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How many parts are there to a triangle ?

a

b

c

C

PardekooperPardekooper

A

B

C

tan = opposite

PardekooperPardekooper

adjacent

Lets try setting up for tan

CPardekooperPardekooper

tan = oppositeadjacent

tan = 8

6

10

86

Lets try setting up for tan

CPardekooperPardekooper

tan = oppositeadjacent

tan = 8

6

10

68

Lets try setting up for tan

CPardekooperPardekooper

tan = oppositeadjacent

tan = 12

5

13

125

Lets try setting up for tan

CPardekooperPardekooper

tan = oppositeadjacent

tan = 12

5

13

512

PardekooperPardekooper

Solve right triangle ABC if b=32, A=25o, and C=90o

a

b=32

c

= 25o

= 90o

The sum of the angles of a triangle is 180o.

= 65o

A

B

C

a c

b

A

B

C

A+B+C = 180o.25o+B+90o= 180o.

B+115o = 180o

B = 65o

65o

32

Solve right triangle ABC if b=32, A=25o, and C=90o

a

b=32

c

= 25o

= 90o

= 65o

A

B

C

a c

=15

32

A

B

C

PardekooperPardekooper

tan = oppositeadjacent

tan250 = a

65o

3232 32

32tan250 = a

15 = a

15

Solve right triangle ABC if b=32, A=25o, and C=90o

a

b=32

c

= 25o

= 90o

= 65o

A

B

C

c

=15

32

A

B

C

PardekooperPardekooper

We will find c tomorrow

65o

15

Now lets find Ato the nearest degree.

CPardekooperPardekooper

tan = oppositeadjacent

tan = 11

7

117

= tan-1 117

= 580

Now lets find Bto the nearest degree.

CPardekooperPardekooper

tan = oppositeadjacent

tan = 11

7

711

= tan-1 711

= 320

PardekooperPardekooper

Here Here comes comes

the the assignmeassignme

ntnt

AssignmentWorkbook

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