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Solutions to Homework assigned from Montgomery Design and Analysis of Experiments 8th Ed
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Individual Homework #4Design of Experiment and Analysis
2.33. ManuallyBO1BO2diff
6.085.730.35
6.225.80.42
7.998.42-0.43
7.446.840.6
6.486.430.05
7.998.76-0.77
6.326.320
7.67.62-0.02
6.036.59-0.56
7.527.67-0.15
mean-0.051
sd0.441
b) Ho = d=0 vs Ha: d0
to = d/Sd/sqrt(n) = -0.051/ 0.441/sqrt(10) = -0.3657 t0.025,9= 2.262
to < t0.025,9 No rejection of Null hypothesis.
CI = to*Sd/10 d = -0.051 0.3159 The interval includes zero (0) so no rejection of null hypothesis.c) Ho = d=0 vs Ha: d>0 mean score of Date of birth 1 is greater than Date of birth 2
to = 0.3657< t0.05,9 =1.833 No rejection of Null hyp.
Ho = d=0 vs Ha: d0
t.test(bo1, bo2, alternative ="greater", paired =TRUE)
Paired t-test
data: bo1 and bo2
t = -0.3658, df = 9, p-value = 0.6385
alternative hypothesis: true difference in means is greater than 0
95 percent confidence interval:
-0.3065927 Inf
sample estimates:
mean of the differences
-0.051Ho: d=0
Ho: d