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icosidodecahedron9

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  • To {Eikosidwdekedron} parousizei jmata pou qoun suzhthje ston isttopo http://www.mathematica.gr.H epilog kai h frontda tou perieqomnou gnetai ap tou Epimelht tou http://www.mathematica.gr.Metatrop se LATEX: Fwtein Kald, Anastsh Kotrnh, Leutrh Prwtopap, Aqilla Sunefakpouo , Sqmata: Miqlh Nnno, Qrsto Tsifkh Seli-dopohsh: Anastsh Kotrnh, Nko Mauroginnh, Exfullo: Grhgrh Kwstko. Stoiqeiojetetai me to LATEX.Mpore na anaparaqje kai na dianemhje elejera.

    Eikosidwekedro filoteqnhmno ap ton Leonardo da Vinci

    To eikosidwdekedro enai na poledro (32-edro) me ekosi trigwnik dre kai ddeka pentagwnik. 'Eqei 30 panomoitupe koruf st opoe sunantntai do

    trgwna kai do pentgwna kai exnta se akm pou h kje ma tou qwrzei na trgwno ap na pentgwno. Enai arqimdeio stere - dhlad na hmikanonik

    kurt poledro pou do perissteroi tpoi polugnwn sunantntai me ton dio trpo sti koruf tou - kai eidiktera enai to na ap ta do oiwne kanonik

    - quasiregular poledra pou uprqoun, dhlad stere pou mpore na qei do tpou edrn oi opoe enallssontai sthn koin koruf (To llo enai to kubo -

    oktedro). To eikosidwdekedro qei eikosiedrik summetra kai oi suntetagmne twn korufn en eikosadrou me monadiae akm enai oi kuklik metajsei

    twn (0, 0,),(

    12,

    2,

    1+2

    ), pou o qrus lgo

    1+

    52

    en to duadik tou poledro enai to rombik triakontedro.

    Phg:http://en.wikipedia.org/wiki/Icosidodecahedron

    Apdosh: Pno Giannpoulo

    O diktuak tpo mathematica.gr ankei kai dieujnetai smfwna me ton kanonism tou pou uprqei sthn arqiktou selda (http://www.mathematica.gr) ap omda Dieujunntwn Meln.

    Dieujnonta Mlh tou mathematica.gr

    Suntoniste

    Airet Mlh

    1. Fwtein Kald (Fwtein) Genik Suntonstria

    2. Miqlh Lmprou (Mihalis Lambrou) Genik Sun-

    tonist

    3. Nko Mauroginnh (nsmavrogiannis) Genik Sun-

    tonist

    4. Spro Kardamtsh (Kardamtsh Spro)

    Upejuno Enhmrwsh

    5. Qrsto Kuriaz (chris gatos)

    Upejuno Programmatismo

    6. Mlto Papagrhgorkh (m.papagrigorakis)

    Upejuno Oikonomikn

    7. Girgo Rzo (Girgo Rzo)

    Upejuno Ekdsewn

    Mnima Mlh

    1. Grhgrh Kwstko (grigkost) Diaqeirist

    2. Alxandro Sugkelkh (cretanman) Diaqeirist

    Epimelhte

    1. Strth Antwna (stranton)

    2. Andra Barberkh (ANDREAS BARBERAKHS)

    3. Kwnstantno Btta (vittasko)

    4. Nko Katsph (nkatsipis)

    5. Anastsio Kotrnh (Kotrnh Anastsio)

    6. Jno Mgko (matha)

    7. Girgo Mpalglou (gbaloglou)

    8. Rodlfo Mprh (R BORIS)

    9. Miqlh Nnno (Miqlh Nnno)

    10. Leutrh Prwtotopap (Prwtopap Leutrh)

    11. Dhmtrh Skoutrh (dement)

    12. Mpmph Stergou (Mpmph Stergou)

    13. Swtrh Stgia (swsto)

    14. Aqilla Sunefakpoulo (achilleas)

    15. Kwnstantno Thlgrafo (Thlgrafo Ksta)

    16. Serafem Tsiplh (Serafem)

    17. Qrsto Tsifkh (xr.tsif)

    18. Dhmtrh Qristofdh (Demetres)

    Melh

    1. Spro Basilpoulo (spyros)

    2. Ksta Zugorh (kostas.zig)

    3. Girgh Kalajkh (exdx)

    4. Qrsto Kardsh (QRHSTOS KARDASHS)

    5. Jansh Mpelhginnh (mathfinder)

    6. Jwm Rakftsalh (Jwm Rakftsalh)

    7. Kwnstantno Rekomh (rek2)

    8. Girgo Rodpoulo (hsiodos)

    9. Staro Staurpoulo (Staro Staurpoulo)

    10. Baslh Stefandh (bilstef)

  • 1 ( ) 100 , 99% .

    98% .

    2 ( )

    () -

    ( )

    ,

    ...

    6210001000.

    .

    3 ( )

    B, B, A.

    ;

    4 ( )

    A = 62006 + 32003 + 182001 + 92005

    30.

    5 ( ) .

    AB 6m 4m. 9m .

    ()

    .

    () .

    6 ( KARKAR) A , B , ,

    .

    A : ! B : ! . :

    !

    ( -

    ) B

    7 ( )

    :

    P(x) = x15 2012x14 + 2012x13 ... 2012x2 + 2012x. P(2011).

    8 ( ) ABC A = 900

    ab, bc, (a + c)(a c) .

    ,

    9 ( )

    m (m 1)x4 5x2 + 3m 2 = 0 .

    1

  • 10 ( ) :

    x = 111...12

    y = 111...1+1

    z = 666...6

    ,

    : x + y + z + 8 .

    ,

    11 ( )

    AB O . A O E, Z EO 24, Z.

    12 ( KARKAR) S CD ABCD. BS AD T . AM,T M,CN, S N . MDN = A = .

    ,

    13 ( )

    () 1 = 4

    +1 =8 9 + 2

    N.

    ()

    =1

    3 N .

    (). - ().

    14 ( KARKAR) : 2x = 3a = 6b ,

    : x =ab

    a b .

    ,

    15 ( )

    (O,R) , (K, r) E. AB, , OK AB .

    .

    16 ( )

    ABCD AC, BD CAB,BCA,CDB,BDA 70, 30, (50 a), a , , . BD CBA a.

    ,

    17 ( KARKAR) ,

    A(1, 3) B(4, 2), .

    18 ( ) n,

    n 2, :

    1 +12+

    13+ + 1

    n>

    n.

    ,

    19 ( )

    f (x) = x x + 1 x 0 = {1, 2, . . . , n}, P(k) = 12

    5f (k)

    k .

    2

  • () f .() n.

    ()

    x = n. 16% 33, .

    20 ( Parmenides51)

    lit

    < , R. 1, 6 lit 20% 1, 4 lit 90% .

    [, ] :() , .

    () .

    ()

    ,

    1000 2 lit.

    , ,

    21 ( )

    f : R R z z , 1/2

    f 2(x) + sin2(x) = 2x f (x) x R

    limx0

    f (x)x

    = m,

    m = |z2||2z1| .

    () |z 2| = |2z 1|.() z

    () limx0

    f (sin x)x2 x .

    () g(x) = f (x) x (,0) (0,+).

    () f .() (|z + 3 4i| + 5)x = x3 + 10

    [1, 2].

    22

    z = (k t) + (k t)i t R k > 1.

    (1) z.

    (2) w

    y = x (k 1) , k |z w|min = 52

    2 1.

    (3) k (2) z |z z|.

    (4) k (2) |w 3 + 4i|.

    (5) u

    u = (1 + mt) + (1 + mt)i, m

    u .

    (6) k,m (2) (5) , |z u|.

    , , ,

    23 ( )

    f (x) = ex ln x + 2 1 1, ex

    21 ln(x2 + 1) = 1e,

    e1x + 2 ln x > ex.

    24 ( ) f

    h(x) = e f (x) f 3(x) + 2 .

    f (x) :(12

    ) f (x2x) ( 12

    ) f (4x)> 0

    , ,

    25 ( )

    f [a, b], (a, b) f (a) , f (b). 1, 2 (a, b) 1 , 2 : f (1) f (2) =

    ( f (b) f (a)b a

    )2.

    26 ( )

    f : [1, e] R f (1) = 0, f (e) = 1 f (x) + e f (x) = x + 1

    x, x [1, e] . :

    f (x) = ln x x [1, e] .

    , ,

    27 ( ) :2

    0

    x10 + 210

    x15 + 215dx < 181

    2816.

    28 ( )

    f : R R :( f (x))2 + ( f (x))2 x2 + 1, x R.

    :

    1. ( f (1))2 ( f (0))2 43,

    2. | f (1)| 43,

    3. |F (1) F (0)| 109, F f .

    3

  • , ,

    29 ( )

    f (x), g(x) : [a, b] R g(x) > 0,x [a, b].

    (x a) f (x) = (x b)g(x),x [a, b] 1)

    g(x) > 0 f (x) < 0, x (a, b)

    2) b

    af (x)dx = b

    ag(x)dx

    ) f (b) = g(a)) (a, b) : f () = g()

    30 ( parmenides51)

    z1 = a + eai, z2 = b + bi, z3 = c + i ln c a, b R, c > 0.

    1.

    z1, z2, z3,

    2. |z1 z2 | - z1, z2 ,

    3. |z1 z3| - z1, z3 .

    , ,

    31 ( )

    f : [0,+) R

    f (x) + x f (x) = 12

    f ( x2

    ) x [0,+) .

    32 ( )

    f (x) = ln(x2)

    x2+1, N , N ,

    .

    33 ( )

    f : [0, 1] R

    f (0) = 0 10

    e f(x) f (x) dx = f (1).

    f (x) = 0,x [0, 1]

    34 ( )

    f : (0,+) R f

    (x

    y

    )=

    f (x)y

    x f (y)y2

    x, y (0,+) 1, f (1) = 1

    Juniors,- -

    35 ( )

    n,

    sin2n x + cos2n x + n sin2 x cos2 x = 1, x R.

    36 ( ) a, b, c a + b + c = 3,

    a2

    (b + c)3 +b2

    (c + a)3 +c2

    (a + b)3 3

    8.

    Juniors,

    37 ( )

    ABC BC, I . BI AC D E, D CI. EI AB Z. DZ CI.

    38 ( )

    ABC E M, .

    M, ABC ,

    E1, E2 , E3. 1

    E1+

    1

    E2+

    1

    E3 18

    E.

    Seniors,- -

    39 ( )

    f :(x y) f (x + y) (x + y) f (x y) = 4xy(x2 y2)

    4

  • 40 ( ) -

    f : {1, 2, . . . , 10} {1, 2, . . . , 100} x + y|x f (x) + y f (y), x, y {1, 2, . . . , 10}.

    Seniors,

    41 ( )

    ABCD (O) P AC BD.

    ABCD Q,

    QAB + QCB = QBC + QDC = 90o.

    P, Q, O , O (O).

    42 ( )

    P ABCD, AB, BC, CD, DA, . ABCD -.

    43 ( - 1

    1995) 6-

    5. ,

    6 -

    44 ( )

    ABC AB AC D E , DE

    . :ADDB

    +AEEC

    = 1

    45 ( IMC 1996) n

    .

    sin nx(1 + 2x) sin x dx.

    46 ( ) (an)nN an >

    1n

    n.

    +n=1

    an .

    47 ( ) M = R \ {3} x y = 3(xy3x3y)+m, m R. m (M, ) .

    48 (vzf) m n n .

    , n , -

    .

    49 ( )

    ln(1 aix)x2 + m

    dx , a > 0, m > 0

    50 ( ) an = 1 +n

    j=21

    ln j lim( nn)an

    51 ( ) An = {n, 2n, 3n, ...} n N

    J N, iJ

    Ai

    52 ( )

    A, B AB = (A \ B) (B \ A), - .

    A1A2...An Ai

    53 ( ) p Pp > 5 (p 1)! + 1 p( pk k N).

    5

  • 54 ( dimtsig) -

    .

    55 ( ) S ,

    s1, s2, ..., sn s1+s2+...+sn b ab > b2, a > c ab > bc, ab.

    a2b2, b2c2, b4

    a2b2 = (b2 + c2)b2 = b4 + c2b2, , .

    10

  • :

    9 ( ) -

    m

    (m 1)x4 5x2 + 3m 2 = 0 - .

    http://www.mathematica.gr/forum/viewtopic.php?f=19&t=24722

    ( ) m = 1

    : 5x2 + 1 = 0 x = 15.

    .

    m , 1 x2 = z

    (m 1)z2 5z + 3m 2 = 0

    (z) = (5)2 4(m 1)(3m 2)= 25 4(3m2 5m + 2)= 25 12m2 + 20m 8= 12m2 + 20m + 17 0 12m2 20m 17 0 (1)

    (m) = (20)2 4(17)12 = 400 + 816 = 1216

    m1 =20 +

    1216

    24=

    5 + 219

    6,

    m2 =20

    1216

    24=

    5 219

    6.

    (1) 5 219

    6 m 5 + 2

    19

    6.

    , ,

    . Vieta :

    z1 + z2 = ba=

    5

    m 1 > 0 m > 1

    z1z2 =

    a=

    3m 2m 1 0 3m 2 0

    3m 2

    m 23

    m > 1

    1 < m 5 +19

    6.

    10 ( ) :

    x = 111...12

    y = 111...1+1

    z = 666...6

    ,

    : x + y + z + 8 .

    http://www.mathematica.gr/forum/viewtopic.php?f=19&t=23823

    ( ) :

    x = 111 1 2

    = 1 100 + 1 101 + 1 102 + + 1 1021

    =102 1

    9

    2

    a1 = 1 = 10.

    :

    y = 111 1 +1

    = 1 100 + 1 101 + 1 102 + + 1 10

    =10+1 1

    9

    =10 10 1

    9

    11

  • z = 666 6

    = 6 100 + 6 101 + 6 102 + + 6 101

    = 6 10 19

    =6 10 6

    9.

    x + y + z + 8 =102 1

    9+10 10 1

    9+6 10 6

    9+ 8

    x + y + z + 8 =102 + 16 10 + 64

    9

    x + y + z + 8 =(10 + 8

    3

    )2.

    12

  • :

    11 ( )

    AB O -

    . A O

    E, Z EO 24,

    Z.

    http://www.mathematica.gr/forum/viewtopic.php?f=20&t=120

    ( ) ON//Z.

    AZ A = 45,

    ZA = = 22, 5.

    AEO = 67, 5 (1) ,

    AOE.

    ENO = EAB = 22, 5 + 45 = 67, 5 (2) ,

    - . (1) , (2) ONE (OE = ON = 24). O A ZA

    Z .

    Z = x = 2ON = 48.

    2 ( )

    .

    A x

    a x =A

    A=

    2, x =

    2

    1 +2

    a.

    ,

    AO OE =1

    2

    2

    1 +2

    a

    , x = 2OE = 48. 12 ( KARKAR) S CD ABCD. BS AD T . AM, T M,CN, S N . MDN = A = .

    13

  • http://www.mathematica.gr/forum/viewtopic.php?f=20&t=23657

    (Antonis-Z) BM I BM, DC. BN AD E. N, M , BN

    S BC = S BN + NBC = 2x BM ABS = ABM +MBT = 2y.

    DCN = MAD = x + y. MABE , ABM =AEM = y.

    BEA = EBC = x

    . IBCN , CBN = CIN = x, DIN = NED DIEN . DIB = ABI = y, DIB = DEM, MIDE .

    DIEN, MIDE MDNE ,

    MDN = = 180 x y = 180 B2= 90 +

    2.

    14

  • :

    13 ( )

    () 1 = 4

    +1 =8 9 + 2

    N. ()

    =1

    3 N .

    (). - ().

    http://www.mathematica.gr/forum/viewtopic.php?f=21&t=24924

    ( )

    :

    v+1 =1

    av+1 3=

    18av9av+2

    3

    =1

    8av93(av+2)av+2

    =av + 2

    5av 15

    =av + 2

    5(av 3), v N, :

    v+1 v =av + 2

    5(av 3) 1

    av 3=

    av + 2 55(av 3)

    v+1 v =av 3

    5(av 3) =1

    5:

    . ,

    1 =1

    a1 3= 1 v = 1 + (v 1) 1

    5=

    v + 4

    5, v N.

    :

    S v =v

    2(1 + v) = v

    2

    (1 +

    v + 4

    5

    )=

    v

    2

    v + 9

    5=

    v2 + 9v

    10.

    :

    v =1

    av 3 v + 4

    5=

    1

    av 3

    av 3 =5

    v + 4 av = 3 +

    5

    v + 4 av =

    3v + 17

    v + 4, v N.

    14 ( KARKAR) : 2x =3a = 6b , : x =

    aba b .

    http://www.mathematica.gr/forum/viewtopic.php?f=21&t=24475

    1 ( f reyia)x ln 2 = a ln 3 = b ln 6 = b ln(2.3) = b ln 2 + b ln 3

    x ln 2 = a ln 3

    (a b) ln 3 = b ln 2 ln 2 = a bb ln 3. :

    x ln 2 = a ln 3 xa bb ln 3 = a ln 3 x =ab

    a b

    2 ( )

    2x = 3a = 6b = m

    x =m

    ln 2 , a =m

    ln 3 , b =m

    ln 6 , a , b

    ab = m2

    ln 3 ln 6, a b = m ln 2

    ln 3 ln 6

    aba b =

    m

    ln 2 = x.

    3 ( )

    2x = 3a = 6b x ln 2 = a ln 3 = b ln 6ab

    a b =x ln 2ln 3 x ln 2ln 6

    x ln 2ln 3 x ln 2ln 6

    =x2 ln2 2

    x ln 2 ln 6 x ln 2 ln 3 =

    15

  • x ln2 2

    ln 2 (ln 6 ln 2) = x ln2 2

    ln 2 ln 2 = x

    4 ( )

    3 = 2xa , 6 = 2

    xb 3 = 2 xbb x

    a=

    x bb x =

    aba b .

    5 ( ) x = a = b = 0 - .

    a, b, x , 0 a , b, {a = b3a = 6b

    3a = 6a .

    16

  • :

    15 ( )

    (O,R) , (K, r) E. AB, , OK - AB .

    .

    http://www.mathematica.gr/forum/viewtopic.php?f=22&p=127551#p127551

    1 (KARKAR) R2 + r2 AL = CL . E = E

    1

    2E

    1

    2E E E

    =1

    2(R2 + r2) E E .

    E !

    2 ( ) LA = LC =R2 + r2 , (1) ,

    L LA = LB. , (1)

    (

    R2 + (LO)2 = (LA)2 = (LC)2 = r2 + (LK)2 R + r = OK = LO + LK ).

    16 ( )

    ABCD AC, BD CAB, BCA,CDB, BDA 70, 30, (50a), a , , . BD CBA a.

    http://www.mathematica.gr/forum/viewtopic.php?f=22&t=24890

    1 ( ) :

    M AC BD,C BD = A BD = x,C MB = 70 + x

    x = 40o

    -

    ABC, BCD, CDA, DAB

    sin 70sin 30

    =sin(50 a) sin(70 a)

    sin a sin(60 + a) sin 70sin 30 =

    cos 20 cos(120 2a)cos 60 cos(60 + 2a)

    2 cos 20 =cos 20 + cos(60 + 2a)

    12 cos(60 + 2a)

    cos(60 + 2a) = 0 a = 15o

    2 ( ) ABC (70, 80, 30).

    17

  • C BD, BA E. BCE (80, 50, 50) ( - ),

    BCDE AEDC (CEA = CDA = 50). ADE = ACE = 20, DCE (70, 55, 55) BCD : a = 15.

    3 ( ) A BD CB E ADCE( 50 ),

    DEB, DAB a = 15.

    18

  • :

    17 ( KARKAR) ,

    A(1, 3) B(4, 2), .

    http://www.mathematica.gr/forum/viewtopic.php?f=23&t=21244

    1 ( ) > 0

    C(, ), D(,). AC, BD :x + y = 2 x y = 2, . A B : + 3 = 2 4 2 = 2 . =

    2

    2 =

    2

    2,

    :

    2 + 2 = 2 . . . 2 = 2, c x2 + y2 = 2.

    2 ( )

    a ()

    r > 0 .

    (AC) : y 3 = a(x 1) ax y a + 3 = 0 (BD) : y 2 = a(x 4) ax y 4a + 2 = 0.

    , :

    d(O, AC) = r |3 a|

    a2 + 1= r

    |3 a| = r

    a2 + 1

    d(O, BD) = r |2 4a|

    a2 + 1= r

    |2 4a| = r

    a2 + 1.

    |3 a| = |2 4a|, a = 1 a = 1

    3.

    a = 1 r =2,

    C : x2 + y2 = 2 ( ) a = 13

    r =10 C : x2 + y2 = 10 ( ).

    ,

    .

    3 ( ) y = x + , , R 1 A xx. 3 = 1 + = 3 .

    yy K (0, 3 ). y = x + , , R 2

    B 1. 2 = 4 + = 2 4.

    yy L (0, 2 4).

    O R C, D , - KON, LOD , CO = DO = R, CON = DOL ( ), OK = OL |3 | = |2 4| . . .

    ( = 1 = 1

    3

    ).

    R = d (O, 1) = ...2 R =

    10.

    4 (parmenides51)

    AC, BD - .

    M AB.

    19

  • M(1 + 4

    2,3 + 2

    2

    )=

    (5

    2,5

    2

    ).

    OM AC, BD, AC, BD, AC BD.

    xM =5

    2, 0 = xO

    OM =yM yOxM xO

    =

    52 052 0

    = 1 ,

    OM y 0 = 1(x 0) y = x. -

    AC,OM, = d(AC,OM) = d(A,OM) = |yAxA |

    (1)2+12=

    |31|2=

    22=2.

    x2 + y2 = 2 =22= 2.

    AC, BD

    , AB ( C D). xA = 1 , 4 = xB

    AB =yB yAxB xA

    =2 34 1 =

    1

    3,

    AB y 3 = 1

    3(x 1) 3y 9 = x + 1 x + 3y = 10.

    AB, = d(O, AB) = |0 + 0 10|

    12 + 32=

    1010=

    10.

    x2 + y2 = 2 = 10.

    18 ( )

    n, n 2, :

    1 +12+

    13+ + 1

    n>

    n.

    http://www.mathematica.gr/forum/viewtopic.php?f=23&t=22805

    1 ( ) k +

    k 1 >

    k k > 1 k = 1

    .

    1

    k

    k 1>

    k,

    1k>

    k

    k 1.,

    1 +12+

    13+ + 1

    n>

    1 +2

    1 +

    3

    2 + +

    n 1

    n 2 + n

    n 1 = n. 2 ( )

    nk=1

    1k> n n

    n

    k=1

    1k=

    n2n

    n!.

    n

    2nn!

    >

    n,

    n >nn!.

    -

    n2 >n(n + 1)

    2= 1 + 2 + 3 + + n >

    nn1 2 3 n = n n

    n!,

    .

    3 ( )

    1 +12+

    13+ + 1

    n+

    1n + 1

    >

    n +1

    n + 1,

    >

    n + 1.

    (

    ) n + 1 n = 1

    n + 1 +

    n 0

    .

    ()

    P(1) + P(2) + + P(n) = 1

    f (1) + f (2) + + f (n) = 512

    f (x) x = 1, . . . , x =n

    5

    12=

    (1

    2 122

    )+

    (1

    22 123

    )+

    +

    (1

    2

    n 12

    n + 1

    )

    =1

    2 12

    n + 1

    n = 35.

    () 16% 33 x s = 33 s = 2.

    CV = sx 100% = 5, 71%

    CV < 10% -.

    20 ( Parmenides51)

    lit < , R. 1, 6 lit 20% 1, 4 lit

    90% . [, ] :

    () , .

    () .

    ()

    ,

    1000

    2 lit.

    http://www.mathematica.gr/forum/viewtopic.php?f=18&t=15918

    1 ( )

    () X . A = {X 1, 6} B ={X 1, 4}. X , - -

    [, ]. -:

    P(A) = 1, 6 a a = 0, 2

    P(B) = 1, 4 a = 0, 9.

    = 1, 2 = 3, 2

    21

  • ()

    a +

    2= 2, 2.

    ()

    = {X 2}

    N()N() = P() =

    2 1, 23, 2 1, 2 = 0, 4

    N() = 1000 N() = 2500. 2 (parmenides51)

    [, ], ,

    .

    () :

    100% . 1, 6 20% .

    1, 6 =

    100

    20. (1)

    100% . 1, 4 90% .

    1, 4 =

    100

    90. (2)

    (1),(2)

    = 1, 2 = 2, 2.

    :

    [, ] 100% [, 1.6] 20%

    , [1.6, ] 80% . [1.4, ] 90% [1.4, 1.6] 10% . 1, 6 1, 4 = 0, 2 10% . 2 0, 2 = 0, 4 2 10% = 20% 1, 6 20%

    1, 6 = 0, 4 = 1, 6 0, 4 = 1, 2.

    10 0, 2 = 2 10 10 = 100% [, ] 100%

    = 2 = + 2 = 1, 2 + 2 = 3, 2.

    ()

    ,

    x = +

    2=

    1, 2 + 3, 2

    2=

    4, 4

    2= 2, 2.

    () 3, 2 1, 2 = 2 ( ).

    2 1, 2 = 0, 8 1000 .

    2

    0, 8=

    1000

    =2000

    0, 8= 2500

    .

    22

  • :

    21 ( )

    f : R R z z , 1/2

    f 2(x) + sin2(x) = 2x f (x)

    x R

    limx0

    f (x)x

    = m,

    m =|z2||2z1| .

    () |z 2| = |2z 1|.

    () z

    () limx0

    f (sin x)x2 x .

    () g(x) = f (x)x

    (, 0) (0,+).

    () f .

    () (|z+34i|+5)x = x3+ 10 [1, 2].

    http://www.mathematica.gr/forum/viewtopic.php?p=111574#p111574

    ( )

    () x , 0

    f 2(x)x2

    +sin2(x)

    x2=

    2 f (x)x

    ,

    limx0

    ( f (x)

    x

    )2+

    (sin x

    x

    )2 = limx0

    2 f (x)x

    ,

    m2 + 12 = 2m m = 1.

    m = 1 |z2||2z1| = 1 |2z 1| = |z 2|.

    ()

    |2z 1| = |z 2||2z 1|2 = |z 2|2(2z 1)(2z 1) = (z 2)(z 2)4zz 2z 2z + 1 = zz 2z 2z + 43zz = 3|z| = 1.

    ()

    limx0

    f (sin x)x2 x = limx0

    f (sin x)sin x

    sin xx

    1

    x 1= 1 1 (1) = 1.

    limx0

    f (sin x)sin x

    sin x=ux0u0= lim

    u0f (u)u

    = 1.

    ()

    f 2(x) + sin2 x = 2x f (x) f 2(x) 2x f (x) + x2 = x2 sin2 x( f (x) x)2 = x2 sin2 xg2(x) = x2 sin2 x.

    | sin x| 6 |x|, x R x = 0 x , 0

    x2 sin2 x , 0, g2(x) , 0. g (, 0) (0,+),

    .

    () 4 f .

    (1) f (x) = x +

    x2 sin2 x.(2) f (x) = x

    x2 sin2 x.

    (3) f (x) =x +

    x2 sin2 x x > 0,

    x

    x2 sin2 x x < 0.

    (4) f (x) =x +

    x2 sin2 x x 6 0,

    x

    x2 sin2 x x > 0.

    23

  • ()

    h(x) = (|z + 3 4i| + 5)x x3 10 x [1, 2]. h .

    h(1) = |z + 3 4i| + 5 11= |z + 3 4i| 6 6 0

    |z + 3 4i| 6 |z| + |3 4i| = 6.

    h(2) = 2 |z + 3 4i| + 10 8 10= 2(|z + 3 4i| 4) > 0

    |z + 3 4i| > ||z| |3 4i|| = 4. h(1)h(2) 6 0. h(1)h(2) < 0 Bolzano x0 (1, 2) h(x0) = 0.

    (|z + 3 4i| + 5)x = x3 + 10 (1, 2). h(1)h(2) =0, x = 1 x = 2 .

    (|z + 3 4i| + 5)x = x3 + 10 [1, 2].

    22

    z = (k t) + (k t)i t R k > 1.

    (1) -

    z.

    (2) w

    y = x (k 1) , k |z w|min = 5

    2

    2 1. (3) k (2) z |z z|.

    (4) k (2) |w 3 + 4i|.

    (5) u

    u = (1 + mt) + (1 + mt)i, m

    u

    .

    (6) k,m (2) (5) , |z u|.

    http://www.mathematica.gr/forum/viewtopic.php?p=110457#p110457

    ( )

    (1) z = x + yi, x, y R

    x = k t, y = k t.

    ,

    2(t) + 2(t) = 1 (x k)2 + (y k)2 = 1.

    z A(k, k) 1 = 1 k > 1.

    (2) d(A, ) = |3k1|2

    > 1 k > 1, .

    |z w|min = d(A, ) 1 = |3k 1|2

    1

    |z w|min =52

    2 1 |3k 1|

    2 1 = 5

    2

    2 1

    |3k 1| = 5 k = 2,

    k > 1.

    (3) k = 2

    z = (2 t) + (t 2)i.

    z = + i, , R = 2 (t) = (t) 2

    2(t) + 2(t) = 1 ( 2)2 + ( + 2)2 = 1.

    24

  • z B(2,2) 2 = 1 = 1. : (1) k = 2

    |z (2 + 2i)| = 1 |z (2 2i)| = 1 z B(2,2) 2 = 1 = 1. |z z| == |(2 t) + (2 + t)i (2 t) + (2 t)i|= |2(2 t)i| |z z|min = |2 1| = 2 |z z|max = |2 3| =6.

    (4) |w 3 + 4i| = |w (3 4i)| w K(3,4). |w3+4i|min = d(K, ) = |34+1|

    2= 0 (

    K ).

    (5) u = + i, , R.

    (t) = 1 + m

    , (t) = 1 + m

    ( m , 0 m = 0, u

    (1,1)). ( + 1)2

    m2+

    ( + 1)2m2

    = 1 ( + 1)2 + ( + 1)2 = m2

    u

    (1,1) 3 = |m|. O(0, 0) (0 + 1)2 + (0 + 1)2 =m2 m2 = 2 m =

    2.

    :

    w

    m R

    u = 0 + 0i { 1 + mt = 01 + mt = 0

    t =1m

    t = 1m

    2t + 2t = 1 (1m

    )2+

    (1m

    )2= 1

    2m2= 1 m2 = 2 m =

    2.

    (6)

    c =z u=(k t) + (k t)i (1 + mt) (1 + mt)i

    =(k t) + (k t)i + (1 mt) + (1 mt)i=(k t + 1 mt) + (k t + 1 mt)i=[k + 1 (1 + m)t] + [(k + 1 (1 + m)t)] i

    c = x + yi, x, y R

    x = k + 1 (1 + m)t x (k + 1) = (1 + m)t,

    y = k+ 1 (1+m)t y (k + 1) = (1+m)t.

    (x (k + 1))2 + (y (k + 1))2=(1 + m)22t + (1 + m)22t

    (x (k + 1))2 + (y (k + 1))2 = (1 + m)2k=2

    m=2

    (x 3)2 + (y 3)2 = (1 2)2

    M(x, y)

    (x 3)2 + (y 3)2 =(1 +

    2)2.

    25

  • OK, A, B. (OK) = d(K,O) =

    32 + 32 =

    32. OB

    (OM) (OA). |C|max = (OA) = (OK) + = =

    = 32 + 1 +

    2 = 4

    2 + 1

    |C|min = (OB) = (OK) + = == 3

    2 1

    2 = 2

    2 1.

    M(x, y) (x 3)2 + (y 3)2 =

    (2 1

    )2.

    OK, A, B. (OK) = d(K,O) =

    32 + 32 =

    32. OB

    (OM) (OA).

    |C|max = (OA) = (OK) + = == 3

    2 +

    2 1 = 4

    2 1

    |C|min = (OB) = (OK) + = == 3

    2

    2 + 1 = 2

    2 + 1.

    26

  • :

    23 ( )

    f (x) = ex ln x + 2 1 1,

    ex21 ln(x2 + 1) = 1

    e,

    e1x + 2 ln x > ex.

    http://www.mathematica.gr/forum/viewtopic.php?f=52&t=17341

    ( ).

    ) x > 0.

    0 < x1 < x2 x1 > x2 ex1 > ex2 (1)

    (y = ex . )

    0 < x1 < x2

    ln x1 < ln x2 ln x1 + 2 > ln x2 + 2(2)

    (y = ln x . )

    (1) , (2) f (x1) > f (x2) f 1 1

    ) ex21 ln

    (x2 + 1

    )=

    1e

    e(x2+1) ln

    (x2 + 1

    )+ 2 = 1

    e+ 2

    f(x2 + 1

    )= f (1) f :11

    x2 + 1 = 1 x = 0 x > 0, .

    ) e1x + 2 ln x > ex

    e1x + ln x + 2 > ex ln x + 2

    f(1x

    )> f (x) 1

    x< x

    x>0 x2 > 1 x > 1

    24 ( )

    f

    h(x) = e f (x) f 3(x) + 2 .

    f (x) :

    (12

    ) f (x2x) ( 12) f (4x) > 0http://www.mathematica.gr/forum/viewtopic.php?f=52&t=12656

    ( ) h R, x1, x2 R x1 > x2

    :h(x1) > h(x2)

    e f (x1) f 3(x1) + 2 > e f (x2) f 3(x2) + 2

    ( f (x1) f (x2))( f 2(x1) + f (x1) f (x2) + f 2(x2))

    f (x2) () ()

    , .

    : f (x1) < f (x2), f R.

    27

  • g(x) = x, 0 < < 1 R,

    :

    (12

    ) f (x2x)>(12

    ) f (4x) f (x2 x) < f (4 x) x2 x > 4 x x2 > 4 x < 2 x > 2.

    :

    h R : x < y h(x) > h(y), x, y R.

    * .

    * .

    - x = y, h(x) = h(y), .

    - x > y h , h(x) < h(y), .

    x < y.

    2 ( ) ( )

    f

    . .

    f .. x1, x2 R x1 < x2 f (x1) 6 f (x2).

    e f (x1) > e f (x2) f 3(x1) > f 3(x2) h(x1) 2 > h(x2) 2 h . .

    x1, x2 R x1 < x2

    f (x1) > f (x2), f . .

    28

  • :

    25 ( )

    f [a, b], (a, b) f (a) , f (b). 1, 2 (a, b) 1 , 2 : f (1) f (2) =

    ( f (b) f (a)b a

    )2.

    http://www.mathematica.gr/forum/viewtopic.php?f=53&t=23144

    1 ( )

    a < x < b f (x) f (a)

    x a =f (b) f (a)

    b a := ,

    f (b) f (x)b x =

    -

    [a, x] [x, b].,

    > 0

    f (x) f (a)x a >

    f (b) f (a)b a >

    f (b) f (x)b x ,

    a < x < b.

    g(x) := f (x) f (a)x a) (a, b]

    [, c) ( ) ,

    h(x) := f (x) f (b)x b [a, b)

    (d, ] ( ).

    k > 1 g() = k h() = /k , (a, b). [a, ] 1 (a, ) f (1) = g(). [, b] 2 (, b) f (2) = h().

    k .

    :

    f [a, b], (a, b) f (a) , f (b). 1, 2, . . . , n (a, b)(n N)

    f (1) f (2) f (n) =( f (b) f (a)

    b a

    )n.

    2 ( )

    f

    f (b) f (a)b a = f

    () > 0. U y : f (x) > 0, f (x) U . ln f ()

    1, 2 U : ln f () = ln f(1) + ln f (2)

    2, f (1) > 0, f (2) > 0

    (1, 2) = V . ,

    1 < < 2.

    3 ( )

    1 (a, k), 2 (k, b), :

    f (1) = f (k) f (a)k a (1)

    f (2) = f (b) f (k)b k (2)

    f (1) f (2) =( f (b) f (a)

    b a

    )2,

    (1) (2),

    :

    f (k) f (a)k a

    f (b) f (k)b k =

    ( f (b) f (a)b a

    )2(3)

    - =f (b) f (a)

    b a , (3) k,

    29

  • :

    f (k) f (a)k a

    f (b) f (k)b k =

    2

    ( f (k) f (a)) ( f (b) f (k)) = (k a) (b k) ()

    k (a, b), :

    f (k) f (a) = (b k) (4)

    f (b) f (k) = (k a) (5).

    k (4). (5) ...

    (4):

    f (b) f (k) = f (b) [ f (a) + (b k)]= f (b) f (a) (b k)= [b a b + k] == (k a) (2)

    (5)

    k. (4), ( )

    h(x) = f(x) f(a) (b x), x [a, b]

    Bolzano

    h(a) = (b a) = f (a) f (b)h(b) = f (b) f (a) 0

    = f (b) f (a).

    :

    h(a) h(b) = ( f (a) f (b))2 < 0, f (a) , f (b). .Bolzano h [a, b]

    k (a, b) : h(k) = 0,

    (4)

    (5).

    ,

    [a, k], [k, b], ,

    .

    (atemlos)

    ..

    26 ( )

    f : [1, e] R f (1) = 0,f (e) = 1 f (x) + e f (x) = x + 1

    x, x [1, e] .

    : f (x) = ln x x [1, e] .

    http://www.mathematica.gr/forum/viewtopic.php?f=53&t=24617

    1 ( )

    h(x) = f (x) lnx, x [1, e],

    ( ) -

    .

    x0 (1, e) h(x0) , 0, , , f (x0) > 0, (

    ) x1

    [1, e] ( ), Fermat

    h(x1) = 0 f (x1) = 1x1,

    x = x1

    e f (x1) = x1 f (x1) = lnx1 h(x1) = 0,

    .

    2 ( )

    ,

    g(x) = f (x) lnx [1, e].

    g [1, e] .

    : g(1) = g(e) = 0 :

    g(x) = x(eg(x) 1), x [1, e] (1)

    g .

    .

    30

  • , x1 ,

    g(x1) > 0 .Fermat

    g(x1) = 0.

    , (1) . . ; ...

    x2, (1) Fermat g(x2) = 0. .

    g . g [1, e]...

    g(x) = 0, x [1, e] f (x) = lnxx [1, e].

    3 ( )

    . -

    :

    g(x) = f (x) lnx g(x) = x xe f (x) xeg(x) + (eg(x)) = x

    h(x) = eg(x), xh(x) + h(x) = x,

    ex2

    2

    (e x2

    2 h(x)) = xe x2

    2

    e x2

    2 h(x) = e x2

    2 + c elnx f (x) = 1 + ce x2

    2

    x = 1, c = 0.

    elnx f (x) = 1 f (x) = lnx.

    .

    4 ( ) x (0,+): f (x) + e f (x) = x + 1

    x(1).

    x+1

    x g(x) = x

    2

    2+lnx, x > 0.

    (1) :

    e f (x) = (g(x) f (x)) e f (x) (g(x) f (x)) = 1. eg(x) = x e x

    2

    2 : eg(x) f (x) (g(x) f (x)) = xe x

    2

    2 , (eg(x) f (x)

    )=

    (e

    x2

    2

    ),

    eg(x) f (x) = ex2

    2 + c.

    x = 1 c = 0

    f (x) = lnx, x > 0.

    5 ( ) h : (0,+) , h (x) = ef (x)

    x.

    h (1) = h (e) = 1 f (x) = h (x) + xh

    (x)xh (x) =

    1

    x+

    h (x)h (x) ,

    1

    x+

    h (x)h (x) + xh (x) = x +

    1

    x

    h (x) = xh (x) (1 h (x)) .

    ,

    x = x0,

    h (x0) = 1 h (x0) = 0 (.Fermat) .

    h h (1) = h (e) = 1, . h (x0) = h (1) = h (e) = 1.

    h (x) = 1, x [1, e] e f (x) = x f (x) = ln x,x [1, e].

    6 ( )

    x : lnx , f (x), lnx > f (x). f (x) 1

    x= x e f (x) = elnx e f (x) = (lnx f (x))e

    lnx, f (x) ex. lnx, f (x) [1, e] {1, M} e max{e, eM} = k ( ). ( f (x) lnx) = (lnx f (x))e (lnx f (x))k

    (( f (x) lnx)ekx)) < 0 1 x e, 0 = (( f (e) lne)eke)) (( f (x) lnx)ekx)) (( f (1) lnx)ek)) = 0, f (x) = lnx . lnx < f (x), lnx = f (x),x [1, e].

    7 ( ) f f + f e f = 1 1

    x2

    f = f (x +

    1

    xx f

    )+ 1 1

    x2=

    31

  • = ( f )2 (x + 1/x) f + 1 1/x2 (

    e f ) y = y2 (x +

    1

    x

    )y + 1 1

    x2, y = f (

    Ricatti).

    y =1

    x+

    1

    u, ... u + u

    (1

    x x

    )= 1,

    (xe x2

    2 y) = (ex2/2) y = 1

    x+

    a

    xe

    x2

    2 .

    f (1) = 1 y(1) = 1

    a = 0 f (x) = lnx + b f (1) = 0 b = 0 f (x) = lnx, x [1, e] ( f (e) = 1)?

    32

  • :

    27 ( )

    :

    20

    x10 + 210

    x15 + 215dx < 181

    2816.

    http://www.mathematica.gr/forum/viewtopic.php?f=54&t=8997

    ( )

    20

    x10 + 210

    x15 + 215dx = 1

    32

    20

    1 + (x/2)101 + (x/2)15 dx

    =1

    16

    10

    1 + y10

    1 + y15dy

    =1

    16

    (1 +

    10

    y10 y151 + y15

    dy)

    (1 + x2

    ) (( f (x))2 + ( f (x))2)

    >( f (x) + x f (x))2 (

    1 + x2)2>( f (x) + x f (x))2 f (x) + x f (x) 6 1 + x2

    (1 + x2

    )6 (x f (x)) 6 1 + x2

    10

    (1 + x2

    )dx 6

    10

    (x f (x))dx 61

    0

    (1 + x2

    )dx

    | f (1)| 6 43

    3. -

    t > 0

    t0

    (1 + x2

    )dx 6

    t0

    (x f (x))dx 6t

    0

    (1 + x2

    )dx

    t t3

    3 t f (t) t + t

    3

    3 1 t

    2

    3 f (t) 1 + t

    2

    3.

    f t = 0 10

    (1 + t

    2

    3

    )dt 6

    10

    f (t)dt 610

    (1 + t

    2

    3

    )dx.

    .

    33

  • :

    29 ( )

    f (x), g(x) : [a, b] R g(x) > 0,x [a, b].

    (x a) f (x) = (x b)g(x),x [a, b]

    1)

    g(x) > 0 f (x) < 0,x (a, b)

    2) b

    af (x)dx = b

    ag(x)dx

    ) f (b) = g(a)) (a, b) : f () = g()

    http://www.mathematica.gr/forum/viewtopic.php?f=55&t=24860

    ( )

    1) g(x) > 0, x [a, b] g [a, b] x a

    (x a) f (x) = (x b)g(x) 0 = (a b)g(a) g(a) = 0 x > a g(x) > g(a) = 0

    (xa) f (x) = (xb)g(x) a < x < b g(x) > 0 x a > 0, x b < 0 f (x) < 0

    :

    g(a) = 0, f (b) = 0 [a, b] g(a) 0, f (b) 0

    2) )

    (x a) f (x) = (x b)g(x) b

    a

    (x a) f (x)dx =b

    a

    (x b)g(x)dx

    [(x a) f (x)]ba b

    a

    f (x)dx =

    [(x b)g(x)]ba b

    a

    g(x)dx

    b

    a

    f (x)dx =b

    a

    g(x)dx

    [(x a) f (x)]ba = [(x b)g(x)]ba

    (b a) f (a) = (b a)g(b) f (a) = g(b)

    2.)

    h(x) = f (x)g(x), x [a, b] [a, b]

    h(a) = f (a) g(a) = f (a) f (b) > 0

    f ( (1)) [a, b] f (a) > f (b) h(b) = f (b) g(b) = g(a) g(b) < 0 (1) g [a, b] g(a) < g(b) h(a)h(b) < 0 Bolzano x0 (a, b)

    h(x0) = 0 f (x0) = g(x0)

    h(x) = f (x) g(x) < 0, x (a, b) h [a, b] x0 .

    30 ( parmenides51)

    z1 = a + eai, z2 = b + bi, z3 = c + i ln c

    a, b R, c > 0.

    1.

    z1, z2, z3,

    2. |z1 z2| z1, z2 ,

    3. |z1 z3| z1, z3 .

    34

  • http://www.mathematica.gr/forum/viewtopic.php?f=55&t=24493

    ( ) ) z1 z = x + yi, x, y R, x = a, y = ea, a R y = ex. z1 y = ex.

    z2 z = x+yi, x, y R, x = b, y = b, b R y = x. z2 y = x.

    z3 z = x+yi, x, y R, x = c, y = lnc, c > 0 y = lnx. z3 y = lnx, x > 0.

    ) z1 = k + eki, k R |z1 z2| ,

    L(k, ek) y x = 0, : d(L, ) = |e

    a a|12 + (1)2

    .

    f (x) = ex x R

    ex () x () f (x) = ex 1. :* f (x) = 0 x = 0* f (x) > 0 x > 0, * f [0,+)

    * f (, 0]* f x = 0 f (0) = 1. d(L, ) a =0 ( L(0, e0) L(0, 1)) 1

    2=

    2

    2.

    1. L : y 1 = 1(x 0) y = x + 1. y = x, y = x + 1 (x, y) =

    (1

    2,1

    2

    ),

    z2

    2

    2.

    |z1 z2| z1 = i z2 =

    1

    2+

    1

    2i.

    )

    y = ex, y = lnx - y = x,

    |z1 z2| ,|z2 z3| 2

    2

    z3 L(0, 1) y = x, N(1, 0), z2 M

    (1

    2,1

    2

    )( ()

    ).

    |z1 z3| :z1 = i z3 = 1 |z1 z3| = 2

    2

    2=

    2.

    35

  • :

    31 ( )

    f :[0,+) R

    f (x) + x f (x) = 12

    f ( x2 ) x [0,+) .

    http://www.mathematica.gr/forum/viewtopic.php?f=56&t=21507

    ( ) g(x) = x f (x) ,x [0,+) [0,+)

    g(x) =1

    2

    g(x/2)x/2

    =g(x/2)

    x, x > 0

    0 , x = 0(1) .

    ..... g [0, x/2] 0 < 1 < x/2 ,

    1

    2g(1) = g(x/2) g(0)

    x=

    g(x/2)x

    (1)= g(x) .

    ..... g [0, 1/2] 0 < 2 < 1/2 ,

    1

    2g(2) = g(1/2) g(0)

    1=

    g(1/2)1

    (1)= g(1) .

    .....

    n , n N , 0 < n+1 < n/2 .

    g(x) = 12

    g(1) = 122

    g(2) = . . . = 12n

    g(n) (2) .

    limx0

    g(x) = limx0

    g(x/2)x

    00= lim

    x01

    2

    g(x/2)x

    =

    limx0

    1

    2g(x/2) = 1

    2limx0

    g(x) limx0

    g(x) = 0 = g(0) . g [0,+) . n + n 0 , 0 < n+1 < n/2 0 < n < 1/2n1 . lim

    n+g(n) = 0 (3) .

    , x [0,+),

    limn+

    g(x) (2)= limn+

    1

    2ng(n) = lim

    n+1

    2nlim

    n+g(n)

    (3)= 0 0 = 0 g(x) = 0 g(x) = c x f (x) = c 0 f (0) = c , f (x) = 0 , x [0,+) .

    2 ( ) f x1, x2 [0, ] , > 0 m M, , [0, ] .

    m f (x) M , x [0, ] .

    m f ( x2 ) M , x [0, ] .

    (x f (x)) = 12

    f ( x2 ) M2 (x f (x) Mx

    2

    ) 0 . g(t) = t f (t) Mt

    2, t [0, ] .

    x > 0 [0, x] (0, x)

    g() = g(x) g(0)x 0 = f (x)

    M2.

    g() 0 f (x) M2.

    x = x1, x1 ( x1 = 0 ,

    M = 0)

    f (x1) M2

    M M2

    M 0 .

    , (x f (x)) = 12

    f ( x2 ) m2 (x f (x) mx

    2

    ) 0 h(t) = t f (t) mt

    2, t [0, ]

    , f (x) m2.

    x = x2, x2 ( x2 = 0 ,

    m = 0)

    f (x2) m2

    m m2

    m 0 . 0 m f (x) M 0 f (x) = 0 , x [0, ] . , [0,+). , .

    36

  • 32 ( )

    f (x) = ln(x2)

    x2+1, N , N ,

    .

    http://www.mathematica.gr/forum/viewtopic.php?f=56&t=5181

    ( ) f (x) = ln(x2)

    x2+1,

    f (x) = 2 (2 + 1) ln(x2)

    x2+2

    f (x) = 2(4 + 3) + (2 + 1)(2 + 2) ln(x2)

    x2k+3,

    x R , N , N . f f .

    1.

    f (

    ) .

    f A (x1, f (x1)) , B (x2, f (x2)) , 0 < x1 < x2. f (x1) = f (x2) = . f [x1, x2] (x1, x2) , f () = f (x2) f (x1)

    x2 x1= .

    0 < x1 < < x2

    f (x1) = f () = f (x2) . . Rolle f [x1, ], [, x2] f

    . ,

    f .

    2. -

    f () A(x1, f (x1)) , B(x2, f (x2))

    y f (x1) = f (x1)(x x1) (1) . :

    ) f (x1) = f (x2) 1. f x2 = x1 . B (x1, f (x1)) = (x1, f (x1)) .( - - x1 > 0)

    ) B (1) f (x1) f (x1) = f (x1)(x1 x1) f (x1) = x1 f (x1) (2) ln(x21 )x2+11

    = x12 (2 + 1) ln(x21 )

    x2+21

    ln(x21 ) = 2 (2 + 1) ln(x21 )

    (2 + 2) ln(x21 ) = 2 ln(x21 ) =

    + 1

    x21 = e

    +1 x1 = e1

    2+2 .

    (1) :

    (1) (2) y = f (x1) x f (x1) = e( + 1)

    : y =

    e( + 1) x .

    .

    37

  • :

    33 ( )

    f : [0, 1] R

    f (0) = 0 10

    e f(x) f (x) dx = f (1).

    f (x) = 0,x [0, 1]

    http://www.mathematica.gr/forum/viewtopic.php?f=69&t=24696

    ( ) 10

    e f(x) f (x)dx = f (1) = f (1) f (0) =

    10

    f (x)dx

    10

    (e f (x) f (x) f (x))dx = 0 10

    f (x)(e f (x) 1)dx = 0

    , f (x), e f (x)1 .

    x (0, 1), f (x)(e f (x) 1) 0

    x0 [0, 1] f (x0) , 0

    (. f (x0) < 0),

    10

    f (x)(e f (x) 1)dx > 0, .

    , f (x) = 0,x [0, 1]

    f (x) = c,x [0, 1].

    f (0) = 0, f (x) = 0, x [0, 1] 34 ( )

    f : (0,+) R f

    (x

    y

    )=

    f (x)y

    x f (y)y2

    x, y (0,+) 1, f (1) = 1

    http://www.mathematica.gr/forum/viewtopic.php?f=69&t=22009

    ( ) y x f (1) = 0.

    :

    f (1) = limx1

    f (x) f (1)x 1 = 1

    limx1

    f (x)x 1 = 1 (3)

    x0 > 0.

    x x0, h =x0

    x 1.

    :

    L = limxx0

    f (x) f (x0)x x0

    = limh1

    f(

    x0

    h

    ) f (x0)

    x0

    h x0.

    ( x = x0 y = h):

    L = limh1

    f (x0)h

    x0 f (h)h2 f (x0) x0(1 h)

    h ,

    ,

    (1) :

    L =f (x0)

    x0+ 1.

    x0 , f / .. :(

    f (x) = f (x)x

    + 1,x > 0) f (x)x (x) f (x)x2 =

    ( f (x)x

    )=

    1

    x= (lnx) ,x > 0

    ( f (x)x

    = lnx + c,x > 0).

    38

  • f (x) = xlnx + xc,x > 0 .

    x 1 : c = 0.

    f (x) = xlnx,x > 0

    .

    39

  • , , :

    35 ( )

    n,

    sin2n x + cos2n x + n sin2 x cos2 x = 1, x R.

    http://www.mathematica.gr/forum/viewtopic.php?f=109&t=24910

    ( ) x =

    41

    2n+

    1

    2n+

    n

    4= 1

    2n(n 4) + 8 = 0. (*) n 4 2n(n 4) 0 2n(n 4) + 8 > 0 0 n < 4, n = 2 n = 3 (*).

    sin4x + cos4x + 2sin2xcos2x = (sin2x + cos2x)2 = 1 x R Euler sin2 x + cos2 x + (1) = 0(sin2 x)3 + (cos2 x)3 + (1)3 = 3 sin2 x cos2 x(1), sin6 x + cos6 x + 3 sin2 x cos2 x = 1, x R., n 2 3.

    36 ( )

    a, b, c a + b + c = 3,

    a2

    (b + c)3 +b2

    (c + a)3 +c2

    (a + b)3 3

    8.

    http://www.mathematica.gr/forum/viewtopic.php?f=109&t=24754

    1 (BillK) f (x) = x2

    (3 x)3 , x (0, 3) f (x) > 0 . Jensen f (a) + f (b) + f (c) 3 f (a+b+c3 ) f (a) + f (b) + f (c) 38

    a2

    (b + c)3 +b2

    (c + a)3 +c2

    (a + b)3 3

    8

    2 ( )

    CS Nesbitt :(a2

    (b+c)3 +b2

    (c+a)3 +c2

    (a+b)3)

    [(b + c) + (c + a) + (a + b)] (a

    (b+c) +b

    (c+a) +c

    (a+b))2 94 .

    3 ( )

    a2 (a + b + c)(b + c)3 +

    b2 (a + b + c)(c + a)3 +

    c2 (a + b + c)(a + b)3

    9

    8

    a3

    (b + c)3 + a2

    (b + c)2 9

    8.

    :

    Chebyshev 9(x3 + y3 + z3) (x + y + z)3. Nesbitt

    9 a3

    (b + c)3 ( a

    b + c

    )3 27

    8

    3 a2

    (b + c)2 ( a

    b + c

    )2 9

    4

    40

  • :

    37 ( )

    ABC BC, I . BI AC D E, D CI. EI AB Z. DZ CI.

    http://www.mathematica.gr/forum/viewtopic.php?f=110&t=13272

    (KARKAR) C, E BC CEI = CDI = 90o+ B

    2= DIE = 90o , (1) (1)

    A = 90o DIZA IDZ = IAZ = 45o , (2)

    (2) ADB = 90o B2, ADZ =

    C2= ACI , (3) (3) DZ CI

    .

    2 ( ) E, - D CI BC, FD = FE , (1) F CI DE. DIC = EIC , (2)

    (2) DIC = 180o IDC C2

    = 180o

    90o B2

    C2

    = 45o, DIE = 90o =BD EZ , (3)

    (3) = IE = IZ , (4) BD B.

    (1), (4) DEZ, DZ FI CI .

    38 ( )

    ABC E M, .

    M, ABC , E1, E2, E3. 1

    E1+

    1

    E2+

    1

    E3 18

    E.

    41

  • http://www.mathematica.gr/forum/viewtopic.php?f=110&t=17211

    ( )

    MA1A2, MB2C2 A1MA2 = B2MC2

    E1(MB2C2) =

    (MA1)(MA2)(MB2)(MC2) , (1)

    , E2

    (MA1B1) =(MC1)(MC2)(MA1)(MB1) , (2)

    E3(MA2C1) =

    (MB1)(MB2)(MA2)(MC1) , (3)

    (1), (2), (3) = E1 E2 E3 =(MA1A2)(MC1C2)(MA2C1) , (4) (4) , .

    - :

    1

    E1+

    1

    E2+

    1

    E3 3

    3

    E1 E2 E3=

    36

    E1 E2 E3 (MB2C2)(MA1B1)(MA2C1)

    18

    E1 + E2 + E3 + (MB2C2) + (MA1B1) + (MA2C1) 18

    E

    42

  • , , :

    39 ( )

    f :

    (x y) f (x + y) (x + y) f (x y) = 4xy(x2 y2)

    http://www.mathematica.gr/forum/viewtopic.php?f=111&t=24585

    1 ( ) x + y = a

    x y = b x = a + b2

    y =a b2

    .

    b f (a) a f (b) = ab(a2 b2)

    a, b R, a, b R

    f (a)a

    f (b)b = a2 b2,

    f (a)a

    a2 = f (b)b b2.

    h(x) = f (x)x

    x2 x R , f (x) = x3 + cx, x R. f (0) = 0, f (x) = x3 + cx, x R, . 2 ( ) x = y + 1

    f (2y + 1) = (2y + 1) f (1) + 4y(y + 1)(2y + 1).

    f (1) = c + 1

    f (2y + 1) = c(2y + 1) + (2y + 1)(4y2 + 4y + 1)= c(2y + 1) + (2y + 1)3,

    f (x) = x3 + cx x R. 40 ( )

    f : {1, 2, . . . , 10} {1, 2, . . . , 100}

    x + y|x f (x) + y f (y), x, y {1, 2, . . . , 10}.

    http://www.mathematica.gr/forum/viewtopic.php?f=111&t=18963

    ( ) , x 1, 2, . . . , 9, 2x + 1 x f (x) + f (x + 1)(x + 1) 2x f (x) + 2(x + 1) f (x + 1). , 2x + 1 f (x + 1) f (x). ,

    99 f (10) f (1) =9

    x=1

    f (x + 1) f (x)

    9

    x=1

    (2x + 1)

    = 99.

    , f (x+1) f (x) = 2x+1 f (1) = 1. f (x) = x2 x 1, 2, . . . , 10.

    43

  • :

    41 ( )

    ABCD (O) P AC BD.

    ABCD Q,

    QAB + QCB = QBC + QDC = 90o.

    P, Q, O , O (O).

    http://www.mathematica.gr/forum/viewtopic.php?f=112&t=17404

    ( .) QBC + QDC = 90o= QBD + DBC + QDB + DBC = 90o , (1)

    (1) QBD + QDB = 180o BQD DBC +BDC = A, BQD = 90o + A (2)

    , AQC = 90o + D , (3) (2), (3), Q

    (K), (M), BD, AC -

    BQD, AQC R, Q, (K), (M.)

    (K) , BQD + BKD

    2= 180o , (4)

    K (K). (2), (4) BOD = 2A,

    BOD + BKD = 180o , KBOD

    OBK + ODK = 180o = OBK = ODK = 90o, KB = KD OB = OD.

    , (O) ABCD, (K) , (M)(

    MAOC , M (M) ).

    , O (O) (K), (M) , QR, ,

    P AC BD,

    44

  • (O), (K), (M) . 42 ( )

    P ABCD, AB, BC, CD, DA, -. ABCD .

    http://www.mathematica.gr/forum/viewtopic.php?f=112&t=24878

    ( .)

    , .

    . - P BC ABC, . P, ABCD a, b, c, d, AB, BC, CD, DA,.

    P A, (a + d) ,

    , (b + c) , P C.

    , -

    a + b + c + d , A, C .

    ,

    B, D .

    ABCD ,

    .

    ,

    ,

    , .

    45

  • :

    43 ( -

    1 1995)

    6- 5. ,

    6

    http://www.mathematica.gr/forum/viewtopic.php?p=120445

    1 ( )

    . .

    b 599.997 106 b2 599.997 103 > 774 103

    2b > 1500 103.

    (b + 2)2 = b2 + 4b + 4 > 599.997 106 + 3 106 =600.000 106.

    b2 (b + 2)2 .

    b2 < 599.998 106 < 600.000 106 < (b + 2)2.

    (599.998 106, 600.000 106) ,

    599.998 599.999. .

    2 ( ) 100000

    5 .

    -

    . ,

    (700000, 790000) (70000)2 < 5 1011 (79000)2 > 6 1011. 89999

    .

    44 ( )

    ABC AB AC D E , DE

    . :ADDB

    +AEEC

    = 1

    http://www.mathematica.gr/forum/viewtopic.php?p=111876

    1 ( ) H BO W CO AH OD AW OE. WAH = DOE = DAE = 60, WOH = 120.

    A,W,O, H

    AWH = AOH = 60 = AOH = AHW.

    AWH . (

    ) : OW + OH = OA(= OB = OC).

    ADDB

    =OHOB =

    OHOA

    AEEC =

    OWOC =

    OWOA

    ADDB

    +AEEC

    =OH + OW

    OA=

    OAOA

    = 1.

    : 1) D S E A ADDB

    +AEEC

    =AB/2AB/2

    +0

    EC= 1.

    2) 1) E AC , D A. 2 ( )

    : BD = x CE = y, : AD = x AE = y. , , : ED + BC = BD + CE,: ED + = x + y : ED = x + y .

    46

  • ADE : ED2 = AE2 + AD2 2AD AF (1) F E AD. FEA = 30, AFE: AF =

    1

    2AE =

    1

    2( y). , (1),

    : (x + y )2 = ( y)2 + ( x)2 ( x) ( y) =

    3xyx + y

    . -

    : AD = x = x (2y x)x + y

    AE = y = y (2x y)x + y

    . :ADDB

    +AEEC =

    x (2y x)x (x + y) +

    y (2x y)y (x + y) = 1.

    3 (Math Rider ) c

    -

    . H DE F,G AB, AC :

    :

    AF = BF = AG = CG = c2

    (1)

    FD = DH, GE = HE (2) ( ) c = 2

    3 (3) ( . . -

    OGC)

    + = 60, = DOH = HOE( FOG = 120 FOD = DOH, HOE =EOG)

    + = 60 ( + ) =3 +

    1 =3

    3( + ) = 3(1 ) (4)

    ADBD

    +AEEC =

    AF FDBF + FD

    +AG GECG +GE

    (1)=

    c2 FDc2 + FD

    +

    c2 GEc2 +GE

    =c 2FDc + 2FD

    +c 2GEc + 2GE

    (2)=

    c 2DHc + 2DH

    +c 2EHc + 2EH

    (3)=

    23 2DH

    23 + 2DH

    +23 2EH

    23 + 2EH

    =

    3 DH

    3 + DH

    +

    3 EH

    3 + EH

    =

    3 3 +

    +

    3 3 +

    =6 2

    3 +3( + ) +

    (4)=

    6 23 + 3(1 ) +

    =6 26 2 = 1

    47

  • :

    45 ( IMC 1996)

    n .

    sin nx(1 + 2x) sin x dx.

    http://www.mathematica.gr/forum/viewtopic.php?f=59&t=25166

    ( )

    In =

    sin nx(1 + 2x) sin x dx

    =

    0

    sin nx(1 + 2x) sin x dx +

    0

    sin nx(1 + 2x) sin x dx

    =

    0

    sin nx(1 + 2x) sin x dx +

    0

    sin nu(1 + 2u) sin u du

    =

    0

    sin nx(1 + 2x) sin x dx +

    0

    2u sin nu(1 + 2u) sin u du

    =

    0

    sin nxsin x dx.

    sin a sin b = 2 sin(a

    2 b2

    )cos

    (a

    2+

    b2

    )

    In In2 = 0

    sin nx sin (n 2)xsin x dx

    =

    0

    2 sin x cos (n 1)xsin x

    dx

    = 2

    0

    cos (n 1)x dx = 0.

    I0 = 0 I1 =

    In =

    0 n = 2k, n = 2k + 1.

    46 ( )

    (an)nN an >

    1n n.

    +n=1

    an .

    http://www.mathematica.gr/forum/viewtopic.php?f=59&t=24073

    1 ( ) kn .

    +n=1

    an +n=1

    (kn kn1)akn >+n=1

    (1 kn1kn

    ).

    1 kn1kn 0 ln xx1 1 x 1,

    ln(kn) = ln(k1) +n

    i=1ln(

    kiki1

    ),

    .

    2 ( )

    , kn kn > 2kn1 n. 1 kn1kn 0 .

    3 ( ) n

    k=1ak

    . n

    k=1(akan) (

    ),

    nan. , an >cn

    c > 0 n,

    . limn+ nan = 0,

    .

    48

  • :

    47 ( )

    M = R \ {3} x y = 3(xy 3x 3y)+m, m R. m (M, ) .

    http://www.mathematica.gr/forum/viewtopic.php?f=10&t=23549

    ( )

    ,

    e. :

    1 e = 1 3e 9 9e + m = 1 m = 6e + 10

    2 e = 2 6e 18 9e + m = 2 m = 3e + 20.

    e = 103

    m = 30. m = 30

    .

    a, b M

    a b = 3ab 9a 9b + 30= 3(ab 3a 3b + 27) + 3= 3(a 3)(b 3) + 3 , 3

    a , 3 b , 3. . a M

    a 103=

    10

    3 a

    = 3a10

    3 9a 9

    = 10a 9a 30 + 30= a

    103 .

    a M

    a x = x a = 103

    3ax 9a 9x + 30 = 103

    x = 27a 809(a 3) , 3

    .

    a, b, c M a (b c) = 9abc 27(ab + bc + ca) + 81(a + b + c) 240

    = (a b) c

    (M, ) . 48 (vzf) m -

    nn . , n

    , .

    http://www.mathematica.gr/forum/viewtopic.php?f=10&t=23825

    ( )

    k > n A1, A2, . . . , Ak n n . :

    ,I{1,2,...,k}

    (1)|I| det

    jIA j

    = 0 (1) , k = 3, (1) 2 2 A1, A2, A3

    det (A1 + A2 + A3) det (A1 + A2) det (A2 + A3) det (A3 + A1) + det (A1) + det (A2) + det (A3) = 0.

    (1) : m > n A1, A2, . . . , Am nn .

    r

    , r 6 n, .

    , (1) k = n + 1 r , r 6 n + 1, .

    , (1) k = n +2, . . . ,m A1 + A2 + + Am .

    (1). [k] := {1, 2, . . . , k} :

    ,I{1,2,...,k}

    (1)|I| det

    jIA j

    =

    ,I[k]

    (1)|I|S n

    sgn ()n

    i=1

    jI

    A j (i, (i)) .

    49

  • , :

    ,I{1,2,...,k}

    (1)|I| det

    jIA j

    =

    S n

    sgn () ,I[k]

    (1)|I|n

    i=1

    jI

    A j (i, (i)) .

    , , S n. ai j = A j (i, (i)) . :

    ,I{1,2,...,k}

    (1)|I|n

    i=1

    jI

    ai j

    = 0. (2) (2) aJ := a1, j1a2, j2 an, jn , J :=[ j1, j2, . . . , jn] ( j1, j2, . . . , jn ,

    , J

    j1, j2, . . . , jn.) , I {1, 2, . . . , k} J I,

    aJ (2)

    , (1)|I|. |J| 6 n < k, r = |I| |J|, 0 6 r 6 k |J|, aJ (2)

    k|J|r=0

    (1)|J|+r(k |J|

    r

    )

    =(1)|J|k|J|r=0

    (1)r(k |J|

    r

    )

    =(1)|J|(1 + 1)k|J| = 0.

    (2), (1), .

    50

  • :

    49 ( )

    ln(1 aix)x2 + m

    dx , a > 0, m > 0

    http://www.mathematica.gr/forum/viewtopic.php?f=9&t=7842&start=160

    1 ( )

    I1 = 0

    x2(x2 + b2) (x2 + c2) dx = 2 (b + c) , b, c > 0 .

    I2 = 0

    ln(1 + x2)x2 + m2

    dx = m

    ln(m + 1) ,

    I2 = 0

    ln(1 + x2)x2 + m2

    dx = 0

    1

    x2 + m2

    ( x0

    2y1 + y2

    dy)

    dx y= xt===

    0

    1

    x2 + m2

    ( 10

    2x2t1 + x2t2

    dt)

    dx =

    2

    10

    t

    ( 0

    x2(x2 + m2

    ) (1 + x2t2

    ) dx) dt =2

    10

    1

    t

    ( 0

    x2(x2 + m2

    ) ( 1t2+ x2

    ) dx) dt I1==1

    0

    1

    t

    m + 1t

    dt = m

    ln(m + 1) .

    ln(1 axi)x2 + m

    dx ax=y====

    a

    ln(1 + yi)y2 + a2m

    dy = a2

    ln(1 + y2) + i arctan yy2 + a2m

    dy

    = a

    0

    ln(1 + y2)y2 + a2m

    dy + 0 = a 0

    ln(1 + y2)y2 +

    (a

    m)2 dy I2==

    m

    ln(1 + a

    m).

    2 ( ) -

    f (z) = ln(1 aiz)z2 + m

    , z C, a > 0,m > 0

    , branch cut

    z1 = ia , .

    ln(1 aiz) = ln(az + i)ln i = ln |az + i|+i arg(az + i)i2

    ln i = ln |i| + i arg(i) = i2.

    C : [0, ] C A (R, 0) , B (R, 0). branch cut,

    f ( ),

    Cauchy:

    C

    f (z) dz = 2i Res( f , im ) , i

    m.

    C

    f (z) dz = 0

    f (Reit) iR eit dt + RR

    f (z) dz .

    0

    f (R eit) iR eit dt = 0

    ln(1 aiR eit)R2e2it + m

    iR eit dt .

    R

    0

    iR eit f (R eit) dt 6

    0

    R

    ln(1 ai R eit)R2 e2it + m dt . R2 e2it + m > R2 |e2it | m = R2 m , R > m,

    ln(1 aiR eit) = |ln(1 + aR sin t aiR cos t)| =ln 2 + 2aR sin t + i arg(1 + aR sin t aiR cos t) 63

    2+

    1

    2ln(1 + 2aR sin t) 6 3 + ln(1 + 2aR)

    2.

    0

    R

    ln(1 aiR eit)|R2 e2it + m| dt 6 R

    0

    3 + ln(1 + 2aR)2R2 2m dt =

    R 3 + ln(1 + 2aR)

    2R2 2m 0 , R .

    limR

    0

    f (Reit) iR eit dt = 0

    limR+

    RR

    f (z) dz =

    f (z) dz .

    f (z) dz = 2i Res( f , im ).

    51

  • Res( f , im ) =ln(ai

    m + i)

    2i

    m=

    lni (am + 1) + i arg (i (am + 1)) i/2

    2i

    m=

    ln(1 + a

    m)

    2i

    m.

    ln(1 aix)x2 + m

    dx = m

    ln(1 + am ) . 50 ( ) an =

    1 +n

    j=21

    ln j lim( n

    n)an

    http://www.mathematica.gr/forum/viewtopic.php?f=9&t=23985

    1 ( ) 2 j n 1

    ln j =1

    ln n1

    1 + ln( j/n)ln n=

    1

    ln n(1 + O

    ( ln( j/n)ln n

    ))=

    1

    ln n + O( ln( j/n)

    ln2 n

    ), 1 < ln( j/n)ln n 0.

    n

    j=2

    1

    ln j =n 1ln n + O

    (1

    ln2 nn

    j=2 ln( j/n)).

    ln(x/n) [2, n].

    n2

    ln(x/n) dx + ln(2/n) n

    j=2ln( j/n)

    n+12

    ln(x/n) dx ,

    nj=2

    ln( j/n) = n2

    ln(x/n) dx + O(ln n) = n + O(ln n) .

    n

    j=2

    1

    ln j =n 1ln n + O

    ( nln2 n

    )

    ( nn)an

    = exp(ln nn

    (1 +

    n 1ln n

    + O(n ln2 n))) =

    exp(1 + O(ln1 n)

    ) e .

    2 ( ) (

    n

    n)an

    = eann

    ln n .

    an

    nln n = ann

    ln n.

    an

    , 1 +n

    j=2

    1

    ln j > 1 +n

    j=2

    1

    j 1 .

    n

    ln n n

    . :

    an+1 ann+1

    ln(n+1) nln n=

    1ln(n+1)

    (n+1) ln nn ln(n+1)ln(n+1) ln n

    =ln n

    ln[( nn+1

    )nn] =

    ln nln 1(

    1+ 1n

    )n + ln n = 1 ln(1+ 1n )nln n + 1 1 Cesaro-Stolz : lim

    nann

    ln n= 1 .

    e .

    52

  • :

    51 ( ) An = {n, 2n, 3n, ...} n N

    J N,

    iJ

    Ai

    http://www.mathematica.gr/forum/viewtopic.php?f=64&t=22887

    ( ) : .

    A j , N. , m N. J , j J j > m( J {1, 2, ...,m} = ). m < A j, . .

    52 ( )

    A, B AB = (A \ B) (B \ A), .

    A1A2...An

    Ai

    http://www.mathematica.gr/forum/viewtopic.php?f=64&t=23440

    ( ) A x

    A(x) = 0 x < A A(x) = 1 x A.

    (AB)(x) A(x) + B(x) mod 2.

    x A1 An (A1 An)(x) = 1 A1(x) + + An(x) 1 mod 2 x Ai.

    modulo2.

    53

  • :

    53 (

    ) p P p > 5 (p 1)! + 1 p ( pk k N).

    http://www.mathematica.gr/forum/viewtopic.php?f=63&t=20371

    ( )

    p > 5 , (p 1)! + 1 = pk k. ,

    (p 1)! = pk 1.: (p 1)! 0

    (mod(p 1)2

    ).

    ,

    (p 1)2 = 2 p 12

    (p 1) ,, p > 5,

    2

    (p 1)p1. ,

    pk (p 1)p1 + 1 > (p 1)! + 1 = pk, . .

    54 ( dimtsig)

    .

    http://www.mathematica.gr/forum/viewtopic.php?f=63&t=22945

    ( ) -

    1 .

    m

    111...1n

    = m2, n > 1.

    , m

    1 9.

    m m = 10a 1, a N.

    ,

    111...1n

    = 100a2 20a + 1,

    111...10n1

    = 100a2 20a,

    111...1n1

    = 10a2 2a.

    , ,

    .

    54

  • :

    55 ( )

    S ,

    s1, s2, ..., sn s1 + s2 + ... + sn < 1. S - ;

    http://www.mathematica.gr/forum/viewtopic.php?f=13&t=18203

    ( ) n N An = {sk : sk 1n }. ( n

    ). S = An, S -.

    56 ( -

    ) (entire) f , g

    f (z)2 + g(z)2 = 1 z C.

    http://www.mathematica.gr/forum/viewtopic.php?f=13&t=13878

    ( ) f 2 (z) + g2 (z) = 1

    ( f (z) + i g (z)) ( f (z) i g (z)) = 1

    f (z) + i g (z) , 0 z C

    (z)

    ( C) f (z) + i g (z) = e(z) . 1

    f (z) + i g (z) = f (z) i g (z) = e(z) .

    { f (z) + i g (z) = e(z)f (z) i g (z) = e(z)

    }

    f (z) = e(z)

    + e(z)

    2g (z) = e

    (z) e(z)2i

    (z) = i (z) ()

    f (z) = cos ( (z)) g (z) = sin ( (z))

    (z) .

    55

  • :

    57 ( )

    BE B O

    BOOE

    =

    32.

    .

    http://www.mathematica.gr/forum/posting.php?mode=edit&f=27&p=119266

    ( )

    ABE, BEC :32=

    BOOE

    =ABAE

    =BCCE

    =AB + BC

    AC.

    :

    sin C + cos C =32

    1 + sin 2 C = 32

    C = 150 A = 750

    2 ( ) (ABC) = (ABE) + (BEC).

    1

    2AB BC = 1

    2AB BE

    2

    2+

    1

    2BC BE

    2

    2.

    BE2=

    AB BCAB + BC (1).

    r

    ABC BO =2r

    EO = 23

    3r.

    1

    2AB BC = 1

    2(AB + BC +CA)r (1)

    2 +

    23

    32

    =AB + BC +CA

    AB + BC .

    1 +

    23= 1 +

    ACAB + BC

    . -

    AB2 4AB BC + BC2 = 0 ABBC = 2

    3.

    ABBC = 2

    3 = tan 15o

    sin Csin A = tan 15

    o .

    C = 15o A = 75o.

    ABBC

    = 2 +3 = tan 75o

    .

    58 ( )

    sin(

    arctan(1

    3

    )+ arctan

    (1

    5

    )+ arctan

    (1

    7

    )

    + arctan(1

    11

    )+ arctan

    (1

    13

    )+ arctan

    (111

    121

    ) ).

    http://www.mathematica.gr/forum/viewtopic.php?f=27&t=23387

    ( )

    arctan (x) + arctan (y) = z tan z =

    x + y1 xy

    z = arctan(

    x + y1 xy

    ).

    56

  • tan (x) = z 1

    z= tan

    (

    2 x

    )

    arctan(1

    z

    )=

    2 x =

    2 arctan (z)

    arctan(1

    z

    )+ arctan (z) =

    2.

    arctan(1

    3

    )+ arctan

    (1

    5

    )+ arctan

    (1

    7

    )+ arctan

    (1

    11

    )+

    arctan(1

    13

    )+ arctan

    (111

    121

    )=

    arctan(4

    7

    )+ arctan

    (1

    7

    )+ arctan

    (1

    11

    )+ arctan

    (1

    13

    )+

    arctan(111

    121

    )=

    arctan(7

    9

    )+ arctan

    (1

    11

    )+ arctan

    (1

    13

    )+ arctan

    (111

    121

    )=

    arctan(43

    46

    )+ arctan

    (1

    13

    )+ arctan

    (111

    121

    )=

    arctan(121

    111

    )+ arctan

    (111

    121

    )=

    2.

    sin(

    arctan(1

    3

    )+ arctan

    (1

    5

    )+ arctan

    (1

    7

    )

    + arctan(1

    11

    )+ arctan

    (1

    13

    )+ arctan

    (111

    121

    ) )= 1.

    57

  • :

    59 ( KARKAR)

    A ABC BC. (O) A AB, AC P, Q .

    PQ S , S T . AT M BC.

    http://www.mathematica.gr/forum/viewtopic.php?f=62&t=22297

    1 ( ) AQT P , AT AQP. BPQC ( ) BC PQ. AT BC.

    2 ( ) AM S . PQ ( S ) S . - A.PRQS . BC// BC AT .

    3 ( )

    A = AK AN = AP AB = AT AM =AQ AC. (o) BC. S T A, M, S ,(S S , AS ) BC M. S A M MM AS , = PBCQ, = QCS S , = ()//BC, ABCS , M AS , M BC.

    4 ( ) N PQ, NAP = MAC, ABC, APQ . S , A,O, N, T S O, S NA = S T A = S AT , NPA = S AQ NAP = MAC( ).

    58

  • 60 (

    [ ] ) ABC A , BAC BC .

    ABC .

    http://www.mathematica.gr/forum/viewtopic.php?f=62&t=22802

    1 ( )

    ,

    p, c, Q = (0, p), KQ KA = c(1). BKC = 2A, KBC ,

    > 1,

    KA = y0 x20 = 2y20 y20 2 + 2y0(2). (1)

    x20 + (y0 p)2 = y0 + c (2)

    2y0( p c) = c2 + 2 p2. c = p, c2 + 2 = p2

    c =2

    2 1 > 0, p =(2 + 1

    )1 2 < 0.

    ,

    (Q, 2

    2 1

    ).

    2 ( )

    AW, AS , BAC = AEZ = AZE (), c ,

    .

    : BAC = AEZ = AZE KBFC, QZFE. L, F,. Q QA = r2

    QH QA = KQ2 R2 = 2Rr + r2, QH

    Q =2Rr + r2

    r2

    H

    Q =2Rr.

    Q

    r=

    KLR

    =AH2R

    H

    r=

    AH2R

    2Rr H = AH D = AD,

    QZ = A, ct, Q - .

    , r2 = Q QA.

    3 ( ) AD A = AD2 () (c) AD B,C B,C .

    59

  • (o) (ABC) BC. A , BC (n) (c). ( BC (n)) , (ABC) (n) (n).

    60

  • :

    61 ( )

    C :z + 1z =

    z2 + 1z2 = 2

    http://www.mathematica.gr/forum/viewtopic.php?f=60&t=24667

    1 ( ) |z + 1z| = 2

    |z2 + 1z2+ 2| = 4. w = z2 + 1

    z2.

    |w + 2| = 4 |w| = 2.

    w = 2 z2 = 1. z = 1 z = 1. 2 ( ) z + 1z

    = 2 z + 1z

    2 = 4 z2 + 1z2 + 2

    = 4 : (1) z2 + 1z2

    = 2 : (2)

    z2 +1

    z2= x + yi, (x, y R)

    (2)

    x2 + y2 = 2 x2 + y2 = 4 : (3)

    (1) |(x + 2) + yi| = 4 (x + 2)2 + y2 = 4 (x + 2)2 + y2 = 16 : (4)

    (3) (4) (x, y) = (2, 0).

    z2 +1

    z2= 2 z4 2z2 + 1 = 0

    (z2 1

    )2= 0 (z = 1 z = 1)

    3 ( )

    z +1

    z= w

    |w| = |w2 2| = 2

    2 =ww

    2

    |w2 2| = 2 |w2 ww2| = 2 |2w w| = 2

    w = x + yi |w| = 2 |2w w| = 2 w = 2 w = 2 (x = 2 y = 0). .

    62 ( )

    P(x) , n x1, x2, ..., xn.

    ni=1

    P(xi)P(xi) = 0

    http://www.mathematica.gr/forum/viewtopic.php?f=60&t=22338

    1 ( ) an = 1, -

    Q(x) = 1an

    P(x).P(x) = (x x1)(x x2)(x x3)...(x xn1)(x xn)P(x) = (x x2)(x x3)...(x xn1)(x xn)+(x x1)(x x3)...(x xn1)(x xn)...

    +(x x1)(x x2)(x x3)...(x xn2)(x xn)+(x x1)(x x2)(x x3)...(x xn1)P(x) = (xx3)...(xxn1)(xxn)+(xx2)(xx4)...(x

    xn1)(x xn) +...+ (x x2)(x x3)...(x xn2)(x xn)+ (xx2)(x x3)...(x xn1)

    +(x x3)...(x xn1)(x xn) + (x x1)(x x4)...(x xn1)(x xn)+ (x x1)(x x3)...(x xn2)(x xn)+ ...+ (xx1)(x x3)...(x xn1)

    ...

    +(x x2)...(x xn2)(x xn) + (x x1)(x x3)...(x xn2)(x xn) +..+ (x x1)(x x2)...(x xn3)(x xn)+ (xx1)(x x2)...(x xn2)

    +(x x2)...(x xn1) + (x x1)(x x3)...(x xn1)+... + (x x1)(x x2)...(x xn2)

    : P(xi) = (xi x1)...(xi xi1)(xi xi+1)...(xi xn)

    61

  • P(xi) = 2(xi x2)...(xi xi1)(xi xi+1)...(xi xn)+...+ 2(xi x1)...(xi xi2)(xi xi+1)...(xi xn)+

    2(xi x1)...(xi xi1)(xi xi+2)...(xi xn) + ...+ 2(xi x1)...(xi xi1)(xi xi+1)...(xi xn1)

    :P(xi)P(xi) =

    2

    (1

    xi x1+ ... +

    1

    xi xi1+

    1

    xi xi+1+ ... +

    1

    xi xn

    ):

    ni=1

    P(xi)P(xi) = 2

    (1

    x1 x2+

    1

    x1 x3+ ... +

    1

    x1 xn

    )+

    2

    (1

    x2 x1+

    1

    x2 x3+ ... +

    1

    x2 xn

    )+ ...

    +2

    (1

    xn x1+

    1

    xn x2+ ... +

    1

    xn xn1

    )= 0

    2 ( )

    ( p

    p) = 1

    x r1+ ... +

    1

    x rn= S ,x , r1, ..., rn

    ( pp

    ) = 1S,x , u1, ..., un1 u1, ..., un1

    p ()

    (p)2 pp(p)2 =

    S S 2

    p

    p= 1 +

    S

    S 2,x , u1, ..., un1

    p

    p=

    ( 1xr1 + ... +

    1xrn )

    2 ( 1(xr1)2 + ... +1

    (xrn)2

    ( 1xr1 + ... +

    1xrn )

    2=

    2

    ni, j

    1xix j

    ( 1xr1 + ... +

    1xrn )

    2

    P(ri)P(ri) =

    2

    (1

    ri r1+ ... +

    1

    ri ri1+

    1

    ri ri+1+ ... +

    1

    ri rn

    )...

    62

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