HW#4 for Montgomery Design and Analysis of Experiments

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Solutions to Homework assigned from Montgomery Design and Analysis of Experiments 8th Ed

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Individual Homework #4Design of Experiment and Analysis

2.33. ManuallyBO1BO2diff

6.085.730.35

6.225.80.42

7.998.42-0.43

7.446.840.6

6.486.430.05

7.998.76-0.77

6.326.320

7.67.62-0.02

6.036.59-0.56

7.527.67-0.15

mean-0.051

sd0.441

b) Ho = d=0 vs Ha: d0

to = d/Sd/sqrt(n) = -0.051/ 0.441/sqrt(10) = -0.3657 t0.025,9= 2.262

to < t0.025,9 No rejection of Null hypothesis.

CI = to*Sd/10 d = -0.051 0.3159 The interval includes zero (0) so no rejection of null hypothesis.c) Ho = d=0 vs Ha: d>0 mean score of Date of birth 1 is greater than Date of birth 2

to = 0.3657< t0.05,9 =1.833 No rejection of Null hyp.

Ho = d=0 vs Ha: d0

t.test(bo1, bo2, alternative ="greater", paired =TRUE)

Paired t-test

data: bo1 and bo2

t = -0.3658, df = 9, p-value = 0.6385

alternative hypothesis: true difference in means is greater than 0

95 percent confidence interval:

-0.3065927 Inf

sample estimates:

mean of the differences

-0.051Ho: d=0

Ho: d