 2

c) 625 mW/m 2

(d) 125 mW/rn 2

0 GUG K FUA { 2 D l


3/44


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15. Cun si d er tht fo llowin g slalcm en lS :

T lw i n ter eleml nt s paci ng of

l\lon th an /. in arra y a nt en n a wil l pr od u ce gr t i ng lo bes in unsc annC dco nd i tion.

> i\lo r e th n > /2 b ul less t h a n /, in a r ray

an l c nna will prod uc t' g ra ti n g lobe u n d e r

>canned cnnd il io n.

:\. Le ss t h n i /2 in a rray an ten n a w ill not

pro duc e a ny g r a t i n g lo be

1. i\lor e th an 1.5 /, i n a r ray an lenna w i llnot p ro du ce a ny gra t in g lobe .

Wh ich or h e ab ove s t.at.eme n t s a re co r re c t?\ai l an d 2 only

ih l 3 an d 4 only

ki 1, 2 and :3 on ly

id 1. 2, :l a nd 4

1H. Match List. 1 w ith Lis t ri an d se lect. theco r rect an swer

th e lists :

A

B .

C.

D.

(b)

fc l

id

L is t

Exc itat o )

11, l:i

v"'

2

4 2

:l

4 ;3

. g

4. h

c D

a 4

3 l

2 4

2 1

1 7. Co n s id er t h e fo llo win g s t a te m e n t s for as ym m e t ric a l T se c t ion :

1 8

l . Z u an d Z22 ar e equ a l.

2 2 and 21 are equal

:5. z ' l l an d z l2 a re equal

4. z 2l a n d z2 2 are eq ua l.

W hich of th e a bov e s t a tements ar e o r l ?

(a) / 1 an d 2 only \

(b ) 2 and 3 on ly

(c) :3 a n d 4 on ly

(d J 1 ,. 2 , 3 and 4

Two milli a m m et e rs with fu ll scal e cur r e n ts o fl rnA and 10 m A ar e conne c t ed in p r ll e l an dt h e y re a d 05 m.A a nd 25 mA re sp e c tive lyT heir in te rn a l res i s t a nc es a r c i n t h e r a ti o o f

tal 1 : 10

t b) 10 : 1

( c ) 1 : 5

(d ) 5 :

20. Th e F o u r i e r t ra ns f o r m of u ni t s te p s e qu e n ce i:;

al

(b )

n o ( .Q)

1

l- e n

0 G UCi K-FUA ( 4 D )

__ .....


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22.

1\ lung I metre thick thelednc i = ; r:,}i slab 24.(Jccupying the tegion 0 < x < is placedperpendicularly m a uniform _electnc fic JE G;i\ Th e pularization P; inside the

dH'kctnc 1s

[-Q-\ _J_ -----130AI r}v t. ~

2 ;. 3~ ?

------.......l------1The power dissipated in lhe I 0 resistor isI \V dw lu tlw 5 V vollagl' suurce al01w and:i7f W ch a ~ l11 ;) ) A current 1iource alone. Thetoted p11wer absorbed Ill tlw sanw resistor due\() bolh Lht . (HlJT{'S j:,;

; \ \ ~ 6 2 : 1w1d S 2 ~ \V

2:l. ( \m s He r th e (;llown:1n FET

l.

2.

or

h or h e ab ove s tatements ar e cor r ect 1. 2. :3 and 4

hi J a nd 2 only

ic y 2 an d :.J only

u l i :l and 4 o nly

0 -GUG K-FUA ( 5

y

AB

Consider points A B. Cradius 2 units as initems in L i ~ t ll are t

c

at

diffewent points on, . c 'latch Li.,l lwith List If ar.:d_ ; \1 e c:JJTect an s v.c rus1 ng the code gwen ~~ h e l s L ~:

Us

L

).- : ly

:> 1 ix + :iy I i i

Code : w ~

A B c D

l ;l l :) 4 f} 2

l b l 6 5 2

I( ) G 2 'j

un :l ; 4 2


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T lw n c or r ec t st at t. lll en t i,.;

1 ,I 1 T her n iJ;;to r h as a hig h :-:cnsitivil.y.

1 h T h e r m ocou pie do(s n ot req u in . an

ex te rnal el ectrical so u rce fo r iu:

op e r a t iu n .

1c1 P la i.JtH lr n h as a l ine ar I{ - T n laLiuns hip.

i d t / l'lwr rnlsl J r d oes noL requi re an extL rn a l\..

c e clrica l sour ce for i t:; o per at i on.

:W. In ion ic cr v st als, e lec t ri c a l co n du cl i v ity is

h l lkpe n ds on rn al( r ia l

1\. :/ l k p c nd s o n t c r n p t r t u r e

ie .ll P n1ct 1c;d y zero

Cons id er the follt)win g s t k mt ~ nt s :

1. Th e J n p b ce t ra n s form of

im puls e fu nct i on 1s s

) .

I .

. ov c s ta tem e nts ar c corr ( 't l ')

.

lc l 2 an d :1 onl_1

ldt I : . l n d 4

2 8.

2H.

0 GUG -K-HJA ( 6 - 0 )

-

Th e flu x a nd p ot en ti a l fun cl io ns

lin e c h arge a n d d ue to tw o concc-ni.rir

circ u la r co nd uc tor s a re o f th e o n ; ~

f'orm :

1a l C oncen tric c i rc u l ar eq uipo tentia l l int 's

a n d st ra i gh t r a d i


7/44

f-\rti nt r ~ < . r i e s oi' an y perio dic fun ct ion Xr u


8/44

:n.

:JB.

:m.

t

The: intn n sic imp ed a nce or co pp (' r at :3 Gl h 141.1wit h pa ra m et er s :

. i l l ' ,. l ( 'j j}j/'36 lll 4T< :< lO ; m ; r = , ;t ; an c

r. = 5 8 : . 0 1 mho f m )

w ill b ~

1 ;: \i

fbi 002 cJ /i . o h m

I C I 0 2 i..y :'2 oh m

1d I 0 : ty r; l oh m

t = 0i i li ) . / 10 0

r - >--------- w - - - -- - - - -- : F

IOVt_ __ V* iiF In Lhe circ u it s how n a bo ve , s wiwh S i:> c o;.;cd a t l = 0. Th.-: t ime co nst a n t o f the ~i u l andini ti a l val ue of cu r re n t i f.t J a r e

IHI .30 sec . 0 5 J\

fb ) 60 sec . l -0 }\

l c l 90 scr. l i \

Hi-

W : >cc. 0-S A

A \' oi tag ;: c>ourn : inte rn al irn pid a n t: of 1:l

po w e r Lo


9/44

; : l4G.

\latch L i ~ tI 1vith L1sl If and seled the C01Tt'CL 47. In a thn.e tlenwnt Yagi a nkmwa n ~ w c rusing thi' code g-iven be uw the lists ;

{ r :;i I

d - _ ::: (L,.J, u "9 0 ",

d = Ofi. u =0''f_

'C .-:c0-5. u=180"

J:_

dll : ' 10, u = 180"

l

Code:

A

a ' -1

I C 4

i d ) 2

c

I

L sl f l

2.

a J ar systcm 'or step inpul

. LlH lramJer f'uncti()n is

I ;JI All the threl e l e m e n t ~an of equallength

ibJ

H i

The drivt.'n denwnt and the dinct.or anof equal lcn -rth but thl' rd1ecior ~ . ~long:


10/44

;){), Til


11/44

5 9

A n ax i; J l l li i ~ Tl l ' l i c lit.ld i::; a p pl i e d t t nl ~~ n H n s n : b l l l t l ( to

lit1. cavi ty nso na l o r :

I . T h e ca v it y r es n na lo r d oe s n n t pos:-;c;;s as 1"1"1;111\' rn o tk:.; a s l.he co rr esp o n d in g w l \ ( g u i dt ~ d o(: ;.

T h e rc s o n ; tnl frcq m :n rie s o f t:< l vi l ie :; a rc \' i.'rl' c l o ~ l . l . v s p:H (d .

(i2. 'l 'h e n s o n a n t f 'n q l H ~n cy 11 ' :1 ca v i ly

rl 's on a tn r ( a n be c h a n g e d by a lt er i ng its

d nw n s icns.

i ; ; i 'l. :1nd : ~ o I.\'

d


12/44

Tlw value or < in the above circuit is

l i .J n

rb; 40 n

i ~ / 4 42

~ ~ ~ - -

; \ J- - - - - - - - - - < - ~

I()v

i IN

l - - - - - - - - ~I B

__

For the network shown aboveI= (()2 V 2 A. il = the current deliver

In zT

c i / ~ ; == zI_.

Id Ts - I z

Q GUG K FUA

lran :>form are related by

68.

69

12 D J

A line of characten:;tic impedance 50 ohms i; :terminated ai.. one end by +.if)O ohms. TheVSWR on the line is

uv-1

ibJ M

(ci 0

idl 20 0 A

Thevenin equivalent voltage V . 1 ilnd\ .,resistance f\ c ro s ~ i..he terminals AB in Uwabove c ir cuit are

ia ) Ei V, sn

{b V, 5

iG ,2: V, 2 -.1 n

(d) 2: V, 25 n


13/44

7 1 .

Alum ina is a n . C onv olu ti o n of l W O : :eq utm ces Xl l nl an d X ) n li s rep re s en ted a s

u ; C on d uc to r

W hat is th e vo lta ge ac ro s s th e loa d res ist a nc e ,

ftL in tlw abo ve c ir w i t ? T h e va lu e of ea ch Ire;-;is to r co nn e c ted in lh e ci rcu i is l 0 0 .

: t; ) / n :n v . /

t r i :l:J:l

fb i H et. ain in g al l s eq u en ce va lue s o f X pl n

ic } D ivi d in g th e S( que n u ~ valu


14/44


15/44

~

1 '

.'

f' XI( I ' i ~ l t J -t l 1 tlwn XIU 1.s

I ; J f

H4. An eloctrir charge of q coulombs is located atthe ongin. Consider electric potential V and

lkctric n r ~ l inh:nsity E at any point ix y, Zl.

Trwn

i ; t l [ a n d V arv both scalars

1b E and V arc both V l ~ c t o r : : ;

l f l E is a scalar and V is a vector

111 E is a vtcttlr and V is a sralar

H5. Considc1 the following statements rugarding a

transmission line:

..


16/44

88.

89.

IIJ Q

.. c131 = l r/s

1 H

ln Lhe above circuit, ihe value of C for the

circuit to exhibit a po\V(;r factor of 086 is

approximately

Ia 0-4 F

bi 06 F

lc 1-4 F

ldi 0 1 F

correct)

lai

ibi

'i. . 10> o mm Is ---- pa_, m

2 y

The total current carried by the

conduclor is 6-4 n A

90. Consider the following statements :

They are given as necessary conditionsdriving point functions with common factorsin p s) and q{s) cancelled :

I. The codlicients of lhe polynomial in pts iand q s) must be real.

2. Poles and zeroes must be conjugate pairsif imaginary or complex.

3. The terms of lowest degreq s) may differ in demost.

isiare

transmission through LTI

Constant

(b) One

(c J Zero

\4l. Linearly dependent on ( )

92. Consider the fllllowing statements :

1. fhe coefficients in lhe polynmmal:-; p;sand q(s) must be real :and positive.

2. Poles und zeroes of z{s) must beconjugate if imaginary or complex .

\Vhich of these statements are as sociated with. . . o(sl ithe driving pmnt functwn sl = _

q sl

ia) Both 1 and 2

Q)./ '1 only

(c) 2 only

di Neither 1 nor 2

0-GUG-K-FUA 16 - 0 )

--------------


17/44

In

.Tl

lw

i ll

C ~ w l s H J c rthe f(1llowing statements relating lu 96tlw l>it:clrostatic and magnetostatic fields :

1. The relative distribution d r:hmges onun isolated conducting body isdependent on the total charge of theblldy.

, _ Tl-w Tnilgnctic flux through any closed

\VlHCh of the above statements is/are C


18/44

99. When donor atoms are added to irections : Each o the next twenty i: W itemsconsists of two statements, one labelled as th(';Assertz:on rAJ and the other as Reason rRY Yo11 arcUJ exam inc these two statements tanfully and selectthe answers to these items using the codes ftiuc/1below:

100.

'


19/44

r

HH. :\sscr/wn rAt: \lagneiic susceptibility value 109 :Lscrtion rA1: ln an intrinsic ::;emiconcluctnr.or an antiferromag-netic the cnncent.ratwn or electro nssu bsLlllcl' a t 0'' I< is zero.

f?ca ;on iN : i\t 0 K. atomic magneticmoments are l'rozen withmagnetic dipoles pointing 1n

random elircctions.

and hole: > Increases wit.hincrease in lll(' Lemperature.

?cason 11{ Law of mass action ho lds good

in case ofscmiconduct on;_

I 05. :\s.,crliou u\1: \ thcrmucoup i: is an active 110 Assertion rAJ com porw n

between two

f( eu ww [-/) I IS activated b.v atlrnperatun: gradient.

HHi i\sscrtiun U\ i : Synthesis problem IS notunique 111 the sense that wemay be a b i L ~to find more Lhanone network which provides

prescrilKd response.R n ~ . : o n({{i _ The problem of ;;ynlhesis deals

with tlw design andspecification of tlw network

107 :L':;crfwn ( ; \ In an intrinsic semicond electron mobility in c

l?cason IO :

1 0 solving bound::n-y v;d ue

problems, lhe meth od nfimages il ; used.

By this te chnique conduc ti ngsurfaces can be removed fromthe solulion domain.

The ve locity of light in any

medium is slower th a n Lhat o

lfeasou i f ( ;_ vacuum_

0 -GUG K-FUA

l?coson n The diclectric constant of llwvacuum is unity and io k::;scrthan that of any othermedium_

behav eintrinsi c semic onduct or .

as 113 Assertion AI: To obtain high q , a resonat orshould h ave a l r g ra t io of

In Hype se miconductor the

majority carriers are electronsand in a p-type scmicnndunorOw m ajo rity carr iers are h oles,wh ere a s 1n an Intrinsic

sem icond uctor th e n um b e r o fholes a nd el e ctro ns ar e e quaL

I 19 - D )

volume to su r fac e are a .

Rea son IR I t is the volume thal stores

en ergy and i t is the s ur facea rea th a t i ~ s i p at e s en erg_.


20/44

1 1:1 . ;\_ _ ;; rt wn rAJ : TEM T r a n ~ f e r E lec t ro 11 8 As s a ti o n r J : If' we h a ve tw o p -n p an d n- p -n'vl a g n e ti c J w av e s c a nnot.

pr op a ga ll' w it h m a hollowwa v eg u ide o r ;1n y : ;;h ap ( .

l?m ;on If? For


21/44

115. Assertion A) A Casseg rain antenna

uses a main paraboloidal

reflector and a relatively

small hyperboloidal sub-

reflector with a sm a ll

horn - feed at t he vertex

o f the main paraboloidal

refl ector .

Reason (R)

116 Asse rtion {A) :

Reason (R)

The optical technique

developed by William

Cassegrain was used in

telescope design to obtain

large m g n i f i o with

a ph ys i ca l ly short

telesc o pe. This confi -

guration is found to be

eff ective in the design of

microwave antenna also .

this is maximum at the18 GHz band because the

criterion for scattering arc

m o re sa tisfied by the

wavelength dimensions

at th ese frequencies.

22X

117. Assertion (A) : In satell i te communication tech nique. fre-qu ency reuse effec tivelydoubl es the bandwidth

and in for mation capacityo f a satellite.

Reason (R)

I I 8 Asse rtion (

E lectrom ag neti c wa esradiat ed from a

T h . ma in difference

tween a microprocessornd a micr oc o nt ro ller is

th at the former does notha ve any on-chip mainmemory whereas latt erhas.

A micropr ocesso r doesnot need me m ory to runprogram s.

9 Asse rt ion (A) : Logic analyzer of fe r s ade layed sweep .

Reason ( R) Because th e logica na l yzer sweep Isreally a clock s ignal.

12 0. A sse rtion (A) : When you turn o n you rPC, a proces s cal ledPOST ( power-on-s e lf-t es t) begins with anelectrical signal.

Reason (R) The electrical si g nalrestores left ov e r da t afrom the chip's internalmemory register .


22/44


23/44

oo N O T OP E N THI S TE ST B O O K LE T UN T IL Y O U A R E A S K E D T O D O so)T . B .C . : Q GU G K U B T es t Bo o kl e t S eries

er i a l No. [G lO O l l T ES T BO OKL ET

E L EC TRONI C S A NDTELE C OMM U N I C A T IO N E NGINEE R ING

P a pe II

Ti m e A o w e d : T w Hour s

IN S T R U C T IO NSI IMMEDIATE LY AFTE R TH E COM M ENCE MENT OF T HE EXA M U S HOULD

CH ECK T II AT T HIS TEST BOO KLET DOES N O T HAVE A NY T ED OR TORN OR MISS ING PAGES OR ITEMS E T C IF SO, GE T IT REPLA Y A CO M PLETETEST B OOKLET .

2. EN C O D E CLEARLY THE TEST B OOKLET SE R IES D AS THE CASE MAY BE IN T HE APPROPRIAT E PLACE IN T H E NS T.

3 . You h a v e to e n t e r y o u r R o ll Num be r o n theBoo k let i n t h e B o x p rov i ded a l ongs ide . D

w rite a ny th in g else on the Tes t Book l et .

4 . T h i s T es t B oo k let con ta ins 1 2 0 i t e m ns). Each i t em co m p r i s e s fou r respon s e sa n s w e r s). Y ou will select t he resP. ic y ou w a n t to m a r k on t h e A n s w e r S hee t .

In case yo u feel t hat the re is m o re e c rr ec t re s p o n s e , m a r k t he respo nse w h i c h yo u c o n si d e r the be st. In any cas e , h L Y O N E res p o n se fo r ea c h ite m .

5. You h a v e to mark all yo u r O N LY o n t he sepa rate nswe r S h ee t pr ov ided .Se e di r ec t i ons in t he nsw r

6 . A ll i tems carry equa l m r7 . Be fo re you p ro ceed to m h e A n sw e r S h eet t h e res p o n se to v ar iou s items i n the T est

B oo klet, yo u have in o rn e part ic u la r s in th e A n s w e r S hee t as per i nstr u ct ion s sen t to you w i th you r n C er t i f i ca te.

8 . Af te r y ou h a e co a fil l in g in a ll you r re s p on ses o n th e nswe r S h e et an d theexam ina t io n h c o nA ude d , y ou s ho ul d h a nd ove r to th e In vig il ator on l y th e A ns w e r Sh ee t .You are p t k e a w a y w it h you th e Tes t B o o kl e t .

9 . S h e e t s or k a re a p p e n d e d in th e Tes t B ook le t a t t he e n d.

10 . o o ng an s wer s :u. \-1 -"- ILL BE PENA LTY FO R WR ONG ANSWE RS MARKED BY A CAND IDA T E

JECTIVE T YPE QUESTI O N PA P E R S

re are four a l te rn at i ves fo r th e an sw e r to every ques t ion. For ea c h q ues t ion forw h i c h a w ron g a n s w e r h a s b een g iv en by th e cand ida te , o ne - third 0 3 ) o f th e m a r k sass i gned to tha t q ues t ion wil l be deduc t ed a s pe na lt y.If a cand idate giv es mo r e than o n e a n sw er, it w i l l be t rea t ed as a wrong an sw e r e venif o n e of t he g iven a nswe rs happen s to b e co r rec t and th e re w ill b e sa me pen al ty a sa b o ve to th a t ques t ion .

i ii ) If a q u e s t io n is left b la nk , i .e ., no a n swer is g iven b y t he candid ate, th ere w i ll ben o pe n a l ty fo r th a t q ues t io n .

D O N O T OPEN THI S TE ST BO O KLET UN T IL Y O U A R E A S K E D T O DO SO )


24/44

I. Consider the following statements :

2

When compare d with a bridge rectifie r, acentre-tapped full wave rectifier :

1. Has larger transformer utilizationfacto r.

2 Can be used for floating o utputte rminals i.e. no input te rmin al isgrou nded.

3. Needs two diodes instead o f four .4 Needs diodes o f a lower PIV rating.

Which o f the abov e s ta te men t s arecorrect?

(a) m and 2 only(b) 1 ,2 , 3and4

c) 3 only

(d) 3 and 4 only

a) s + 1 2

(b) s( s+ l) 2

sc)

IAFH

D78H

(c) D71 H

d) 32F H

2X

4 . A 13 bit PCM system performance i s benerthan an 8 bit PCM syste m becau se

(a) Noise is lower and is proportional to

recipro ca l o f bandwidth

(b) Bandwidth is larger and detection is

easie r

(c) Quanti z ation no i se is

things being equal

(d)

5. Match Li s tcorrect an sthe li sts :

. .

. Two-cavit y

Klystron

C. PIN diode

D. Bolometer

Code

A B C D

(a) 3

(b) 2

c) 3

(d) 2

1 4 2

y 4 34 2

4 3

u . ~ t - 1

A p p l i c a ~i o n )

. Microwave

amplifier

2. Micr ow a ve

oscilla tor

3. Micr owave

low power

me a sure ment

4. Modulator

6. The de fa ult parameter-passing mechanismin C-programmi ng language is :

(a) Call by reference(b) Call as random

(c) Call by va lue

(d) Ca ll by value res ult

(Contd . )


25/44

57. Co nsider the function F s) =

s s + 3s+ 2w he re r s) is Laplace transform of function

f(t). The initial val ue of f(t) is :

a) 5

b) 5/2

C) 5/3

d) 0

8. The data type defined by user is :

a) Built-in data type

(b) Ab s tract data typ e

(c) llomogencous data type

d) Real d ata type

9. Insertion o f a record in a circularly Iinke

10.

list involves the modification of :

(a)

(b)

c)

(d)

4 poin ters

3 pointers

2 pointers

I pointer

o a b d pass signal sp a n skHz. The signa l can be

(c) 50 kHz

(d) 40kHz

3X

II . Match List-1 wi t h Li st-If and select the

correct answer using the code given below

the lists :

List / Lisl 11

A. Rectangular I. Plane of polariza-

waveg ui d e tion

B . Waveguide 2. Waveguide tuner

twists

C. Slot ted se c tion 3.I

D. Stub screws V o 9

Code

4 3

4

D ideal)

100 l l f 1VJc

The output Vde from the above circuit is :

(a) 12.[2

b) 12 / n

(c) 2 4 /n

(d) 12 I J2

(Contd.)


26/44

13 . Which of he following data structure is usedby a comp iler to manage information aboutva riables and their attributes ?(a) Abstract syntax tree

(b) Linked list

C) Parse table

(d) Symbol tab e

14. A transistor works in three regions :

I. Cut-off

2. Ac tive

3. Satu rati on.

While used as swi t h in digital logic gates,the regions it works in are :

(a) I and 2 only(b) 2 and 3 only

c) I and 3 only

d) I. 2 and 3

15. The number of edg es in a reg ular graph of

16

a) ND

b ) NO I 2

c) N + D

d) N

(a)

(b)

(c)

(d) A + B + C

4X

17. A single bus structu re is primarily found in:(a) Main frames

(b) Mini and micro computers

(c) Super computers

(d) High performance machines

18. In a unity feedback control system with

19

4G s =

s2 + 0-4s

input, it is required that system rshould be se ttled within 2 to

(a) I sec

(b) 2 sec

(c) I0 sec

(d) 20 sec

e C PU temporarily and, f . . . . , . . , time to send in f ormation

Direct memory access

A rectifier(witho ut filter) with fundamentalripple frequency equa l to twice the mainsfrequency, has ripple factor of 0-482 andpower conversion efficiency equal to 812%.The re ctifier is :

I. Brid ge rectifier

2. Full-wave (non bridge) rectifier

3. Half-wave rectifi er.

Which of these are correct?

(a) 2 and 3 only

(b) 2 onlyc) I and 2 only

(d) 1,2and3

(Contd.)


27/44

21. Conside r the following :

I. o ~ p i l e r s

2. Design

3. Eva luation

4 . Instruction set architecture

Whic h of these are included in the present

definition o f computer architecture to design

a full computer system ?

(a) 1, 2 and 3

b) I, 3 and 4

(c) 2, 3 and 4

(d) I , 2, 3 and 4

22 . The Nyquist rate for the signal x(t) = 2 cos

(2000 1tt) cos (5000 m), is :

(a) 7 k Hz

b) 5kHz

c) 14kHz

(d) 10kHz

(c) 80

(d) 75

ory cess time is

t ~ o t time is 100 ns;

\ .. I

I

X

24.

The transfer function

(a)

2

3s+6

\

d s)

+ y(s)2

Js + l

25. An I/0 processor controls the flow of

information between :

(a) Cache memory and 1 0 devices

b) Main memory and I/0 dev ices

(c) Two V devices

(d) Cache and main memory

(Contd.)


28/44

26. 2 9 . W h i c h on e o f h e fo ll ow i n g has t he shortest

a c c e ss time ?3 y s)

s + I a) NM O S EPROM

(b) N M OS RAM

1 c)C MO S RA Ms + 1

(d ) Bipo lar sta t ic RA M

Th e c h a r a c t e r i s t i c e q ua t ion o f th e above

c los e d-loop sy s te m is :30 .

a) s 2 -i I I s + I 0 = 0

( b) s 2 + 11 s + 1 30 = 0 I (a ) L ow se le c t i v i t

( ;) : :. + I s t 12 0 = 0 b ) Low d i s to r t i o n

d) s t I s + I 2 = 0 - (c)'- (d)

27 I he st a n d ard SO P ex p res s io n f o r B o o l ean

e x pre ss io n A B + AC + B C is :

{a) \ B C + A BC +ABC +A B C

b) A B C + A BC+ A B C

( c ) A BC + A B C + A B C

( d) \ B C +ABC + \ B C

Coincid e w i t h the po le s

28. o f exp ression

B Ci s :32 . Th e figu re o f m e r i t o f a lo g ic f amil y is g i v e n

a) by the pro du c t of:

( a ) Gain a nd b a n dwidth

(b) Propa ga ti o n delay ti m e and power

d is s ipa t io n

( d ) A + B) ( A +C) (c) F a n -o u t a n d p ropa gat io n d elay ti m e

d) N o i se marg in an d p o w e r d iss i p a o n

6 Co nt d .) X


29/44

33. In NO R-NOR configuration, the minimumnumber ofNO R gates needed to implement

the switch ing function X + XY + XYZ is :

(a) 5~ \

\

(b) 3 \ \ . . / (c) 2

(d) 0.1

34. The addition o f open loop zero pulls theroo t-loci tow a rd s :

(a) The left a nd th e ref o re syste m becomesmore s tab le

(b) The ri g ht and therefore systembecomes unstable

(c) Ima gi nary axis and therefore systembecomes marginally stab le

(d) The left and th erefore sys tem bec omesunstable

35. Match Li st - 1 wi th List-11 and se lect th

Li s t - /

A. HT L I

B. C MOS 2.

b) 2 4 3

c) 3 I 4 2(d) 2 4 3

. \ ) ?/ ; i\o {

.I_ / 7X

36. On receiving an interrupt from an 1/0

device , the CPU :

(a) Hal ts for a predetermined ti m e.

( b) Branch es off to the interrupt service

routine after completion of the cllrrentinstruction

(c) Branche s off to t he inte

routine imme diat ely

(d) Hands over control . ~ l ~

data bus to th e jn :14o_.._ .., _ ..._

L > ~ n a . n f 8 1upon th e slope of transition~ - dn edge of the low-pa ss filter.

he lock rang e is not affected by the

s lope of ransition band of he low-p assfilter.

Wh i c h o f the above s tatement s is/are

corre c t?

(a) Both I and 2

(b) I only

(c) 2 only

(d) Ne ither I nor 2

38. In microprocessor based systems DMA

facility is required to increas e the speed of

data transfer between the :

(a) Microprocessor and the VO devices

(b) Microprocessor and the memory

(c) Memory and the 1/0 devices

(d) Memory and the reliability sys tem

(Contd .)


30/44


31/44

44 . A TO M sy s tem i s to be designed to

m ultip lex th e fo l lo w in g tw o s ig n a ls :

X 1 = 5 COS 2 000 7tt)

x = 2 cos (2 000 7tt) cos 3 000 m )Th e mi nimu m s amplin g rate is :

(a) 4 kl z

( b) 5 kl z

(c) 1 0kHz

d) 6 kH z

45. A n ex a mp le of a s p oo led de vice is :

( a ) A g rap h ic a l d i s p lay d e v i c e

(b ) A li n e pr inte r u sed to p ri n t the o u tp u to f a numbe r o f obs

( c ) A seco ndary s tora g e d ev ice in a v irtual

me m ory sy s te m

( d )

46 . W h ich one of the fo l lo w in g is a

co n diti on ?

a) J x t) I < oo

(b) m ~ l i ea finit e nur berm inima i n th e

m l l ~ ~d isco n t in u i t i e s in the ex pansion

e rv a l

(d) x2 t) mu s t be a b s o lu t e ly su m ma b le

9X

4 7. Co n s id er t he fo l lo w in g ins truct ions o f8 085

m i c r o p r o c e ss o r :

48.

I. M OV 8, C

2 . ST A ad d ress

3. O R byte

The co r re c t se q u e n ce in th e decreasin

o f their respec t ive

r eq u i r em e n t i s :

(a) 3 2 a n d I

( b) I , 3 an d 2

(c) I , 2 an d 3

d)

m error for any o u tp u t \ Olrage wi ll

5 mV

IO m V

(c) 2 0 mY

( d) 10 mY

: . v .

,,i

-

4 9 . Ifthe C A LL ins truct ion of 8 085 in the m ain

p rogram is co n di tional then R E T U R N

instr uct i on in the su b ro u Une ca n b e :

( a ) C o n d i t io n a l

( b ) C o n d i t io n a l or u n condit i o n al

( c ) Ca n b e d e te rmin ed b y L O A instru c ti o n(d) U n co n d i t ional -

C o n td .)


32/44

5 0 -A

B - . I

- v X o -

= [

I he o ut pu t X o f the a bo v e lo gi c c ir cu it is :

( a ) A B + C D E F

( b ) A l3 + C D + E f

~o : ) 1 \ + B ) ( C + D ) ( E + F )

d ) \ B ) (C + D ) { I F )

5 1. f h e D o ub le m ini m um o r th e "W id t h o fm i n i m u m p o w e r m e t h o d i s u s e d in

m ic r o w a v e m ea s u r em e n ts f o r t h e

m ea s ur em e nt o f :(a ) V elo ci t y m od u la ti o n

( b ) F re q ue nc y d is t o r ti on

(c ) l l i g h V W .R .

( d ) L ow V S .W .R .

52 C o ns id er th e fo ll ow ing s ta te m en ts :

1. T h e l o c k r a ng e o f a P L I id1 ff er en c e be t w e e n th e fi e

lo w e st fr eq u en ci es t ~

_ _.. ._ _

. . _

re m a in in lo ck o nt

2 . 'h e c ap tu re a n~ ; e i th e ra ng e

o f fr e q u e n i cs e v o lt ag e

c o n t ro ll e r o f a P L L c a n

3 .

rr t ? I o n ly

( b ) 3 o nl y

s e d t o s yn c h r o ni z e

an d v er t ic a l o scil la to rs

ce iv e r s to in co m i n g s y nc

st a t e m e n ts is / a r e

(c ) I and 3 o nl y

(d ) 1. 2 a nd 3 10 X

5 3 ., ,

r hc ci rc u it

u s e d to i m p lc

I B a n d J = I

I B an d J = 0

5 4 In

th e B od e pl ot o f a u ni ty feedb ac k co n tro l

s y s te m . th e va lu e o f p h as e an gl e o f G Uw>

is - 9 0 a t th e g a in c ro ss o ve r fr eq ue nc y o f

th e B o d e p l o t , th e p h a se m ar gi n o f t h e

sy st em is :

(a ) - 18 0

b ) + 18 0

(c ) - 9 0

(d ) + 9 0

( Co n td .)


33/44

55 .

-, I

The Boolean ex pression for the o utput o fthe above logic circ ujt i s :

a)Y AB AB C

b)Y = A B + A B + C

c)Y==AE9 B + C

(d) Y = A B + C

56. Match List- w ith List -II and select the

co rrect ans wer using the code given belowthe lists :

List /

A. Cavi ty wave

meter

B. VSWR mete r

c. Bolometer

D. Fraunhofer

regi on

Code

A Ba) 3 :

b) 2

c) 3

d) 2 4 3

L is t - /

I. Impedance

measurement s

2. Frequency

measurements

3. Antenna

measurem

t .

J IX

57. The Ny q uist plot o f loop transfer functi onG(s) H s) o f a clos ed loop control systempasses through the point - 1 jO) in the G(s)H s) plane. The phase margin of he systemis :

(a) oo

(b) 45(c) 90

(d) 180

58. When compared with a n RS2 32Cport. the USB U niversal Serial Ba)

(b) S upport s a faster transtl(c) Does n o t support ' Hot

(d) Controller in P C can no etect the

de vices59. A

the table foro 8-bit unsi gned

integers. Y l ~ m tn eROM required is :(a) 2b)

0'o

4 to IMUX

y ,,12

y

0 ISo s so

A 8

cIn the above c.ircuit .2.X is g i ~ ; e nby :r.

lf- '1 , f f l c11 , , ,(a) X == ABC+ ABC+ ABC+ ABC

(b) X A B C + ABC AB C + ABC

c) X == A B + B C + A C

(d) x = A8 8c A C

0

(Contd.)

X


34/44

_

0

\r

I I > 1 a 1 th e n th eG . II . 1ve n X z ) = 1

62 .

- =

1- az -

region o f conv erge nc e is S ha d ed regio n ) :

a

b)

c)

d )

b e tween

d a ccumula to r

t tran s fe r o f data b et w e e nm o r y and V O d e v ic es without th e

use o f J LP

T ran s fe r o f d a ta e x clusi v el y w it h in JJ Pre g is te rs

d ) A fast tran s fer o f da ta betw een JJ P and V O d e vi ce s

2X

63 .

c

v ,D

C o n s id e r t h e

dB)

20

10

0

- 10

- 2 0

- 3 0

-4 0

/

/

- 2 40 - 180 - 15 0 - 90 - 3 0 0

p ha se de g )

F o r the Ni c ho ls p l o t s h o w n , the s ys t e m is :

a ) U ns ta b le

b ) S ta b le

c) O v e rd a m p e d

d C riti c a ll y s table

C on td .)

. -


35/44


36/44

71 . F or t h e e x p e rim e n t a l s tu d y of sm a ll micro wa v e an tenn as, a f re e space en v ironmen t \v l th minimum int e rfe rence bye x ternal ob je c ts , the faci l it ie s required

arc:

a) RF screens , V SWR m eter , w avegu idetwist

b ) U H I screen s , s lo t ted w av e g u id es,power m eter

c) Anec hoi c cha m be r, N e tw o rk ana lyzer ,Pa t tern reco rde r

d) Da rk roo m fac il ity D igita l r ec o rde r,Bo lo meter

72 . RLADY s ign al in 8085 is useful when th rCPU commu n ic ates with :

73

a) A s low pe r iph e ral device

b) A fast p er i pheral dev ice

c) t DM A co ntroller ch ip

d) A PPI c hip

A

0

U X is used to im p le ment a 3-inpu tA . . . . , . , - un ctio n is as show n above. The

an func tio n F A, B C ) im plemented

F A, B, C )= 1 , 2, 4, 6)

F A, B, C ) = L l , 2, 6)

c) F A, B. C) = 2, 4. 5, 6)

d) F A, 8 = ~ l, 5 6)

14X

74. P op ulatio n in ver sio n in se m ico nd u c tor las e r

d io de is a chieve d by :

75.

a) L ig h t ly d o ping p an d n sides

b ) Introduci n g tra p ce n t res on p and nsid e s

c)

d )

a) 119

b ) 120

c) 78

d ) 77

p rogra m h ow many

D C RC e xecu te d?

M V IC 78 H

DCRC

JNZ LOO P

HLT

76. P ro cessi n g of M OS ICs is les s expensive

t han bipolar IC s pr im arily bec au s e they :

a) U sc cheaper co m p o n ents

b) N eed n o compon e nt iso lation

c) Requ ire much less d iffu sion s teps

d ) Have very h ig h packing d en s ity

Contd.)


37/44

7 7 . v,78 .

J

- Q \ e-r

\. \.

Q

Ide a l C LK

K /

/ Q

T h e c o r re c t w a ve fo r m fo r o u tp u t ( V0

fo r th e ab ov e n e t w o rk is :

( a v0 1 4 3 v

5 v

5 X

p s ho wn a bo ve is in iti a lly a t Q : 0 . f a s eq u e n c e o f k p u l s e s is th e n ap p l ied . w it h th e

inp ut s a s giv en in th e f ig u re , th e

u lt i n g se q u e n c e o f va lu e s tha t a pp ea r a t

th e ou tp u t Q s tan in g w it h i ts in i ti al st a te , is

g i ve n by : \0

a ) 0 1 0 1 1

b )0 1 01 0

c ) 00 11 0

d 0 0 1 0 1

'C '/

7 9. A si n gl e in s tr u c ti o n to cl e ar th e l ow er fo u r

b i ts o f th e a c c um u l at o r in 8 0 8 5 a s s e m b ly

l a ng u a g e is :

a ) X R J O FH

b ) A NI F O H

c ) XR FO H

d ) A N I OF H

( C on td .)

0


38/44

8 0 .

81

X y Qn l

0 0 1

0 I Qn

l 0 Qn

I I 0 - - - - - -

An X -Y l l ip flop. whose c h a rac te r i s t i c tab le

is gi ' en a bo n: is to be imple mented u s in g

J - K tl ip t lop . 1 his c a n be d o ne by m king :- ;

n) J = X, K = Y -

( b) J - X. K = Y

{c) = Y , K = X

d ) J Y ,K = X

I h e / - tran s form o f - u ( - n - 1) i s:

Iwith Z > Ia)

l I

li thO < I Z I m-.,n-Nock p u l se the p attt:rn g et \

c b i t p o s i t i o n to the ri g ht. W i th

84 . A mic ro p ro ce sso r b s ed sys te m can p erfonn

m ny differ e n t functi o n s , be c us e :

(a) It s op e rati o n is control led b y s oftware

(b ) t is d ig i ta l sy s tem

(c) lt u s es a RAM

( d) t can b e co n t ro l led b y in p u t and o ut put

de v i c es

(Co nt d .)


39/44

85.

Q a

Oa\

Anal y z e the seque nti a l ci rcu it s h o w n a b o v e

in fig u re . ss u mi n g t ha t init ial state is 00 ,

determin e wh at in p u t se q u e nce w o u l d lead

to sta te 11 ?

a ) l l

( b) 1 0

c) 0 0

d) S ta t e is unrea chabl e

86. Which ofthe fo llow i ng in st ru c t io

a byte of data in to the accu m u l a t f

m e m o r y a dd r es s g ive n in t he

a ) LOA

(b)

c)

d )

n d ph as e of the t ra n sfe r

I( s = at ro = I is :

s + l

- 3 d B an d 078 rad

(c) 0 70 7 an d - 4

(d) 3 dB and- 90

/ ,

\

88 .

z \

89.

7X

In a ty p ic a l satelli te com munica t io n sys te m ,

w hi c h of he fo l lowing co u ld b e the up- l in kan d d o w n - l ink fr e quenc ies re s pe ct ively ?

a) 40 G H z an d 60 G H z

b 6 0 GHz a n d 40 G H z

c) 6 GH z an d 4 G Hz

d ) 4 GHz and 6 GH z

W h i c h of th e follow ing is th

Ti m e

Time0 r ---------- - - - - -

c ) y( t )

Time0

(d)y (t)

T im e0

Contd . )


40/44

90 1 he outp ut d ata l in es o f micro processo rs

a n d me mories are u su a l ly tr istated, b eca u se :

a ) M ore than o ne device ca n transmit

mformati on over the dat a bus by

en a bl i ng only one de v ice at a time

(b ) More t han o ne devic e ca n tr a nsmitmforma tion o ve r t h e data bu s at the' u n c ti m e

c) I h e data lines can be multiple xed forb o th input and o utpu t

J) It increa ses th e speed o f data t r an s f e r s

o ve r th e d a ta bu s

91.

_ 0 u ~ .__;-o- - 0 ..{ C LK C L K

I or the circui t show n, the c oun

92 . view o f s ta b ility and

e r a c losed loop sy s tem, th er m Q i~ r a n g e for the va lue of damping

04 t o 0 7

c) 8 to 1

(d ) 1 1 to 15

93 .

18X

A

A

A l l

A 2

A ll

A ,o

A9A , j

A l

A6 - - - - -

As

A,

A,- + l

o r y c h ip w i th 1024b )tc sed t o a 8 85 chtp ad d ressmicroproces s or wi t h 16 adJrc : s 'O \ c. W h at is t he ra n ge of m em o [')

I I to 3 FFI I1 H to 1 3 FF H

FOOO H to DFFII I I to F F F F II

rh c ou t put s t age o f a tran s p onder o nboarda satell ite h as a maxim um power outp ut o fI 0 w a t t s . l l owcvc r, it is not opera ted a t themaximum p o wer outp ut in order t o :a) Conse r v e th e av ailab le l imit ed battery

pow er(b) Reduc e no ise d ue t o d evices(c) Av o i d intcrmod ulati on d ist o ni o n(d) Av oid h eating up o f t he sa te llite

be y o n d a pre set va l u e

95. The p ur p ose o f a s tan b it in RS232 se r ialc om munication pr o tocol i s :a) fo s yn c hronize re ceive r fo r r eceivtng

every b y te (b ) 1 0 synchro niLC r t :ccivcr fo r rCCCi\ tng

a se q u e nce o f b ) te s (c) A s a pa rity b i t(d ) To synchron ize re ceiver for re cc i ing

the l ast b yte

Contd.)


41/44

96.

Consider the above block diagram of asuccess iv . approx imation A/0 co nverter..Match l.ist-1 wit h List-11 and selec t the~ o r r l C Iansw er using the code given belowthe lists:

Jn-1

fB/ockJ

1\.

/. i .\t -

Va me)

l Companllor

98. A I 0 bit AID converter is used to digitize

an analog signal in the 0 to 5 Y range . The

maximum peak to peak ripple vohage thatca n be allowed in the DC supply voltage is ,nearly:

(a) JO OmY

b) 50 mY

c) 25 mY

(d) 50 mY

99 . Which ont: o f the

pole-zero location

~ ~ p o s r13.c.

2 . Dl1\ co nverter 1_3. S u c ~ e s s i \ ea p pr

x 1 - mat10ns reg1ster

) 0 ~ ~ 0

D.

C ude

A B

(a) 4(b) 3

(c) 4 2

d) 3

(b) 033 rad Is

(c) I rad /s

d) JO rad Is

c

22

4. Ou tput port b) jw

D

34

c) W

(d)jw

I9

X (Contd.)


42/44

I 00 . C on s ider the follow ing application s :

I . Wind tunnel si mulat ion

2. Real-time vide o viewing

A co mput e r is used for :

(a) ei ther I nor 2

(b) Bo thI

and2

(C) I o nly

d) 2 o nl y

Directio s :

Each or the next T wenty (20) ite m s consists

o f tw o s ta tements , on e label led as the

A ss ert ion (A ) and the othe r as R eas on

( R ) . Yo u a r e to examin e these tw os tate m e nt s c arefully and select the a nswers

to the se item s usin g the co d es give n below :

Codes

(a) Bo th A and

(b )

c) A

d ) A

I I. A ssert ion (A) : A ND gate in

tr ou tput conf igu -r n ca n be used for a

... - . . : ~ a u s ar r angemen t w i t hmore th a n one g a te

output con nected to a

common l i n e.

The tristate c o nfiguration

has a contro l input, which

ca n detach a log ic level011 ) fr om com i ng on to

the bu s line.

20X

I 02. As s e r t ion (A) : Inte gral windup ef fect incontrolle r causes excessiv eovershoot .

R eason ( R) Presen ce o f saturat ion inco n t ro l ler and ac t u atorde te r io r ates th e P I Dco ntrol.

I 03. Assert io n (A) : Stead y s tate error ca n be

R eason (R )

I 04. Asse rt ion (A) .

red uc ed by

be

two

For b etter t ransmis s ioneffici ency , source andchanne l must be matched .

I 05 . Asser t i o n (A) : F re q uency mod ula tionand phase modulationbo th produce diff erent seto f frequ ency bands o r thes am e modulat ion de p th .

Reason ( R ) F re q uency modu la ti onand phase m odulati onv ary the ca rrie r ph seangle o r its r a te .

I 06 . Asse rti on (A ) : In amp li tud e modulat ionsy st e ms the va lu e o fmodul a t ion index sho u ldbe around I .

Reason (R ) Th e p owe r carried in theintellig en ce carryin g s idebands incre a ses with

the modulat ion index .

(Contd.)


43/44

l 07. Ass erti o n (A) : When coding signals like

spe ech signals a-law orJ -law quantizers are used .

Reas on (R) A-law and J . . ~ l a wquantizer s occup ysma ller bandwidth thanunif orm quanti zer s

108 Asse rti o n (A ) : PCM / FM sys te m s

Reaso n R)

transmit PCM pul ses bymodulating a highfrequency carrier and

hen ce occupy lar ge bandwidth and eliminatedist ortion.

Large bandwidth en sure sSN R tid e o ff and hencedi s tortionle ss transmi ss ion i s ens ured .

I 0 9 . Asse rtio n {A) : It is no t ne cessa ry to

incorporate a v ery lono is e amp i fi c r

Reaso n ( R)

co mmunic a tio n s.


44/44

1. c

2 c

3 A

4 D

5 B

6 c

7 D

8 B

c

A

D

B

D

c

1 5 A

1 6 B

17 B

1 8 D

1 9 D

2 0 c

2 1 c

A

B

29 D

3 0 c

B C

B C

C D

B B

c c

C A

B A

C B

C B

D B

B A

A D

A C

B C

C A

D C

A A

D B

B C

D

A

A

C D

A B

D D

A C

Electronics Engineering Paper-II

31 D

32 B

3 3. D

34 A

35 c

36 B

37 A

38 c

A

c

A

A

B

B

4 5 B

4 6

47

D

B

D

A

5 6 B

57 A

5 8 B

59 D

6 0 A

A A

B B

A B

A B

B B

A B

D B

C B

A A

B A

c c

A D

B

D

B

C D

D A

B C

D B

A D

c c

B B

A C

C A

A C

c c

B

62 B

c

64 B

6 5 c

c

67 B

8 c

69

D

77 A

78 D

7 9. B

8 0 D

8 1. B

82 c

83 B

8 4 A

8 5. c

8 A

87 c

88 c

D

A

c c

D A

D B

B A

B B

D

C B

B D

D A

c c

B B

C A

A C

C A

c c

A B

D B

B C

A B

B C

A C

D B

B C

D C

C D

B

D

9 9 c

1 0 0 c

101 A

102 B

B

D

1 05 D

10 6 A

10 7 c1 08 A

10 9 D

11 0 A

111 A

1 12 B

1 13 A

114 A

5 B

11 6 A

7 D

8 c

11 9 A

1 2 0 B

A

B B

B C

B D

B A

B D

A B

A D

C A

C B

D B

B D

C D

A A

A C

B A

B D

B A

A A

D B

C A

C A

A B

C A

A D

B C

C A

B B

Documents

IES Electronics 2010