Upload
others
View
0
Download
0
Embed Size (px)
Citation preview
DATA HANDLING
• Recap: Displaying Ungrouped Data
• Recap: Displaying Grouped Data
• Measures of Central Tendency in Ungrouped Data
• Measures of Central Tendency in Grouped Data
• Measures of Dispersion
• Five Number Summary
1
MEASURES OF CENTRAL TENDENCY
FOR UNGROUPED DATA
Mean
Is most commonly
Also called the average
Formula:
n
xx
setdatainvaluesofNo
valuesdataofSumMean
_____
___
2
Example
1. Class A consists of 9 learners and Class B consists
of 16 kids. Compare the mean of each class.
Class A 1 1 1 2 4 5 7 9 10
Class B 1 1 1 2 4 5 5 5 5 7 7 8 8 8 9 10
• Mean for class A =
= 4,4
• Mean for class B =
= 5,4
• The average for Class B is better; however the lowest marks in Class A distort the mean.
9
1097542111
16
10988877555542111
Calculating the Mean 3
Marks(10) Tally Frequency (/) Mark x/
1 11 2 2
2 III 3 4
3 iiil 4 12
4 iiii iiii iiii iiii 10 40
5 mi 6 30
6 nil 4 24
7 -B 5 35
8 in 3 24
9 i 1 9
10 n 2 20
Total:40 Total:202
Example
2. Calculate the mean from the frequency table:
Mean = 1,5
40
202
4
Mode
Is the data value that occurs most often
Example
1. Determine the mode:
There are two modes in this set of data: 2 and 4
The data is said to be bimodal.
Class
C
1 1 1 2 2 2 3 4 4 4 5 5 6 7 9 10
5
2. Determine the mode:
Mode = 4
6
Median
Is the data value that lies in the middle of the data set
Need to arrange data in ascending order
If even number of data values, add the 2 data values and divide by 2
Not affected by outliers
Example
1. Determine the median:
The median is 5
Class
A
1 1 2 2 3 4 4 5
M
5 6 7 8 8 9 10
7
2. Determine the median:
Median =
For odd numbers – always add innermost 2 and
divide by 2.
Determining the Median
Class
B
1 2 4 4 4 4 5 6
?
7
?
7 8 8 9 9 9 1
0
5,62
76
Mean, Median & Mode Example
8
EXERCISE
Class results for a test out of 30 are recorded in
the table below:
10A 16 12 16 11 14 15 22 16 17 15 26
10B 20 19 14 10 14 9 8 13 14 30 -
(a) Calculate the mean for each class.
(b) Calculate the mode for each class.
(c) Calculate the median for each class.
9
Estimated Mean
Is the data value that lies in the middle of the data set
Need to arrange data in ascending order
If even number of data values, add the 2 data values and divide by 2
Not affected by outliers
Example
1. Determine the median:
The median is 5
Class
A
1 1 2 2 3 4 4 5
M
5 6 7 8 8 9 10
10
MEASURES OF CENTRAL TENDENCY
FOR GROUPED DATA
Estimated Mean
Can’t find the actual mean as we don’t have the actual data values – only the frequency of data values that lie in the class interval
To calculate estimated mean:
- determine midpoint of
class interval
- multiply each midpoint by
the frequency
- sum the answers and divide
by the number of values in
data set
Class Interval Frequency
0 – 9 years 0
10 – 19 years 11
20 – 29 years 14
30 – 39 years 17
40 – 49 years 13
50 – 59 years 7
60 – 69 years 6
70 – 79 years 5
80 – 89 years 4
90 – 99 years 0
Example
11
Class Interval Frequency Midpoint class
interval
Frequency x
Midpoint
0 – 9 years 0 0 -
10 – 19 years 11 14,5 159,5
20 – 29 years 14 24,5 343
30 – 39 years 17 34,5 586,5
40 – 49 years 13 44,5 586,5
50 – 59 years 7 54,5 387
60 – 69 years 6 64,5 381,5
70 – 79 years 5 74,5 372,5
80 – 89 years 4 84,5 372,5
90 – 99 year 0 -
Totals 77 - 3146,5
Estimated mean = 08,4077
5,3146
12
Modal class
The class interval that has the most data values
Modal class = 30 - 39 years
Class Interval Frequency
0 – 9 years 0
10 – 19 years 11
20 – 29 years 14
30 – 39 years 17
40 – 49 years 13
50 – 59 years 7
60 – 69 years 6
70 – 79 years 5
80 – 89 years 4
90 – 99 years 0
Example
13
Estimated median
The value which lies in the middle of the class interval
Median = 38
Example
Stem and Leaf Diagrams 14