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Homework: Page 498, problems 12-13 Page 500, questions 15-19

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Homework:. Page 498, problems 12-13 Page 500, questions 15-19. 12.If 335g of water at 65.5 o C loses 9750J of heat, what is the final temperature of the water?. 12.If 335g of water at 65.5 o C loses 9750J of heat, what is the final temperature of the water? q = cm∆T. - PowerPoint PPT Presentation

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Page 1: Homework:

Homework:

Page 498, problems 12-13

Page 500, questions 15-19

Page 2: Homework:

12.If 335g of water at 65.5oC loses 9750J of heat, what is the final temperature of the water?

Page 3: Homework:

12.If 335g of water at 65.5oC loses 9750J of heat, what is the final temperature of the water?

q = cm∆T

Page 4: Homework:

12.If 335g of water at 65.5oC loses 9750J of heat, what is the final temperature of the water?

q = cm∆T ∆T = q / cm

Page 5: Homework:

12.If 335g of water at 65.5oC loses 9750J of heat, what is the final temperature of the water?

q = cm∆T ∆T = q / cm = 9750J / (4.184J/go)(335g)

Page 6: Homework:

12.If 335g of water at 65.5oC loses 9750J of heat, what is the final temperature of the water?

q = cm∆T ∆T = q / cm = 9750J / (4.184J/go)(335g) = 7oC

Page 7: Homework:

12.If 335g of water at 65.5oC loses 9750J of heat, what is the final temperature of the water?

q = cm∆T ∆T = q / cm = 9750J / (4.184J/go)(335g) = 7oC 65.5 – 7 = 58.5oC

Page 8: Homework:

13.The temperature of a sample of water increases from 20.0oC to 46.6oC as it absorbs 5650J of heat. What is the mass of the sample?

Page 9: Homework:

13.The temperature of a sample of water increases from 20.0oC to 46.6oC as it absorbs 5650J of heat. What is the mass of the sample?

q = cm∆T

Page 10: Homework:

13.The temperature of a sample of water increases from 20.0oC to 46.6oC as it absorbs 5650J of heat. What is the mass of the sample?

q = cm∆T

m = q / c∆T

Page 11: Homework:

13.The temperature of a sample of water increases from 20.0oC to 46.6oC as it absorbs 5650J of heat. What is the mass of the sample?

q = cm∆T

m = q / c∆T = 5650J / (4.184J/go)(26.6o)

Page 12: Homework:

13.The temperature of a sample of water increases from 20.0oC to 46.6oC as it absorbs 5650J of heat. What is the mass of the sample?

q = cm∆T

m = q / c∆T = 5650J / (4.184J/go)(26.6o) = 50.8g

Page 13: Homework:

15.Why does ∆H for an exothermic reaction have a negative value?

Page 14: Homework:

15.Why does ∆H for an exothermic reaction have a negative value?

The reaction gives off heat, so the products have less heat than the reactants did. The change is negative.

Page 15: Homework:

16.Why is a measured amount of water an essential part of a calorimeter?

Page 16: Homework:

16.Why is a measured amount of water an essential part of a calorimeter?

q = cm∆Tc = 4.184 J/go

Page 17: Homework:

17.Explain the meaning of ∆Hrxn. Why is ∆Hrxn sometimes positive and sometimes negative?

Page 18: Homework:

17.Explain the meaning of ∆Hrxn. Why is ∆Hrxn sometimes positive and sometimes negative?

Positive for endothermic reactions

Negative for exothermic reactions.

Page 19: Homework:

18.Could another liquid be used just as effectively as water in a calorimeter? Why or why not?

Page 20: Homework:

18.Could another liquid be used just as effectively as water in a calorimeter? Why or why not?

q = cm∆Tc = _____ J/go

Page 21: Homework:

19.Explain how you would design and experiment to determine the specific heat of a 45g piece of metal.