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Holt Geometry
5-5 Indirect Proof and Inequalities in One Triangle
Apply inequalities in one triangle.
Objectives
Holt Geometry
5-5 Indirect Proof and Inequalities in One Triangle
The positions of the longest and shortest sides of a triangle are related to the positions of the largest and smallest angles.
Holt Geometry
5-5 Indirect Proof and Inequalities in One Triangle
Example 2A: Ordering Triangle Side Lengths and Angle Measures
Write the angles in order from smallest to largest.
The angles from smallest to largest are F, H and G.
The shortest side is , so the smallest angle is F.
The longest side is , so the largest angle is G.
Holt Geometry
5-5 Indirect Proof and Inequalities in One Triangle
Example 2B: Ordering Triangle Side Lengths and Angle Measures
Write the sides in order from shortest to longest.
mR = 180° – (60° + 72°) = 48°
The smallest angle is R, so the shortest side is .
The largest angle is Q, so the longest side is .
The sides from shortest to longest are
Holt Geometry
5-5 Indirect Proof and Inequalities in One Triangle
A triangle is formed by three segments, but not every set of three segments can form a triangle.
Holt Geometry
5-5 Indirect Proof and Inequalities in One Triangle
A certain relationship must exist among the lengths of three segments in order for them to form a triangle.
Holt Geometry
5-5 Indirect Proof and Inequalities in One Triangle
Example 3A: Applying the Triangle Inequality Theorem
Tell whether a triangle can have sides with the given lengths. Explain.
7, 10, 19
No—by the Triangle Inequality Theorem, a triangle cannot have these side lengths.
Holt Geometry
5-5 Indirect Proof and Inequalities in One Triangle
Example 3B: Applying the Triangle Inequality Theorem
Tell whether a triangle can have sides with the given lengths. Explain.
2.3, 3.1, 4.6
Yes—the sum of each pair of lengths is greater than the third length.
Holt Geometry
5-5 Indirect Proof and Inequalities in One Triangle
Example 4: Finding Side Lengths
The lengths of two sides of a triangle are 8 inches and 13 inches. Find the range of possible lengths for the third side.
Let x represent the length of the third side. Then apply the Triangle Inequality Theorem.
Combine the inequalities. So 5 < x < 21. The length of the third side is greater than 5 inches and less than 21 inches.
x + 8 > 13
x > 5
x + 13 > 8
x > –5
8 + 13 > x
21 > x
Holt Geometry
5-5 Indirect Proof and Inequalities in One Triangle
Example 5: Travel Application The figure shows the approximate distances between cities in California. What is the range of distances from San Francisco to Oakland?
Let x be the distance from San Francisco to Oakland.
x + 46 > 51
x > 5
x + 51 > 46
x > –5
46 + 51 > x
97 > x
5 < x < 97 Combine the inequalities.
Δ Inequal. Thm.
Subtr. Prop. of Inequal.
The distance from San Francisco to Oakland is greater than 5 miles and less than 97 miles.
Holt Geometry
5-5 Indirect Proof and Inequalities in One Triangle
Lesson Quiz: Part I1. Write the angles in order from smallest to
largest.
2. Write the sides in order from shortest to longest.
C, B, A
Holt Geometry
5-5 Indirect Proof and Inequalities in One Triangle
Lesson Quiz: Part II
3. The lengths of two sides of a triangle are 17 cm and 12 cm. Find the range of possible lengths for the third side.
4. Tell whether a triangle can have sides with lengths 2.7, 3.5, and 9.8. Explain.
No; 2.7 + 3.5 is not greater than 9.8.
5 cm < x < 29 cm
5. Ray wants to place a chair so it is 10 ft from his television set. Can the other two distancesshown be 8 ft and 6 ft? Explain.
Yes; the sum of any two lengths is greater than the third length.