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    Energy AnalysisHeat, Work & Mass

    Ng Tin Yau (PhD)

    Department of Mechanical Engineering

    The Hong Kong Polytechnic University

    Jan 2013

    By Ng Tin Yau (PhD) 1/20

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    Heat and Work Transfer

    Energy can cross the boundary of a system by means of heatandwork. Itis important to distinguish between these two forms of energy.Heat is defined as the form of energy that is transfered between twosystems by virtue of a temperature difference. That is, an energyinteraction is heat only if it takes places because of a temperaturedifference. A process during which there is no heat transfer is called an

    adiabatic process.Work, like heat, is an energy interaction between a system and itssurroundings. In thermodynamics analysis, we normally decompose thetotal work into reversible work and irreversible work (or dissipative work).That is, for a given process the total amount of work is given by

    Wtot=Wrev+Wirrev (1)

    The amount of heat and work done transferred during the process betweentwo states (states 1 & 2) is denoted by Q12 and W12, respectively.

    By Ng Tin Yau (PhD) 2/20

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    Heat and Work Sign Convention

    Heat and work are directional quantities, and thus the completedescription of a heat or work interaction requires the specification of both

    the magnitude and direction. One way of doing that is to adopt a signconvention.

    Formal Sign Convention

    Heat transfer to a system and work done by a system are positive; heat

    transfer from a system and work done on a system are negative.

    Heat and work are energy transfer mechanisms between a system and itssurroundings, and there are many similarities between them:

    Both are recognized at the boundaries of a system as they cross the

    boundaries. That is, both heat and work are boundary phenomena.Systems possess energy, but not heat or work.

    Both are associated with a process, not a state.

    Both are path functions (i.e. their magnitudes depend on the path

    followed during a process as well as the end states.). By Ng Tin Yau (PhD) 3/20

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    Path and Point Functions

    Path functions have inexact differentials designated by the symbol .Therefore, a differential amount of heat or work is represented by Q orW, respectively. For instance, the total work done during process 1 2is

    W12=

    21

    W (2)

    Properties, however, arepoint functions, and they have exact differentialsdesignated by the symbol d. For example, a small change in volume isrepresented by dVand the total volume change during a process betweenstates 1 and 2 is

    V =V2

    V1

    = 21

    dV (3)

    Clearly, we have dV = 0 (4)

    By Ng Tin Yau (PhD) 4/20

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    The First Law & Internal Energy

    The First Law (Joule)

    For all adiabatic processes between two specified states of a closed system,the net work done is the same regardless of the nature of the closedsystem and the details of the process.

    In the case where only microscropic energy is involved, then we have

    Wad12 =U1 U2=U (5)

    Since only heat and work can cross the boundary of a closed system,therefore, one can define the heat transfer into the system Q12 as

    Q12=W12Wad12 (6)

    which yieldsQ12W12= U (7)

    This is the common mathematical form of the first law of thermodynamics. By Ng Tin Yau (PhD) 5/20

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    A Direct Consequence of the First Law

    Consider the differential form of the first law:Q12 W12=dU (8)

    Since internal energy is a property, therefore,

    dU= 0 and hence, for a

    cycle, we have Q12=

    W12 (9)

    Recall from our sign convention, if both the quantitiesQ12 and

    W12

    are positive, the result represents the net heat transfer to the system and

    net work done by the system, respectively. In other words, for a closedsystem the net amount of heat transfer into the system is equal to the netamount of work done by the system.

    By Ng Tin Yau (PhD) 6/20

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    Free Expansion of Gases

    An insulated rigid tank is divided into two compartments with different

    equal volumes. Initially, side 1 is filled up with gas, then the wallseparating the two compartments is removed and the gas is free to expanduntil the gas is equally distributed on both sides.

    During this process, Q12=W12= 0, hence U= 0. Note that in thiscase V = 0 and pressure is not necessary zero but the total work done ofthe process is zero. This situation is called gas free expansion.

    By Ng Tin Yau (PhD) 7/20

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    Moving Boundary Work

    Consider a closed system subjected to a quasi-static volume change fromV1 and V2, then the work done due to this volume is given by

    Wb=

    2

    1

    PdV (10)

    This work done is called moving boundary work. An example of movingboundary work is the piston-cyclinder device.

    By Ng Tin Yau (PhD) 8/20

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    Boundary Work for a Polytropic Process

    For a polytropic process PV = C where ,C R. For = 1, theboundary work is given by

    21

    CVdV =CV1

    1

    2

    1

    = C

    1

    V2

    V

    2

    V1

    V

    1

    =P2V2 P1V1

    1

    For = 1 we have 21

    CV1dV =P1V1ln

    V2

    V1

    In summary

    Wb=

    P2V2P1V1

    1= 1

    PiViln

    V2V1

    = 1 and i= 1 or 2

    (11)

    By Ng Tin Yau (PhD) 9/20

    S ifi H C i

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    Specific Heat Capacity

    The specific heat capacity or just specific heat is defined as the heatenergy required to raise the temperature of a unit mass of a substance by

    1 degree and is denoted as c.

    c q

    T(12)

    Consider a fixed mass in a stationary closed system undergoing a constant

    volume process, then dv= 0 and q=du, hence

    cv =

    u

    T

    v

    (13)

    which is known as constant volume specific heat. Since the differential

    of enthalpy dh is du+Pdv+vdPand for constant presure, dP= 0 whichimplies q=dh. Hence, the constant pressure specific heat is

    cp=

    h

    T

    p

    (14)

    By Ng Tin Yau (PhD) 10/20

    C fi i (R ibl ) W k

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    Configuration (Reversible) Work

    Up to this point we have encountered two types of reversible work, namely,the adiabatic work and moving boundary work. In general, one may dividethe work into two types: reversible and irreversible work. In this case, wehave

    Wrev=yidZi (15)

    where yi and Ziare intensive and extensive properties, respectively. Anexample ofy and Z are pressure Pand volume V, respectively. Thenaccording to the first law, we have

    Q12=dU+yidZi (16)

    which further implies that Q12 must be reversible. The extensiveproperties Ziare said to determine the configuration of the system andhence, the reversible work

    yidZi is also called configuration work.

    Finally, irreversible work is somtimes called dissipative work.

    By Ng Tin Yau (PhD) 11/20

    A E l f Di i ti W k El t i l W k

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    An Example of Dissipative Work Electrical Work

    The electrical work is the work needed to maintain an electric current I ina resistor of resistance R. According to Ohms law V=IRwe have thework done on the resistor

    We=

    21

    Wedt=

    21

    VIdt (17)

    where V and Iare the potential difference and current, respectively.

    By Ng Tin Yau (PhD) 12/20

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    A B k D f T s i E B l E ti

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    A Break Down of Terms in Energy Balance Equation

    Energy transfer involves heat, work and mass, that is

    Ein Eout= (Qin+Win+Emass in) (Qout+Wout+Emass out) (19)

    Rewrite it as

    Ein Eout=Qnet inWnet out+ (Emass in Emass out) (20)

    where Qin Qout Qnet in and WoutWin Wnet out.In the case of simple compressible system, we assume

    Esys= U+ KE + PE (21)

    The kinetic energy is given by KE = 12m(V V) where V is the velocity of

    the system. The potential energy is written as PE = mgz where z is theelevation of the center of gravity of a system relative to some arbitrarilyselected reference level.

    By Ng Tin Yau (PhD) 14/20

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    Mass Transfer

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    Mass Transfer

    Generally speaking, for open system, one must include the flow energy intothe energy term. As a result, the total energy of a flowing fluid on a

    unit-mass basis, denoted by is given by

    Pv+u+ ke + pe =h+ ke + pe (24)

    In this case, the energy transfer due to mass transport is given byEmass=m. Hence, the total energy transported by mass through the

    boundary is obtained by integration:

    Emass=

    m (25)

    In the case of uniform properties1

    , that is, is constant throughout theboundary surface, and hence,

    Emass=

    m=m (26)

    1

    Uniform means no change with location over a specificed region. By Ng Tin Yau (PhD) 16/20

    Unsteady Flow Analysis

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    Unsteady-Flow Analysis

    Many processes of interest, however, involve changes within the controlvolume with time. Such processes are called unsteady-flow processes.Unlike steady-flow processes, unsteady-flow processes start and end oversome finite time period instead of continuing indefinitely.Most unsteady-flow processes, however, can be represented reasonably well

    by the uniform-flow process, which involves the following idealization:

    Uniform-Flow Approximation

    The fluid flow at any inlet or exit is uniform and steady, and thus the fluidproperties do not change with time or position over the cross section of an

    inlet or exit. If they do, they are averaged and treated as constants for theentire process.

    By Ng Tin Yau (PhD) 17/20

    General Analysis for Multi Inlet Outlet Systems

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    General Analysis for Multi-Inlet-Outlet Systems

    In general unsteady-flow analysis, conservation of mass principle gives

    in

    mout

    m= msys (27)

    and the energy balance is given by

    Qnet,inWnet,out+

    inm

    outm= Esys (28)

    In the case of a closed system,

    in

    m= out

    m= 0msys

    = 0 (29)

    Similarly, we haveQnet,inWnet,out= Esys (30)

    By Ng Tin Yau (PhD) 18/20

    An Example

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    An Example

    Consider a uniform-flow system which involveselectrical, shaft and boundary work with one

    inlet. Suppose that the kinetic and potentialchanges associated with the control volumeand fluid stream are negligible, then the massbalance equation becomes

    mi =m2m1 (31)

    where the subscript i represents the inlet ofthe system.

    On the other hand, the energy balance equation is given by

    Qnet,in+

    21

    VIdt+Wsh

    21

    PdV+mii = (m2u2m1u1)sys (32)

    By Ng Tin Yau (PhD) 19/20

    Steady Flow Analysis

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    Steady Flow Analysis

    In the case of steady flow, we have msys= 0 and Esys= 0.

    Equations for Steady Flow Analysis

    in

    m=out

    m (33)

    andQnet,inWnet,out+

    in

    m out

    m= 0 (34)

    By Ng Tin Yau (PhD) 20/20