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Geometry 12.2 – 12.5 Prep for the STAR Test

Geometry 12.2 – 12.5 Prep for the STAR Test. Geometry 12.2 Pyramids

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Page 1: Geometry 12.2 – 12.5 Prep for the STAR Test. Geometry 12.2 Pyramids

Geometry

12.2 – 12.5 Prep for the STAR Test

Page 2: Geometry 12.2 – 12.5 Prep for the STAR Test. Geometry 12.2 Pyramids

Geometry

12.2 Pyramids

Page 3: Geometry 12.2 – 12.5 Prep for the STAR Test. Geometry 12.2 Pyramids

The lateral area of a regular pyramid with n lateral faces is n times the area of one lateral face.

6

10

7) Find the lateral area and total area of this regular pyramid.

Let’s solve #7 as we learn the formula for lateral area!!

The best way to know the formulas is to understand themrather than memorize them.L.A. = nF

6

10

A = ½ b(h)A = 3(10)A = 30

LA = nFLA = 6(30) LA = 180 square units

OR…

The lateral area of a regular pyramid equals half the perimeter of the base times the slant height.

L.A. = ½ plWhy? Imagine a curtain on the ground around the pyramid(perimeter) and you are pulling the curtain up the slant height. Since the curtain will wrap around triangles we need the ½ .

LA = ½ plLA = ½ 36(10)

LA = 180 square unitsWe have 6 triangles!

Page 4: Geometry 12.2 – 12.5 Prep for the STAR Test. Geometry 12.2 Pyramids

7) Find the lateral area and total area of this regular pyramid.

The total area of a pyramid is its lateral area plus the area of its base.

6

10

T.A. = L.A. + B That makes sense!

A = ½ a(p)

6

30

3

3√3

A = ½ 3√3(36)A = 3√3(18)

A = 54√3

TA = LA + B

TA = 180 + 54√3 sq. units

Page 5: Geometry 12.2 – 12.5 Prep for the STAR Test. Geometry 12.2 Pyramids

Let’s solve #9 as we learn the formula volume!!

9. Find the volume of a regular square pyramid with base edge 24 and lateral edge 24.

Draw a square pyramid with the given dimensions.

24

The volume of a pyramid equals one third the area of the base times the height of the pyramid.

13

V BhWhy? Because a rectangular prism with the same baseand same height would be V = bh and the pyramid, believeit or not, would hold 1/3 the amount of water.

h l

1/3 the volume of its prism.

V = 1/3 B(h)

V = 1/3 24(24)(h)

V = 8(24)(h)

V = 192(h)12

24

Must be a 30-60-90.

12√312√3

12

122 + x2 = (12√3)2

12√2

V = 192(12√2)V = 2304√2 sq. units

Page 6: Geometry 12.2 – 12.5 Prep for the STAR Test. Geometry 12.2 Pyramids

12.3Cylinders and Cones

Page 7: Geometry 12.2 – 12.5 Prep for the STAR Test. Geometry 12.2 Pyramids

To find lateral area (L.A.):

Multiply circumference by height

circumference

height

Take a can of soup

Peel off the label

Page 8: Geometry 12.2 – 12.5 Prep for the STAR Test. Geometry 12.2 Pyramids

To find total area (T.A.): Take the label (LA)

Pop the top and find the area of the base

Top Bottom

Add 2 base areas to the LA

A = πr²

Page 9: Geometry 12.2 – 12.5 Prep for the STAR Test. Geometry 12.2 Pyramids

To find volume (V): Start with the area of the base

Multiply it by height

H

r

That’s how much soup is in the can !

A = πr²

Page 10: Geometry 12.2 – 12.5 Prep for the STAR Test. Geometry 12.2 Pyramids

Lateral Area of a Cylinder: L.A.

The lateral area of a cylinder equals the circumference of a base times the height of the cylinder.

L.A = 2πrH

LA = 12π • 8 = 96π square units

L.A = dπH

L.A = CH

which is

which is

68

Page 11: Geometry 12.2 – 12.5 Prep for the STAR Test. Geometry 12.2 Pyramids

Total Area of a Cylinder: T.A.

The total area of a cylinder is the lateral area plus twice the area of a base.

T.A = L.A. + 2B

TA = 96π + 2(π • 6²) = 96π + 2(36π) = 96π + 72π = 168π square units

68

T.A. = 2πrH + 2πr²

which is

Page 12: Geometry 12.2 – 12.5 Prep for the STAR Test. Geometry 12.2 Pyramids

Volume of a Cylinder: V

The volume of a cylinder equals the area of a base times the height of the cylinder.

V = πr²H

V = (π • 6²) • 8 = 36π • 8 = 288π cubic units

68

Page 13: Geometry 12.2 – 12.5 Prep for the STAR Test. Geometry 12.2 Pyramids

Lateral Area of a Cone: L.A.

LA = π • 6 •10 = 60π square units

L.A = πrl 6

10

8

Page 14: Geometry 12.2 – 12.5 Prep for the STAR Test. Geometry 12.2 Pyramids

Total Area of a Cone: T.A.

T.A = L.A. + B

TA = 60π + (π • 6²) = 60π + 36π = 96π square units

T.A. = πrl + πr²

which is

6

10

8

Page 15: Geometry 12.2 – 12.5 Prep for the STAR Test. Geometry 12.2 Pyramids

Volume of a Cone: V

The volume of a cone equals one third the area of the base times the height of the cone.

V = πr²h

V = 1/3 • π • 6² • 8 = 96π cubic units

6

10

81

3

Page 16: Geometry 12.2 – 12.5 Prep for the STAR Test. Geometry 12.2 Pyramids

12.4 Spheres

Page 17: Geometry 12.2 – 12.5 Prep for the STAR Test. Geometry 12.2 Pyramids

Surface Area Formula24 rSurface Area =

r

What does this represent?It represents the area of a circle with radius = r.

Page 19: Geometry 12.2 – 12.5 Prep for the STAR Test. Geometry 12.2 Pyramids

1. radius = 10 Area: _____ Volume: _____

24 rSurface Area =

= 4π(10)2

= 4π(100)

= 400π units2

Volume =34

3r

3)10(3

4

10003

4

3units 3

4000

Page 20: Geometry 12.2 – 12.5 Prep for the STAR Test. Geometry 12.2 Pyramids

Geometry

12.5 Areas and Volumes of Similar Solids

Page 21: Geometry 12.2 – 12.5 Prep for the STAR Test. Geometry 12.2 Pyramids

If the scale factor of two solids is a:b, then

(1) the ratio of corresponding perimeters is a:b

(2) the ratio of base areas, of lateral areas, and of the total area is a²:b²

(3) the ratio of volumes is a³:b³

Scale Factor

SCALE FACTOR: 1:2Base circumference: 6π:12π 1:2Lateral areas: 15π:60π 1:4Volumes: 12π:96π 1:8

6

10

8

3

4 5

Page 22: Geometry 12.2 – 12.5 Prep for the STAR Test. Geometry 12.2 Pyramids

Exercises

Find the missing information.

4. 5. 6. 7. 8.

scale factor 2 : 5

ratio of base perimeters

ratio of heights 1 : 3

ratio of lateral areas 4 : 49

ratio of total areas

ratio of volumes 125 : 216

27 : 1000

2:5

2:5

4:25

4:25

8:125

1:9

1:27

2:7

8:343

5:6

25:36

3:10

9:100

Page 23: Geometry 12.2 – 12.5 Prep for the STAR Test. Geometry 12.2 Pyramids

HW

• Midpoint WS