GEO....Sore

7/23/2019 GEO....Sore

1/34

TUGAS TERSTRUKTUR

PERANCANGAN GEOMETRIK

JALAN RAYA

Disusun Oleh:

SUHERMAN/ 1987 TS

PROGRAM STUDI TEKNIK SIPIL

FAKULTAS TEKNIK

7/23/2019 GEO....Sore

2/34

UNIVERSITAS WIJAYAKUSUMA

PURWOKERTO

TAHUN 2010

LEMBAR PENGESAHAN

Sebagai usaha untuk mengikuti ujian utama semester ganjil

tahun Akademik !!"#!$! %akultas &eknik 'ni(ersitas

)ija*akusuma Pur+,kert,- maka sa*a telah berhasil

men*elesaikan dan men*usun tugas :

.PERAN/ANGAN GEOME&R01 2ALAN RA3A4

&ugas ini telah disetujui 5ada :

Hari : 666666666666666666666666666666666666

&anggal : 666666666666666666666666666666666666

Pur+,kert,-

!$!

Asisten D,sen

7/23/2019 GEO....Sore

3/34

D+i Sri )i*anti- S&6

PRODI TEKNIK SIPIL FAKULTAS TEKNIKUNIVERSITAS WIJAYAKUSUMA

PURWOKERTO

LEMBAR ASISTENSI

TUGAS TERSTRUKTUR

PERANCANGAN GEOMETRIK JALAN RAYA

NAMA :Suherman NPM : $"78

N

T!"##!$ U%!&!"/ D'()%&*(& T!"+!

T!"#!"

7/23/2019 GEO....Sore

4/34

Asisten D,sen

D+i Sri )i*anti-

S&6

A. PERHITUNGAN PERBEDAAN SUDUT TANGEN

1, P%-')(& .&.&) CD +!" E .'%!+!* (3 4 +!" Y

5+!%& #!3!% (&.!(&6

1,,rdinat titik B 9$$! !!;

B/< = -> ?m @ $!!! B/4 = "-> ?m @ $!!!

= >!! ?m = ">!! ?m

= > m = ">m

BD< = 9"-8 >-; @ $!!! BD4 = $!- ?m @ $!!!

= $$!! ?m = $!!! ?m

= $$ m = $! m

BE< = 9-"-8->; ?m @ $!!! BE4 = -?m @ $!!!

= $>8!! ?m = !! ?m

= $>8 m = m

2, M'"#&."# A3(&( +!" O%+&"!.

Absis / = absis B B/< Ordinat B = Ordinat B

B/4

= $$! ?m >?m = !! ?m C ">

?m

= $> m =$! m

7/23/2019 GEO....Sore

5/34

Jadi- k,,rdinat titik B 9$> $!;

Absis D = absis B BD< Ordinat / = Ordinat B

BD4

= $$! ?m $$ ?m = !! ?m C $!

?m

= $$ m = !"7 m

Jadi- k,,rdinat titik D 9$$ !"7;

Absis E = absis B BE< Ordinat D = Ordinat B

BE4

= $$! ?m $>8 ?m = !! ?m C

?m

=$8 m = $87 m

Jadi- k,,rdinat titik E 9$8 $87;

, M'"#&."# J!%!) 2 T&.&)

2arak B/-BD-dan BE

Formula:

d$ =2

12

2

12 )()( yyxx +

d$ =22)()( yx +

2arak dB/ =

xxB

Cy ByC

=

123412102+(21062200)

= "8-!$ m

7/23/2019 GEO....Sore

6/34

2arak dBD =

xxB

D

yByD

=

13311210 2+(20982200)

= $7- m

2arak dBE =

xxB

EyB

yE

=13571210

2

+(21782200)

= $>7-8 m

, P'%&."#!" S+. T!"#'"

Sudut &angen B/ 9 FB/;

F = tan1 xy

= tan1 (XCXByCyB)

= tan1 ( 1234121021062200 )

F = $>-,

1arena terletak 5ada kuadran l- maka FB/

= "! C $- = 8-8

7/23/2019 GEO....Sore

7/34

Sudut &angen /D 9 F/D;

F = tan

1

x

y

= tan1 (XDXCyDyC)

= tan1 ( 1331121020982016 )

F = 7-$8,

1arena terletak 5ada kuadran l- maka F/D

= "! C 7-$8 = -87

Sudut &angen DE 9 FDE;

F = tan1 x

y

= tan1 (XEXDyEyD)

= tan1 ( 1357133121782098 )

F =$7-!!>,

1arena terletak 5ada kuadran l- maka FDE

= "! C $7-!!> = 8$-""

, P'%&."#!" S+. T!"#'"

B/ = |CDBC|

= |3,78375,667 |

= 8$-77> ,

BD = |CECD|

= |71,996 3,783|

= 7-$

&abel6 $ 1,,rdinat 2arak dan Sudut

&itik 1,,rdinat 9@-*;2arak

9m;F 9C ,; Stati,ning

B 9$$! !!; >!!

7/23/2019 GEO....Sore

8/34

"8-!$ 8-8

/ 9$> $!; 8$-77>

>"8-!$

$7-8" -87,D 9$$ !"7; 7-

$ -7!

$>7-8 8$-"",

E 9$8 $87; 7!>->>

B, PERHITUNGAN LENGKUNG HORISONTAL

$6 Data lengkung Landai Relati dan Diagram Su5er Ele(asi

a6 Perhitungan Data Lengkung di titik /

a;6 Perhitungan data lengkung

Diketahui =I J = 7! km#jam

emaks = 7 K

B = 8$-77>,

Lebar jalan = 9 @ -!! ; tan5a median

1emiringan melintang n,rmal = K

o Nen?ari R min untuk lengkung h,ri,ntalDengan rumus :

R =v2

127 (e+ f)

dimana : J = 1e?e5atan

e = Su5erele(asi

= 1,,sien gesekan melintang

R =80

2

127 (0,1+0,14) = !"-"8 m $! m

Dari tabel 6> di5er,leh Rmin desain $! m- D maks -7,

Di?,ba digunakan R/ = " m D = ,- dari table $ untuk

Met,de Bina Marga di5er,leh

e = !-!"

Ls = 8!

Lengkung diren?anakan SC/CS

7/23/2019 GEO....Sore

9/34

s = Rc

Lsx

90

= 84

4590x

= $-,

s = Ls(1 Ls40xRc )= > (1 4540x 84 )= >>-8 m > m

3? =

==846

45

6

22

xRcx

Ls

> m

? = B @ s

= ", @ $-,

= 6>,

L? =C

180 @ @ 7>

= 54.46180

@ @ 7>

= 768 m

L = L? 9 @ Ls;

= 768 9 @ >;

= $868 m

5 =

)cos1(6

2

sRcRcx

Ls

=

)35,15cos1(84846

452 o

x

= $-!! m

Atau

5 = 5Q @ Ls =I di5er,leh dari tabel >-$!

= !-!7> @ >67"

7/23/2019 GEO....Sore

10/34

= $-! m

k =

sRcRcx

LsLs sin

40 2

2

=

o

x35,15sin84

8440

4545

2

2

= -8 m

Atau

k = kQ @ Ls

= !->"787$$ @ >

= ->> m

&s = [ (Rc+p ) tan B2]+k

= [ (95+1,00 ) tan932]+k= $!68 m= $!8 ?m

E? =

Rc+p

C R?

= [(95+1,00

cos95

2)] C7>

= 68 m = 8?m

b6 Diagram su5er ele(asi

Sisi di luar

emax = + 8%

Sisi di dalam

e = 0

emax = 8%

!s

Sc!c

"o# 1

2%

"o# 2 "o# 3

2%

0 %2%

8%

8%

7/23/2019 GEO....Sore

11/34

2% 2%

+8%

8%

3,5 m 3,5 m

?;6 Perhitungan landai relati

h = e @ B

= 9 86" K K ; @ -

= !- m

3,P'%&."#!" D!.! L'"#)"# +& .&.&) C


Diketahui =I J = ! km#jam

emaks = $!K

/ =6,

Dari tabel >6$di5er,leh

7/23/2019 GEO....Sore

12/34

Rmin = 6 m digunakan R? = 7> m

Dari tabel $6 di5er,leh

e = !6$!! = $! K

Ls = >

=I e dan Ls terletak diba+ah garis batas sehingga

digunakan ti5e tikungan SC/CS

s = Rc

Lsx

90

= 84

4590x

= $-,

s = Ls(1 Ls40xRc )= > (1 4540x 80 )= >>-7 m 45m

3? =

==846

45

6

22

xRcx

Ls

> m? = / @ s

= 6, @ $-,

= 68,

L? =Rcxx

c

180

=52.37

180@ x 84

= 868> m

L = L? 9 @ Ls;

= 868> 9@>;

= $68> m

5 =

)cos1(6

2

sRcRcx

Ls

7/23/2019 GEO....Sore

13/34

=

)35,15cos1(84846

452

o

x

= $-!! m

Atau

5 = 5Q @ Ls =I di5er,leh dari tabel $6>

= !-!7> @ >

= $-! m

k =

sRcRcx

LsLs sin

40 2

2

=

o

x35,15sin84

84404545

2

2

= -8 m

Atau

k = kQ @ Ls

= !->"787$$ @ >

= ->> m

&s = [ (Rc+p ) tan C

2]+K

= [ (84+1,02) tan35.32]+22,76= "76!8 m = "7!8 ?m

E? = [Rc+p

cosC

c2]Rc

= [84+1,02

cos35.3

c2 ]84

= "68 m = "8 ?m

h = e @ B

= 9 $! K K ; @ -

= !-> m

7/23/2019 GEO....Sore

14/34

/6 Perhitungan Data Lengkungkung di &itik D


Diketahui =I J = ! km#jam

emaks = $!K

D =6,

Dari tabel >6$di5er,leh

Rmin = 6 m digunakan R? = 7> m

Dari tabel $6 di5er,leh

e = !6!7! = 7 K

Ls = >

=I e dan Ls terletak diba+ah garis batas sehingga

digunakan ti5e tikungan SC/CS

s = Rc

Lsx

90

= 84

4590x

= $-,

s = Ls(1 Ls40xRc )= > (1 4540x 80 )= >>-7 m 45m

3? =

==846

45

6

22

xRcx

Ls

> m? = D @ s

= 6, @ $-,

= >6m

L? =Rcxx

c

180

=54.33

180@ x 84

7/23/2019 GEO....Sore

15/34

= 876$ m

L = L? 9 @ Ls;

= 876$ 9@>;

= $76$ m

5 =

)cos1(6

2

sRcRcx

Ls

=

)35,15cos1(84846

452 o

x

= $-!! m

Atau

5 = 5Q @ Ls =I di5er,leh dari tabel $6>

= !-!7> @ >

= $-!7 m

k =

sRcRcx

LsLs sin

40 2

2

=

o

x35,15sin84

84404545

2

2

= -8 m

Atau

k = kQ @ Ls

= !->"787$$ @ >

= ->> m

&s = [ (Rc+p ) tanC2]+K

= [ (84+1,02 ) tan25.32]+22,76= $!!68$ m= $!!8$ ?m

E? = [Rc+p

cosC

c2]Rc

7/23/2019 GEO....Sore

16/34

= [84+1,02

cos25.3

c2 ]84

=$6> m =$> ?mb6Diagram su5er ele(asi

Sisi di luar

emax = + 8%

Sisi di dalam

e = 0

emax = 8%

!s

Sc

!c

"o# 1

2%

"o# 2 "o# 3

2%

0 %2%

8%

8%

7/23/2019 GEO....Sore

17/34

?6Perhitungan landai relati

2% 2%

+8%

8%

3,5 m 3,5 m

h = e @ B

= 9 7 K K ; @ -

= !- m

Stationing Lengkung Horisontal

$ie#a&ui ' S#a#ionin = 42 + 320

S#a#ionin * = 42 + 40524

S#a#ionin = 42 + 4911-

S#a#ionin $ = 42 + 54335

S#a#ionin . = 42 + 5944-

S#a#ion !s = S#a#ion * / !s

= (42+ 40524) / 1036-

= 42 + 3015-

S#a#ion Sc = S#a#ion !S + s

= (42 +3015-) + 45

= 42 + 3465-

7/23/2019 GEO....Sore

18/34

S#a#ion s = S#a#ion Sc + c

= (42 +3465-) + 82-3

= 42 + 4293

S#a#ion S# = S#a#ion s + s

= (42 + 4293) + 45

= 42 + 4-43

S#a#ion = S#a#ion S# + (d./ !s)

= (42 + 4-43) + (8593 / 1036-)

= 42 + 45656

S#a#ion !s = S#a#ion / !s

= (42 + 4911-) / 980-

= 42 + 3931

S#a#ion Sc = S#a#ion !s + s

= (42 + 3931) + 45

= 42 + 4381


= (42 + 4381) + -6-4

= 42+ 51484


= (42 + 5141) + 45

= 42 + 55984

S#a#ion $ = S#a#ion S# + (d/ !s)

= (42 + 55984) + ( 5218 / 980-)

= 42 + 51395

S#a#ion !s = S#a#ion $ / !s= (42 + 54335) / 100-1

= 42 + 44262

S#a#ion Sc = S#a#ion !s + s

= (42 + 44262) + 45

= 42 + 48-64


= (42 + 48-64) + -831

7/23/2019 GEO....Sore

19/34

= 42+ 56595


= (42 + 56595) + 45

= 42 + 61095

S#a#ion . = S#a#ion S# + (d/ !s)

= (42 + 61095) + ( 5162 / 100-1)

= 42 + 56186

3 Pelebaran Perkerasan pada Tikungan

"elearan ererasan ada #iunan dicari denan rumus

* = n ( +c ) + ( n 1) !d + 7

$imana

n = aur an#as

= +)( 22 PRR +

= ear endaraan 2,5 m

: = ;ariari lenun

" = ;ara andar (as roda) #ru 6,5 m = "emeasan samin 0,8 m

!d =[ ] RAPAR ++ )2(2

= "anan #anaan 1,5 m

7 = "elearan #ama&an aia# elalaian enemudi

7 = R

V105,0

< = ecea#an rencana

n = 2

Se&ina

= +)( 22 PRR +

= 2,5 +)5,684(84 22 +

= 2,25 m

7/23/2019 GEO....Sore

20/34

!d =[ ] RAPAR ++ )2(2

=[ ] 84)5,15,6+2(5,1842 ++

= 0,129 m ' #ida isa dicari denan ra>i 1

7 = R

V105,0

= 84

50+105,0

= 0,5-3 m ' #ida isa dicari denan ra>i 1

?aa * = n ( +c ) + ( n 1) !d + 7

= 2 ( 2,25 + 0,8) + ( 21 ) 0,129 + 0,5-3

= 6,802 m

ear ererasan alan lurus

*n = 2 3,5 = - m

arena * @ *n, maa #ida dierluan enama&an lear ererasan ada

#iu

C. PERHITUNGAN LENGUNG !ERTIAL

1 "er&i#unan elandaian (rade A;alan)

S#a ""

7/23/2019 GEO....Sore

21/34

= 43 +1-5

S#a ""

7/23/2019 GEO....Sore

22/34

C1 0,3 %

C1 3 %

C2 = 03 %C1= 3 %

"

7/23/2019 GEO....Sore

23/34

.leEasi = .leEasi ""

7/23/2019 GEO....Sore

24/34

C3 9%

C3 0,3 %

S#a#ion = S#a#ion "

7/23/2019 GEO....Sore

25/34

= (42 + -25) / G 80

= 42 + -05

.leEasi = .leEasi ""

7/23/2019 GEO....Sore

26/34

= 100 + 0,03 80) + L

XA

200

2

= 100 + 0,03 80) +8,7.80

2

200x 80

=103,24

3$. Lengkung PP!3

*elu% ada ga%bar #

a "anan lenun ' = |q1q2|=|915|

= 10,5 %

< = 40 mAam

=120 m ' dari ra>i DDD "";:

7/23/2019 GEO....Sore

27/34

S#a ""

7/23/2019 GEO....Sore

28/34

.leEasi = .leEasi ""i DDD "";:

S#a ""

7/23/2019 GEO....Sore

29/34

G lenun ' H = 1-,5

S#a#ion = S#a#ion ""

7/23/2019 GEO....Sore

30/34

= 93,5 + 0,015 -0) + ! X

2

200.L

= 935+ 0,015 -0) +6.7 !70

2

200x 70=948

,$. Lengkung PP!,

*elu% ada ga%bar 3

a "anan lenun ' = |q5q6|=|5.24.7|

= 99% < = 60 mAam


S#a ""

7/23/2019 GEO....Sore

31/34

F lenun ' H =60

S#a#ion = S#a#ion "

7/23/2019 GEO....Sore

32/34

< = 60 mAam


S#a ""

7/23/2019 GEO....Sore

33/34

S#a#ion = S#a#ion "

7/23/2019 GEO....Sore

34/34

&ir lenun 42+ 890 86

""

Documents

GEO....Sore