HIDRAULIC CALCULATION FOR HOTEL.pdf

8/20/2019 HIDRAULIC CALCULATION FOR HOTEL.pdf

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APPENDIX - A

HYDRAULIC CALCULATIONS


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B - HYDRAULIC CALCULATIONS

B.1 Auxiliary Calculations:

Project Name : HYATT Hotel Casino, Manila

Design Reference : NFPA 13 , Standard for the Installation of Sprinkler

System, 2002Edition NFPA 14, Standard for the

Installation of Standpipe, Private Hydrants and

Hose System, 2002 Edition

Area to be Protected : Hotel

Occupancy Classification : Ordinary Hazard ( Section A-2-1.2 , Appendix C )

Water Demand Calculations based on the following Approach ;

a. By Sprinkler Water Demand plus Fire Hose Stream Demand

b. By Most Demanding, Remotest , and Highest Fire Apparatus

( Surveyed as the Roof Outlet )

By Sprinkler Water Demand Approach

Design Area Considered : 1500 ft2 ( Fig. 7-2.3.1.2 Area Density Curve ,

Appendix C)

Design Density : 0.15 gpm/ft2

( Fig. 7-2.3.1.2 Area Density Curve ,

Appendix C, & Fig. 12.1.10 Miscellaneous Storage

& Commodity Classes I to IV Storage less than 3.7

meter or less in height Design Curves, Appendix C)

Theoretical Sprinkler Demand : 225 gpm ( 1500 ft 2 X 0.15 gpm/ft

2 )

Max. Sprinkler Protection Coverage : 130 ft2

( 12.1 m2 ), ( Table 5-6.2.2 (b) )

No. of Sprinkler Considered : 12 nos. ( Closed Head Type )

Minimum Residual Pressure : 20 psi ( Table 7-2.2.1, Appendix C )

Sprinkler “ K “ Factor : 5.6 ( Table 3-2.3.1, Appendix C )

Minimum Flow rate per Sprinkler : 25.04 gpm ( q = K ( psi )0.5

)

( q = 5.6 ( 20 )

0.5

)


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Corrected Sprinkler Water Demand : 300.48 gpm ( 12 nos. X 25.04 gpm )

Hazen Williams Coefficient ( C ) : 120 ( Table 8-4.4.5, Appendix C )

ADD Inside & Outside Hose Allowance : 250 gpm ( Table 7-2.3.1.1, Appendix C )

Total Water Demand ( Theoretical ) : 550.48 gpm (300.48 gpm + 250 gpm )

By The Remotest, Demanding , and Highest Fire Apparatus (Roof Outlet )

Minimum Flow Rate Requirement : 500 gpm ( Appendix C )

ADD Inside & Outside Hose Allowance : 250 gpm ( Table 7-2.3.1.1, Appendix C )

Total Water Demand ( Theoretical ) : 750 gpm

Total Water Demand ( Hydraulically Calculated ) = 1500 gpm @ 290 psi

Note :

1. Since the Roof Outlet has the higher water demand , it is the area / route

hydraulically calculated.

Therefore :

Specify Fire Pump rated at 1500 gpm and 290 psi

B.2 ISOMETRIC LAY-OUT OF THE MOST REMOTEST, HIGHEST &

MOST DEMANDING FIRE PROTECTION NETWORK (

STANDPIPES ROUTE )


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B.3 TABULATED HYDRAULIC CALCULATIONS RESULTS

( As per NFPA 13 Manual Working Sheet )

* : Actual Pipe Inside Diameter, inches

Symbol and Abbreviations :

p : Friction Loss or resistance computed as per Hazen & Williams formula

, psi / foot of pipe ( Appendix C)

GPM : U.S. Gallons per Minute

q : Flow Increment in GPM to be added at specific location

Q : Summation of flow in GPM at specific location

Pt : Total Pressure in psi at a point in a pipe

Pe : Pressure due to elevation difference between indicated points. This can

be a plus value or a minus value based on the pump reference line { (

+ ) if above reference line and ( - ) if below . If minus, the ( - ) shall be

used ; if plus, no sign need be indicated

STE

P NO

NODE

BEGIN

TO

END

FLOW

( GPM )

PIPE

SIZE *

( IN. )

PIPE FITTINGS

& DEVICES

( Feet )

EQUIVAL

ENT

PIPE

LENGTH

( Feet )

FRICTION

LOSS, p

( psi/ft)

PRESSURE

SUMMARY

( psi )

1 1 to 2

q = 0

6.065”

12T x 30= 360’ L = 627’ C = 120 Pt = 100

Q = 500 6E x 14 = 84’ F = 444’ p = 0.0097 Pe =164.97

F = 444’ TL = 1071’ 1071x 0.0097 Pf =10.38

2 2 to 3

q = 830

7.891”

4T x 35 = 140’ L = 18.3’ C = 120 Pt= 275.35

Q= 1330 1 GV x 4 = 4’

1 CV x 45= 45’

1 FC x 4 = 4’

F = 193’ p = 0.0165 Pe = 3.55

F = 193’ TL= 211.3’ 211.3x 0.0165 Pf= 3.486

1330

GPM

Pt= 282.386

Therefore;

1, Hydraulically Calculated Water Demand = 1500 GPM @

= 290.00 psi

Pt= 282.386

Psi say

290 psi


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Pf : Pressure loss due to friction between points indicated in location column

E : Elbow, 900

T : Tee or Cross flow turned 900

GV : Gate Valve

CV : Swing Check Valve

L : Straight Length, feet

F : Fitting Equivalent Straight Length, feet

( Appendix C)

TL : Total Equivalent Length , feet

= ( L ) + ( F )

Formulas :

Friction Loss Formula . Pipe friction losses shall be determined on the

basis of the Hazen & Williams formula expressed as ( Appendix C)

p = 4.52 Q1.85

/ C1.85

d4.87

…….. Equation -01

Where :

p = Friction Loss or resistance in psi/foot

Q = Flow in GPM

d = Actual internal diameter of pipe, inches

( Appendix C)

C = Friction Loss Coefficient

( Appendix C)

Nozzle Discharge Formula. The discharge of a nozzle shall be calculated

by the formula;

Q = K ( P )0.5

........... Equation – 02

Or

K = Q / ( P ) 0.5 ........... Equation - 03


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Where :

Q = GPM flowing from nozzle

K = Nozzle K – Factor

P = Total pressure in psi at the flow Q

Head. The unit for measuring head is the foot or meter. The relation

between a pressure expressed in psi ( bar ) and a pressure

expressed in feet ( meter ) of head expressed in the following

formulas;

Head in feet = psi / 0.433 specific gravity ….. Equation - 04

3.7 Calculations :

Step No. 01 ( Node 1 – 2 )

In Point -01 , a 6 “ x 2 ½” x 2 ½” stand pipe outlet or commonly called roof outlet is

provided. The minimum flow rate ( Q ) to be considered shall be taken as 500

gpm and a minimum residual pressure of 100 psi (Appendix C)

Hence ;

Q = 500 GPM

Pt = 100 psi

Solving for K :

K = Q / ( P )0.5

= 500 gpm / ( 100 psi )0.5

= 50 gpm / psi

Solving for L :

L = (116.3 + 6 + 25 + 29.2 + 2.8 + 2.1 + 7 + 2.9) x 3.28 ft/m

L = 627 feet

Solving for F :

F = Fitting Equivalent Straight Length , feet

6 pc Elbow 900 , 6” ( 150 mm ) dia = 84 feet

12 pc Tee , 6” = 360 feet


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F = Fitting Equivalent Straight Length , feet

4 pc Tee , 8” = 140 feet

1 pc Check Valve = 45 feet

1 pc Gate Valve = 4 feet

1 pc Flexible Connector = 4 feet

F = 193 feet

TL = 18.3 feet + 193 feet

= 211.3 feet

Solving for p ( Friction Loss ) , psi

p = 4.52 ( 1330 gpm)1.85

/ ( 120 )1.85 ( 7.891” )4.87

= 0.0165 psi/foot

Solving for Pressure due to elevation(Pe):

Pe = 2.5m/0.3048m/ft.

= 8.2 feet x 0.433

= 3.55 psi

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HIDRAULIC CALCULATION FOR HOTEL.pdf