i Cos i Dodecahedron 13

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  • http://www.mathematica.gr. mathematica.gr. LaTEX--: , : . LTEX. .ISSN: 2241-7133

    Leonardo da Vinci

    (32-) . 30

    . -

    - - quasiregular ,

    ( - ).

    (0,0,),( 12 ,

    2 ,

    1+2

    ), 1+

    5

    2 .

    :http://en.wikipedia.org/wiki/Icosidodecahedron

    :

    mathematica.gr - (http://www.mathematica.gr) .

    mathematica.gr

    1. ()

    2. (matha)

    3. (nsmavrogiannis)

    4. (chris_gatos)

    5. (Mihalis_Lambrou)

    6. (m.papagrigorakis) -

    7. (Demetres)

    1. (grigkost)

    2. (cretanman)

    1. (stranton)

    2. (vittasko)

    3. ()

    4. (s.kap)

    5. ( )

    6. ( )

    7. (chris_gatos)

    8. (grigkost)

    9. (emouroukos)

    10. ( )

    11. (m.papagrigorakis)

    12. ( )

    13. (cretanman)

    14. (achilleas)

    15. (xr.tsif)

    16. (polysot)

    1. (stranton)

    2. ( )

    3. (spyros)

    4. (vittasko)

    5. ()

    6. (KAKABASBASILEIOS)

    7. (exdx)

    8. (s.kap)

    9. ( )

    http://www.mathematica.grhttp://en.wikipedia.org/wiki/Icosidodecahedronhttp://www.mathematica.gr
  • 10. (nkatsipis)

    11. ( )

    12. ( )

    13. ( )

    14. (emouroukos)

    15. (gbaloglou)

    16. (R BORIS)

    17. ( )

    18. ( )

    19. ( )

    20. (dement)

    21. ( )

    22. (swsto)

    23. (achilleas)

    24. ( )

    25. ()

    26. (xr.tsif)

    27. (polysot)

    1. ( )

    2. (mathfinder)

    3. ( )

    4. (rek2)

    5. (hsiodos)

    6. (bilstef)

    2

  • 1 ( ) - . , , .

    () ;

    () -, ;

    2 ( KARKAR) - a, b,

    1a+

    1b=

    29.

    3 ( ) - 11 20 ;

    4 ( PetranOmayromixalis) 3 , 4 -, 5 . ;

    5 ( KARKAR) AB,CS .

    6 ( KARKAR) ABCD - 8 3 M,N AB,AD.

    () S DC ,

    S MN 13

    ABCD.

    () BT B MS , 3.

    7 ( ) AB = A, B = = P + 2. (AB)

    8 ( vzf) - a, b, c, m > 2, am + bm < cm.

    ,

    9 ( qwerty) :

    A =3

    108 + 10 3

    108 10.

    10 ( ) -

    (3x 1)(4x 1)(6x 1)(12x 1) = 5.

    3

  • ,

    11 ( )

    BC ABCD E, F, : BAE = CDF EAF = EDF. FAC = EDB.

    12 ( )

    ABC(AB = AC). - (O) O. S - O, S AC. (O) B, S P. C, S , P, BP T ( P T ).

    () S O, C, T ;

    () - = ACS = 420, ABC CT PS .

    ,

    13 ( )

    2x2 + xy = 19x2

    2(1x)4 = 1 +3xy

    2(1x)2

    14 ( )

    ) R :

    {x + y = 4

    x4 + y4 = 82

    ) R :441 x + 4

    41 + x = 4

    ,

    15 ( )

    ABC M BC. S A, AB,AC, , S EAB S ZAC. T AM EZ, : T SBC.

    16 ( ) :

    PA,PBE EC A, B,C - () ABC -.

    BHAC. HB PHE,

    ,

    17 ( ) -

    x2 2x y2 4y 32 = 0 (Q) .

    4

  • () - R.

    () .

    () (Q) (3,0) 0 . 0 Q0 x = 1.

    () - Q0 1 - - 2 - - . 1, 2 3

    2 .

    () (1) 1 2 2 2 1 . 1, 2, 1, 2 .

    18 ( ) A(1, 1), B(2,5) AB I(2, 2) - . .

    ,

    19 ( parmenides51) f (x) = ex x 0 .

    () f (x) - A

    P(A) = f (x) = ex

    x 0.() ()

    .

    20 ( ) : x1, x2, ..., x( 2). - :

    f (x) = |x x1 | + |x x2 | + ... + |x x|

    x = .

    , ,

    21 ( ) z K(0, 1) 2,

    |z2 (2z + 1)i + z 5| .

    22 ( ) z

    11z10 + 10iz9 + 10iz 11 = 0.

    :

    () |z| = 1.

    ()

    (2z zi 2i + 1

    1 + zi

    )2 0.

    () Re (z) =|z + 1|2 2

    2.

    () |z2 3z + 1| = 5 |z + 1|2.

    , , ,

    23 ( ) - :

    f (x) =

    1, x < 00, x = 01, x > 0

    g(x) = x2 2x + 4 .

    f g g f .

    24 ( ) x > 0 f

    f (e f (x)) = ln x.

    f .

    , ,

    25 ( ) - f : R R :f (x) = ex+ f (x), x R f (0) = 0.

    26 ( ) f : R R f (R) = R. C f + y = x + :

    () > 0.

    () ( ) C f1 +.() f 1(x) + < x x R.

    , ,

    27 ( ) -

    :

    1x

    1

    ext

    t2dt e (1 x) x > 0.

    28 ( ) f : [1,+) (0,+) :

    f (1) = 1,

    f (1,+), x > 1 xx f (x) = f (x) f

    (x) ln x,

    5

  • x [1,+) x+1

    x

    f (t) dt < f (x).

    , ,

    29 ( )

    f (x) =

    x2 ln

    x +73 c , x 1

    x log1x+ c , 0 < x < 1

    76

    , x = 0

    f x0 = 1.

    1. , .

    2. .

    3. f x0 = 0 - C f x = 0, x = 1 xx.

    30 ( ) x, y R,

    (2x + 3y)

    e24y + y2 + (1 x)ex + 1 =

    (ex + y)

    x2 + y2 + 2xy + x + 3,

    x + 2y = 1.

    , ,

    31 ( ) f : R R

    (f (x) x2

    )( f (x) 1) = 1, x R

    f (0) = 1, f (0) = 0.

    f .

    32 ( ) 0 < a < b f : [a, b] R ,

    ab

    b

    a

    f (x)

    x2dx 0. f M(x0, f (x0) Ox A.

    () AB 1

    | ln x0|.

    () AB 1, M f - .

    34 ( ) x, y R, :

    A =2014

    x2 + y2 4x + 2y + 58.

    Juniors,- -

    35 ( ) a, b > 0, :

    (1 +

    a

    b

    )2014+

    (1 +

    b

    a

    )2014 22015.

    36 ( )

    xn =

    n +

    n2 1 n = 1, 2, . . . .

    1x1+

    1x2+ . . . +

    1x49

    .

    Juniors,

    37 ( KARKAR) A, B CD. B , CD, - P,T . PC T D S , CA DA L,N. S L = S N.

    38 ( ) ABC AB , AC . (C) ABC, H , O (C). M BC. AM (C) N (C) AM P.

    6

  • () AP, BC,OH AH = HN.

    () ;

    Seniors,- -

    39 ( ) f : Z+ Z+ ,

    f (x2 + f (y)) = x f (x) + y,

    x, y Z+.

    40 ( ) a, b, c > 0

    (a + b + c)

    (1a+

    1b+

    1c

    ) 9

    a2 + b2 + c2

    ab + bc + ca.

    Seniors,

    41 ( parmenides51.) ABCD (O,R) (I, r). OI = x

    1r2=

    1(R + x)2

    +1

    R x)2.

    42 ( .)

    ABC (O) (K), - AD. BE, CF, DZ , E (K)AC, F (K)AB, Z (K) (O) Z , A.

    43 ( ) - 100 . 30% - , .

    44 ( ) p1 < p2 < ... < p99

    p1 + p2, p2 + p3, . . . , p98 + p99, p99 + p1

    ;

    45 ( Kyiv Taras 2013) n n A, B n n C

    AX + Y B = C

    . n n C

    A2013X + Y B2013 = C

    .

    46 ( ) a R f : (a,+) R, (a, b) b R a < b.

    limx+

    f (x + 1) f (x)xk

    ,

    k N,

    limx+

    f (x)

    xk+1=

    1k + 1

    limx+

    f (x + 1) f (x)xk

    7

  • 47 ( ) V Rnn -, W Rnn Rnn V,W.

    48 ( ) p(x) - 2. -

    A = {x R \Q : p(x) Q}

    R.

    49 ( )

    f : [0, 1] R, f (x) = 1

    0sin

    (x + f 2(t)

    )dt,

    x [0, 1].

    50 ( ) an - . {

    an

    m: n.m N

    } (0,+).

    51 ( )

    = OA , = OB = O

    3,

    (~, ~

    )=

    (~, ~

    )=

    (~, ~

    )=

    3.

    A =( ( ( ))) ( ) .

    52 ( ) - M

    x2

    2+

    y2

    2= 1 , , R ,

    , MA MB, -. A B,

    2

    x2+2

    y2= 1 .

    53 ( ) 2 , 2 .

    54 ( vzf) . , 9.

    55 ( petros r). a - .

    I =

    +

    0

    sin x cos x

    x(x2 + a2)dx.

    56 ( vz f ) - W B , h.

    ()

    57 ( )

    K := cot 70 + 4 cos 70.

    58 ( )

    f (x) =| sin 2x|

    | sin x| + | cos x| + 1.

    ,

    59 ( - . ) (an)nN . :

    n=1

    an < ,

    n=1

    an1

    nn < .

    , , :

    n=2

    an = s < ,

    n=2

    an1

    nn s + 2

    s.

    60 ( ) - f : R R ,

    f (x + y + f (2xy)) = 2xy + f (x + y),

    x, y R.

    ,

    8

  • 61 ( ) y2 = 2px E . n 3 A1A2A3 An E - . EA1, EA2, . . . , EAn B1, B2, . . . , Bn - :

    EB1 + EB2 + EB3 + + EBn np.

    62 ( ) - ABCD. , O :

    (AOB) = (BOC) = (COD) = (DOA).

    ,

    63 ( ) n 1 a C R |a| = 1.

    n

    k=0

    (nk

    )(1 + ak)xk = 0.

    :

    () a

    () a, b a + b = 0.

    64 ( )

    arccos

    (15

    )= 2 arctan

    23

    .

    9

  • :

    1 ( ) - . , , .

    () ;

    () , ;

    http://www.mathematica.gr/forum/viewtopic.php?f=44&t=31906

    ( ) .

    :

    () , -

    .

    () ,

    .

    ()

    -

    ,

    .

    -

    .

    Nk

    k. (Nk) .

    Nk+1 < Nk,

    k + 1 ().

    ()

    m , m .

    (Nk(m+1))

    , -

    .

    -

    ,

    .

    2 ( KARKAR) - a, b,

    1a+

    1b=

    29.

    http://www.mathematica.gr/forum/viewtopic.php?f=44&t=31494

    1 ( )

    1a+

    1b=

    29 2ab 9a 9b = 0

    4ab 18a 18b = 0 (2a 9) (2b 9) = 81.

    : (a, b) = (5, 45) , (a, b) =(6, 18) , (a, b) = (9, 9) , (a, b) = (18, 6) , (a, b) = (45, 5) .

    2 ( ) -

    Rh-ind, -

    2

    2n + 1 n = 2, 3, . . . , 50 -

    , 1.

    29=

    16+

    118.

    -

    :

    10

    http://www.mathematica.gr/forum/viewtopic.php?f=44&t=31906http://www.mathematica.gr/forum/viewtopic.php?f=44&t=31494
  • 22n + 1

    =1

    (2n + 1)(n + 1)+

    1n + 1

    .

    :

    29=

    145+

    15.

    :

    - G. Loria, , .

    3 ( )

    1a+

    1b=

    29 a = 1

    2

    (9 +

    812b 9

    )

    a -

    :

    2b 9 = 1 b = 5, a = 45, (a, b) = (45, 5).2b 9 = 3 b = 6, a = 18, (a, b) = (18, 6).2b 9 = 9 b = 9, a = 9, (a, b) = (9, 9).2b 9 = 27 b = 18, a = 6, (a, b) = (6, 18).2b 9 = 81 b = 45, a = 5, (a, b) = (5, 45). -

    .

    11

  • :

    3 ( ) - 11 20 ;

    http://www.mathematica.gr/forum/viewtopic.php?f=33&t=41194

    ( ) 10 , 40. 10

    212

    360 = 60.

    10

    4060

    112

    360 = 20.

    80.

    4 ( PetranOmayromixalis) 3 , 4 , 5 . ;

    http://www.mathematica.gr/forum/viewtopic.php?f=33&t=10369

    (Geopa)) ,

    :

    + = 3. + = 4. + = 5.

    2( + + ) = 12. + + = 6.)

    :

    + + = 3. + + = 4. + + = 5. :

    = = = 1. 2 = 2. 3 = 3., .

    12

    http://www.mathematica.gr/forum/viewtopic.php?f=33&t=41194http://www.mathematica.gr/forum/viewtopic.php?f=33&t=10369
  • :

    5 ( KARKAR) - AB,CS .

    http://www.mathematica.gr/forum/viewtopic.php?f=34&t=40719

    ( )

    COS = 20. BO CO COB

    OCB = OBC = 40.

    OCS = 140 CS O = 20. S CO S C = CO. CO = BO

    :

    S C = BO (1)

    BAO

    BOK, K AO .

    BOK = 120 :

    BAO =BOK

    2= 60

    , BOA :

    AB = BO (2)

    (1) (2) .

    6 ( KARKAR) ABCD 8 3 M,N AB, AD.

    () S DC , -

    S MN 13

    ABCD.

    () BT - B MS , 3.

    http://www.mathematica.gr/forum/viewtopic.php?f=34&t=40296

    ( )

    () DS = x, S C = 8 x. (ABCD) = 24, (MAN) = 3, (MNS ) = 8

    (DNS ) + (S MBC) = 13.

    3x4+

    3(12 x)2

    = 13

    x =203.

    () S E = CB = 3, EB = S C =43

    ME =83.

    S ME

    S M2 =

    (83

    )2+ 32 S M =

    1453

    .

    13

    http://www.mathematica.gr/forum/viewtopic.php?f=34&t=40719http://www.mathematica.gr/forum/viewtopic.php?f=34&t=40296
  • S MB

    BT S M2

    =S E MB

    2 BT = 36

    145.

    BT 2 =1296145

    < 9 = 32 1296 < 1305,

    BT < 3.

    14

  • :

    7 ( ) AB = A, B = = P + 2. (AB)

    http://www.mathematica.gr/forum/viewtopic.php?f=35&t=33893

    ( ) A -

    B , A

    B.

    AP = 6 .

    2= P2 + P2 (P + 2)2 = 64 + P2

    4P = 60 P = 15

    P = BP = 8.

    (AB) = (AB) + (B) E =6 16 + 15 16

    2= 168.

    8 ( vzf) a, b, c, m > 2, - am + bm < cm.

    http://www.mathematica.gr/forum/viewtopic.php?f=35&t=25144

    ( ) ac< 1, b

    c< 1 m > 2

    :

    (a

    c

    )m+

    (b

    c

    )m 0 , 0 P(A) 1. ex 0 . f (x) = ex 1 . f (x) = ex < 0 f .

    x 0

    f (x) f (0) ex 1 0 ex 1.

    () -

    P(A) =N(A)

    N() N() =

    N(A)

    P(A)

    N() =N(A)

    ex.

    N()

    N(A) ex. -

    N(A) , N(A)

    . ..

    .

    20 ( ) :x1, x2, ..., x( 2). :

    f (x) = |x x1| + |x x2| + ... + |x x|

    x = .

    http://www.mathematica.gr/forum/viewtopic.php?f=18&t=5879

    ( ) :

    x1 x2 ... x.

    () : = 2 + 1 ( N).:

    x1 ... x x+1 = x+2 ... x2 x2+1 (I)

    x < x1, :

    |x x1| +x x2+1

    = x + x1 x + x2+1= x2+1 x1 + 2 (x1 x)

    > x2+1 x1 .

    x > x2+1, :

    |x x1| +x x2+1

    = x x1 + x x2+1= x2+1 x1 + 2

    (x x2+1

    )

    > x2+1 x1 .

    x1 x x2+1, :

    |x x1| +x x2+1

    = x x1 x + x2+1= x2+1 x1.

    :

    |x x1| +x x2+1

    x2+1 x1 (1),

    = x1 x x2+1.:

    29

    http://www.mathematica.gr/forum/viewtopic.php?f=18&t=15652http://www.mathematica.gr/forum/viewtopic.php?f=18&t=5879
  • |x x2| +x x2

    x2 x2 (2),

    = x2 x x2.x x

    +x x+2

    x+2 x (),

    = x x x+2.x x+1

    0 ( + 1) ,

    = x = x+1.

    -

    :

    f (x) (x2+1 + x2 + ... + x+2

    )

    (x1 + x2 + ... + x

    )(II)

    , x , x+1, (+1) - > (II) >.

    x = x+1 = , (I) (+ 1) = (II)

    = . , x = f

    .

    () : = 2 ( N). :

    x1 ... x x + x+1

    2= x+1

    ... x21 x2 (I)

    :

    |x x1| +x x2

    x2 x1 (1),

    (=) x1 x x2.

    |x x2| +x x21

    x21 x2 (2),

    = x2 x x21.

    x x +

    x x+1 x+1 x (),

    = x x x+1. -

    :

    f (x) (x2 + x21 + ... + x+1

    )

    (x1 + x2 + ... + x

    )(II)

    x =x + x+1

    2= ,

    (I), () = (II) =. x = f .

    30

  • :

    21 ( ) z - K(0, 1) 2,

    |z2 (2z + 1)i + z 5| .

    http://www.mathematica.gr/forum/viewtopic.php?f=51&t=40335

    1 ( ) w = z i - :

    |w| = 2, |w2 + w 4|. w = x + yi, x, y R x2 + y2 = 4

    |w|2 = (x2 y2 + x 4)2 + (2xy + y)2

    = (2x2 + x 8)2 + (4 x2)(2x + 1)2

    = ..........................................

    = 68 16x2 .

    |w|2 68 = |w| 217 -

    .. x = 0, y = 2. 2

    17.

    2 ( )

    |z2 (2z + 1)i + z 5| = |z2 2iz + i2 + z i 4|

    =

    (z i)2 + (z i) 4

    =

    (z i)2 + (z i) (z i) (z i)

    = 2 |(z i) + 1 (z + i)|

    = 2 |z z + 1 2i|

    = 21 + 4(Im (z) 1)2

    z=3i 2

    1 + 4(3 1)2

    = 217 .

    3 ( )

    2 |z z + 1 2i| = 2 |(z z) (1 + 2i)| , , -

    (1, 2) (0,2) (0, 6). |(z z) (1 + 2i)|max =

    17, z

    (0, 3) (0,1).

    22 ( ) - z

    11z10 + 10iz9 + 10iz 11 = 0.

    :

    () |z| = 1.

    ()

    (2z zi 2i + 1

    1 + zi

    )2 0.

    () Re (z) =|z + 1|2 2

    2.

    () |z2 3z + 1| = 5 |z + 1|2.

    http://www.mathematica.gr/forum/viewtopic.php?f=51&t=27420

    1 ( )

    ()

    z9 =11 10zi11z + 10i

    ,

    |z|9 = |11 10iz||11z + 10i|

    .

    z = x + yi, x, y R ,

    (x2 + y2)9 =121 + 220y + 100y2 + 100x2

    121x2 + 121y2 + 220y + 100.

    x2 + y2 > 1 x2 + y2 < 1, . - x2 + y2 < 1. x2 + y2 = 1.

    31

    http://www.mathematica.gr/forum/viewtopic.php?f=51&t=40335http://www.mathematica.gr/forum/viewtopic.php?f=51&t=27420
  • () z =1z,

    2z zi 2i + 11 + zi

    2z+

    i

    z+ 2i + 1

    1 iz

    =2 + i + 2iz + z

    z i

    , i

    2z zi 2i + 1

    1 + zi.

    .

    ()

    |z + 1|2 22

    =(z + 1)(z + 1) 2

    2

    =|z|2 + z + z + 1 2

    2

    =z + z

    2

    = Re(z) .

    () ,

    |z + 1|2 = z + z + 2 (1)

    |z2 3z + 1|2 = (z2 3z + 1)(z2 3z + 1)

    = (z2 3z + 1)( 1z2

    3z+ 1

    )

    =(z2 3z + 1)2

    z2

    =

    (z +

    1z 3

    )2

    = (z + z 3)2 .

    |z2 3z + 1| = |z + z 3|,

    ,

    z + z . ,

    z + z < 3, z + z = 2Re(z) 2|z| = 2.

    2 ( )

    () |z| > 1.

    |z| > 1 z9

    > 1

    11 10zi11z + 10i

    > 1

    |11 10zi|2 > |11z + 10i|2

    ..........................

    21 > 21|z|2

    |z| < 1 .

    |z| < 1 - . 1.

    32

  • :

    23 ( ) - :

    f (x) =

    1, x < 00, x = 01, x > 0

    g(x) = x2 2x + 4 .

    f g g f .

    http://www.mathematica.gr/forum/viewtopic.php?f=52&t=38484

    ( ) D ( f ) = D (g) =

    R . ,

    D ( f g) ,D (g f ) R (I) .

    x R . x D (g) x D ( f ) f (x) {1, 0, 1} R

    f (x) R = D (g) .

    g(x) = x2 2x + 4 R = D ( f ) .

    R D ( f g) , D (g f ) (II) .

    (I) (II)

    D ( f g) = D (g f ) = R .

    x R ( f g) (x) = f (g(x)) .

    g(x) = x2 2x + 4 = (x 1)2 + 3 > 0 , x R

    ( f g) (x) = f (g(x)) = 1 .

    f g . (g f ) (x) = g ( f (x)) , x R . x R : x < 0, (g f ) (x) = g ( f (x)) = g(1) = 7 . x = 0, (g f ) (x) = g ( f (0)) = g(0) = 4 . x > 0, (g f ) (x) = g ( f (x)) = g(1) = 3 .,

    (g f ) (x) =

    7 , x < 04 , x = 03 , x > 0

    g f (, 0) (0,+) x = 0

    limx0

    (g f ) (x) = 7 , 4 = g(0) , 3 = limx0+

    (g f ) (x).

    24 ( ) x > 0 f

    f (e f (x)) = ln x.

    f .

    http://www.mathematica.gr/forum/viewtopic.php?f=52&t=39318

    1 ( )

    g (x) = f (x) + ln x, x > 0

    1 - 1.

    g(e f (x)

    )= f

    (e f (x)

    )+ ln e f (x)

    = ln x + f (x)

    = g (x)11

    e f (x) = x

    f (x) = ln x .

    2 ( ) -

    g ( ) g = g1, g (, .. g(x) > x g1

    x = g1(g(x)) > g1(x) = g(x) > x,

    ). : E -

    ,

    33

    http://www.mathematica.gr/forum/viewtopic.php?f=52&t=38484http://www.mathematica.gr/forum/viewtopic.php?f=52&t=39318
  • f E f = E1.

    E f = f 1 E1 = (E f )1,

    E f = , f = E1 = ln .

    3 ( )

    x0 > 0 f (x0) > ln x0,

    e f (x0) > eln x0 e f (x0) > x0 .

    e f (x0) > 0 , x0 > 0 f (0,+).

    f(e f (x0)

    )> f (x0) ln x0 > f (x0)

    .

    x0 > 0 f (x0) 0.

    4 ( ) ex = k(x),

    ln x = k1(x).

    f (k( f (x))) = k1(x) .

    x = k(x)

    f (k( f (k(x)))) = x .

    f (k(x)) = g(x), g(g(x)) = x . g(g(x))

    f (ex) , 1 - 1,

    . g(x) = g1(x) - , g(x) = x .

    f (k(x)) = x f (x) = k1(x) f (x) = ln x .

    34

  • :

    25 ( ) - f : R R : f (x) = ex+ f (x), x R f (0) = 0.

    http://www.mathematica.gr/forum/viewtopic.php?f=53&t=41418

    1 ( ) -

    g (x) = f (x) x, x R, -

    g (0) = f (0) 0 = 0.

    f (x) = ex+ f (x) (g (x) + x) = ex+g(x)x g (x) = eg(x) 1 : (1) g (x) = eg(x) 1 : (2).(1) (2) g (x)

    (eg(x) 1

    )= g (x)

    (eg(x) 1

    )

    eg(x)g (x) + eg(x)(g (x)) = g (x) + (g (x)) (eg(x) + eg(x)

    )= (g (x) + g (x))

    eg(x) + eg(x) = g (x) + g (x) + c. x = 0 eg(0) + eg(0) = g (0) + g (0) + c c = 2. x R eg(x) + eg(x) = g (x) + g (x) + 2 : (3) ex x + 1,x R

    x = 0. eg(x) g (x)+ 1

    g (x) = 0. eg(x) g (x) + 1

    g (x) = 0. eg(x) + eg(x) g (x) + g (x) + 2

    g (x) = g (x) = 0. (3) x R

    g (x) = g (x) = 0,x R, x R g (x) = 0 f (x) x = 0 f (x) = x. .

    2 ( ) g(x) = f (x) x. g

    g(x) = f (x) = ( f (x) + 1)ex+ f (x)

    = ( f (x) + 1) f (x) = (e f (x)x + 1) f (x)= (1 eg(x))(1 + g(x)), g(0) = 0 (1)

    g , -

    2 r > 0 (a, b) a > 0, b > 0 g(a) = 0, g(b) = 0 g(x) , 0, x (a, b). ( g [0, a] a = 0).

    g(x) , 0 - g(x) , 0 g(a) = 0, g(c) = 0 ( Rolle g (a, b) Rolle g (a, c)). - r < 0. g x > 0 x < 0.

    g(x) > 0 R+ g(x) < 0, (2)

    g(x) < g(0) = 0 g(x) < 0 . - R

    g g(0) = 0. g(x) = 0, x R

    :

    1.

    a = 0.

    2. g(0) = f (0) 1 = e0+ f (0) 1 = 0.

    3. (2) (1)

    g(x) = (e0 eg(x))(1 + g(x))= g(x)eu(1 + g(x))

    -

    ex

    (1 + g(x)) = ex+ f (x) > 0.

    26 ( ) f : R R f (R) = R. C f + y = x + :

    () > 0.

    () ( ) C f 1 +.

    () f 1(x)+ < x x R.

    35

    http://www.mathematica.gr/forum/viewtopic.php?f=53&t=41418
  • http://www.mathematica.gr/forum/viewtopic.php?f=53&t=40954

    ( )

    () f : R R f

    x0 R f (x0) = 0 x < x0 f (x) < f (x0) = 0 f - (, x0] f R f (x) > 0, x R.

    f

    (x0, f (x0))

    y f (x0) = f (x0)(xx0) y = f (x0)(xx0)+ f (x0)

    limx+

    f (x0)(x x0) = + ( f (x0) > 0) g(x) = f (x0)(x x0)+ f (x0) lim

    x+g(x) = +

    , -

    f (x) g(x), x R, lim

    x+f (x) = +.

    limx+

    ( f (x) x ) = 0 h(x) = f (x)x lim

    x+h(x) = 0 -

    x = f (x)h(x) limx+

    ( f (x)h(x)) =+, lim

    x(x) = + -

    > 0.

    () f 1( f (x)) = x, x R x > 0

    f 1( f (x))x= 1 f

    1( f (x))f (x)

    f (x)

    x= 1

    limx+

    f (x)

    x= > 0 f

    1( f (x))f (x)

    =1

    f (x)x

    limx+

    f 1( f (x))f (x)

    = limx+

    1f (x)

    x

    =1.

    limx+

    f (x) = + u = f (x)

    limu+

    f 1(u)u=

    1 .

    f 1( f (x)) = x f 1( f (x)) 1

    f (x) =x f (x)

    limx+

    ( f (x)x) = -

    limx+

    ( f 1( f (x)) 1 f (x)) = limx+x f (x)

    =

    limu+

    ( f 1(u) 1u) = ,

    y = 1 x C f 1 +.

    () x f (x),

    f 1( f (x)) + < f (x) x + < f (x)

    h(x) = f (x) x

    limx+

    h(x) = 0

    h(x) = f (x) f - h h R, h(x) > 0. x0 R h(x0) > 0 - h lim

    x+h(x) = +

    h(x) 0 , x R (1)

    x0 R h(x0) = 0 - h x > x0 h(x) > h(x0) = 0, (1) h(x) < 0 , x R h - R lim

    x+h(x) = 0

    h(x) > 0, x R.

    36

    http://www.mathematica.gr/forum/viewtopic.php?f=53&t=40954
  • :

    27 ( )

    :

    1x

    1

    ext

    t2dt e (1 x) x > 0.

    http://www.mathematica.gr/forum/viewtopic.php?p=191552

    ( )

    1x

    1

    ext

    t2dt e (1 x)

    1x

    1

    ext

    (xt)2x dt e

    (1 x)x

    xt=u, du=xdt

    1

    x

    eu

    u2du e

    (1 x)x

    0

    e (1 x)x

    +

    x

    1

    eu

    u2du 0

    F(x) =e (1 x)

    x+

    x

    1

    eu

    u2du x > 0.

    F

    F(x) =

    e (1 x)

    x+

    x

    1

    eu

    u2du

    = e

    x2+

    ex

    x2=

    ex ex2

    F(x) 0 x 1. F - (0, 1] [1,+). - x = 1 F(1) = 0. F(x) 0 x > 0.

    1. ( Fermat) Chebyshev:

    b

    a

    f (x)g(x) dx 1b a

    b

    a

    f (x) dx b

    a

    g(x) dx,

    [a, b].

    2. ( ) ( -

    ):

    ext

    t2

    e

    t2

    .

    28 ( ) f : [1,+)(0,+) :

    f (1) = 1,

    f (1,+),

    x > 1 xx f (x) = f (x) f(x) ln x,

    x [1,+) x+1

    x

    f (t) dt < f (x).

    http://www.mathematica.gr/forum/viewtopic.php?f=54&t=37941

    ( )

    xx f (x) = f (x) f(x) ln x x > 1

    x f (x) ln x = f (x) ln x ln f (x) ln x > 0 x > 1, x f (x) = f (x) ln f (x).

    f (x) > 0 ,

    x =f (x)

    f (x)ln f (x) 2x = 2 f

    (x)

    f (x)ln f (x)

    (x2) = (ln2 f (x)),

    c R, ln2 f (x) = x2 + c, x > 1.

    f ,

    limx1+

    ln2 f (x) = ln2 f (1) = 0

    37

    http://www.mathematica.gr/forum/viewtopic.php?p=191552http://www.mathematica.gr/forum/viewtopic.php?f=54&t=37941http://www.mathematica.gr/forum/viewtopic.php?f=54&t=37941
  • limx1+

    (x2 + c) = 1 + c, c = 1

    ln2 f (x) = x2 1, x > 1. x > 1 x2 1 , 0, ln2 f (x) , 0 .

    ln f (x) =

    x2 1 ln f (x) =

    x2 1,

    f (x) = e

    x21 f (x) = e

    x21 x 1.

    g(x) =

    x

    1f (t)dt [x, x + 1]

    (x, x + 1) g(x + 1) g(x) = g() x+1

    x

    f (t)dt = f ()

    x+1

    x

    f (t) dt < f (x)

    f () < f (x), (1)

    x < .

    f (x) = e

    x21: f [1,+)

    f (x) = e

    x21 xx2 1

    > 0, x > 1

    (1).

    f (x) = e

    x21: f [1,+)

    f (x) = e

    x21 xx2 1

    < 0, x > 1

    .

    f (x) = e

    x21, x 1.

    38

  • :

    29 ( )

    f (x) =

    x2 ln

    x +73 c , x 1

    x log1x+ c , 0 < x < 1

    76

    , x = 0

    f x0 = 1.

    1. , - .

    2. .

    3. f x0 = 0 C f x = 0, x = 1 x

    x.

    http://www.mathematica.gr/forum/viewtopic.php?p=195414

    ( ) D( f ) = [0,+). f x = 1 , lim

    x1f (x) = f (1) R .

    limx1

    f (x) = limx1+

    f (x)

    limx1

    (x log

    1x+ c

    )= lim

    x1+

    (x2 ln

    x +

    73 c

    )

    c =73 c

    c =76

    ,

    ,

    f (x) =

    x2 ln

    x + 7/6 , x [1,+)

    (x ln x/ ln 10) + 7/6 , x (0, 1)

    7/6 , x = 0

    () x > 1

    f (x) = 2 x ln

    x + x2 (

    x)

    x

    = 2 x ln

    x +x

    2> 0

    f

    [1,+) . , x (0, 1)

    f (x) = ln x + 1

    ln 10

    f (x) < 0 x (1e, 1

    )

    f (x) = 0 x =1e

    f (x) > 0 x (0, 1

    e

    ).

    limx0

    x ln x = limx0

    ln x

    1/xD.L.H==== lim

    x0

    1/x

    1/x2

    = limx0

    (x) = 0 .

    , f x = 0 f -

    [1e, 1

    ]

    [0, 1

    e

    ] -

    x = 1e

    f(1e

    )=

    1e ln 10 +

    76

    x = 1 f (1) = 76 .

    , f (x) f (0) = 76 , x 0 , f x = 0 , f (0) = 76 .

    : f - x = 1 [0,+) , f (1) = 0 f

    39

    http://www.mathematica.gr/forum/viewtopic.php?p=195414
  • .

    limx1

    f (x) f (1)x 1

    = limx1

    x ln x

    ln 10 (x 1)

    = 1

    ln 10limx1

    x ln x 1 ln 1x 1

    = 1

    ln 10

    [d

    dx(x ln x)

    ]

    x=1

    = 1ln 10

    [ln x + 1

    ]x=1

    = 1

    ln 10,

    limx1+

    f (x) f (1)x 1

    = limx1+

    x2 ln

    x

    x 1

    = limx1+

    x2 ln

    x 12 ln1

    x 1

    =

    [d

    dx

    (x2 ln

    x)]

    x=1

    =

    [2 x ln

    x +

    x

    2

    ]

    x=1

    =12.

    x = 0 [0,+). -, x = 1

    e [0,+), f

    f ( 1

    e

    )= 0 ( Fermat) .

    , x = 1e -

    f (0, 1) f [0, 1], (0, 1), f (0) = f (1) = 76 f (0, 1). (-, , -

    f (x) = 0 , x (0, 1).) f (x) > 0 , x 0 .

    ()

    f ([0,+)) =[f (0), f

    (1e

    )]

    [f (1), f

    (1e

    )]

    [f (1), lim

    x+f (x)

    )

    f (0) =76, f

    (1e

    )=

    1e ln 10

    +76, f (1) =

    76,

    limx+

    f (x) = limx+

    (x2 ln

    x +

    76

    )= + .

    f ([0,+)) =[76 ,+

    ).

    1. ), f -

    x = 0 .

    E =

    1

    0f (x) dx =

    1/2

    0f (x) dx +

    1

    1/2f (x) dx

    = I1 + I2 .

    , , -

    76 .

    I1 =

    1/2

    0f (x) dx = lim

    a0+

    1/2

    a

    f (x) dx

    1/2

    a

    f (x) dx =

    1/2

    a

    ( x ln x

    ln 10+

    76

    )dx

    =

    [ 1/2

    a

    x ln x

    ln 10dx +

    1/2

    a

    76

    dx

    ]=

    [ x

    2 ln x

    2 ln 10

    ]1/2

    a

    +

    1/2

    a

    x2

    2 ln 10 1

    xdx +

    76

    (12 a

    ) =[

    ln 28 ln 10

    +a2 ln a

    2 ln 10+

    1/2

    a

    x

    2 ln 10dx +

    76

    (12 a

    )]=

    ln 2

    8 ln 10+

    a2 ln a

    2 ln 10+

    [x2

    4 ln 10

    ]1/2

    a

    +76

    (12 a

    )

    I1 =2 ln 2 + 116 ln 10

    +712

    I2 =

    1

    1/2f (x) dx

    = limb1

    b

    1/2f (x) dx

    = limb1

    b

    1/2

    ( x ln x

    ln 10+

    76

    )dx

    = limb1

    [ b

    1/2

    x ln x

    ln 10dx +

    b

    1/2

    76

    dx

    ]

    = limb1

    [ x

    2 ln x

    2 ln 10

    ]b

    1/2+

    b

    1/2

    x2

    2 ln 10 1

    xdx +

    76

    (b 1

    2

    )

    = limb1

    [

    ln 28 ln 10

    b2 ln b

    2 ln 10+

    b

    1/2

    x

    2 ln 10dx +

    76

    (b

    12

    )]

    = limb1

    ln 2

    8 ln 10 b

    2 ln b

    2 ln 10+

    [x2

    4 ln 10

    ]b

    1/2+

    76

    (b 1

    2

    )

    = limb1

    [ ln 28 ln 10

    b2 ln b

    2 ln 10 1

    16 ln 10+

    b2

    4 ln 10+

    76

    (b 1

    2

    )]

    = 2 ln 2 + 116 ln 10

    +712.

    40

  • 30 ( ) - x, y R,

    (2x + 3y)

    e24y + y2 + (1 x)ex + 1 =

    (ex + y)

    x2 + y2 + 2xy + x + 3,

    x + 2y = 1.

    http://www.mathematica.gr/forum/viewtopic.php?f=55&t=40496

    ( )

    (3, 2) ( y , 2) x = 1 2y, :

    (e12y + y

    )2+ 1

    e12y + y=

    (2 y)2 + 12 y

    (1)

    f (x) =

    x2+1x

    ,

    R f (x) = 1x2

    x2+1< 0

    x R f (, 0), (0,+).

    (1) e12y + y, 2 y (1) :

    f (e12y + y) = f (2 y)

    f

    , 1 1

    e12y + y = 2 y

    e12y = 1 + (1 2y).

    ex 1 + x - x = 0 1 2y = 0 y = 12 x = 0 (x, y) =

    (0, 12

    )

    .

    41

    http://www.mathematica.gr/forum/viewtopic.php?f=55&t=40496
  • :

    31 ( )

    f : R R (

    f (x) x2) (

    f (x) 1)= 1, x R

    f (0) = 1, f (0) = 0.

    f .

    http://www.mathematica.gr/forum/viewtopic.php?f=56&t=41822

    ( ) g(x) = f (x) x2 :

    g(0) = 1, g(0) = 0 g(x)(g(x) + 1) = 1, g.

    g(x) , 0, g(0) > 0

    g . g(x) > 0 .

    g(x) + 1 =1

    g(x)= g(x)g(x) + g(x) =

    g(x)

    g(x)

    = 12

    (g(x))2 + g(x) = ln g(x) + c.

    c = 1. , ln A A 1,

    12

    (g(x))2 0 = g(x) 0 = g ,

    g(x) = 1 x. f (x) = x2 + 1, .

    32 ( ) 0 < a < b f : [a, b] R -,

    ab

    b

    a

    f (x)

    x2dx 0.

    g(x) > 0 , [a, b],

    g(b) > g(a) 1b

    b

    a

    f (t)dt a b

    a

    f (t)

    t2dt > 0

    b

    a

    f (t)dt > ab

    b

    a

    f (t)

    t2dt.

    2 ( ) -

    Chebychev. -

    ( f ) ( 1x2

    ).

    :

    42

    http://www.mathematica.gr/forum/viewtopic.php?f=56&t=41822http://www.mathematica.gr/forum/viewtopic.php?f=56&t=38844
  • b

    a

    f (x)

    x2dx 0. - f M(x0, f (x0) Ox A.

    () AB 1

    | ln x0|.

    () AB 1, - M f .

    http://www.mathematica.gr/forum/viewtopic.php?f=69&t=41743

    (dr.tasos)

    ()

    y f (x0) = f (x0)(x x0),

    A(x0 1ln x0 , 0

    )

    (AB) =

    (x0 x0

    1ln x0

    )2 =1

    | ln x0|.

    ()

    | ln x0| = 1 x = e x = e1.

    M1(e, ee) M2

    (( 1

    e)1e ), ( 1

    e)1e

    ). -

    y ee = ee(x x0)

    y = (1e

    ) 1e

    (x x0) +(1e

    ) 1e

    .

    34 ( )

    x, y R, -:

    A =2014

    x2 + y2 4x + 2y + 58.

    http://www.mathematica.gr/...php?f=69&t=42368&p=198072#p198072

    ( )

    A =2014

    (x2 2 2x + 4) + (y2 + 1 2y + 1) + 53

    =2014

    (x 2)2 + (y + 1)2 + 53

    201453= 38

    x = 2 y = 1

    44

    http://www.mathematica.gr/forum/viewtopic.php?f=69&t=41743http://www.mathematica.gr/forum/viewtopic.php?f=69&t=42368&p=198072
  • , , :

    35 ( ) a, b > 0, :

    (1 +

    a

    b

    )2014+

    (1 +

    b

    a

    )2014 22015.

    http://www.mathematica.gr/forum/viewtopic.php?f=109&t=41776

    1 ( )

    - :

    (1 +

    b

    )2014+

    (1 +

    b

    a

    )2014 2

    [(1 +

    b

    ) (1 +

    b

    a

    )]2014

    = 2

    (a

    b+

    b

    a+ 2

    )2014

    = 2

    a

    b+

    b

    a

    2

    2014

    = 2

    a

    b+

    b

    a

    2014

    2 22014 = 22015.

    2 ( ) a

    b= k

    b

    a=

    1k

    k > 0. -

    (1 + k)2014 +(1 + 1

    k

    )2014

    2

    (1 + k)2014(1 +

    1k

    )2014.

    :

    (1 + k)2014(1 +

    1k

    )2014 22014

    ((1 + k)

    (1 +

    1k

    ))1007 22014

    (1 + k)

    (1 +

    1k

    ) 22

    (k + 1)2 4k,

    (a + b)2 4ab.

    3( ) :

    (1 +

    a

    b

    )2014+

    (1 +

    b

    a

    ) 2

    (1 +

    a

    b

    )1007 (1 +

    b

    a

    )1007

    = 2[(1 +

    a

    b

    ) (1 +

    b

    a

    )]1007

    = 2

    (1 +

    a

    b+

    b

    a+

    ab

    ab

    )1007

    = 2

    (2 +

    a

    b+

    b

    a

    )1007

    2 (2 + 2)1007

    = 2 41007 = 2 22014 = 22015.

    a = b,

    a, b , 0.

    36 ( )

    xn =

    n +

    n2 1 n = 1, 2, . . . .

    1x1+

    1x2+ . . . +

    1x49

    .

    http://www.mathematica.gr/forum/viewtopic.php?f=109&t=40916

    ( )

    n +

    n2 1 = n + 12+

    n 12+ 2

    n 12

    n + 12

    =

    n 12+

    n + 12

    2

    .

    xn =

    n+1+

    n12

    ,

    1xn=

    2

    n + 1 +

    n 1

    =

    22

    (n + 1

    n 1

    ).

    45

    http://www.mathematica.gr/forum/viewtopic.php?f=109&t=41776http://www.mathematica.gr/forum/viewtopic.php?f=109&t=40916
  • 1x1+

    1x2+ . . . +

    1x49=

    22

    ((2 0) + (

    3 1) + + (

    50

    48)

    )=

    22

    (52 1 + 7

    )=

    5 + 32.

    46

  • :

    37 ( KARKAR) - A, B - CD. B , CD, P, T . PC T D S , CA DA L,N. S L = S N.

    http://www.mathematica.gr/forum/viewtopic.php?f=110&t=37822

    1 ( ) M ABCD M CD ( M -

    AB ( ) (O) , (K)

    MC, MD (O) , (K) ).

    LAD, BAM,NAC CD LN, M CD, B

    LN, S B S LN.

    S DC = DT B (, )

    = CBD (. )

    S CD = CPB (, )

    = BCD (. ).

    S DC = BDC (DS ) = (DB) S DB - DS S DB DCS B

    CDPT S BPT .

    S LN S B -

    , (S L) = (S N)

    .

    38 ( ) ABC AB , AC . (C) ABC, H , O (C). M BC. AM (C) N (C) AM P.

    () AP, BC,OH AH = HN.

    () ;

    47

    http://www.mathematica.gr/forum/viewtopic.php?f=110&t=37822
  • http://www.mathematica.gr/forum/viewtopic.php?f=110&t=38382

    1 ( )

    :

    : O

    . AN .

    O

    ( ) -

    H

    HG = 2 OG. AH -

    O

    AN M.

    OM

    (O) B,C

    A .

    :

    AH -

    D AD OM

    BC. (AHG), (GOM) - : AH = 2 OM. H ABC. -

    H AN :

    AH = HN.

    :

    .

    AN -

    .

    AN

    -

    . ,

    .

    :

    BC,OH, AP

    ,

    , .

    2 ( )

    .

    : ABC (AB , AC)

    M BC. P (

    A) (O)

    ABC (K) AM, - PM H

    ABC.

    48

    http://www.mathematica.gr/forum/viewtopic.php?f=110&t=38382
  • H PM AD (ADBC) E PM (O) .

    MPA ============== 900

    EPA = 900 AE (O)

    :

    ECAC (1)

    OMBC ( BC (O)) ADBC

    OM ADAHE ( O AE)============ M

    M BC======= BHCE

    ( )

    BH EC(1) BHAC

    ADBC H ABC

    .

    P,H, M .

    AH = HNOA=ON=RO====== AHNO ()

    OHAN ( )

    OHAM. (1)

    APMHP, AM - (K) MBAH, H ABC,

    AP,OH,CB AHM

    T .

    :

    OM, AP, BC (

    T ), AHT M ( H - ABC) MHPAT ( AM - (K)) H

    AT M (

    ) T HO -

    , T HOAN O ABC AN -

    (O) T HO AN

    HA = HN .

    3 ( ) ,

    H1 MP AH AK = KH1, KH1MO . -

    AH1 = 2KH1 = 2OM = AH H H1 TOAN HA = HN.

    AH = HN T OH,CB. AT M MH

    , P MH AT MPA = 90.

    49

  • 50

  • , , : -

    39 ( ) f : Z+ Z+,

    f (x2 + f (y)) = x f (x) + y,

    x, y Z+.

    http://www.mathematica.gr/forum/viewtopic.php?f=111&t=35047

    ( )

    x = 1, f (1 + f (y)) = f (1) + y y Z+. f (1) = a.

    f (1 + f (x)) = a + x (1)

    x Z+.

    f ((a + 1)n) = (a + 1)n (2)

    n N. n = 1

    f (a + 1) = a + 1 f (1 + f (1)) = f (1) + 1

    (1). f ((a + 1)n) = (a + 1)n. (1)

    f (1 + f ((a + 1)n)) = a + (a + 1)n

    f (na + n + 1) = a + na + n

    (1) :

    f (1 + f (na + n + 1)) = a + na + n + 1

    f (1 + a + na + n) = a(n + 1) + n + 1

    f ((a + 1)n) = (a + 1)n.

    f (1 + f (a + 1)) = a + a + 1 f (a + 2) = 2a + 1.

    x = a , y = a + 2 ,

    f (a2 + f (a + 2)) = a f (a) + a + 2

    f (a2 + 2a + 1) = a f (a) + a + 2

    f ((a + 1)(a + 1)) = a f (a) + a + 2(2)

    (a + 1)(a + 1) = a f (a) + a + 2

    f (a) = a + 1 1a.

    a, f (a) N, a = 1, f (1) = 1. f (n) = n n N. n = 1 f (1) = 1, . f (n) = n. (1)

    f (1 + f (n)) = f (1) + n f (n + 1) = n + 1.

    f (x) = x , x Z+.

    40 ( ) a, b, c > 0 -

    (a + b + c)

    (1a+

    1b+

    1c

    ) 9

    a2 + b2 + c2

    ab + bc + ca.

    http://www.mathematica.gr/forum/viewtopic.php?f=111&t=12183#p66050

    ( ) -

    , a + b + c = 9.

    a2 + b2 + c2 = 27 + 6t2

    t [0, 1]. t = 0, , a = b = c = 3. 0 < t 1. (x, y, z) a, b, c, (.

    )

    3 2t x 3 + 2t (2)

    x = 3 + 2t y = z = 3 t x = 3 2t y = z = 3 + t. ,

    1a+

    1b+

    1c

    9 + 2t2

    9 t2.

    , ,

    1x=

    13 + 2t

    +3 + 2t x(3 + 2t)x

    51

    http://www.mathematica.gr/forum/viewtopic.php?f=111&t=35047http://www.mathematica.gr/forum/viewtopic.php?f=111&t=12183#p66080
  • x (0, 9)

    33 + 2t

    +1

    3 + 2t

    cyclic

    3 + 2t aa

    9 + 2t2

    9 t2.

    (2),

    Cauchy-Schwarz

    cyclic

    3 + 2t aa

    cyclic

    (3 + 2t a)2

    cyclic

    a(3 + 2t a)=

    6t3 t

    .

    , ,

    33 + 2t

    +6t

    (3 + 2t)(3 t)

    9 + 2t2

    9 t2,

    3t + 9(3 + 2t)(3 t)

    9 + 2t2

    9 t2.

    , -

    9(t + 3)2(9 t2) (9 + 2t2)(3 + 2t)2(3 t)2.

    ,

    t2(3 t)(8t3 9t + 27) 0

    0 < t 1.:

    Cauchy-Schwarz

    :

    http://www.mathematica.gr/forum/viewtopic.php?p=165244#p165244

    52

    http://www.mathematica.gr/forum/viewtopic.php?p=165244
  • :

    41 ( parmenides51.) - ABCD (O,R) - (I, r). OI = x

    1

    r2=

    1

    (R + x)2+

    1

    R x)2.

    http://www.mathematica.gr/forum/viewtopic.php?f=112&t=42144

    ( .) ABCD

    ,

    B + D = 180 IBC + IDC = B2+D

    2= 90 (1)

    Z L, C, LZ = KB KIB,KIZ

    (1), IDZ -

    DIZ = 90 (2)

    ,

    ( )

    1

    (IL)2=

    1

    (IZ)2+

    1

    (ID)2(3)

    (3), IL = r IZ = IB

    1

    r2=

    1

    (IB)2+

    1

    (ID)2(4)

    E (O) DI F (O) BI., AOE = D AOF = B

    AOE + AOF = 180(5)

    (5) E,O, F -

    (IB)(IF) = (ID)(IE) = R2 x2 (6)

    (6)

    1

    (IB)2=

    (IF)2

    (R2 x2)2(7)

    1

    (ID)2=

    (IE)2

    (R2 x2)2(8)

    (4), (7), (8)

    1

    r2=

    (IE)2 + (IF)2

    (R2 x2)2(9)

    IEF,

    ,

    (IE)2 + (IF)2 = 2(OI)2 +(EF)2

    2= 2(R2 + x2) (10)

    (9), (10)

    1

    r2=

    2(R2 + x2)

    (R2 x2)2=

    (R + x)2 + (R x)2

    (R + x)2 (R x)2(11)

    (11)

    1

    r2=

    1

    (R + x)2+

    1

    (R x)2

    .

    53

    http://www.mathematica.gr/forum/viewtopic.php?f=112&t=42144
  • 42 ( .) -

    ABC (O) (K), AD. - BE, CF, DZ , E (K)AC, F (K)AB, Z (K) (O) Z , A.

    http://www.mathematica.gr/forum/viewtopic.php?f=112&t=42240

    ( .) -

    (K) AEDF AFE = ADE (1) DAC DE AC

    ADE = C (2) (1), (2) AFE = C , -

    BCEF (L).

    AZ, EF, BC, -

    (O), (K), (L), ,

    , S .

    AEDFBC

    A. S BPC , P BE CF.

    CF , M, F, P, C ,

    M AS CF. N (K) CZ ZNF =

    ZAF ZAB = ZCB FN BC FN AD (3) (3) , -

    (K) F, N, T, AD.

    AFDN

    FN, T

    (K) , Z. AFDN -

    .

    CM M, F, P, C,

    ZD P BE CF, M F, C .

    54

    http://www.mathematica.gr/forum/viewtopic.php?f=112&t=42240
  • :

    43 ( ) - 100 . 30% - , .

    http://www.mathematica.gr/forum/viewtopic.php?p=190087

    ( )

    : 5 3 , - 3 , , .

    : ,

    , .

    () ABC - D, E -

    .

    ADB, BDC,CDA

    D. , -

    AEB, BEC,CEA . -

    .

    () ABCD

    E .

    -

    . E ABC CDA.

    , ,

    .

    .

    () ,

    . -

    ,

    -.

    A, B,C .

    ACDE. -

    ,

    . ,

    .

    -

    .

    :

    -

    . (1005

    )

    ,

    . -

    / (972

    ).

    3

    (1005

    )

    (972

    )

    100 -.

    100 (1003

    ).

    :

    3

    (1005

    )

    (972

    )(1003

    ) = 3100 99 98 97 96 2 6120 97 96 100 99 98

    = 30%

    .

    44 ( ) - p1 < p2 < ... < p99

    p1 + p2, p2 + p3, . . . , p98 + p99, p99 + p1

    ;

    http://www.mathematica.gr/forum/viewtopic.php?p=192844

    1 ( ) . -

    p1 < p2 < < p99

    55

    http://www.mathematica.gr/forum/viewtopic.php?p=190087http://www.mathematica.gr/forum/viewtopic.php?p=192844
  • p1 + p2 = n21 , p2 + p3 = n

    22, . . . , p99 + p1 = n

    299

    n1, . . . , n99 .

    p1 + p2 + + p99 =n21 + n

    22 + + n

    299

    2 pi . ,

    ni

    .

    pi . p1.

    p1 = 2, , n1, n99 , n2, ..., n98 .

    p1 + n22 + n

    24 + ... + n

    298 =

    n21 + n22 + + n

    299

    2

    p1 =n21 n

    22 + n

    23 n

    24 + n

    298 + n

    299

    2.

    n21 n22 + n

    23 n

    24 + n

    298 + n

    299 = 4.

    n22 + n23 n

    24 + n

    298

    4, n21 n299 1 mod 4.

    4 - 2, .

    2 ( ) ,

    2 4k + 1, 4k + 3, k N.

    , 4n 4n + 1, n N. :

    1: p1 = 2 p1 + p2 ,

    p2 = 4m2 + 3 ( p2 = 4m2 + 1, p1 + p2 = 2 + 4m2 + 1 =4 + 3 - ).

    , p2 = 4m2 + 3, p2 + p3 , p3 = 4m3 + 1 (- p3 = 4m3 + 3 , p2 + p3 =4 + 2 ).

    , :

    p3 = 4m3 + 1, p4 = 4m4 + 3, p5 = 4m5 + 1, . . . , p99 = 4m99 + 1.

    p99 + p1 = 4m99 + 1 + 2 = .4 + 3

    .

    2: p1 = 4m1 + 1. p1 + p2 ,

    p2 = 4m2 + 3, p2 + p3 , p3 = 4m3 + 1 , , p99 = 4m99 + 1. -

    p99 + p1 = 4m99 + 1 + 4m1 + 1 = .4 + 2,

    .

    3: p1 = 4m1 + 3. p1 + p2 ,

    p2 = 4m2 + 1, p2 + p3 , p3 = 4m3 + 3, -, p99 = 4m99 + 3.

    p99 + p1 = 4m99 + 3 + 4m1 + 3 = 4(m99 + m1) + 4 + 2

    = .4 + 2

    .

    .

    3 ( )

    .

    p1 > 2. .

    4a1, 4a2, . . . , 4a99 (

    4).

    (p1 + p2) + (p2 + p3) + + (p99 + p1)= 4a1 + 4a2 + + 4a99,

    p1 + p2 + p3 + + p99 = 2(a1 + a2 + a3 + + a99)

    99 .

    p1 = 2. p1 + p2, p99 + p1.

    4a1 + 1, 4a99 + 1 ( -

    8k + 1 4m + 1).

    56

  • ,

    (p1 + p2) + (p2 + p3) + + (p99 + p1)= 4a1 + 1 + 4a2 + 4a3 + 4a4 + + 4a99 + 1.

    p1 + p2 + + p99 = 2(a1 + a2 + a99) + 1

    , 98 -

    .

    : - ,

    -

    viewtopic.php?p=185428 ( 2 3 )

    .

    57

    http://www.mathematica.gr/forum/viewtopic.php?p=185428
  • :

    45 ( Kyiv Taras 2013) n n A, B n n C

    AX + YB = C

    . n n C

    A2013X + YB2013 = C

    .

    http://www.mathematica.gr/forum/viewtopic.php?f=59&t=40087

    ( )

    A, B . -

    r1, r2

    n.

    A = Q1

    (Ir1 O

    O O

    )P1 B = Q2

    (Ir2 O

    O O

    )P2

    P1, P2,Q1,Q2 .

    S 1 =

    (O O

    O Inr1

    )Q11 S 2 = P

    12

    (O O

    O Inr2

    ).

    S 1A = BS 2 = O. C = Q1P2 -

    X1, Y1

    AX1 + Y1B = Q1P2,

    S 1 S 2

    O = (S 1Q1)(P2S 2) =

    (O O

    O Inr1

    ) (O O

    O Inr2

    ).

    n r1, n r2 > 0. ,

    A ( B). C Z

    A2013Z = C. (Z,O)

    .

    46 ( ) - a R f : (a,+) R, (a, b) b R a < b.

    limx+

    f (x + 1) f (x)xk

    ,

    k N,

    limx+

    f (x)

    xk+1=

    1k + 1

    limx+

    f (x + 1) f (x)xk

    http://www.mathematica.gr/forum/viewtopic.php?f=59&t=39843

    ( )

    an = f (n)

    limn

    an

    nk+1.

    Stolz

    limn

    an

    nk+1= lim

    n

    an an1nk+1 (n 1)k+1

    = limn an an1k

    t=1

    (k+1

    t

    )(1)k+1tnt

    =1(

    k+1k

    ) limn

    an an1nk

    =1

    k + 1limn

    an an1nk

    .

    . ( )

    58

    http://www.mathematica.gr/forum/viewtopic.php?f=59&t=40087http://www.mathematica.gr/forum/viewtopic.php?f=59&t=39843
  • :

    47 ( ) V - Rnn , W Rnn - Rnn V,W .

    http://www.mathematica.gr/forum/viewtopic.php?f=10&t=42265

    ( )

    () V : -

    .

    () W : ( - ).

    48 ( ) p(x) - 2.

    A = {x R \ Q : p(x) Q}

    R.

    http://www.mathematica.gr/forum/viewtopic.php?f=10&t=40333

    ( ) -

    :

    1: f Q [x] n xn f

    (1x

    )

    .

    :. h, s m, k

    xn f

    (1x

    )= h (x) s (x)

    1xn

    f (x) = h

    (1x

    )s

    (1x

    )

    f (x) = xmh

    (1x

    )xk s

    (1x

    ).

    f (x) = h1 (x) s1 (x)

    h1 (x) = xmh

    (1x

    ) s1 (x) = x

    k s

    (1x

    ).

    2:

    f (x) = anxn+ + a0

    Z[x] p

    an

    g (x) = anxn+ + a0 +

    1p

    .

    : 1

    xng

    (1x

    )= an + an1x + +

    (a0 +

    1p

    )xn

    .

    xng

    (1x

    )=

    1p

    ((pa0 + 1) x

    n+ pa1x

    n1+ + pan

    )

    (pa0 + 1) xn+ pa1x

    n1+ + pan

    Eisenstein: - p -

    p2 p

    an.

    : (a, b). p(x) -

    c, d a < c < d < b p (c) , p (d).

    59

    http://www.mathematica.gr/forum/viewtopic.php?f=10&t=42265http://www.mathematica.gr/forum/viewtopic.php?f=10&t=40330
  • s = p(c)+p(d)

    2 .

    p(c), p(d)

    (p (c) s) (p (d) s) < 0.

    q(x) = p(x) s. - :

    q (x) =1r

    (anx

    n+ ... + a0

    )

    a0, . . . , an . -

    p1 < p2 < < pk <

    an. 2 -

    anxn+ + a0 +

    1pk

    .

    qk (x) =1r

    (anx

    n+ + a0 +

    1pk

    )= q (x) +

    1rpk Q [x]

    .

    1rpk

    qk (c) = q (c) +1

    rpk q (c)

    qk (d) = q (d) +1

    rpk q (d) .

    k qk (c) , qk (d)

    q(c), q(d)

    Bolzano qk(x) t c, d (a, b).

    :

    () qk(x)

    1 t ,

    () qk(t) = 0

    p (t) s +1

    rpk= 0

    p (t) = s 1rpk Q

    p -

    .

    60

  • : -

    49 ( ) f : [0, 1] R,

    f (x) =

    1

    0sin

    (x + f 2(t)

    )dt, x [0, 1].

    http://www.mathematica.gr/forum/viewtopic.php?f=9&t=37825

    ( ) -

    K [0, 1] sin(.), cos(.) ||.||.

    T : K C[0, 1], (T f )(x) = 1

    0sin

    (x + f 2(t)

    )dt.

    T .

    ,

    1

    0sin

    (x + f 2(t)

    )dt =

    ( 1

    0cos f 2(t) dt

    )sin x +

    ( 1

    0sin f 2(t) dt

    )cos x =

    a sin x + b cos x

    T f K. |a| 1, |b| 1

    ||T f || = ||a sin(.) + b cos(.)|| =

    a2 + b2 2,

    {||T f || : f : [0, 1] R }

    -

    .

    T -

    K.

    ( Schauder), T , .

    50 ( ) an .

    {

    an

    m: n.m N

    }

    (0,+).

    http://www.mathematica.gr/forum/viewtopic.php?f=9&t=41661

    ( ) x > 0 0 < < x. = x = x + .

    bn = n cn = n.

    k n k bn+1 < cn. k >

    .

    A = (bk, ck)

    (bk+1, ck+1)

    A = (bk,+) . A an (an) , - m an (bm, cm) .

    m (x ) < an < m (x + ) ,

    an

    m x

    < . .

    61

    http://www.mathematica.gr/forum/viewtopic.php?f=9&t=37825http://en.wikipedia.org/wiki/Schauder_fixed_point_theoremhttp://www.mathematica.gr/forum/viewtopic.php?f=9&t=41661
  • :

    51 ( )

    = OA , = OB = O

    3,

    (~, ~

    )=

    (~, ~ ) = (~, ~ ) = 3.

    A =( ( ( ))) ( ) .

    http://www.mathematica.gr/forum/viewtopic.php?f=11&t=41083

    ( )

    ( ) = ( ) ( ) =12 .

    ( ( )) = ( 12

    )

    =12

    = .

    A = ( ) ( )

    = (( ) )

    = ( ( ))

    =

    [( ) ( )

    ]

    =

    ( 12 1

    2

    )

    =12 1

    2

    =14 1

    2= 1

    4.

    52 ( ) M

    x2

    2+

    y2

    2= 1 , , R ,

    , MA MB, . - A B,

    2

    x2+2

    y2= 1 .

    http://www.mathematica.gr/forum/viewtopic.php?f=11&t=42673

    1 ( ) M(a cos t, b sin t), t [0, 2).

    A(a cos t, 0), B(0, b sin t). P(x0, y0)

    A B,

    AB :xx0

    a2+

    yy0

    a2= 1.

    A, B AB, a cos tx0

    a2= 1 cos t =

    a

    x0

    b sin tx0

    b2= 1 sin t =

    b

    y0.

    cos2 t + sin2 t = 1 a2

    x20

    +b2

    y20

    = 1,

    P 2

    x2+2

    y2= 1.

    62

    http://www.mathematica.gr/forum/viewtopic.php?f=11&t=41083 http://www.mathematica.gr/forum/viewtopic.php?f=11&t=42673
  • :

    53 ( ) 2 -, 2 .

    http://www.mathematica.gr/forum/viewtopic.php?f=63&t=41369#p192805

    ( ) k

    ,

    k2 = (n + 1)3 n3 = 3n2 + 3n + 1,

    n. , :

    4k2 = 12n2 + 12n + 4

    4k2 1 = 12n2 + 12n + 3 (2k 1)(2k + 1) = 3(2n + 1)2

    2k 1 2k + 1 . , -

    () ,

    .

    2k + 1 = (2m + 1)2

    m,

    2k = (2m + 1)2 1 = 4m (m + 1)

    k ,

    k2 = 3n (n + 1) 1,

    n (n + 1) .,

    2k 1 = (2m + 1)2,

    k = (m + 1)2 + m2,

    .

    54 ( vzf) -. , 9.

    http://www.mathematica.gr/forum/viewtopic.php?f=63&t=31929#p147794

    1 ( )

    a1, a2, . . . , a17.

    ,

    a1, a2, . . . , a5,

    3, 0,1 2 3.

    , , -

    a1, a2, a3.

    , a4, a5, a6, a7, a8,

    3, ... , 17

    5 3.

    0, 3 6 9., 3

    5, - 9.: ( )

    Erdos-Ginzburg: - 2n 1 n n.

    63

    http://www.mathematica.gr/forum/viewtopic.php?f=63&t=41369#p192805http://www.mathematica.gr/forum/viewtopic.php?f=63&t=31929#p147794
  • :

    55 ( petros r). a - .

    I =

    +

    0

    sin x cos x

    x(x2 + a2)dx.

    http://www.mathematica.gr/forum/viewtopic.php?f=47&t=40995

    ( )

    :

    0

    sin 2xx

    dx =

    0

    sin y

    ydy =

    2.

    :

    0

    sin x cos x

    x(x2 + a2

    ) dx = 12

    0

    sin 2x

    x(x2 + a2

    ) dx

    =1

    2a2

    0

    sin 2x

    (1x x

    x2 + a2

    )dx

    =1

    2a2

    0

    sin 2xx

    dx 1

    2a2

    0

    x sin 2x

    x2 + a2dx

    =

    4a2 1

    2a2

    0

    x sin 2x

    x2 + a2dx

    =

    4a2 1

    4a2

    x sin 2x

    x2 + a2dx

    f (z) =ze2iz

    z2 + a2,

    . -

    | f (z)| =ze2i(x+iy)

    z2 + a2

    =|z|

    e2y (cos 2x + i sin 2x)

    z2 + a2

    =|z| e2yz2 + a2

    z 0.

    ( )

    z = ia

    Res ( f (z) , z = ia) = limzia

    (z ia) f (z) =e2a

    2.

    f (z)

    C -

    xx x1 = M x2 = M = M :

    C

    f (z) dz = 2i Res ( f (z) , z = ia) = ie2a.

    M +

    xe2ix

    x2 + a2dx = ie2a

    x (cos 2x + i sin 2x)

    x2 + a2dx = ie2a

    x sin 2x

    x2 + a2dx = e2a

    0

    sin x cos x

    x(x2 + a2

    ) dx = 4a2

    1

    4a2

    x sin 2x

    x2 + a2dx

    =

    4a2 1

    4a2e2a =

    4a2(1 e2a

    ).

    64

    http://www.mathematica.gr/forum/viewtopic.php?f=47&t=40995
  • 56 ( vz f ) - W - B , - h.

    http://www.mathematica.gr/forum/viewtopic.php?f=47&t=6626

    ( ) -

    ,

    B = GMm

    R2,

    m =BR2

    GM.

    h :

    GM

    R G

    M

    R + h,

    -

    :

    (G

    M

    RG M

    R + h

    )BR2

    GM= B

    Rh

    R + h.

    65

    http://www.mathematica.gr/forum/viewtopic.php?f=47&t=6626
  • :

    57 ( ) -

    K := cot 70 + 4 cos 70.

    http://www.mathematica.gr/forum/viewtopic.php?f=27&t=41829

    ( )

    K =sin 20

    cos 20+ 4 sin 20

    =sin 20 + 2 sin 40

    cos 20

    =

    3

    cos 20

    12

    sin 10 +

    32

    cos 10

    =

    3

    cos 20sin 70

    =

    3

    58 ( )

    f (x) =| sin 2x|

    | sin x| + | cos x| + 1.

    http://www.mathematica.gr/forum/viewtopic.php?f=27&t=39505

    ( ) -

    0 x =k

    2, k Z.

    | sin 2x| = 2| sin x|| cos x| | sin x|2 + | cos x|2 = 1

    x = k +

    4, k Z. -

    2| sin 2x| | sin x| + | cos x|

    2| sin 2x|2 1 + | sin 2x| 2| sin 2x|2 | sin 2x| 1 0 (| sin 2x| 1)(2| sin 2x| + 1) 0

    .

    | sin 2x| = 1 x = k +

    4, k Z.

    | sin 2x|+2| sin 2x| | sin x|+ | cos x|+ 1 f (x)

    1

    1 +2

    x = k +

    4, k Z.

    1

    1 +2.

    66

    http://www.mathematica.gr/forum/viewtopic.php?f=27&t=41829http://www.mathematica.gr/forum/viewtopic.php?f=27&t=39505
  • :

    59 ( - . ) (an)nN . :

    n=1

    an < ,

    n=1

    an1

    nn < .

    , ,:

    n=2

    an = s < ,

    n=2

    an1

    nn s + 2

    s.

    http://www.mathematica.gr/forum/viewtopic.php?f=61&t=31976

    ( ) n > 2 -

    an1

    nn 6

    (n 2)an + 2

    an

    n< an +

    2n

    an.

    n=2

    an1

    nn 6 s + 2

    n=2

    an

    n.

    Cauchy Schwarz

    n=2

    an

    n

    2

    6

    n=2

    1

    n2

    n=2

    an

    =2 6

    6s < s.

    -

    s.

    n=1

    1

    n2=2

    6

    n=2

    1

    n2 0, lim

    xf (x) = (*) -

    x0 < 0 f (x0) = 0, (3) u = x0

    f (0) = x0 + f (0) x0 = 0,

    . f (0) = 0.*[ lim

    xf (x) = a R, ,

    (3) f (a) = , , lim

    xf (x) = ].

    (3)

    f ( f (x)) = x (4),

    x (, 0]. x 0 f (x) < x.

    f ( f (x)) < f (x) < x, .

    x 0 f (x) > x. f ( f (x)) > f (x) > x, .

    67

    http://www.mathematica.gr/forum/viewtopic.php?f=61&t=31976http://www.mathematica.gr/forum/viewtopic.php?f=61&t=40597
  • f (x) = x (5),

    x 0. (1) y = 1

    2

    f

    (x 1

    2+ f (x)

    )= x + f (x 1

    2)

    f (x 12

    ) = x 12,

    x > 0, x = x +12

    f (x) = x,

    x > 0,

    f (x) = x x R,

    , (1).2 : f

    (, 0].

    limx

    f (x) = + ( , -) a > f (0) f (h(a)), h(a) < 0.

    1: f (0) > 0 . f x

    , x0 > 0 f (x0) = 0.

    (1) x, y

    x0

    2

    f

    (2

    x0

    2+ f (x0)

    )= x0 + f

    (2

    x0

    2

    ) x0 = 0,

    . f x

    , (1) y = x > 0

    f (2x + f (2x2) = 2x2 + f (2x) > 2x2.

    .

    f (x1) .

    h(x1)

    f (x1) = f (h(x1))

    f ( f (x1)) = f ( f (h(x1))) f ( f (x1)) = h(x1) + f (0) < 0,

    . 2: f (0) < 0 ., , f ( f (0)) > f (0), -

    , f ( f (0)) = f (0).

    f (0) = 0,

    f ( f (x)) = x (a),

    x 0. x1, x2 > 0 f (x1) = f (x2).

    f ( f (h(x1))) = f ( f (h(x2)) h(x1), h(x2) < 0 -

    h(x1) = h(x2) f (h(x1)) = f (h(x2)) x1 = x2. f 1 1 [0,+),

    .

    , f (x) > 0 x > 0.

    x1 > 0 x2 < 0

    f (x1) = f (x2) f ( f (x1)) = f ( f (x2)) = x2 < 0,

    .

    f -

    , , R,

    f (x) < 0 x > 0. x > 0 f ( f (x)) , x.

    f ( f ( f (x))) , f (x) f (x) , f (x),

    .

    f ( f (x)) = x (b),

    x R. (b) f -

    R f (x) = f 1(x) x R. , a > 0, b 0

    x, y x + y = a 2xy = b, (1)

    f (a + f (b)) = b + f (a) ().

    a, b > 0,

    f (a + b) = f ( f (h(a)) + f (h(b)) = h(b) + f ( f (h(a)) =

    = h(b) + h(a) = f 1(b) + f 1(a) = f (b) + f (a).

    f Cauchy (0,+), - f (x) = kx x > 0, k < 0. - f (x) = x x > 0.

    f (x) = x x < 0,

    f (x) = x x R,

    , (1).

    68

  • :

    61 ( ) y2 = 2px E . n 3 - A1A2A3 An E - . EA1, EA2, . . . , EAn B1, B2, . . . , Bn :

    EB1 + EB2 + EB3 + + EBn np.

    http://www.mathematica.gr/forum/viewtopic.php?f=62&t=39416

    ( ) p > 0, ( p < 0).

    Ak

    (z

    p

    2

    )n= rn(cos + i sin ),

    (0,

    2n

    ) r > 0 (r ).

    wn rn(cos + i sin ) = 0

    wk = r

    (cos

    2(k 1) + n

    + i sin2(k 1) +

    n

    )

    = r(cos k + i sin k)

    .

    n

    k=1

    wk = 0n

    k=1

    cos k = 0 (1)

    Bk k = 1, 2, . . . , n

    zk Arg(zk

    p

    2

    )= k.

    zk p

    2= rk(cos k + i sin k) zk = rk cos k +

    p

    2+ rk sin k

    k = 1, . . . , n. zk -,

    r2k sin2 k = 2p

    (rk cos k +

    p

    2

    )

    r2k sin2 k + r

    2k cos

    2 k = r2k cos

    2 k + 2prk cos k + p2

    r2k = (rk cos k + p)2

    rk>0,p>0 rk =p

    1 cos k

    rk =p(1 + cos k)

    sin2 k p(1 + cos k).

    1 cos k > 0 Ak x

    x.

    EBk =

    zk p

    2

    = rk p(1 + cos k).

    EB1 + EB2 + + EBn np + pn

    k=1

    cos k(1)= np.

    62 ( ) - ABCD. , O - :

    (AOB) = (BOC) = (COD) = (DOA).

    http://www.mathematica.gr/forum/viewtopic.php?f=62&t=38914

    1 ( ) -

    .

    O M.

    -

    : A (t, 0) t > 0, B (p, q) q > 0, C (t, 0) D (r, s) s < 0. O AC.

    69

    http://www.mathematica.gr/forum/viewtopic.php?f=62&t=39416http://www.mathematica.gr/forum/viewtopic.php?f=62&t=38914
  • CB

    qx + (p t) y + tq = 0

    O .

    BA

    qx + (p + t) y tq = 0

    O .

    DC

    sx + (r t) y + ts = 0

    O .

    DA

    sx + (r + t) y ts = 0

    O .

    M

    M DA, CB -

    BA, DC .

    -

    .

    (MCB) =12

    p q 1t 0 1x y 1

    , (MAB) =

    12

    p q 1t 0 1x y 1

    ,

    (MCD) = 12

    r s 1t 0 1x y 1

    , (MAD) =

    12

    r s 1t 0 1x y 1

    .

    qx py = 0 (1)

    sx ry = 0 (2)

    (q + s) x + (p r 2t) y = t (s + q) (3)

    :

    q p 0s r 0

    q + s p r 2t t (s + q)

    = 0

    t (s + q) (qr ps) = 0,

    t > 0

    (s + q) (qr ps) = 0.

    :

    ()

    s + q = 0

    BD AC ,

    p+ r+2t , 0 (B,C,D ), y = 0, x = 0, M AC.

    () p q

    r s

    = 0. (4)

    (4) OB,

    OD .

    BD AC.

    (1) M - y = q

    px

    BD (CMD) = (CMB)

    BD (*).

    .

    .

    :

    .

    -

    .(*) :

    . (1), (2) (4)

    x =p

    q

    s + q

    2, y =

    q + s

    2

    M BD.

    70

  • 2 ( ) E

    ABCD.

    O - ABCD

    (OBA) = (OAD) = (ODC) = (OCB) (1)

    O E

    (1), ABCD -

    .

    (1) - O ,

    BD. -

    (1)

    BF1AO, DG1AO (2)

    (1), (2) BF1= DG1. -

    : BE1 = E1D E1 DB OA. BF2OC, DG2OC -

    (BOC) = (DOC)

    BE2 = E2D, E2 DB OC. E1, E2 L BD. -

    A OL, C OL L AC L E.

    A OL, C OL (1) O AC.

    (1) O BD

    AC -

    BD O

    AC. (1) O AC

    BD

    AC O

    BD.

    (1) - O ABCD,

    : .

    .

    3 ( ) .

    xOy

    OA,OB

    , OM M

    AB.

    (OBA) = (OBC) (ODA) = (ODC) -

    O BM, DM, M

    AC. (OAB) = (OAD) (OCB) = (OCD)

    O AN, CN, N

    BD. O M N AC O N M BD ( , ABCD -).

    71

  • :

    63 ( ) n 1 a C R |a| = 1.

    n

    k=0

    (nk

    )(1 + ak)xk = 0.

    :

    () a

    () a, b a + b = 0.

    http://www.mathematica.gr/forum/viewtopic.php?f=60&t=41670

    ( )

    ()

    (x + 1)n + (ax + 1)n = 0.

    x0 , (x0 + 1)

    n+ (ax0 + 1)

    n= 0

    |x0 + 1| = |ax0 + 1| .

    |a| = 1,

    |x0 + 1| = |x0 + a| .

    x0

    (1, 0) a.

    () a = xa + yai a -

    a =ya

    1 xa b =

    yb

    1 xb b = xb + ybi x

    2a + y

    2a = x

    2b+ y2

    b= 1.

    a b yayb

    (1 xa) (1 xb)= 1

    yayb

    (1 xa) (1 xb)=

    (1 + xa) (1 + xb)

    yayb

    xaxb + yayb = xa xb 1 (xa + xb)2 + (ya + yb)2 = 2xa 2xb = 2xa + 2xb xa + xb = ya + yb = 0 a + b = 0

    64 ( )

    arccos

    (15

    )= 2 arctan

    23

    .

    http://www.mathematica.gr/forum/viewtopic.php?f=60&t=31191

    1 ( )

    2 arctan x = arctan2x

    1 x2

    ( tan 2a =2 tan a

    1 tan2 a),

    2

    23

    1 23= 6

    23.

    cos a = 1tan2 a + 1

    cos C =a2 + b2 c2

    2ab=

    52 + 62 72

    2 5 6=

    1260=

    15

    C = arccos(15

    )

    ( 6

    23 280

    ).

    72

    http://www.mathematica.gr/forum/viewtopic.php?f=60&t=41670http://www.mathematica.gr/forum/viewtopic.php?f=60&t=31191
  • .

    2 ( ) ABC a = 5, b = 6 c = 7. ,

    cos C =a2 + b2 c2

    2ab=

    52 + 62 72

    2 5 6=

    1260=

    15

    C = arccos

    (15

    ).

    s =a + b + c

    2= 9 -

    ,

    tan

    (C

    2

    )=

    (s a) (s b)

    s (s c)

    tan

    (C

    2

    )=

    4 39 2

    =

    23 C = 2 arctan

    23

    !

    73