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To {Eikosidwdekedron} parousizei jmata pou qoun suzhthje ston isttopo http://www.mathematica.gr.H epilog kai h frontda tou perieqomnou gnetai ap tou Epimelht tou http://www.mathematica.gr.Metatrop se LATEX: Fwtein Kald, Anastsh Kotrnh, Leutrh Prwtopap, Aqilla Sunefakpouo , Sqmata: Miqlh Nnno, Qrsto Tsifkh Seli-dopohsh: Anastsh Kotrnh, Nko Mauroginnh, Exfullo: Grhgrh Kwstko. Stoiqeiojetetai me to LATEX.Mpore na anaparaqje kai na dianemhje elejera.
Eikosidwekedro filoteqnhmno ap ton Leonardo da Vinci
To eikosidwdekedro enai na poledro (32-edro) me ekosi trigwnik dre kai ddeka pentagwnik. 'Eqei 30 panomoitupe koruf st opoe sunantntai do
trgwna kai do pentgwna kai exnta se akm pou h kje ma tou qwrzei na trgwno ap na pentgwno. Enai arqimdeio stere - dhlad na hmikanonik
kurt poledro pou do perissteroi tpoi polugnwn sunantntai me ton dio trpo sti koruf tou - kai eidiktera enai to na ap ta do oiwne kanonik
- quasiregular poledra pou uprqoun, dhlad stere pou mpore na qei do tpou edrn oi opoe enallssontai sthn koin koruf (To llo enai to kubo -
oktedro). To eikosidwdekedro qei eikosiedrik summetra kai oi suntetagmne twn korufn en eikosadrou me monadiae akm enai oi kuklik metajsei
twn (0, 0,),(
12,
2,
1+2
), pou o qrus lgo
1+
52
en to duadik tou poledro enai to rombik triakontedro.
Phg:http://en.wikipedia.org/wiki/Icosidodecahedron
Apdosh: Pno Giannpoulo
O diktuak tpo mathematica.gr ankei kai dieujnetai smfwna me ton kanonism tou pou uprqei sthn arqiktou selda (http://www.mathematica.gr) ap omda Dieujunntwn Meln.
Dieujnonta Mlh tou mathematica.gr
Suntoniste
Airet Mlh
1. Fwtein Kald (Fwtein) Genik Suntonstria
2. Miqlh Lmprou (Mihalis Lambrou) Genik Sun-
tonist
3. Nko Mauroginnh (nsmavrogiannis) Genik Sun-
tonist
4. Spro Kardamtsh (Kardamtsh Spro)
Upejuno Enhmrwsh
5. Qrsto Kuriaz (chris gatos)
Upejuno Programmatismo
6. Mlto Papagrhgorkh (m.papagrigorakis)
Upejuno Oikonomikn
7. Girgo Rzo (Girgo Rzo)
Upejuno Ekdsewn
Mnima Mlh
1. Grhgrh Kwstko (grigkost) Diaqeirist
2. Alxandro Sugkelkh (cretanman) Diaqeirist
Epimelhte
1. Strth Antwna (stranton)
2. Andra Barberkh (ANDREAS BARBERAKHS)
3. Kwnstantno Btta (vittasko)
4. Nko Katsph (nkatsipis)
5. Anastsio Kotrnh (Kotrnh Anastsio)
6. Jno Mgko (matha)
7. Girgo Mpalglou (gbaloglou)
8. Rodlfo Mprh (R BORIS)
9. Miqlh Nnno (Miqlh Nnno)
10. Leutrh Prwtotopap (Prwtopap Leutrh)
11. Dhmtrh Skoutrh (dement)
12. Mpmph Stergou (Mpmph Stergou)
13. Swtrh Stgia (swsto)
14. Aqilla Sunefakpoulo (achilleas)
15. Kwnstantno Thlgrafo (Thlgrafo Ksta)
16. Serafem Tsiplh (Serafem)
17. Qrsto Tsifkh (xr.tsif)
18. Dhmtrh Qristofdh (Demetres)
Melh
1. Spro Basilpoulo (spyros)
2. Ksta Zugorh (kostas.zig)
3. Girgh Kalajkh (exdx)
4. Qrsto Kardsh (QRHSTOS KARDASHS)
5. Jansh Mpelhginnh (mathfinder)
6. Jwm Rakftsalh (Jwm Rakftsalh)
7. Kwnstantno Rekomh (rek2)
8. Girgo Rodpoulo (hsiodos)
9. Staro Staurpoulo (Staro Staurpoulo)
10. Baslh Stefandh (bilstef)
1 ( ) 100 , 99% .
98% .
2 ( )
() -
( )
,
...
6210001000.
.
3 ( )
B, B, A.
;
4 ( )
A = 62006 + 32003 + 182001 + 92005
30.
5 ( ) .
AB 6m 4m. 9m .
()
.
() .
6 ( KARKAR) A , B , ,
.
A : ! B : ! . :
!
( -
) B
7 ( )
:
P(x) = x15 2012x14 + 2012x13 ... 2012x2 + 2012x. P(2011).
8 ( ) ABC A = 900
ab, bc, (a + c)(a c) .
,
9 ( )
m (m 1)x4 5x2 + 3m 2 = 0 .
1
10 ( ) :
x = 111...12
y = 111...1+1
z = 666...6
,
: x + y + z + 8 .
,
11 ( )
AB O . A O E, Z EO 24, Z.
12 ( KARKAR) S CD ABCD. BS AD T . AM,T M,CN, S N . MDN = A = .
,
13 ( )
() 1 = 4
+1 =8 9 + 2
N.
()
=1
3 N .
(). - ().
14 ( KARKAR) : 2x = 3a = 6b ,
: x =ab
a b .
,
15 ( )
(O,R) , (K, r) E. AB, , OK AB .
.
16 ( )
ABCD AC, BD CAB,BCA,CDB,BDA 70, 30, (50 a), a , , . BD CBA a.
,
17 ( KARKAR) ,
A(1, 3) B(4, 2), .
18 ( ) n,
n 2, :
1 +12+
13+ + 1
n>
n.
,
19 ( )
f (x) = x x + 1 x 0 = {1, 2, . . . , n}, P(k) = 12
5f (k)
k .
2
() f .() n.
()
x = n. 16% 33, .
20 ( Parmenides51)
lit
< , R. 1, 6 lit 20% 1, 4 lit 90% .
[, ] :() , .
() .
()
,
1000 2 lit.
, ,
21 ( )
f : R R z z , 1/2
f 2(x) + sin2(x) = 2x f (x) x R
limx0
f (x)x
= m,
m = |z2||2z1| .
() |z 2| = |2z 1|.() z
() limx0
f (sin x)x2 x .
() g(x) = f (x) x (,0) (0,+).
() f .() (|z + 3 4i| + 5)x = x3 + 10
[1, 2].
22
z = (k t) + (k t)i t R k > 1.
(1) z.
(2) w
y = x (k 1) , k |z w|min = 52
2 1.
(3) k (2) z |z z|.
(4) k (2) |w 3 + 4i|.
(5) u
u = (1 + mt) + (1 + mt)i, m
u .
(6) k,m (2) (5) , |z u|.
, , ,
23 ( )
f (x) = ex ln x + 2 1 1, ex
21 ln(x2 + 1) = 1e,
e1x + 2 ln x > ex.
24 ( ) f
h(x) = e f (x) f 3(x) + 2 .
f (x) :(12
) f (x2x) ( 12
) f (4x)> 0
, ,
25 ( )
f [a, b], (a, b) f (a) , f (b). 1, 2 (a, b) 1 , 2 : f (1) f (2) =
( f (b) f (a)b a
)2.
26 ( )
f : [1, e] R f (1) = 0, f (e) = 1 f (x) + e f (x) = x + 1
x, x [1, e] . :
f (x) = ln x x [1, e] .
, ,
27 ( ) :2
0
x10 + 210
x15 + 215dx < 181
2816.
28 ( )
f : R R :( f (x))2 + ( f (x))2 x2 + 1, x R.
:
1. ( f (1))2 ( f (0))2 43,
2. | f (1)| 43,
3. |F (1) F (0)| 109, F f .
3
, ,
29 ( )
f (x), g(x) : [a, b] R g(x) > 0,x [a, b].
(x a) f (x) = (x b)g(x),x [a, b] 1)
g(x) > 0 f (x) < 0, x (a, b)
2) b
af (x)dx = b
ag(x)dx
) f (b) = g(a)) (a, b) : f () = g()
30 ( parmenides51)
z1 = a + eai, z2 = b + bi, z3 = c + i ln c a, b R, c > 0.
1.
z1, z2, z3,
2. |z1 z2 | - z1, z2 ,
3. |z1 z3| - z1, z3 .
, ,
31 ( )
f : [0,+) R
f (x) + x f (x) = 12
f ( x2
) x [0,+) .
32 ( )
f (x) = ln(x2)
x2+1, N , N ,
.
33 ( )
f : [0, 1] R
f (0) = 0 10
e f(x) f (x) dx = f (1).
f (x) = 0,x [0, 1]
34 ( )
f : (0,+) R f
(x
y
)=
f (x)y
x f (y)y2
x, y (0,+) 1, f (1) = 1
Juniors,- -
35 ( )
n,
sin2n x + cos2n x + n sin2 x cos2 x = 1, x R.
36 ( ) a, b, c a + b + c = 3,
a2
(b + c)3 +b2
(c + a)3 +c2
(a + b)3 3
8.
Juniors,
37 ( )
ABC BC, I . BI AC D E, D CI. EI AB Z. DZ CI.
38 ( )
ABC E M, .
M, ABC ,
E1, E2 , E3. 1
E1+
1
E2+
1
E3 18
E.
Seniors,- -
39 ( )
f :(x y) f (x + y) (x + y) f (x y) = 4xy(x2 y2)
4
40 ( ) -
f : {1, 2, . . . , 10} {1, 2, . . . , 100} x + y|x f (x) + y f (y), x, y {1, 2, . . . , 10}.
Seniors,
41 ( )
ABCD (O) P AC BD.
ABCD Q,
QAB + QCB = QBC + QDC = 90o.
P, Q, O , O (O).
42 ( )
P ABCD, AB, BC, CD, DA, . ABCD -.
43 ( - 1
1995) 6-
5. ,
6 -
44 ( )
ABC AB AC D E , DE
. :ADDB
+AEEC
= 1
45 ( IMC 1996) n
.
sin nx(1 + 2x) sin x dx.
46 ( ) (an)nN an >
1n
n.
+n=1
an .
47 ( ) M = R \ {3} x y = 3(xy3x3y)+m, m R. m (M, ) .
48 (vzf) m n n .
, n , -
.
49 ( )
ln(1 aix)x2 + m
dx , a > 0, m > 0
50 ( ) an = 1 +n
j=21
ln j lim( nn)an
51 ( ) An = {n, 2n, 3n, ...} n N
J N, iJ
Ai
52 ( )
A, B AB = (A \ B) (B \ A), - .
A1A2...An Ai
53 ( ) p Pp > 5 (p 1)! + 1 p( pk k N).
5
54 ( dimtsig) -
.
55 ( ) S ,
s1, s2, ..., sn s1+s2+...+sn b ab > b2, a > c ab > bc, ab.
a2b2, b2c2, b4
a2b2 = (b2 + c2)b2 = b4 + c2b2, , .
10
:
9 ( ) -
m
(m 1)x4 5x2 + 3m 2 = 0 - .
http://www.mathematica.gr/forum/viewtopic.php?f=19&t=24722
( ) m = 1
: 5x2 + 1 = 0 x = 15.
.
m , 1 x2 = z
(m 1)z2 5z + 3m 2 = 0
(z) = (5)2 4(m 1)(3m 2)= 25 4(3m2 5m + 2)= 25 12m2 + 20m 8= 12m2 + 20m + 17 0 12m2 20m 17 0 (1)
(m) = (20)2 4(17)12 = 400 + 816 = 1216
m1 =20 +
1216
24=
5 + 219
6,
m2 =20
1216
24=
5 219
6.
(1) 5 219
6 m 5 + 2
19
6.
, ,
. Vieta :
z1 + z2 = ba=
5
m 1 > 0 m > 1
z1z2 =
a=
3m 2m 1 0 3m 2 0
3m 2
m 23
m > 1
1 < m 5 +19
6.
10 ( ) :
x = 111...12
y = 111...1+1
z = 666...6
,
: x + y + z + 8 .
http://www.mathematica.gr/forum/viewtopic.php?f=19&t=23823
( ) :
x = 111 1 2
= 1 100 + 1 101 + 1 102 + + 1 1021
=102 1
9
2
a1 = 1 = 10.
:
y = 111 1 +1
= 1 100 + 1 101 + 1 102 + + 1 10
=10+1 1
9
=10 10 1
9
11
z = 666 6
= 6 100 + 6 101 + 6 102 + + 6 101
= 6 10 19
=6 10 6
9.
x + y + z + 8 =102 1
9+10 10 1
9+6 10 6
9+ 8
x + y + z + 8 =102 + 16 10 + 64
9
x + y + z + 8 =(10 + 8
3
)2.
12
:
11 ( )
AB O -
. A O
E, Z EO 24,
Z.
http://www.mathematica.gr/forum/viewtopic.php?f=20&t=120
( ) ON//Z.
AZ A = 45,
ZA = = 22, 5.
AEO = 67, 5 (1) ,
AOE.
ENO = EAB = 22, 5 + 45 = 67, 5 (2) ,
- . (1) , (2) ONE (OE = ON = 24). O A ZA
Z .
Z = x = 2ON = 48.
2 ( )
.
A x
a x =A
A=
2, x =
2
1 +2
a.
,
AO OE =1
2
2
1 +2
a
, x = 2OE = 48. 12 ( KARKAR) S CD ABCD. BS AD T . AM, T M,CN, S N . MDN = A = .
13
http://www.mathematica.gr/forum/viewtopic.php?f=20&t=23657
(Antonis-Z) BM I BM, DC. BN AD E. N, M , BN
S BC = S BN + NBC = 2x BM ABS = ABM +MBT = 2y.
DCN = MAD = x + y. MABE , ABM =AEM = y.
BEA = EBC = x
. IBCN , CBN = CIN = x, DIN = NED DIEN . DIB = ABI = y, DIB = DEM, MIDE .
DIEN, MIDE MDNE ,
MDN = = 180 x y = 180 B2= 90 +
2.
14
:
13 ( )
() 1 = 4
+1 =8 9 + 2
N. ()
=1
3 N .
(). - ().
http://www.mathematica.gr/forum/viewtopic.php?f=21&t=24924
( )
:
v+1 =1
av+1 3=
18av9av+2
3
=1
8av93(av+2)av+2
=av + 2
5av 15
=av + 2
5(av 3), v N, :
v+1 v =av + 2
5(av 3) 1
av 3=
av + 2 55(av 3)
v+1 v =av 3
5(av 3) =1
5:
. ,
1 =1
a1 3= 1 v = 1 + (v 1) 1
5=
v + 4
5, v N.
:
S v =v
2(1 + v) = v
2
(1 +
v + 4
5
)=
v
2
v + 9
5=
v2 + 9v
10.
:
v =1
av 3 v + 4
5=
1
av 3
av 3 =5
v + 4 av = 3 +
5
v + 4 av =
3v + 17
v + 4, v N.
14 ( KARKAR) : 2x =3a = 6b , : x =
aba b .
http://www.mathematica.gr/forum/viewtopic.php?f=21&t=24475
1 ( f reyia)x ln 2 = a ln 3 = b ln 6 = b ln(2.3) = b ln 2 + b ln 3
x ln 2 = a ln 3
(a b) ln 3 = b ln 2 ln 2 = a bb ln 3. :
x ln 2 = a ln 3 xa bb ln 3 = a ln 3 x =ab
a b
2 ( )
2x = 3a = 6b = m
x =m
ln 2 , a =m
ln 3 , b =m
ln 6 , a , b
ab = m2
ln 3 ln 6, a b = m ln 2
ln 3 ln 6
aba b =
m
ln 2 = x.
3 ( )
2x = 3a = 6b x ln 2 = a ln 3 = b ln 6ab
a b =x ln 2ln 3 x ln 2ln 6
x ln 2ln 3 x ln 2ln 6
=x2 ln2 2
x ln 2 ln 6 x ln 2 ln 3 =
15
x ln2 2
ln 2 (ln 6 ln 2) = x ln2 2
ln 2 ln 2 = x
4 ( )
3 = 2xa , 6 = 2
xb 3 = 2 xbb x
a=
x bb x =
aba b .
5 ( ) x = a = b = 0 - .
a, b, x , 0 a , b, {a = b3a = 6b
3a = 6a .
16
:
15 ( )
(O,R) , (K, r) E. AB, , OK - AB .
.
http://www.mathematica.gr/forum/viewtopic.php?f=22&p=127551#p127551
1 (KARKAR) R2 + r2 AL = CL . E = E
1
2E
1
2E E E
=1
2(R2 + r2) E E .
E !
2 ( ) LA = LC =R2 + r2 , (1) ,
L LA = LB. , (1)
(
R2 + (LO)2 = (LA)2 = (LC)2 = r2 + (LK)2 R + r = OK = LO + LK ).
16 ( )
ABCD AC, BD CAB, BCA,CDB, BDA 70, 30, (50a), a , , . BD CBA a.
http://www.mathematica.gr/forum/viewtopic.php?f=22&t=24890
1 ( ) :
M AC BD,C BD = A BD = x,C MB = 70 + x
x = 40o
-
ABC, BCD, CDA, DAB
sin 70sin 30
=sin(50 a) sin(70 a)
sin a sin(60 + a) sin 70sin 30 =
cos 20 cos(120 2a)cos 60 cos(60 + 2a)
2 cos 20 =cos 20 + cos(60 + 2a)
12 cos(60 + 2a)
cos(60 + 2a) = 0 a = 15o
2 ( ) ABC (70, 80, 30).
17
C BD, BA E. BCE (80, 50, 50) ( - ),
BCDE AEDC (CEA = CDA = 50). ADE = ACE = 20, DCE (70, 55, 55) BCD : a = 15.
3 ( ) A BD CB E ADCE( 50 ),
DEB, DAB a = 15.
18
:
17 ( KARKAR) ,
A(1, 3) B(4, 2), .
http://www.mathematica.gr/forum/viewtopic.php?f=23&t=21244
1 ( ) > 0
C(, ), D(,). AC, BD :x + y = 2 x y = 2, . A B : + 3 = 2 4 2 = 2 . =
2
2 =
2
2,
:
2 + 2 = 2 . . . 2 = 2, c x2 + y2 = 2.
2 ( )
a ()
r > 0 .
(AC) : y 3 = a(x 1) ax y a + 3 = 0 (BD) : y 2 = a(x 4) ax y 4a + 2 = 0.
, :
d(O, AC) = r |3 a|
a2 + 1= r
|3 a| = r
a2 + 1
d(O, BD) = r |2 4a|
a2 + 1= r
|2 4a| = r
a2 + 1.
|3 a| = |2 4a|, a = 1 a = 1
3.
a = 1 r =2,
C : x2 + y2 = 2 ( ) a = 13
r =10 C : x2 + y2 = 10 ( ).
,
.
3 ( ) y = x + , , R 1 A xx. 3 = 1 + = 3 .
yy K (0, 3 ). y = x + , , R 2
B 1. 2 = 4 + = 2 4.
yy L (0, 2 4).
O R C, D , - KON, LOD , CO = DO = R, CON = DOL ( ), OK = OL |3 | = |2 4| . . .
( = 1 = 1
3
).
R = d (O, 1) = ...2 R =
10.
4 (parmenides51)
AC, BD - .
M AB.
19
M(1 + 4
2,3 + 2
2
)=
(5
2,5
2
).
OM AC, BD, AC, BD, AC BD.
xM =5
2, 0 = xO
OM =yM yOxM xO
=
52 052 0
= 1 ,
OM y 0 = 1(x 0) y = x. -
AC,OM, = d(AC,OM) = d(A,OM) = |yAxA |
(1)2+12=
|31|2=
22=2.
x2 + y2 = 2 =22= 2.
AC, BD
, AB ( C D). xA = 1 , 4 = xB
AB =yB yAxB xA
=2 34 1 =
1
3,
AB y 3 = 1
3(x 1) 3y 9 = x + 1 x + 3y = 10.
AB, = d(O, AB) = |0 + 0 10|
12 + 32=
1010=
10.
x2 + y2 = 2 = 10.
18 ( )
n, n 2, :
1 +12+
13+ + 1
n>
n.
http://www.mathematica.gr/forum/viewtopic.php?f=23&t=22805
1 ( ) k +
k 1 >
k k > 1 k = 1
.
1
k
k 1>
k,
1k>
k
k 1.,
1 +12+
13+ + 1
n>
1 +2
1 +
3
2 + +
n 1
n 2 + n
n 1 = n. 2 ( )
nk=1
1k> n n
n
k=1
1k=
n2n
n!.
n
2nn!
>
n,
n >nn!.
-
n2 >n(n + 1)
2= 1 + 2 + 3 + + n >
nn1 2 3 n = n n
n!,
.
3 ( )
1 +12+
13+ + 1
n+
1n + 1
>
n +1
n + 1,
>
n + 1.
(
) n + 1 n = 1
n + 1 +
n 0
.
()
P(1) + P(2) + + P(n) = 1
f (1) + f (2) + + f (n) = 512
f (x) x = 1, . . . , x =n
5
12=
(1
2 122
)+
(1
22 123
)+
+
(1
2
n 12
n + 1
)
=1
2 12
n + 1
n = 35.
() 16% 33 x s = 33 s = 2.
CV = sx 100% = 5, 71%
CV < 10% -.
20 ( Parmenides51)
lit < , R. 1, 6 lit 20% 1, 4 lit
90% . [, ] :
() , .
() .
()
,
1000
2 lit.
http://www.mathematica.gr/forum/viewtopic.php?f=18&t=15918
1 ( )
() X . A = {X 1, 6} B ={X 1, 4}. X , - -
[, ]. -:
P(A) = 1, 6 a a = 0, 2
P(B) = 1, 4 a = 0, 9.
= 1, 2 = 3, 2
21
()
a +
2= 2, 2.
()
= {X 2}
N()N() = P() =
2 1, 23, 2 1, 2 = 0, 4
N() = 1000 N() = 2500. 2 (parmenides51)
[, ], ,
.
() :
100% . 1, 6 20% .
1, 6 =
100
20. (1)
100% . 1, 4 90% .
1, 4 =
100
90. (2)
(1),(2)
= 1, 2 = 2, 2.
:
[, ] 100% [, 1.6] 20%
, [1.6, ] 80% . [1.4, ] 90% [1.4, 1.6] 10% . 1, 6 1, 4 = 0, 2 10% . 2 0, 2 = 0, 4 2 10% = 20% 1, 6 20%
1, 6 = 0, 4 = 1, 6 0, 4 = 1, 2.
10 0, 2 = 2 10 10 = 100% [, ] 100%
= 2 = + 2 = 1, 2 + 2 = 3, 2.
()
,
x = +
2=
1, 2 + 3, 2
2=
4, 4
2= 2, 2.
() 3, 2 1, 2 = 2 ( ).
2 1, 2 = 0, 8 1000 .
2
0, 8=
1000
=2000
0, 8= 2500
.
22
:
21 ( )
f : R R z z , 1/2
f 2(x) + sin2(x) = 2x f (x)
x R
limx0
f (x)x
= m,
m =|z2||2z1| .
() |z 2| = |2z 1|.
() z
() limx0
f (sin x)x2 x .
() g(x) = f (x)x
(, 0) (0,+).
() f .
() (|z+34i|+5)x = x3+ 10 [1, 2].
http://www.mathematica.gr/forum/viewtopic.php?p=111574#p111574
( )
() x , 0
f 2(x)x2
+sin2(x)
x2=
2 f (x)x
,
limx0
( f (x)
x
)2+
(sin x
x
)2 = limx0
2 f (x)x
,
m2 + 12 = 2m m = 1.
m = 1 |z2||2z1| = 1 |2z 1| = |z 2|.
()
|2z 1| = |z 2||2z 1|2 = |z 2|2(2z 1)(2z 1) = (z 2)(z 2)4zz 2z 2z + 1 = zz 2z 2z + 43zz = 3|z| = 1.
()
limx0
f (sin x)x2 x = limx0
f (sin x)sin x
sin xx
1
x 1= 1 1 (1) = 1.
limx0
f (sin x)sin x
sin x=ux0u0= lim
u0f (u)u
= 1.
()
f 2(x) + sin2 x = 2x f (x) f 2(x) 2x f (x) + x2 = x2 sin2 x( f (x) x)2 = x2 sin2 xg2(x) = x2 sin2 x.
| sin x| 6 |x|, x R x = 0 x , 0
x2 sin2 x , 0, g2(x) , 0. g (, 0) (0,+),
.
() 4 f .
(1) f (x) = x +
x2 sin2 x.(2) f (x) = x
x2 sin2 x.
(3) f (x) =x +
x2 sin2 x x > 0,
x
x2 sin2 x x < 0.
(4) f (x) =x +
x2 sin2 x x 6 0,
x
x2 sin2 x x > 0.
23
()
h(x) = (|z + 3 4i| + 5)x x3 10 x [1, 2]. h .
h(1) = |z + 3 4i| + 5 11= |z + 3 4i| 6 6 0
|z + 3 4i| 6 |z| + |3 4i| = 6.
h(2) = 2 |z + 3 4i| + 10 8 10= 2(|z + 3 4i| 4) > 0
|z + 3 4i| > ||z| |3 4i|| = 4. h(1)h(2) 6 0. h(1)h(2) < 0 Bolzano x0 (1, 2) h(x0) = 0.
(|z + 3 4i| + 5)x = x3 + 10 (1, 2). h(1)h(2) =0, x = 1 x = 2 .
(|z + 3 4i| + 5)x = x3 + 10 [1, 2].
22
z = (k t) + (k t)i t R k > 1.
(1) -
z.
(2) w
y = x (k 1) , k |z w|min = 5
2
2 1. (3) k (2) z |z z|.
(4) k (2) |w 3 + 4i|.
(5) u
u = (1 + mt) + (1 + mt)i, m
u
.
(6) k,m (2) (5) , |z u|.
http://www.mathematica.gr/forum/viewtopic.php?p=110457#p110457
( )
(1) z = x + yi, x, y R
x = k t, y = k t.
,
2(t) + 2(t) = 1 (x k)2 + (y k)2 = 1.
z A(k, k) 1 = 1 k > 1.
(2) d(A, ) = |3k1|2
> 1 k > 1, .
|z w|min = d(A, ) 1 = |3k 1|2
1
|z w|min =52
2 1 |3k 1|
2 1 = 5
2
2 1
|3k 1| = 5 k = 2,
k > 1.
(3) k = 2
z = (2 t) + (t 2)i.
z = + i, , R = 2 (t) = (t) 2
2(t) + 2(t) = 1 ( 2)2 + ( + 2)2 = 1.
24
z B(2,2) 2 = 1 = 1. : (1) k = 2
|z (2 + 2i)| = 1 |z (2 2i)| = 1 z B(2,2) 2 = 1 = 1. |z z| == |(2 t) + (2 + t)i (2 t) + (2 t)i|= |2(2 t)i| |z z|min = |2 1| = 2 |z z|max = |2 3| =6.
(4) |w 3 + 4i| = |w (3 4i)| w K(3,4). |w3+4i|min = d(K, ) = |34+1|
2= 0 (
K ).
(5) u = + i, , R.
(t) = 1 + m
, (t) = 1 + m
( m , 0 m = 0, u
(1,1)). ( + 1)2
m2+
( + 1)2m2
= 1 ( + 1)2 + ( + 1)2 = m2
u
(1,1) 3 = |m|. O(0, 0) (0 + 1)2 + (0 + 1)2 =m2 m2 = 2 m =
2.
:
w
m R
u = 0 + 0i { 1 + mt = 01 + mt = 0
t =1m
t = 1m
2t + 2t = 1 (1m
)2+
(1m
)2= 1
2m2= 1 m2 = 2 m =
2.
(6)
c =z u=(k t) + (k t)i (1 + mt) (1 + mt)i
=(k t) + (k t)i + (1 mt) + (1 mt)i=(k t + 1 mt) + (k t + 1 mt)i=[k + 1 (1 + m)t] + [(k + 1 (1 + m)t)] i
c = x + yi, x, y R
x = k + 1 (1 + m)t x (k + 1) = (1 + m)t,
y = k+ 1 (1+m)t y (k + 1) = (1+m)t.
(x (k + 1))2 + (y (k + 1))2=(1 + m)22t + (1 + m)22t
(x (k + 1))2 + (y (k + 1))2 = (1 + m)2k=2
m=2
(x 3)2 + (y 3)2 = (1 2)2
M(x, y)
(x 3)2 + (y 3)2 =(1 +
2)2.
25
OK, A, B. (OK) = d(K,O) =
32 + 32 =
32. OB
(OM) (OA). |C|max = (OA) = (OK) + = =
= 32 + 1 +
2 = 4
2 + 1
|C|min = (OB) = (OK) + = == 3
2 1
2 = 2
2 1.
M(x, y) (x 3)2 + (y 3)2 =
(2 1
)2.
OK, A, B. (OK) = d(K,O) =
32 + 32 =
32. OB
(OM) (OA).
|C|max = (OA) = (OK) + = == 3
2 +
2 1 = 4
2 1
|C|min = (OB) = (OK) + = == 3
2
2 + 1 = 2
2 + 1.
26
:
23 ( )
f (x) = ex ln x + 2 1 1,
ex21 ln(x2 + 1) = 1
e,
e1x + 2 ln x > ex.
http://www.mathematica.gr/forum/viewtopic.php?f=52&t=17341
( ).
) x > 0.
0 < x1 < x2 x1 > x2 ex1 > ex2 (1)
(y = ex . )
0 < x1 < x2
ln x1 < ln x2 ln x1 + 2 > ln x2 + 2(2)
(y = ln x . )
(1) , (2) f (x1) > f (x2) f 1 1
) ex21 ln
(x2 + 1
)=
1e
e(x2+1) ln
(x2 + 1
)+ 2 = 1
e+ 2
f(x2 + 1
)= f (1) f :11
x2 + 1 = 1 x = 0 x > 0, .
) e1x + 2 ln x > ex
e1x + ln x + 2 > ex ln x + 2
f(1x
)> f (x) 1
x< x
x>0 x2 > 1 x > 1
24 ( )
f
h(x) = e f (x) f 3(x) + 2 .
f (x) :
(12
) f (x2x) ( 12) f (4x) > 0http://www.mathematica.gr/forum/viewtopic.php?f=52&t=12656
( ) h R, x1, x2 R x1 > x2
:h(x1) > h(x2)
e f (x1) f 3(x1) + 2 > e f (x2) f 3(x2) + 2
( f (x1) f (x2))( f 2(x1) + f (x1) f (x2) + f 2(x2))
f (x2) () ()
, .
: f (x1) < f (x2), f R.
27
g(x) = x, 0 < < 1 R,
:
(12
) f (x2x)>(12
) f (4x) f (x2 x) < f (4 x) x2 x > 4 x x2 > 4 x < 2 x > 2.
:
h R : x < y h(x) > h(y), x, y R.
* .
* .
- x = y, h(x) = h(y), .
- x > y h , h(x) < h(y), .
x < y.
2 ( ) ( )
f
. .
f .. x1, x2 R x1 < x2 f (x1) 6 f (x2).
e f (x1) > e f (x2) f 3(x1) > f 3(x2) h(x1) 2 > h(x2) 2 h . .
x1, x2 R x1 < x2
f (x1) > f (x2), f . .
28
:
25 ( )
f [a, b], (a, b) f (a) , f (b). 1, 2 (a, b) 1 , 2 : f (1) f (2) =
( f (b) f (a)b a
)2.
http://www.mathematica.gr/forum/viewtopic.php?f=53&t=23144
1 ( )
a < x < b f (x) f (a)
x a =f (b) f (a)
b a := ,
f (b) f (x)b x =
-
[a, x] [x, b].,
> 0
f (x) f (a)x a >
f (b) f (a)b a >
f (b) f (x)b x ,
a < x < b.
g(x) := f (x) f (a)x a) (a, b]
[, c) ( ) ,
h(x) := f (x) f (b)x b [a, b)
(d, ] ( ).
k > 1 g() = k h() = /k , (a, b). [a, ] 1 (a, ) f (1) = g(). [, b] 2 (, b) f (2) = h().
k .
:
f [a, b], (a, b) f (a) , f (b). 1, 2, . . . , n (a, b)(n N)
f (1) f (2) f (n) =( f (b) f (a)
b a
)n.
2 ( )
f
f (b) f (a)b a = f
() > 0. U y : f (x) > 0, f (x) U . ln f ()
1, 2 U : ln f () = ln f(1) + ln f (2)
2, f (1) > 0, f (2) > 0
(1, 2) = V . ,
1 < < 2.
3 ( )
1 (a, k), 2 (k, b), :
f (1) = f (k) f (a)k a (1)
f (2) = f (b) f (k)b k (2)
f (1) f (2) =( f (b) f (a)
b a
)2,
(1) (2),
:
f (k) f (a)k a
f (b) f (k)b k =
( f (b) f (a)b a
)2(3)
- =f (b) f (a)
b a , (3) k,
29
:
f (k) f (a)k a
f (b) f (k)b k =
2
( f (k) f (a)) ( f (b) f (k)) = (k a) (b k) ()
k (a, b), :
f (k) f (a) = (b k) (4)
f (b) f (k) = (k a) (5).
k (4). (5) ...
(4):
f (b) f (k) = f (b) [ f (a) + (b k)]= f (b) f (a) (b k)= [b a b + k] == (k a) (2)
(5)
k. (4), ( )
h(x) = f(x) f(a) (b x), x [a, b]
Bolzano
h(a) = (b a) = f (a) f (b)h(b) = f (b) f (a) 0
= f (b) f (a).
:
h(a) h(b) = ( f (a) f (b))2 < 0, f (a) , f (b). .Bolzano h [a, b]
k (a, b) : h(k) = 0,
(4)
(5).
,
[a, k], [k, b], ,
.
(atemlos)
..
26 ( )
f : [1, e] R f (1) = 0,f (e) = 1 f (x) + e f (x) = x + 1
x, x [1, e] .
: f (x) = ln x x [1, e] .
http://www.mathematica.gr/forum/viewtopic.php?f=53&t=24617
1 ( )
h(x) = f (x) lnx, x [1, e],
( ) -
.
x0 (1, e) h(x0) , 0, , , f (x0) > 0, (
) x1
[1, e] ( ), Fermat
h(x1) = 0 f (x1) = 1x1,
x = x1
e f (x1) = x1 f (x1) = lnx1 h(x1) = 0,
.
2 ( )
,
g(x) = f (x) lnx [1, e].
g [1, e] .
: g(1) = g(e) = 0 :
g(x) = x(eg(x) 1), x [1, e] (1)
g .
.
30
, x1 ,
g(x1) > 0 .Fermat
g(x1) = 0.
, (1) . . ; ...
x2, (1) Fermat g(x2) = 0. .
g . g [1, e]...
g(x) = 0, x [1, e] f (x) = lnxx [1, e].
3 ( )
. -
:
g(x) = f (x) lnx g(x) = x xe f (x) xeg(x) + (eg(x)) = x
h(x) = eg(x), xh(x) + h(x) = x,
ex2
2
(e x2
2 h(x)) = xe x2
2
e x2
2 h(x) = e x2
2 + c elnx f (x) = 1 + ce x2
2
x = 1, c = 0.
elnx f (x) = 1 f (x) = lnx.
.
4 ( ) x (0,+): f (x) + e f (x) = x + 1
x(1).
x+1
x g(x) = x
2
2+lnx, x > 0.
(1) :
e f (x) = (g(x) f (x)) e f (x) (g(x) f (x)) = 1. eg(x) = x e x
2
2 : eg(x) f (x) (g(x) f (x)) = xe x
2
2 , (eg(x) f (x)
)=
(e
x2
2
),
eg(x) f (x) = ex2
2 + c.
x = 1 c = 0
f (x) = lnx, x > 0.
5 ( ) h : (0,+) , h (x) = ef (x)
x.
h (1) = h (e) = 1 f (x) = h (x) + xh
(x)xh (x) =
1
x+
h (x)h (x) ,
1
x+
h (x)h (x) + xh (x) = x +
1
x
h (x) = xh (x) (1 h (x)) .
,
x = x0,
h (x0) = 1 h (x0) = 0 (.Fermat) .
h h (1) = h (e) = 1, . h (x0) = h (1) = h (e) = 1.
h (x) = 1, x [1, e] e f (x) = x f (x) = ln x,x [1, e].
6 ( )
x : lnx , f (x), lnx > f (x). f (x) 1
x= x e f (x) = elnx e f (x) = (lnx f (x))e
lnx, f (x) ex. lnx, f (x) [1, e] {1, M} e max{e, eM} = k ( ). ( f (x) lnx) = (lnx f (x))e (lnx f (x))k
(( f (x) lnx)ekx)) < 0 1 x e, 0 = (( f (e) lne)eke)) (( f (x) lnx)ekx)) (( f (1) lnx)ek)) = 0, f (x) = lnx . lnx < f (x), lnx = f (x),x [1, e].
7 ( ) f f + f e f = 1 1
x2
f = f (x +
1
xx f
)+ 1 1
x2=
31
= ( f )2 (x + 1/x) f + 1 1/x2 (
e f ) y = y2 (x +
1
x
)y + 1 1
x2, y = f (
Ricatti).
y =1
x+
1
u, ... u + u
(1
x x
)= 1,
(xe x2
2 y) = (ex2/2) y = 1
x+
a
xe
x2
2 .
f (1) = 1 y(1) = 1
a = 0 f (x) = lnx + b f (1) = 0 b = 0 f (x) = lnx, x [1, e] ( f (e) = 1)?
32
:
27 ( )
:
20
x10 + 210
x15 + 215dx < 181
2816.
http://www.mathematica.gr/forum/viewtopic.php?f=54&t=8997
( )
20
x10 + 210
x15 + 215dx = 1
32
20
1 + (x/2)101 + (x/2)15 dx
=1
16
10
1 + y10
1 + y15dy
=1
16
(1 +
10
y10 y151 + y15
dy)
(1 + x2
) (( f (x))2 + ( f (x))2)
>( f (x) + x f (x))2 (
1 + x2)2>( f (x) + x f (x))2 f (x) + x f (x) 6 1 + x2
(1 + x2
)6 (x f (x)) 6 1 + x2
10
(1 + x2
)dx 6
10
(x f (x))dx 61
0
(1 + x2
)dx
| f (1)| 6 43
3. -
t > 0
t0
(1 + x2
)dx 6
t0
(x f (x))dx 6t
0
(1 + x2
)dx
t t3
3 t f (t) t + t
3
3 1 t
2
3 f (t) 1 + t
2
3.
f t = 0 10
(1 + t
2
3
)dt 6
10
f (t)dt 610
(1 + t
2
3
)dx.
.
33
:
29 ( )
f (x), g(x) : [a, b] R g(x) > 0,x [a, b].
(x a) f (x) = (x b)g(x),x [a, b]
1)
g(x) > 0 f (x) < 0,x (a, b)
2) b
af (x)dx = b
ag(x)dx
) f (b) = g(a)) (a, b) : f () = g()
http://www.mathematica.gr/forum/viewtopic.php?f=55&t=24860
( )
1) g(x) > 0, x [a, b] g [a, b] x a
(x a) f (x) = (x b)g(x) 0 = (a b)g(a) g(a) = 0 x > a g(x) > g(a) = 0
(xa) f (x) = (xb)g(x) a < x < b g(x) > 0 x a > 0, x b < 0 f (x) < 0
:
g(a) = 0, f (b) = 0 [a, b] g(a) 0, f (b) 0
2) )
(x a) f (x) = (x b)g(x) b
a
(x a) f (x)dx =b
a
(x b)g(x)dx
[(x a) f (x)]ba b
a
f (x)dx =
[(x b)g(x)]ba b
a
g(x)dx
b
a
f (x)dx =b
a
g(x)dx
[(x a) f (x)]ba = [(x b)g(x)]ba
(b a) f (a) = (b a)g(b) f (a) = g(b)
2.)
h(x) = f (x)g(x), x [a, b] [a, b]
h(a) = f (a) g(a) = f (a) f (b) > 0
f ( (1)) [a, b] f (a) > f (b) h(b) = f (b) g(b) = g(a) g(b) < 0 (1) g [a, b] g(a) < g(b) h(a)h(b) < 0 Bolzano x0 (a, b)
h(x0) = 0 f (x0) = g(x0)
h(x) = f (x) g(x) < 0, x (a, b) h [a, b] x0 .
30 ( parmenides51)
z1 = a + eai, z2 = b + bi, z3 = c + i ln c
a, b R, c > 0.
1.
z1, z2, z3,
2. |z1 z2| z1, z2 ,
3. |z1 z3| z1, z3 .
34
http://www.mathematica.gr/forum/viewtopic.php?f=55&t=24493
( ) ) z1 z = x + yi, x, y R, x = a, y = ea, a R y = ex. z1 y = ex.
z2 z = x+yi, x, y R, x = b, y = b, b R y = x. z2 y = x.
z3 z = x+yi, x, y R, x = c, y = lnc, c > 0 y = lnx. z3 y = lnx, x > 0.
) z1 = k + eki, k R |z1 z2| ,
L(k, ek) y x = 0, : d(L, ) = |e
a a|12 + (1)2
.
f (x) = ex x R
ex () x () f (x) = ex 1. :* f (x) = 0 x = 0* f (x) > 0 x > 0, * f [0,+)
* f (, 0]* f x = 0 f (0) = 1. d(L, ) a =0 ( L(0, e0) L(0, 1)) 1
2=
2
2.
1. L : y 1 = 1(x 0) y = x + 1. y = x, y = x + 1 (x, y) =
(1
2,1
2
),
z2
2
2.
|z1 z2| z1 = i z2 =
1
2+
1
2i.
)
y = ex, y = lnx - y = x,
|z1 z2| ,|z2 z3| 2
2
z3 L(0, 1) y = x, N(1, 0), z2 M
(1
2,1
2
)( ()
).
|z1 z3| :z1 = i z3 = 1 |z1 z3| = 2
2
2=
2.
35
:
31 ( )
f :[0,+) R
f (x) + x f (x) = 12
f ( x2 ) x [0,+) .
http://www.mathematica.gr/forum/viewtopic.php?f=56&t=21507
( ) g(x) = x f (x) ,x [0,+) [0,+)
g(x) =1
2
g(x/2)x/2
=g(x/2)
x, x > 0
0 , x = 0(1) .
..... g [0, x/2] 0 < 1 < x/2 ,
1
2g(1) = g(x/2) g(0)
x=
g(x/2)x
(1)= g(x) .
..... g [0, 1/2] 0 < 2 < 1/2 ,
1
2g(2) = g(1/2) g(0)
1=
g(1/2)1
(1)= g(1) .
.....
n , n N , 0 < n+1 < n/2 .
g(x) = 12
g(1) = 122
g(2) = . . . = 12n
g(n) (2) .
limx0
g(x) = limx0
g(x/2)x
00= lim
x01
2
g(x/2)x
=
limx0
1
2g(x/2) = 1
2limx0
g(x) limx0
g(x) = 0 = g(0) . g [0,+) . n + n 0 , 0 < n+1 < n/2 0 < n < 1/2n1 . lim
n+g(n) = 0 (3) .
, x [0,+),
limn+
g(x) (2)= limn+
1
2ng(n) = lim
n+1
2nlim
n+g(n)
(3)= 0 0 = 0 g(x) = 0 g(x) = c x f (x) = c 0 f (0) = c , f (x) = 0 , x [0,+) .
2 ( ) f x1, x2 [0, ] , > 0 m M, , [0, ] .
m f (x) M , x [0, ] .
m f ( x2 ) M , x [0, ] .
(x f (x)) = 12
f ( x2 ) M2 (x f (x) Mx
2
) 0 . g(t) = t f (t) Mt
2, t [0, ] .
x > 0 [0, x] (0, x)
g() = g(x) g(0)x 0 = f (x)
M2.
g() 0 f (x) M2.
x = x1, x1 ( x1 = 0 ,
M = 0)
f (x1) M2
M M2
M 0 .
, (x f (x)) = 12
f ( x2 ) m2 (x f (x) mx
2
) 0 h(t) = t f (t) mt
2, t [0, ]
, f (x) m2.
x = x2, x2 ( x2 = 0 ,
m = 0)
f (x2) m2
m m2
m 0 . 0 m f (x) M 0 f (x) = 0 , x [0, ] . , [0,+). , .
36
32 ( )
f (x) = ln(x2)
x2+1, N , N ,
.
http://www.mathematica.gr/forum/viewtopic.php?f=56&t=5181
( ) f (x) = ln(x2)
x2+1,
f (x) = 2 (2 + 1) ln(x2)
x2+2
f (x) = 2(4 + 3) + (2 + 1)(2 + 2) ln(x2)
x2k+3,
x R , N , N . f f .
1.
f (
) .
f A (x1, f (x1)) , B (x2, f (x2)) , 0 < x1 < x2. f (x1) = f (x2) = . f [x1, x2] (x1, x2) , f () = f (x2) f (x1)
x2 x1= .
0 < x1 < < x2
f (x1) = f () = f (x2) . . Rolle f [x1, ], [, x2] f
. ,
f .
2. -
f () A(x1, f (x1)) , B(x2, f (x2))
y f (x1) = f (x1)(x x1) (1) . :
) f (x1) = f (x2) 1. f x2 = x1 . B (x1, f (x1)) = (x1, f (x1)) .( - - x1 > 0)
) B (1) f (x1) f (x1) = f (x1)(x1 x1) f (x1) = x1 f (x1) (2) ln(x21 )x2+11
= x12 (2 + 1) ln(x21 )
x2+21
ln(x21 ) = 2 (2 + 1) ln(x21 )
(2 + 2) ln(x21 ) = 2 ln(x21 ) =
+ 1
x21 = e
+1 x1 = e1
2+2 .
(1) :
(1) (2) y = f (x1) x f (x1) = e( + 1)
: y =
e( + 1) x .
.
37
:
33 ( )
f : [0, 1] R
f (0) = 0 10
e f(x) f (x) dx = f (1).
f (x) = 0,x [0, 1]
http://www.mathematica.gr/forum/viewtopic.php?f=69&t=24696
( ) 10
e f(x) f (x)dx = f (1) = f (1) f (0) =
10
f (x)dx
10
(e f (x) f (x) f (x))dx = 0 10
f (x)(e f (x) 1)dx = 0
, f (x), e f (x)1 .
x (0, 1), f (x)(e f (x) 1) 0
x0 [0, 1] f (x0) , 0
(. f (x0) < 0),
10
f (x)(e f (x) 1)dx > 0, .
, f (x) = 0,x [0, 1]
f (x) = c,x [0, 1].
f (0) = 0, f (x) = 0, x [0, 1] 34 ( )
f : (0,+) R f
(x
y
)=
f (x)y
x f (y)y2
x, y (0,+) 1, f (1) = 1
http://www.mathematica.gr/forum/viewtopic.php?f=69&t=22009
( ) y x f (1) = 0.
:
f (1) = limx1
f (x) f (1)x 1 = 1
limx1
f (x)x 1 = 1 (3)
x0 > 0.
x x0, h =x0
x 1.
:
L = limxx0
f (x) f (x0)x x0
= limh1
f(
x0
h
) f (x0)
x0
h x0.
( x = x0 y = h):
L = limh1
f (x0)h
x0 f (h)h2 f (x0) x0(1 h)
h ,
,
(1) :
L =f (x0)
x0+ 1.
x0 , f / .. :(
f (x) = f (x)x
+ 1,x > 0) f (x)x (x) f (x)x2 =
( f (x)x
)=
1
x= (lnx) ,x > 0
( f (x)x
= lnx + c,x > 0).
38
f (x) = xlnx + xc,x > 0 .
x 1 : c = 0.
f (x) = xlnx,x > 0
.
39
, , :
35 ( )
n,
sin2n x + cos2n x + n sin2 x cos2 x = 1, x R.
http://www.mathematica.gr/forum/viewtopic.php?f=109&t=24910
( ) x =
41
2n+
1
2n+
n
4= 1
2n(n 4) + 8 = 0. (*) n 4 2n(n 4) 0 2n(n 4) + 8 > 0 0 n < 4, n = 2 n = 3 (*).
sin4x + cos4x + 2sin2xcos2x = (sin2x + cos2x)2 = 1 x R Euler sin2 x + cos2 x + (1) = 0(sin2 x)3 + (cos2 x)3 + (1)3 = 3 sin2 x cos2 x(1), sin6 x + cos6 x + 3 sin2 x cos2 x = 1, x R., n 2 3.
36 ( )
a, b, c a + b + c = 3,
a2
(b + c)3 +b2
(c + a)3 +c2
(a + b)3 3
8.
http://www.mathematica.gr/forum/viewtopic.php?f=109&t=24754
1 (BillK) f (x) = x2
(3 x)3 , x (0, 3) f (x) > 0 . Jensen f (a) + f (b) + f (c) 3 f (a+b+c3 ) f (a) + f (b) + f (c) 38
a2
(b + c)3 +b2
(c + a)3 +c2
(a + b)3 3
8
2 ( )
CS Nesbitt :(a2
(b+c)3 +b2
(c+a)3 +c2
(a+b)3)
[(b + c) + (c + a) + (a + b)] (a
(b+c) +b
(c+a) +c
(a+b))2 94 .
3 ( )
a2 (a + b + c)(b + c)3 +
b2 (a + b + c)(c + a)3 +
c2 (a + b + c)(a + b)3
9
8
a3
(b + c)3 + a2
(b + c)2 9
8.
:
Chebyshev 9(x3 + y3 + z3) (x + y + z)3. Nesbitt
9 a3
(b + c)3 ( a
b + c
)3 27
8
3 a2
(b + c)2 ( a
b + c
)2 9
4
40
:
37 ( )
ABC BC, I . BI AC D E, D CI. EI AB Z. DZ CI.
http://www.mathematica.gr/forum/viewtopic.php?f=110&t=13272
(KARKAR) C, E BC CEI = CDI = 90o+ B
2= DIE = 90o , (1) (1)
A = 90o DIZA IDZ = IAZ = 45o , (2)
(2) ADB = 90o B2, ADZ =
C2= ACI , (3) (3) DZ CI
.
2 ( ) E, - D CI BC, FD = FE , (1) F CI DE. DIC = EIC , (2)
(2) DIC = 180o IDC C2
= 180o
90o B2
C2
= 45o, DIE = 90o =BD EZ , (3)
(3) = IE = IZ , (4) BD B.
(1), (4) DEZ, DZ FI CI .
38 ( )
ABC E M, .
M, ABC , E1, E2, E3. 1
E1+
1
E2+
1
E3 18
E.
41
http://www.mathematica.gr/forum/viewtopic.php?f=110&t=17211
( )
MA1A2, MB2C2 A1MA2 = B2MC2
E1(MB2C2) =
(MA1)(MA2)(MB2)(MC2) , (1)
, E2
(MA1B1) =(MC1)(MC2)(MA1)(MB1) , (2)
E3(MA2C1) =
(MB1)(MB2)(MA2)(MC1) , (3)
(1), (2), (3) = E1 E2 E3 =(MA1A2)(MC1C2)(MA2C1) , (4) (4) , .
- :
1
E1+
1
E2+
1
E3 3
3
E1 E2 E3=
36
E1 E2 E3 (MB2C2)(MA1B1)(MA2C1)
18
E1 + E2 + E3 + (MB2C2) + (MA1B1) + (MA2C1) 18
E
42
, , :
39 ( )
f :
(x y) f (x + y) (x + y) f (x y) = 4xy(x2 y2)
http://www.mathematica.gr/forum/viewtopic.php?f=111&t=24585
1 ( ) x + y = a
x y = b x = a + b2
y =a b2
.
b f (a) a f (b) = ab(a2 b2)
a, b R, a, b R
f (a)a
f (b)b = a2 b2,
f (a)a
a2 = f (b)b b2.
h(x) = f (x)x
x2 x R , f (x) = x3 + cx, x R. f (0) = 0, f (x) = x3 + cx, x R, . 2 ( ) x = y + 1
f (2y + 1) = (2y + 1) f (1) + 4y(y + 1)(2y + 1).
f (1) = c + 1
f (2y + 1) = c(2y + 1) + (2y + 1)(4y2 + 4y + 1)= c(2y + 1) + (2y + 1)3,
f (x) = x3 + cx x R. 40 ( )
f : {1, 2, . . . , 10} {1, 2, . . . , 100}
x + y|x f (x) + y f (y), x, y {1, 2, . . . , 10}.
http://www.mathematica.gr/forum/viewtopic.php?f=111&t=18963
( ) , x 1, 2, . . . , 9, 2x + 1 x f (x) + f (x + 1)(x + 1) 2x f (x) + 2(x + 1) f (x + 1). , 2x + 1 f (x + 1) f (x). ,
99 f (10) f (1) =9
x=1
f (x + 1) f (x)
9
x=1
(2x + 1)
= 99.
, f (x+1) f (x) = 2x+1 f (1) = 1. f (x) = x2 x 1, 2, . . . , 10.
43
:
41 ( )
ABCD (O) P AC BD.
ABCD Q,
QAB + QCB = QBC + QDC = 90o.
P, Q, O , O (O).
http://www.mathematica.gr/forum/viewtopic.php?f=112&t=17404
( .) QBC + QDC = 90o= QBD + DBC + QDB + DBC = 90o , (1)
(1) QBD + QDB = 180o BQD DBC +BDC = A, BQD = 90o + A (2)
, AQC = 90o + D , (3) (2), (3), Q
(K), (M), BD, AC -
BQD, AQC R, Q, (K), (M.)
(K) , BQD + BKD
2= 180o , (4)
K (K). (2), (4) BOD = 2A,
BOD + BKD = 180o , KBOD
OBK + ODK = 180o = OBK = ODK = 90o, KB = KD OB = OD.
, (O) ABCD, (K) , (M)(
MAOC , M (M) ).
, O (O) (K), (M) , QR, ,
P AC BD,
44
(O), (K), (M) . 42 ( )
P ABCD, AB, BC, CD, DA, -. ABCD .
http://www.mathematica.gr/forum/viewtopic.php?f=112&t=24878
( .)
, .
. - P BC ABC, . P, ABCD a, b, c, d, AB, BC, CD, DA,.
P A, (a + d) ,
, (b + c) , P C.
, -
a + b + c + d , A, C .
,
B, D .
ABCD ,
.
,
,
, .
45
:
43 ( -
1 1995)
6- 5. ,
6
http://www.mathematica.gr/forum/viewtopic.php?p=120445
1 ( )
. .
b 599.997 106 b2 599.997 103 > 774 103
2b > 1500 103.
(b + 2)2 = b2 + 4b + 4 > 599.997 106 + 3 106 =600.000 106.
b2 (b + 2)2 .
b2 < 599.998 106 < 600.000 106 < (b + 2)2.
(599.998 106, 600.000 106) ,
599.998 599.999. .
2 ( ) 100000
5 .
-
. ,
(700000, 790000) (70000)2 < 5 1011 (79000)2 > 6 1011. 89999
.
44 ( )
ABC AB AC D E , DE
. :ADDB
+AEEC
= 1
http://www.mathematica.gr/forum/viewtopic.php?p=111876
1 ( ) H BO W CO AH OD AW OE. WAH = DOE = DAE = 60, WOH = 120.
A,W,O, H
AWH = AOH = 60 = AOH = AHW.
AWH . (
) : OW + OH = OA(= OB = OC).
ADDB
=OHOB =
OHOA
AEEC =
OWOC =
OWOA
ADDB
+AEEC
=OH + OW
OA=
OAOA
= 1.
: 1) D S E A ADDB
+AEEC
=AB/2AB/2
+0
EC= 1.
2) 1) E AC , D A. 2 ( )
: BD = x CE = y, : AD = x AE = y. , , : ED + BC = BD + CE,: ED + = x + y : ED = x + y .
46
ADE : ED2 = AE2 + AD2 2AD AF (1) F E AD. FEA = 30, AFE: AF =
1
2AE =
1
2( y). , (1),
: (x + y )2 = ( y)2 + ( x)2 ( x) ( y) =
3xyx + y
. -
: AD = x = x (2y x)x + y
AE = y = y (2x y)x + y
. :ADDB
+AEEC =
x (2y x)x (x + y) +
y (2x y)y (x + y) = 1.
3 (Math Rider ) c
-
. H DE F,G AB, AC :
:
AF = BF = AG = CG = c2
(1)
FD = DH, GE = HE (2) ( ) c = 2
3 (3) ( . . -
OGC)
+ = 60, = DOH = HOE( FOG = 120 FOD = DOH, HOE =EOG)
+ = 60 ( + ) =3 +
1 =3
3( + ) = 3(1 ) (4)
ADBD
+AEEC =
AF FDBF + FD
+AG GECG +GE
(1)=
c2 FDc2 + FD
+
c2 GEc2 +GE
=c 2FDc + 2FD
+c 2GEc + 2GE
(2)=
c 2DHc + 2DH
+c 2EHc + 2EH
(3)=
23 2DH
23 + 2DH
+23 2EH
23 + 2EH
=
3 DH
3 + DH
+
3 EH
3 + EH
=
3 3 +
+
3 3 +
=6 2
3 +3( + ) +
(4)=
6 23 + 3(1 ) +
=6 26 2 = 1
47
:
45 ( IMC 1996)
n .
sin nx(1 + 2x) sin x dx.
http://www.mathematica.gr/forum/viewtopic.php?f=59&t=25166
( )
In =
sin nx(1 + 2x) sin x dx
=
0
sin nx(1 + 2x) sin x dx +
0
sin nx(1 + 2x) sin x dx
=
0
sin nx(1 + 2x) sin x dx +
0
sin nu(1 + 2u) sin u du
=
0
sin nx(1 + 2x) sin x dx +
0
2u sin nu(1 + 2u) sin u du
=
0
sin nxsin x dx.
sin a sin b = 2 sin(a
2 b2
)cos
(a
2+
b2
)
In In2 = 0
sin nx sin (n 2)xsin x dx
=
0
2 sin x cos (n 1)xsin x
dx
= 2
0
cos (n 1)x dx = 0.
I0 = 0 I1 =
In =
0 n = 2k, n = 2k + 1.
46 ( )
(an)nN an >
1n n.
+n=1
an .
http://www.mathematica.gr/forum/viewtopic.php?f=59&t=24073
1 ( ) kn .
+n=1
an +n=1
(kn kn1)akn >+n=1
(1 kn1kn
).
1 kn1kn 0 ln xx1 1 x 1,
ln(kn) = ln(k1) +n
i=1ln(
kiki1
),
.
2 ( )
, kn kn > 2kn1 n. 1 kn1kn 0 .
3 ( ) n
k=1ak
. n
k=1(akan) (
),
nan. , an >cn
c > 0 n,
. limn+ nan = 0,
.
48
:
47 ( )
M = R \ {3} x y = 3(xy 3x 3y)+m, m R. m (M, ) .
http://www.mathematica.gr/forum/viewtopic.php?f=10&t=23549
( )
,
e. :
1 e = 1 3e 9 9e + m = 1 m = 6e + 10
2 e = 2 6e 18 9e + m = 2 m = 3e + 20.
e = 103
m = 30. m = 30
.
a, b M
a b = 3ab 9a 9b + 30= 3(ab 3a 3b + 27) + 3= 3(a 3)(b 3) + 3 , 3
a , 3 b , 3. . a M
a 103=
10
3 a
= 3a10
3 9a 9
= 10a 9a 30 + 30= a
103 .
a M
a x = x a = 103
3ax 9a 9x + 30 = 103
x = 27a 809(a 3) , 3
.
a, b, c M a (b c) = 9abc 27(ab + bc + ca) + 81(a + b + c) 240
= (a b) c
(M, ) . 48 (vzf) m -
nn . , n
, .
http://www.mathematica.gr/forum/viewtopic.php?f=10&t=23825
( )
k > n A1, A2, . . . , Ak n n . :
,I{1,2,...,k}
(1)|I| det
jIA j
= 0 (1) , k = 3, (1) 2 2 A1, A2, A3
det (A1 + A2 + A3) det (A1 + A2) det (A2 + A3) det (A3 + A1) + det (A1) + det (A2) + det (A3) = 0.
(1) : m > n A1, A2, . . . , Am nn .
r
, r 6 n, .
, (1) k = n + 1 r , r 6 n + 1, .
, (1) k = n +2, . . . ,m A1 + A2 + + Am .
(1). [k] := {1, 2, . . . , k} :
,I{1,2,...,k}
(1)|I| det
jIA j
=
,I[k]
(1)|I|S n
sgn ()n
i=1
jI
A j (i, (i)) .
49
, :
,I{1,2,...,k}
(1)|I| det
jIA j
=
S n
sgn () ,I[k]
(1)|I|n
i=1
jI
A j (i, (i)) .
, , S n. ai j = A j (i, (i)) . :
,I{1,2,...,k}
(1)|I|n
i=1
jI
ai j
= 0. (2) (2) aJ := a1, j1a2, j2 an, jn , J :=[ j1, j2, . . . , jn] ( j1, j2, . . . , jn ,
, J
j1, j2, . . . , jn.) , I {1, 2, . . . , k} J I,
aJ (2)
, (1)|I|. |J| 6 n < k, r = |I| |J|, 0 6 r 6 k |J|, aJ (2)
k|J|r=0
(1)|J|+r(k |J|
r
)
=(1)|J|k|J|r=0
(1)r(k |J|
r
)
=(1)|J|(1 + 1)k|J| = 0.
(2), (1), .
50
:
49 ( )
ln(1 aix)x2 + m
dx , a > 0, m > 0
http://www.mathematica.gr/forum/viewtopic.php?f=9&t=7842&start=160
1 ( )
I1 = 0
x2(x2 + b2) (x2 + c2) dx = 2 (b + c) , b, c > 0 .
I2 = 0
ln(1 + x2)x2 + m2
dx = m
ln(m + 1) ,
I2 = 0
ln(1 + x2)x2 + m2
dx = 0
1
x2 + m2
( x0
2y1 + y2
dy)
dx y= xt===
0
1
x2 + m2
( 10
2x2t1 + x2t2
dt)
dx =
2
10
t
( 0
x2(x2 + m2
) (1 + x2t2
) dx) dt =2
10
1
t
( 0
x2(x2 + m2
) ( 1t2+ x2
) dx) dt I1==1
0
1
t
m + 1t
dt = m
ln(m + 1) .
ln(1 axi)x2 + m
dx ax=y====
a
ln(1 + yi)y2 + a2m
dy = a2
ln(1 + y2) + i arctan yy2 + a2m
dy
= a
0
ln(1 + y2)y2 + a2m
dy + 0 = a 0
ln(1 + y2)y2 +
(a
m)2 dy I2==
m
ln(1 + a
m).
2 ( ) -
f (z) = ln(1 aiz)z2 + m
, z C, a > 0,m > 0
, branch cut
z1 = ia , .
ln(1 aiz) = ln(az + i)ln i = ln |az + i|+i arg(az + i)i2
ln i = ln |i| + i arg(i) = i2.
C : [0, ] C A (R, 0) , B (R, 0). branch cut,
f ( ),
Cauchy:
C
f (z) dz = 2i Res( f , im ) , i
m.
C
f (z) dz = 0
f (Reit) iR eit dt + RR
f (z) dz .
0
f (R eit) iR eit dt = 0
ln(1 aiR eit)R2e2it + m
iR eit dt .
R
0
iR eit f (R eit) dt 6
0
R
ln(1 ai R eit)R2 e2it + m dt . R2 e2it + m > R2 |e2it | m = R2 m , R > m,
ln(1 aiR eit) = |ln(1 + aR sin t aiR cos t)| =ln 2 + 2aR sin t + i arg(1 + aR sin t aiR cos t) 63
2+
1
2ln(1 + 2aR sin t) 6 3 + ln(1 + 2aR)
2.
0
R
ln(1 aiR eit)|R2 e2it + m| dt 6 R
0
3 + ln(1 + 2aR)2R2 2m dt =
R 3 + ln(1 + 2aR)
2R2 2m 0 , R .
limR
0
f (Reit) iR eit dt = 0
limR+
RR
f (z) dz =
f (z) dz .
f (z) dz = 2i Res( f , im ).
51
Res( f , im ) =ln(ai
m + i)
2i
m=
lni (am + 1) + i arg (i (am + 1)) i/2
2i
m=
ln(1 + a
m)
2i
m.
ln(1 aix)x2 + m
dx = m
ln(1 + am ) . 50 ( ) an =
1 +n
j=21
ln j lim( n
n)an
http://www.mathematica.gr/forum/viewtopic.php?f=9&t=23985
1 ( ) 2 j n 1
ln j =1
ln n1
1 + ln( j/n)ln n=
1
ln n(1 + O
( ln( j/n)ln n
))=
1
ln n + O( ln( j/n)
ln2 n
), 1 < ln( j/n)ln n 0.
n
j=2
1
ln j =n 1ln n + O
(1
ln2 nn
j=2 ln( j/n)).
ln(x/n) [2, n].
n2
ln(x/n) dx + ln(2/n) n
j=2ln( j/n)
n+12
ln(x/n) dx ,
nj=2
ln( j/n) = n2
ln(x/n) dx + O(ln n) = n + O(ln n) .
n
j=2
1
ln j =n 1ln n + O
( nln2 n
)
( nn)an
= exp(ln nn
(1 +
n 1ln n
+ O(n ln2 n))) =
exp(1 + O(ln1 n)
) e .
2 ( ) (
n
n)an
= eann
ln n .
an
nln n = ann
ln n.
an
, 1 +n
j=2
1
ln j > 1 +n
j=2
1
j 1 .
n
ln n n
. :
an+1 ann+1
ln(n+1) nln n=
1ln(n+1)
(n+1) ln nn ln(n+1)ln(n+1) ln n
=ln n
ln[( nn+1
)nn] =
ln nln 1(
1+ 1n
)n + ln n = 1 ln(1+ 1n )nln n + 1 1 Cesaro-Stolz : lim
nann
ln n= 1 .
e .
52
:
51 ( ) An = {n, 2n, 3n, ...} n N
J N,
iJ
Ai
http://www.mathematica.gr/forum/viewtopic.php?f=64&t=22887
( ) : .
A j , N. , m N. J , j J j > m( J {1, 2, ...,m} = ). m < A j, . .
52 ( )
A, B AB = (A \ B) (B \ A), .
A1A2...An
Ai
http://www.mathematica.gr/forum/viewtopic.php?f=64&t=23440
( ) A x
A(x) = 0 x < A A(x) = 1 x A.
(AB)(x) A(x) + B(x) mod 2.
x A1 An (A1 An)(x) = 1 A1(x) + + An(x) 1 mod 2 x Ai.
modulo2.
53
:
53 (
) p P p > 5 (p 1)! + 1 p ( pk k N).
http://www.mathematica.gr/forum/viewtopic.php?f=63&t=20371
( )
p > 5 , (p 1)! + 1 = pk k. ,
(p 1)! = pk 1.: (p 1)! 0
(mod(p 1)2
).
,
(p 1)2 = 2 p 12
(p 1) ,, p > 5,
2
(p 1)p1. ,
pk (p 1)p1 + 1 > (p 1)! + 1 = pk, . .
54 ( dimtsig)
.
http://www.mathematica.gr/forum/viewtopic.php?f=63&t=22945
( ) -
1 .
m
111...1n
= m2, n > 1.
, m
1 9.
m m = 10a 1, a N.
,
111...1n
= 100a2 20a + 1,
111...10n1
= 100a2 20a,
111...1n1
= 10a2 2a.
, ,
.
54
:
55 ( )
S ,
s1, s2, ..., sn s1 + s2 + ... + sn < 1. S - ;
http://www.mathematica.gr/forum/viewtopic.php?f=13&t=18203
( ) n N An = {sk : sk 1n }. ( n
). S = An, S -.
56 ( -
) (entire) f , g
f (z)2 + g(z)2 = 1 z C.
http://www.mathematica.gr/forum/viewtopic.php?f=13&t=13878
( ) f 2 (z) + g2 (z) = 1
( f (z) + i g (z)) ( f (z) i g (z)) = 1
f (z) + i g (z) , 0 z C
(z)
( C) f (z) + i g (z) = e(z) . 1
f (z) + i g (z) = f (z) i g (z) = e(z) .
{ f (z) + i g (z) = e(z)f (z) i g (z) = e(z)
}
f (z) = e(z)
+ e(z)
2g (z) = e
(z) e(z)2i
(z) = i (z) ()
f (z) = cos ( (z)) g (z) = sin ( (z))
(z) .
55
:
57 ( )
BE B O
BOOE
=
32.
.
http://www.mathematica.gr/forum/posting.php?mode=edit&f=27&p=119266
( )
ABE, BEC :32=
BOOE
=ABAE
=BCCE
=AB + BC
AC.
:
sin C + cos C =32
1 + sin 2 C = 32
C = 150 A = 750
2 ( ) (ABC) = (ABE) + (BEC).
1
2AB BC = 1
2AB BE
2
2+
1
2BC BE
2
2.
BE2=
AB BCAB + BC (1).
r
ABC BO =2r
EO = 23
3r.
1
2AB BC = 1
2(AB + BC +CA)r (1)
2 +
23
32
=AB + BC +CA
AB + BC .
1 +
23= 1 +
ACAB + BC
. -
AB2 4AB BC + BC2 = 0 ABBC = 2
3.
ABBC = 2
3 = tan 15o
sin Csin A = tan 15
o .
C = 15o A = 75o.
ABBC
= 2 +3 = tan 75o
.
58 ( )
sin(
arctan(1
3
)+ arctan
(1
5
)+ arctan
(1
7
)
+ arctan(1
11
)+ arctan
(1
13
)+ arctan
(111
121
) ).
http://www.mathematica.gr/forum/viewtopic.php?f=27&t=23387
( )
arctan (x) + arctan (y) = z tan z =
x + y1 xy
z = arctan(
x + y1 xy
).
56
tan (x) = z 1
z= tan
(
2 x
)
arctan(1
z
)=
2 x =
2 arctan (z)
arctan(1
z
)+ arctan (z) =
2.
arctan(1
3
)+ arctan
(1
5
)+ arctan
(1
7
)+ arctan
(1
11
)+
arctan(1
13
)+ arctan
(111
121
)=
arctan(4
7
)+ arctan
(1
7
)+ arctan
(1
11
)+ arctan
(1
13
)+
arctan(111
121
)=
arctan(7
9
)+ arctan
(1
11
)+ arctan
(1
13
)+ arctan
(111
121
)=
arctan(43
46
)+ arctan
(1
13
)+ arctan
(111
121
)=
arctan(121
111
)+ arctan
(111
121
)=
2.
sin(
arctan(1
3
)+ arctan
(1
5
)+ arctan
(1
7
)
+ arctan(1
11
)+ arctan
(1
13
)+ arctan
(111
121
) )= 1.
57
:
59 ( KARKAR)
A ABC BC. (O) A AB, AC P, Q .
PQ S , S T . AT M BC.
http://www.mathematica.gr/forum/viewtopic.php?f=62&t=22297
1 ( ) AQT P , AT AQP. BPQC ( ) BC PQ. AT BC.
2 ( ) AM S . PQ ( S ) S . - A.PRQS . BC// BC AT .
3 ( )
A = AK AN = AP AB = AT AM =AQ AC. (o) BC. S T A, M, S ,(S S , AS ) BC M. S A M MM AS , = PBCQ, = QCS S , = ()//BC, ABCS , M AS , M BC.
4 ( ) N PQ, NAP = MAC, ABC, APQ . S , A,O, N, T S O, S NA = S T A = S AT , NPA = S AQ NAP = MAC( ).
58
60 (
[ ] ) ABC A , BAC BC .
ABC .
http://www.mathematica.gr/forum/viewtopic.php?f=62&t=22802
1 ( )
,
p, c, Q = (0, p), KQ KA = c(1). BKC = 2A, KBC ,
> 1,
KA = y0 x20 = 2y20 y20 2 + 2y0(2). (1)
x20 + (y0 p)2 = y0 + c (2)
2y0( p c) = c2 + 2 p2. c = p, c2 + 2 = p2
c =2
2 1 > 0, p =(2 + 1
)1 2 < 0.
,
(Q, 2
2 1
).
2 ( )
AW, AS , BAC = AEZ = AZE (), c ,
.
: BAC = AEZ = AZE KBFC, QZFE. L, F,. Q QA = r2
QH QA = KQ2 R2 = 2Rr + r2, QH
Q =2Rr + r2
r2
H
Q =2Rr.
Q
r=
KLR
=AH2R
H
r=
AH2R
2Rr H = AH D = AD,
QZ = A, ct, Q - .
, r2 = Q QA.
3 ( ) AD A = AD2 () (c) AD B,C B,C .
59
(o) (ABC) BC. A , BC (n) (c). ( BC (n)) , (ABC) (n) (n).
60
:
61 ( )
C :z + 1z =
z2 + 1z2 = 2
http://www.mathematica.gr/forum/viewtopic.php?f=60&t=24667
1 ( ) |z + 1z| = 2
|z2 + 1z2+ 2| = 4. w = z2 + 1
z2.
|w + 2| = 4 |w| = 2.
w = 2 z2 = 1. z = 1 z = 1. 2 ( ) z + 1z
= 2 z + 1z
2 = 4 z2 + 1z2 + 2
= 4 : (1) z2 + 1z2
= 2 : (2)
z2 +1
z2= x + yi, (x, y R)
(2)
x2 + y2 = 2 x2 + y2 = 4 : (3)
(1) |(x + 2) + yi| = 4 (x + 2)2 + y2 = 4 (x + 2)2 + y2 = 16 : (4)
(3) (4) (x, y) = (2, 0).
z2 +1
z2= 2 z4 2z2 + 1 = 0
(z2 1
)2= 0 (z = 1 z = 1)
3 ( )
z +1
z= w
|w| = |w2 2| = 2
2 =ww
2
|w2 2| = 2 |w2 ww2| = 2 |2w w| = 2
w = x + yi |w| = 2 |2w w| = 2 w = 2 w = 2 (x = 2 y = 0). .
62 ( )
P(x) , n x1, x2, ..., xn.
ni=1
P(xi)P(xi) = 0
http://www.mathematica.gr/forum/viewtopic.php?f=60&t=22338
1 ( ) an = 1, -
Q(x) = 1an
P(x).P(x) = (x x1)(x x2)(x x3)...(x xn1)(x xn)P(x) = (x x2)(x x3)...(x xn1)(x xn)+(x x1)(x x3)...(x xn1)(x xn)...
+(x x1)(x x2)(x x3)...(x xn2)(x xn)+(x x1)(x x2)(x x3)...(x xn1)P(x) = (xx3)...(xxn1)(xxn)+(xx2)(xx4)...(x
xn1)(x xn) +...+ (x x2)(x x3)...(x xn2)(x xn)+ (xx2)(x x3)...(x xn1)
+(x x3)...(x xn1)(x xn) + (x x1)(x x4)...(x xn1)(x xn)+ (x x1)(x x3)...(x xn2)(x xn)+ ...+ (xx1)(x x3)...(x xn1)
...
+(x x2)...(x xn2)(x xn) + (x x1)(x x3)...(x xn2)(x xn) +..+ (x x1)(x x2)...(x xn3)(x xn)+ (xx1)(x x2)...(x xn2)
+(x x2)...(x xn1) + (x x1)(x x3)...(x xn1)+... + (x x1)(x x2)...(x xn2)
: P(xi) = (xi x1)...(xi xi1)(xi xi+1)...(xi xn)
61
P(xi) = 2(xi x2)...(xi xi1)(xi xi+1)...(xi xn)+...+ 2(xi x1)...(xi xi2)(xi xi+1)...(xi xn)+
2(xi x1)...(xi xi1)(xi xi+2)...(xi xn) + ...+ 2(xi x1)...(xi xi1)(xi xi+1)...(xi xn1)
:P(xi)P(xi) =
2
(1
xi x1+ ... +
1
xi xi1+
1
xi xi+1+ ... +
1
xi xn
):
ni=1
P(xi)P(xi) = 2
(1
x1 x2+
1
x1 x3+ ... +
1
x1 xn
)+
2
(1
x2 x1+
1
x2 x3+ ... +
1
x2 xn
)+ ...
+2
(1
xn x1+
1
xn x2+ ... +
1
xn xn1
)= 0
2 ( )
( p
p) = 1
x r1+ ... +
1
x rn= S ,x , r1, ..., rn
( pp
) = 1S,x , u1, ..., un1 u1, ..., un1
p ()
(p)2 pp(p)2 =
S S 2
p
p= 1 +
S
S 2,x , u1, ..., un1
p
p=
( 1xr1 + ... +
1xrn )
2 ( 1(xr1)2 + ... +1
(xrn)2
( 1xr1 + ... +
1xrn )
2=
2
ni, j
1xix j
( 1xr1 + ... +
1xrn )
2
P(ri)P(ri) =
2
(1
ri r1+ ... +
1
ri ri1+
1
ri ri+1+ ... +
1
ri rn
)...
62
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