Hollow Section Bracing Connetion - LRFD

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  • 7/28/2019 Hollow Section Bracing Connetion - LRFD

    1/5

    EVERSENDAI ENGINEERING LLC sheet of

    PROJECT Job no Designed by

    CLIVELAND CLINIC ABU DHABI LSY

    Date Checked by

    SUBJECT KMK

    Reference Approved by

    MEMBER END CONNECTION DESIGN AISC-LRFD

    Member profile SHS 300x300x8 FBR1

    Properties of the Section

    Width/depth D = mm

    Thickness t = mm

    Cross Sectional Area A = mm2

    Design Input

    Grade of bolt =

    Shear strength of bolt Fn = N/mm2

    Minimum tensile strength of plate Fu = N/mm2

    Mininmum yield strength of plate Fy = N/mm2

    Dia of bolt d = mm Actual Provided Ratio

    Dia of bolt hole dbh = mm Bolt shear kN kN

    No of bolt row nc = Nos Bolt bearing kN kN

    No of bolt column nr = Nos Plt block shear kN kN

    End distance in the connected plate in SHS e = mm Plt tensile yield kN kN

    Pitch distance in the connected plate in SHS p = mm Plt tensile rupture kN kN

    Gauge distance in the connected plate in SH g = mm Plt compression kN kN

    Total no bolts nt = Nos SHS tensile yield kN kN

    Thickness of connected plate tp = mm SHS tensile rupture kN kN

    No of shear plane np = Weld kN kN

    Thickness of splice plate = mm Splice plt block shear kN kN

    = mm Splice plt tensile kN kN

    size of the weld for connected plate to SHS s = mm Splice plt compressio kN kN

    Length of connected plate inserted in SHS Ls = mm

    Electrode classification number Fexx = N/mm2

    Member Forces ( Un factored Forces)

    Member profile SHS 300x300x8

    Compressive Force C = kN

    Tensile Force T = kN

    Check for Bolts

    Shear capacity of bolt (cl J3-1)

    Max shear force V = kNShear capacity of one bolt fRn = fFnv*AbC/S area of bolt A = 24^2*PI()/4

    = mm2

    nominal unthreded body area of the bolt Ab = 24^2*PI()/4

    = mm2

    f = 0.75

    (Double shear) = 2*Ab*414 / 1

    Shear capacity of one bolt fRn = kN > kN (Safe)

    Total Shear capacity of bolt group = fRn*8

    = kN > kN (Safe)

    stress ratio = (Tensile force)

    Bearing capacity of bolt hole(Plate) (cl J3-6b)

    Bearing capacity of one bolt Pbb = d*tp*pbb f = 0.75

    Thickness of thinner part t = mm

    17/8/2008

    1410

    176.3

    452.39

    0.63

    20

    2247.47

    6

    1410

    400

    1410

    1410

    452.39

    482.759

    70

    24

    2

    280.93

    A325-X

    414

    345

    12

    450

    8

    20

    24

    50

    90

    2

    4

    27

    300

    8

    9280

    0.631410 2247

    1410 1844

    1410 1769

    176 370 0.48

    0.76

    1410 2881

    1410 2107 0.67

    0.49

    1410 2728 0.52

    0.80

    1410 3013 0.47

    1410 1474 0.96

    705 1288 0.55

    705 1106 0.64

    705 814 0.87

    EVERSENDAI

  • 7/28/2019 Hollow Section Bracing Connetion - LRFD

    2/5

    EVERSENDAI ENGINEERING LLC sheet of

    PROJECT Job no Designed by

    CLIVELAND CLINIC ABU DHABI LSY

    Date Checked by

    SUBJECT KMK

    Reference Approved by MEMBER END CONNECTION DESIGN AISC-LRFD

    17/8/2008

    EVERSENDAI

    Clear distance in the direction of force between Lc = - / 2

    the edge of adjacent hole or edge of the material = mm

    Rn = min(1.5*Lc*t*Fu , 3*d*t*Fu)

    = min(1.5*36.5*20*450, 3*24*20*450)

    Total Bearing capacity = kN

    fRn = *

    = kN > kN (Safe)

    stress ratio = (Tensile force)

    Block shear capacity 50 = e

    90

    (Asper AISC Specification for structural steel building cl J4-5) 90 Lt T

    9050

    connected plate

    Check for Block shear of Plate

    Maximum Axial force = kN

    nr =

    nc =

    p = mm

    g = mm

    Lev pt = mm

    Leh,ph = mm

    tp = mm

    No of shear plane np =

    Ubs =

    Fy = N/mm2

    Fu = N/mm2

    f =

    d =

    dbh =

    Block shear strength of Plate fRn = f{(0.6*Fu*Anv+Ubs*Fu * Ant)}

    < f{(0.6*Fy*Agv+Ubs*Fu * Ant)}

    Gross area subject to shear Agv = {(nc-1)*g+Lev,ph} * tp=

    Gross area subject to tension Agt = {(nr-1)*p+Leh,pt} * tp=

    Net area subject to shear Anv = {(nc-1)*g+Leh,ph+0.5*dbh - nc*dbh} * tp=

    Net area subject to tension Ant = {(nr-1)*p+Leh,pt+0.5*dbh - nr*dbh} * tp=

    Rn = kN

    Block shear strength of plate fRn = > kN safestress ratio =

    Check for connected plate

    Tension capacity of plate (cl.J4-1 and J4-2)

    Tensile Plate

    Tensile strength of yielding

    T = kN

    Fy = N/mm2

    Fu = N/mm2

    U =

    Ag = W*t

    Ag = mm2

    Ae = U*An

    Ae = 1*[(50+90+90+90+50)-4*24]20Ae = mm2

    2

    1410

    345

    450

    1

    mm2

    0.75

    0.76

    1

    345

    450

    2400

    1590

    mm2

    mm2

    kN

    mm2

    2458.8

    1844.10

    176369.563

    493

    5240

    90

    8785.64

    4510

    6400

    0.48

    2

    24

    27

    50

    0.75

    20

    70

    50

    50

    1410

    4

    1410

    5090

    27

    36.5

    492.75

  • 7/28/2019 Hollow Section Bracing Connetion - LRFD

    3/5

    EVERSENDAI ENGINEERING LLC sheet of

    PROJECT Job no Designed by

    CLIVELAND CLINIC ABU DHABI LSY

    Date Checked by

    SUBJECT KMK

    Reference Approved by

    MEMBER END CONNECTION DESIGN AISC-LRFD

    17/8/2008

    EVERSENDAI

    f =

    For tensile yielding of Plate Rn = Fy*Ag

    = 345*8785.641

    = kN

    fRn = kN > Safe

    Tensile strength of rupture

    f =

    Rn = Fu*Ae

    = 450*5240

    = kN

    fRn = kN > Safe

    Compresssion capacity of plate

    Compresssion capacity of plate Pn = Fy*Ag SHS 300x300x8

    un supported Length L = 65+90 kN

    stress ratio =

    (Safe)

    Check for weld between connected plate and SHS

    Size of the weld s2 = mm

    Throat thickness t = mm

    Length of weld L = 4*400

    = mm

    Rn = Fw*Aw

    = =

    Design strength of weld Fw = N/mm2

    f =

    Fw = 0.6Fexx(1+.5sin 1.5()

    Capacity of weld fRn = kN > kN (Safe)

    stress ratio =

    Lv

    Check for splice plate 50

    Block shear capacity 90

    90 Lt

    Length of shear face Lv = mm 90

    Length of tension face Lt = mm 50

    Check for Block shear of splice plateMaximum Axial force = kN

    nr =

    nc =

    p = mm

    g = mm

    Lev pt = mm

    Leh,ph = mm

    t = mm

    No of shear plane n =

    Ubs =

    Fy = N/mm2

    Fu = N/mm2

    f =

    d =

    dbh =

    fRn = f{(0.6*Fu*Anv+Ubs*Fu * Ant)}

    < f{(0.6*Fy*Agv+Ubs*Fu * Ant)}

    Agv = {(nc-1)*g+Lev,ph} * tp

    =

    Agt = {(nr-1)*p+Leh,pt} * tp

    =

    Anv = {(nc-1)*g+Leh,ph+0.5*dbh - nc*dbh} * tp

    =

    Ant = {(nr-1)*p+Leh,pt+0.5*dbh - nr*dbh} * tp

    =

    Rn =

    fRn = > kN safe1106.46

    4.24

    1440 mm2

    3840 mm2

    954

    50

    mm2

    kN

    2706

    289.655

    1965.95

    0.75

    2

    90

    450

    2

    5090

    0.75

    1410

    1474.5 1410

    1600

    4017.6

    3013.20

    70

    0.47

    0.96

    6

    180

    280

    345

    705

    50

    12

    24

    27

    mm2

    1475.28

    1

    0

    705

    4

    0.75

  • 7/28/2019 Hollow Section Bracing Connetion - LRFD

    5/5

    EVERSENDAI ENGINEERING LLC sheet of

    PROJECT Job no Designed by

    CLIVELAND CLINIC ABU DHABI LSY

    Date Checked by

    SUBJECT KMK

    Reference Approved by MEMBER END CONNECTION DESIGN AISC-LRFD

    17/8/2008

    EVERSENDAI

    Tension capacity of splice plate

    Tensile yielding of connecting elements Rn = Fy*Ag

    Ag = [(50+90+90+90+50)*12]

    = f =

    Rn =

    = kN

    fRn = kN > (Safe)

    Stress ratio =

    Tensile rupture of connecting elements Rn =

    Net area of splice plate An = [(50+90+90+90+50)-4*27]12

    = mm2

    U = 1 f =

    Ae = U * An

    = mm2Rn = 450*3144

    =

    fRn = kN > kN

    stress ratio =

    Compresssion capacity of splice plate =

    Compresssion capacity of spl ice plate Pn = FcrAg

    un supported Length L = 50+50+10

    = mm

    Selenderness ratio = kL/r

    Radius of gyration rmin = t/sqrt(12)

    =Compressive strength of the splice plate

    C = kN

    K =

    L = mm

    t = mm

    r = mm

    f =

    E = N/mm2

    Fy = N/mm2

    Ag = mm2

    kL/r= 1*110*/3.46410161513775

    = >

    Fcr = Fy if(kL/r safe RATIO :

    0.90

    0.511

    4440

    705

    1

    110

    3.46

    0.9

    31.8 25

    1955.62

    113

    322.31

    200000

    0.87 (1410/2)

    1431

    1288

    345*4440

    1532

    12

    1379

    3144

    3.46

    110

    L 110

    345

    4440

    705

    0.5

    705

    705

    Fu*Ae

    3144

    814

    1084.68

    0.75