IBPS CLERK MOCK TEST - 152 (PHASE-II) (SOLUTION). (5) 18. (2) 19. (5) 20. (5) 21. (5) (22-27): In the first step, the word that comes first in the reverse alphabetical order comes

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Centres at: MUKHERJEE NAGAR MUNIRKA UTTAM NAGAR DILSHAD GARDEN ROHINI BADARPUR JAIPUR GURGAON NOIDA MEERUT VARANASI ROHTAK PANIPAT SONEPAT BAHADURGARH PATNA AGRA CHANDIGARH LUCKNOW ALLAHABAD

IBPS CLERK MOCK TEST - 152 (PHASE-II) (SOLUTION)

REASONING1. (3) The left letter moves three letters

backward while the right one

moves three letters forward. The

number in the middle increases

by 3, 4, 5, 6, ....

2. (1) Observe the first letters of each

group. These letters make a

simple "skip two letters"

sequence: K(LM) N(OP) Q(RS)

T(UV) W. Hence the first letter of

the missing group will be W.

Similarly, look at the second

letters of each group. These letters

make a simple "skip one letter and

move backward" sequence. N(M)

L(K) J(I) H(G) F. Hence, the second

letter of the missing group will be

F. Therefore, the required answer

is WF.

3. (2) Here specified letters are: V, I, L

and E. Words formed with these

letters are as follows:

1. EVIL 2. LIVE 3. VEIL 4. VILE

4. (1) See the table given below:

the coded for LANE is 5427.

5. (2)

6. (2) The actual positions of the

directions are as shown in I while

the changed positions of the

pointer can be described by II.

Clearly, the directions of West

shown by the pointer in wrong

position (Fig II) is actually South.

(7-11):7. (3) We have to look for symbol-digit

combination. Underlined digits

given below are required digits.

A E C B % 7 D $ E B 5 C ? 3 D E 9

@ 2 #

8. (1)

= 12 + 18 = 30

= (40 – 30) = 10

9. (5) After dropping vowels we have the

following arrangement:

C B % 7 D $ B 5 C ? 3 D 9 @ 2 #

Hence, D is twelfth from the left

end of the above arrangement.

10. (5) Second to the left of the fourteenth

from the left end means (14 – 2 =)

12th from the left end, i.e. C.

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11. (2) According to the direction givenin the question, we have thefollowing new arrangementA E C B % 2 D $ E B 3 C ? 5 D E 7@ 9 #Hence, 5 is fourteenth from theleft end of the above arrangement.

(12-16):a friend of mine 4 9 1 6 ... (i)mine lots of metal 3 1 0 9 ... (ii)a piece of metal 7 1 6 3 ... (iii)From (i), (ii) and (iii),of 1 ... (iv)From (i), (iii) and (iv),a 6 ... (v)From (i), (ii) and (iv),mine 9 ... (vi)From (i), (iv), (v) and (vi),friend 4 ... (vii)From (ii), (iii), and (iv),metal 3 ... (viii)From (ii), (iv), (vi) and (viii),lots 0 ... (ix)From (iii), (iv), (v) and (viii),piece 7 ... (x)

12. (*) 13. (2) 14. (3) 15. (4) 16. (5)(17-21):17. (5) 18. (2) 19. (5) 20. (5) 21. (5)(22-27):

In the first step, the word thatcomes first in the reversealphabetical order comes to thefirst place and the rest of the lineshifts rightward. In the next step,the largest number occupies thenext place and the rest of the lineshifts rightward. This goes onalternately till the words getarranged in the reversealphabetical order and thenumbers in a descending order.

22. (2)Step III: year 92 ultra 15 23 strive house 39Step IV: year 92 ultra 39 15 23 strive

houseStep V: year 92 ultra 39 strive 15 23

houseStep VI: year 92 ultra 39 strive 23 15

houseStep VII: year 92 ultra 39 strive 23 house 15

Hence 7 – 3 = 4 more steps willbe required.

23. (3)Input: any how 49 24 far wide 34 69Step I: wide any how 49 24 far 34 69Step II: wide 69 any how 49 24 far 34Step III: wide 69 how any 49 24 far 34Step IV: wide 69 how 49 any 24 far 34Step V: wide 69 how 49 far any 24 34Step VI: wide 69 how 49 far 34 far 24

Hence Step V will be the last butone.

24. (4) We can't proceed backward.25. (4)Input: play over 49 37 12 match now 81Step I: play 81 over 49 37 12 match

nowStep II: play 81 over 49 now 37 12

matchStep III: play 81 over 49 now 37 match 12

Since the line is alreadyarranged, there will be no 4thstep.

26. (2)Step II: war 58 box cart 33 49 star 24Step III: war 58 star box cart 33 49 24Step IV: war 58 star 49 box cart 33 24Step V: war 58 star 49 cart box 33 24Step VI: war 58 star 49 cart 33 box 24

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27. (4)Input: shower fall water 34 51 67 98

goalStep I: water shower fall 34 51 67 98

goalStep II: water 98 shower fall 34 51 67

goalStep III: water 98 shower 67 fall 34 51

goalStep IV: water 98 shower 67 goal fall 34 51Step V: water 98 shower 67 goal 51 fall 34(28-32):

H is the husband of A. C is thehusband of D. E is the husband of B.

28. (5) Option (5) is true.29. (3) E is the husband of B.30. (3) Two persons F and G sit between B

and C.31. (1) D is the wife of C.32. (5) Position of E with respect to C is

second to the right.(33-37):

33. (5) S, T and A34. (4)35. (3)36. (1)37. (2)

(38-40):38. (3) Both (C) and (D) suggest that the

students were merely trying toprevent the theft of theirpossessions.

39. (4) The announcement is measuretaken to stop cheating in exams.

40. (1) This is the only choice where "theinvigilator" is the subject of thesentence.

MATHS

81. (5) (?)3 = 2 2( 5 10) ( 2 5)

5 2 50 10 2 10 2 25

5 10 2 10 2 10 2 25 42

or, (?)3 = 42 + 22 = 64

? = 3 64 = 4

82. (1) 55 2116 0.01 ? 20100

( 2116 46 46 46)

or, ? × 20 =55 46

100 0.01

= 55 461 = 2530

2530? 126.520

83. (1) (?)2 = 212 16 24 193 7 5

= 16144 193 3524

= 96 193 35 324

or, (?)2 324 18

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84. (4) (?)2 = 31.36 0.64 25236

=

5.6 2520.8

36

=

7 25236

= 49

? = 49 = +7.Hence, –7.

85. (3)3

4 3 ? 22197(1.69) 13 131000

or, (1.3)8 ÷ (1.3)3×3 × 133 = 13? – 2

or, 1.38 – 9 + 3 = 13? – 2

or, 132 = 13? – 2

or, ? – 2 = 2 ? = 2 + 2 = 4

86. (4) ? = 68 1288 26 734 215

100 100

= 875.84 + 190.84 – 215= 876 + 191 – 215= 852 850

87. (2) ? = (32.05)2 – (18.9)2 – (11.9)2

= 1027 – 357 – 144= 526 530

88. (2) ? = 6578 15

67 6

= 250

89. (5) ? = 680 2130 12645 23 169

= 680 2130 12645 23 170

= 1043104090. (3) 5687 1245 689 = ? ÷ 13

? = 5687 1245 13

689

= 74.4 35.2 13 1320

26.2

91. (3) –202, –162, –122, –82, –42

92. (2) +46, +92, +138, +184, +23093. (4) +(11×1+0), +(11×3+2), +(11×5+4),

+(11×7+6), +(11×9+8), ...

94. (5) The given series is a combinationof two series.

Pattern I: 454 648 842 1036194 added in each subsequent

term.Pattern II: 237 521 715194 added in each subsequent

term.Hence 713 should be replacedwith 715.

95. (3) +13.5, +27, +54, +108, +216,+432Hence, 168 should be replacedwith 167.

96. (3) Let the money of C be ` x.According to the question,

Total money of B = x + x × 50%

= x + 50100

x = 32x

Total money of A = 2 × 32x

= 3x

Average money of three persons =12000

Total money of three 12000 × 3

3x + 32x

+ x = 12000 × 3

6 3 2

2x x x

= 36000

x = 36000 211

= 7200011

Now, money of A

= 3x = 3 × 7200011

= 21600011

`

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97. (3) Total number of students = 480Percentage of total studentspassed= 75% of total students

= 75 480

100

= 360 students

Now, using the condition from thequestion,Let the number of boys be x.Then, 70% of x + 85% of (480 – x)= 360

75 85 (480 )100 100

x x = 360

70x – 85x + 40800 = 36000 40800 – 36000 = 85x – 70x 4800 = 15x

x =480015 = 320

There are 320 boys whoappeared for the examination.

98. (4) Let the weight of fresh grapes bex.Quantity of water in it

= 80

100 × x = 45x

Quantity of pulp in it

45 5x xx

Quantity of water in 500 kg dry

grapes = 10

100 × 500 = 50 kg

Quantity of pulp in it= (500 – 50) = 450 kg

5x

= 450

x = 2250 kg

99. (3) If the principal = P and interest =R%Then, required ratio

P × R ×1212 2100 2 : 3

P × R ×18 18 3100

100. (5)Let total number of employees inbegining = 8K and total numberof employees in present = 7KLet salary of an employee inbeginning = 5land salary of an employee inpresent = 6lTotal salary in beginning= 8K × 5l = 40Kland total salary in present= 7K × 6l =42KlRequired ratio = 40 Kl : 42 Kl= 20 : 21Clearly, salary is increased.

101. (3)A's share : B's share : C's share= (20000 × 12) : (25000 × 4) :(15000 × 8)= 240000 : 100000 : 120000= 24 : 10 : 12= 12 : 5 : 6Let A's share = 12x

B's share = 5xC's share = 6x

According to the question,12x + 5x + 6x = 23000

23x = 23000

x = 23000

23 = 1000

C's share= 6x= 6 × 1000= ` 6000

102. (2)Reqd cost= 4 361 62 = 4 × 19 × 62= ` 4712

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103. (4)By rule of fraction:

Cost price = 1242 × 100 10090 115

= ` 1200104. (3)Supervisor's age

= 32 + 6 = 38 years105. (3)Speed of train

= Length(platform + train)Time

175 35 21012 12

m/sec

210 1812 5

kmph = 63 kmph

(106-110):

Number of boys = 800 54

100

= 432

Number of girls= 800 – 432 = 368Number of girls visited Mumbai

1368 92

4

Number of girls visited Delhi

= 25% of 368 25 368 92

100

Number of girls visited Jodhpur

92 462

Number of girls visited Ajmer

= (368 – (92 + 92 + 46)56

= (368 – 230)56 = 138 ×

56 = 115

Number of girls visited Varanasi= 368 – 230 – 115 = 23Number of boys visited Mumbai= 192 – 92 = 100Number of boys visited Varanasi

1 432 1084

Number of boys visited Ajmer = 101Number of boys visited Delhi

= (432 – 309) × 23 = 82

Number of boys visited Jodhpur= (432 – 309 – 82) = 41

106. (3)Required ratio = 92 : 100 = 23 : 25107. (2)Required average

82 108 41 231 773 3

108. (1)Required number of girls

2(46 23) 463

109. (5)Number of students who visitedJodhpur = 41 + 46 = 87

Required percentage 87 100

115

= 75.65 76%110. (5)Number of students who visited

Varanasi = 108 + 23 = 131(111-115):

Runs scored by the batsmanagainst each country are as givenbelow:

ODI TestAustralia 1980 1080England 1155 765WI 8801170New Zealand 1430 1350Pakistan 1320 945Zimbabwe 1485 1170Sri Lanka 1650 1710South Africa 1100 810

111. (3)Required % 945 100 85%

1100

112. (5)Percent of runs scored by thebatsman in Test matches againstSouth Africa

900 100 10%9000

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113. (3)From the table it is clear that theminimum difference is for SriLanka.

114. (1)Required difference = 1710 – 1650= 60

115. (2)Average runs = 88022 = 40

(116-120):116. (3)Only in 2nd and 7th five-year

plans the increase in GDP is100% whereas in other cases it isless than 100%.

117. (4)Let the industry growth be x%.The sum of growth rates weightedby their proportion of contributionto GDP = GDP growth rateAgriculture growth = 4%Service sector growth = 6% (fromthe graph)

Now, 8 4 7 5 6

8 7 5x

= 9.4

or, 32 + 7x + 30 = 188or, 7x = 126or, x = 18%

118. (2)Decline in service sector

= 3 1.80

3

× 100 = 40%

119. (1)Let the contribution of industrybe x%. Then contribution ofagriculture= (80 – x)%(As sum of contribution of the 3sectors = 100%)Agriculture growth = 3%Service sector growth = 4%GDP growth = 6.48% (from thegraph)

Now,(80 ) 3 11 20 4 6.48

100x x

[Weighing the growth rate of thecomponents by their percentagecontribution]or, 240 – 3x + 11x + 80 = 648or, 8x + 320 = 648or, 8x = 328or, x = 41% contribution of agriculture= 80 – 41 = 39Required ratio = 41 : 39

120. (5)Required % increase

3.5 2.5 100 40%2.5

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1. (3)2. (1)3. (2)4. (1)5. (2)6. (2)7. (3)8. (1)9. (5)10. (5)11. (2)12. (4)13. (2)14. (3)15. (5)16. (5)17. (4)18. (2)19. (5)20. (5)21. (5)22. (2)23. (3)24. (4)25. (4)26. (2)27. (4)28. (5)29. (3)30. (3)31. (1)32. (5)33. (5)34. (4)35. (3)36. (1)37. (2)38. (3)39. (4)40. (1)

41. (1)42. (5)43. (2)44. (1)45. (3)46. (2)47. (3)48. (1)49. (4)50. (2)51. (1)52. (5)53. (3)54. (1)55. (4)56. (2)57. (5)58. (1)59. (3)60. (2)61. (3)62. (5)63. (1)64. (4)65. (3)66. (2)67. (5)68. (1)69. (4)70. (3)71. (3)72. (5)73. (2)74. (1)75. (4)76. (3)77. (2)78. (3)79. (4)80. (1)

IBPS CLERK MOCK TEST - 152 (PH - II) [ANSWER KEY]

81. (5)82. (1)83. (1)84. (4)85. (3)86. (4)87. (2)88. (2)89. (5)90. (3)91. (3)92. (2)93. (4)94. (5)95. (3)96. (3)97. (3)98. (4)99. (3)100. (5)101. (3)102. (2)103. (4)104. (3)105. (3)106. (3)107. (2)108. (1)109. (5)110. (5)111. (3)112. (5)113. (3)114. (1)115. (2)116. (3)117. (4)118. (2)119. (1)120. (5)

121. (4)122. (1)123. (2)124. (1)125. (1)126. (4)127. (2)128. (4)129. (2)130. (3)131. (1)132. (2)133. (4)134. (4)135. (4)136. (1)137. (1)138. (3)139. (2)140. (2)141. (1)142. (4)143. (3)144. (4)145. (1)146. (4)147. (3)148. (3)149. (2)150. (4)151. (3)152. (1)153. (2)154. (2)155. (4)156. (5)157. (1)158. (4)159. (3)160. (3)

161. (5)162. (4)163. (5)164. (2)165. (1)166. (1)167. (5)168. (4)169. (1)170. (5)171. (1)172. (5)173. (2)174. (3)175. (3)176. (4)177. (3)178. (1)179. (4)180. (2)181. (2)182. (1)183. (1)184. (5)185. (1)186. (4)187. (2)188. (4)189. (3)190. (3)191. (4)192. (3)193. (3)194. (2)195. (2)196. (5)197. (2)198. (4)199. (1)200. (5)

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IBPS CLERK MOCK TEST - 152 (PHASE-II) (SOLUTION). (5) 18. (2) 19. (5) 20. (5) 21. (5) (22-27): In the first step, the word that comes first in the reverse alphabetical order comes