Upload
others
View
2
Download
0
Embed Size (px)
Citation preview
Persans 1
Honors Physics
Notes Nov 16, 20Heat
Persans 2
Properties of solids
Persans 3
Persans 4
Vibrations of atoms in crystalline solids
( )
1 1
2
1 12
( ) ( )
2
Assuming only nearest neighbor interactions (+Hooke's law)
is the displacement of the sth plane.
The equation of motion of the sth plane is thus:
We look
s s s s s
s
s
s s s
F C u u C u u
u
d uM C u u udt
+ !
+ !
= ! + !
= + !
( )
( )
( )
2
1 1
2
2 2
1/ 2
.
2
2
2 41 cos sin
2
4sin
2
for solutions where all atoms move as a travelling wave i t ikx
s s s s
iksa ika ika iksa
e e
M u C u u u
M e C e e e
C C kaka
M M
C ka
M
"
"
"
"
"
!
+ !
!
! = + !
! = + !
# $ # $= ! =% & % &' ( ' (
# $= % &' (
Persans 5
Normal Mode Frequencies (Continued)
Persans 6
TopicsHeat and temperatureKinetic modelProperties of materials
Heat capacityThermal expansionTransfer of heat
First Law of thermodynamics: Heat and work
Persans 7
What is temperature?• Temperature is a measure of the average
kinetic energy of the particles in a space. It isproportional to the internal energy of thesystem.
What is heat?• Heat is the energy that flows between a
system and its environment by virtue of atemperature difference between them .
Persans 8
Temperature scales• Common scales are based on temperatures
at which everyday things happen.• The Fahrenheit scale is based on the freezing
point of brine (~00F) and the temperature ofthe human body (~1000F).
• The Centigrade or Celsius scale assigns thefreezing point of pure water to 00C and theboiling point to 1000C. Celsius is the metricunit and is used worldwide, except in the US.
• The Kelvin scale is based onthermodynamics and kinetic theory.
( )9 5
32; 32 ; 2735 9
F C C F K CT T T T T T= + = ! = +
Persans 9
Units of Heat• Since heat is a form of energy, the SI unit is
the Joule.• Another common unit of heat is the
kilocalorie, which is the amount of heatenergy needed to raise the temperature of 1kg of water by 10C. 1kcal=4185 J
• Some US engineers insist on using the BTU(British Thermal Unit) 1 BTU is the amount ofheat needed to raise the temperature of 1 lbof water by 10F. 1BTU=0.252 kcal
Persans 10
Kinetic Theory of Gases• A series of experiments on dry air led to the
following equation of state for an ideal gas:
23 5
; ;
1.38 10 8.65 10
pressure volume
number of gas molecules in that volume;
= Boltzman's constant= J/K= eV/K
number of moles of gas
universal gas constant=
B
B
A B
pV Nk T
p V
N
k
pV nRT
n
R N k
! !
=
= =
=
" "
=
=
=
Persans 11
Kinetic theory: a model1. A gas consists of molecules2. The molecules are in random motion and
obey Newton’s laws.3. The total number of molecules is very large
(so we can use statistical averages)4. The average distance between molecules is
large compared to the size of the molecules.5. Molecules experience only collisions forces.6. Collisions are elastic and of short duration.
Persans 12
Deducing pressure from kineticenergy
• Find the average change in momentum when amolecule bounces elastically between two massivewalls separated by distance L.
• Assume that all molecules have the same averagespeed.
• Compare the pressure we deduce with the ideal gaslaw.
Persans 13
11 1
1
2
1 11 3
2 2
3 3
2 2 2 2 2
2 2
2
2
22 ;
(2 / )
;
3
1 2 1
3 3 2
2 1
3 2
1 3
2 2
For many atoms:
and comparing to
we conclude that :
xx x
x
x x
xi x
x y z x
B
mvmomentum mv F
L v
F mvp
A L
m mp v N v
L L
v v v v v
m Np N v mv
V V
pV N mv pV Nk T
mv k
! = " =
= =
= =#
= + + =
$ %= = & '
( )
$ %= =& '
( )
= BT
Persans 14
Properties of common matter• Phases
– solid– liquid– gas– (plasma)
• Phase changes– melting– vaporization (boiling)– dissociation of valence electrons from atoms
• Thermal expansion
Persans 15
Interatomic forces include higher order terms than linearterm in atomic displacement.
Figure 6-2 (a) Harmonic and (b) Anharmonic potential energyfunctions for the interaction of two atoms. R is the atomicseparation , while E1, and E2 represent two possible vibrationalenergies. For (a) an increase in energy does not result in achange in the average atomic separation, given by themidpoints of constant energy lines. For (b) an increase inenergy results in an increase in average separation.
• Anharmonic Forces
Persans 16
Thermal Expansion• To a good approximation over moderate
temperature ranges, the change in length of asolid increases proportionately to the changein temperature.
L = original length, = linear expansion coefficient
L L T!
!
" # "
~12Concrete3Glass12Steel25Alα (10-6/C)material
Persans 17
Thermal expansion of area andvolume
( )
( )
2 2 2
3 3
( ) 2 2 2
2
For solids, the amount by which the area of a plate
or the volume of a block changes can be easily estimated
from the linear expansion:
simple squareL
A L L L L L L L L AL
A L
A L
L L LV
V
!! = + ! " = ! + ! # ! =
! !#
+ ! "!=
33L
L L
!#
Persans 18
Volume Thermal Expansion• The change in volume with temperature can
be defined for solids, liquids and gases.3
V = original volume, = volume expansion coefficient
V V T! ! "
!
# $ # $
~35Concrete210Water3400Air
9Glass35Steel75Alβ (10-6/C)material
Persans 19
Thermal Expansion: The specialcase of ideal gases
• For many gases, it is found that the pressure,volume, and temperature are related in asimple way:
; ;pressure volume
number of moles of gas; = a constant
pV nRT
p V
n R
=
= =
=
8.314 J/(mol K)
mass (grams)
molecular mass (g/mol)
R
n
=
=
Persans 20
Exercise: 16 Nov 06________________
• An ideal gas is cooled from 300C to 00C. Bywhat ratio does its volume change?
Persans 21
Exercise: 16 Nov 06• Two aluminum plates are held in place by a steel
bridge as shown. The temperature for the figure onthe left is 0oC. The plates heat in the sun to 40oCand expand. This causes a buckle as shown in thefigure on the right.
20 m
a) Find the differential expansion of Al and steel.
b) Estimate the height of the buckle.
Persans 22
( )
-6 6
6 1 3
( ) 11 10 ; ( ) 23 10
20 12 10 40 9.6 10
2
a) Find the differential expansion of Al and steel.
meters
b) Estimate the height of the buckle. Use L=10 m for one side.
S
Steel Al
L L T m K K x
LL L
! !
!
"
" " "
= # = #
$$ = $ $ = # # # =
$$%+ $ +&
'( )
( )
22 2
222
22
2 2 2
24
4
10 10 0.1 0.3
S
S S
S
L L h
LL L L L L L L L
LL L L L L L
h L L m m m h m"
(= + $ +)
*
$$+ $ + + $ + $$ + $ $$
$$= + $ + + $$ + $ $$
+ $$ = # = , +
Persans 23
• The specific heat takes the mass of materialbeing heated into account.
Heat capacity and specific heat• When heat energy is added to or subtracted
from an object, its temperature changes(unless it undergoes a phase change). Inmany cases, near room temperature, thetemperature change is linear in energyadded.
heat capacity
Q C T
C
! = !
=
/c C m Q mc T= ! " = "
Persans 24
Some approximate specific heats
• Aluminum 0.9 kJ/(kg C)• Glass 0.84• Steel 0.45• Wood 1.7• Water (liquid) 4.2• Ice 2.1• Air (const V) 1
Persans 25
Latent heat of phase change• When the phase of material changes, it takes
up or gives off heat but the temperature doesnot change. The energy goes into breakingor making bonds between atoms.
• The energy relationship is expressed usingthe latent heat of melting (or condensation, orvaporization, or freezing)
Q Lm! =
Persans 26
Persans 27
Example: Energy required to heatand boil a cup of water
• Estimate the amount of energy that isrequired to heat a cup of water (0.2 kg) fromroom temperature to boiling.
• Estimate the amount of energy that isrequired to convert that cup of water to vapor.
Persans 28
Example continued
4190 .2 80 67000 67
2256 .2 451
To raise the temperature of 0.2 kg of water from
20 C to 100 C we use the approximate formula:
To vaporize the same amount:
The total ener
v v
JQ cm T kg K J kJ
kgK
kJQ L m kg kJ
kg
° °
! = ! = • • = =
! = = " =
518
gy is thus:
TQ kJ! =
Persans 29
Comparison of thermal andgravitational potential energy
270 4 9 10
Let's estimate temperature change due to
conversion of gravitational potential energy to heat energy
from dropping a student from from the top of a 9 story building:
m mKE mgh kg floors
floor s! = " # # # =
2
25
36010 36
0.086 .
4200 4200
(6 kcal).
If all of this energy were converted to heat
the temperature of the water would increase by
water
kJ
Jmm
Q mgh gh kgsT KJ Jcm cm c
kgK kgK
#!
! " = = = = =
Persans 30
The flow of heat
Persans 31
The flow of heat• Heat energy flows from warmer volume to
colder volumes.• Convection: energy transfer by collective
motion of a macroscopic volume of the fluid.• Conduction: energy transfer by transfer of
vibrational kinetic energy on the atomic scale.• Radiative: energy transfer by emission of
electromagnetic radiation from a hot material.
Persans 32
Heat Conduction• Heat transfer by conduction can be
represented using a simple andsensible relation:
•
( )
For a slab of thickness and area
= rate of heat flow
specific thermal conductivity
area;
is the hot (cold) temperature
H C
H C
H C
d A
T TdQ dTH kA kA
dt x x dx
H
Wk
m K
A
T T
! "# ! "= = =$ % $ %
# & '& '
! "= $ %
& '
=
dx
A
Persans 33
Thermal conductivity of commonmaterials
0.1
0.7
1.0
235
0.026
ρ (W/m.K)
0.05Wood
0.35Concrete
0.50Glass
140Aluminum
0.011Still Air
BTU/(ft 0F hr)Material
Persans 34
Solving a differential equation fortemperature of an object
• We can use whatwe know aboutheat flow andinternal energy todeduce thetemperature of anobject as a functionof time. ( )
( )
( )
( )
0
ln
is a constant, so
H
H CH
H C
CC
H C
H C
finalfinal
H C initialinitial
kAt
xcmH C
Q cmT
T TdQ dTcm kA
dt dt x x
dTT
dt
d T T kAdt
T T xcm
kAT T t
xcm
T T e!"
=
# $!= ! = % &
!' (
=
!! =
! "
! ! ="
! =
Persans 35
Exercise _________________• The temperature difference between two
sides of a 1 cm thick sheet of foam board isT1
0C. The rate at which heat passes throughit is 400 W per square meter.– What would the heat flow be if the thickness were
increased to 2 cm?
– What would the heat flow be if the temperaturedifference were doubled?
Persans 36
Convection• “Still air” is a very good insulator. The
problem is that air can flow and its densitydepends on temperature. (1/ρ~V/nR~T).– Cold air is denser than hot air and flows
downward.– Good insulators frequently just use air, but trap it
so in can’t convect.• Heat can then be carried around by the flow
of macroscopic volumes of air whose motionis caused by temperature differences.
Persans 37
Radiative heat transfer• All objects radiate heat, but hot objects
radiate a lot more of it per unit area.4
8 25.7 10 . Stephan-Boltzman constant= W/m
(~1 for black surface, ~0.05 for shiny metal)
emitobj
QAT
t
emissivity
!"
!
"
#
$=
$
= %
=
4absorbenv
QAT
t!"
#=
#
• All objects absorb heat from theirenvironment as well.
Persans 38
Heat energy and work
Persans 39
Work by a system
• If we change the volume and there is a netpressure difference between inside andoutside a cylinder, there is work done.
For many cases we have to do the integral
because pressure varies with volume and temp.
f
i
V
V
W pdV= !
Persans 40
The p-V diagram
p
V
work
• isothermal• adiabatic• constant volume• constant pressure
Persans 41
First Law of Thermodynamics• The change in internal energy (cmΔT) of a
material is the difference between the heatadded to the material system and the workdone by the system.
int
(
heat added to the material
work done on the system
is negative if the system expands
against an external pressure)
E Q W
Q
W
W
! = +
=
=
Persans 42
Using Thermodynamic Laws:The Ideal Gas
231.38 10 /
Equation of state for an ideal gas:
number of moles of gas
number of molecules
B
B
pV nRT Nk T
n
N
k J K!
= =
=
=
= "
Persans 43
Ideal gas: Adiabatic process• In an adiabatic process, no heat energy
enters or leaves the system.
int
int
0
( ) ( )
.
;
so d
But the internal energy only depends on the temperature
so
We also know
so from which
V V
p
p
V
Q E dW pdV
dE nC dT pdV nC dT
d pV d nRT
Vdp pdV nRdT Vdp nC dT
Cdp dV
p V C
p AV !
! !
"
# = = = "
= = "
=
+ = =
= " =
=
Persans 44
Ideal gas: Isothermal process0No change in internal energy: Q W
nRTp
V
+ =
=
Constant volume
int
Work done by system must be zero.
All the heat added to a system is stored
as internal energy.
dE dQ dW dQ= + =
Persans 45
Work in special cases: Ideal gas
( ).
ln
Constant pressure:
Constant Temperature:
f f
i i
V V
p f iV V
fBT B B
i
W pdV p dV p V V
VNk T dVp W Nk T Nk T
V V V
= = = !" "
# $= % = =" & '
( )
Persans 46
Some special processes
( 0) -
Adiabatic process: No transfer of heat is made between the system
and the outside world. adiabaticQ E W! = "! =
0;
Constant volume process: No work is done on/by the system.
cvW E Q= ! = !
0.
Free expansion: An adiabatic process in which no work
is done on or by the system. feE! =
0.
Cyclical process: A process in which the system returns to
a specific state or position on a p-V diagram.
Work done by the system must equal energy added.
cyclicE! =
Persans 47
A Heat/Work Conversion Engine
• By applyingpressure, allowinga piston to slide,and adding orsubtracting heat,we can convertheat energy intowork, ormechanical,energy.
Persans 48
Heat engines move heat between tworeservoirs and produce or use work
(any engine)H
W
Q! =
Persans 49
The Carnot Cycle• The most efficient heat engine cycle is the
Carnot cycle, consisting of two isothermalprocesses and two adiabatic processes. TheCarnot cycle is the most efficient heat enginecycle allowed by physical laws.
1H L H
CARNOT
H L
Q Q T
Q T!
"= = "
Persans 50