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Gauss’s Law The beauty of 1/R 2 “From our derivation you see that Gauss' law follows from the fact that the exponent in Coulomb's law is exactly two. A 1/r 3 field, or any 1/r n field with n 2, would not give Gauss' law. So Gauss' law is just an expression, in a different form, of the Coulomb law...” -- Richard Feynman R E ˆ 4 2 0 R q 0 2 2 0 2 0 4 1 4 ˆ 1 4 q R R q d R q d s R s E For a point charge, a constant for any R. For a chunk of charge, 0 0 Q dV d s E

Gauss’s Law - web.eecs.utk.eduweb.eecs.utk.edu/~ggu1/files/ECE341Notes_14_ElectrostaticsII-Gauss... · Gauss’s Law The beauty of 1/R2 ... This is the physics. ... sP = P. The

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Gauss’s Law

The beauty of 1/R2

“From our derivation you see that Gauss' law follows from the fact that the exponent in Coulomb's law is exactly two. A 1/r3 field, or any 1/rn field with n ≠ 2, would not give Gauss' law. So Gauss' law is just an expression, in a different form, of the Coulomb law...”

-- Richard Feynman

RE ˆ4 2

0R

q

0

22

0

20

41

4

ˆ1

4

q

RR

q

dR

qd

sRsE

For a point charge,

a constant for any R.

For a chunk of charge,

00 Q

dVd sE

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Integral form of Gauss's law: the "big picture"
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dot product of vectors
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Gauss's Law
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The "big picture"
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with the differential form
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(the "small picture")
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The net flux:
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(The divergence is a scalar)
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This is just notation.
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For a dielectric,...
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Up to here, just math. "Gauss's theorem." The E here does not have to be an electric field.
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This is the physics
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We will talk about what the dielectric constant epsilon really means. Before that, let's look at some examples in free space (vacuum).
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Example: find the field of an infinitely large charge plane
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Do Homework #7 Problem 5. Finish Homework #7.
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(Make sure you solve this problem on your own.)

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… …

Another look at the parallel-plate capacitor (Two infinitely large sheets of opposite charges)

Gauss’s law leads to

Here, the negative sign just signifies the “downward” direction.It’s kind of arbitrary.

Electric Fields in Insulators (Dielectrics)

Polarization1. Electronic polarization

d

p = qd

2. Ionic polarization

3. Orientational polarization

Dipole

pointing from to +

When E = 0, p = 0.

Vi

i

V

pP

0lim

Define polarization

When E = 0, net dipole is 0, therefore P = 0. A finite E will induce a net polarization P.

Again, P = 0 (no net dipole) when E = 0. A finite E induces a net polarization P by line up the dipoles.

In all cases, no matter what the mechanism is, E induces P.For materials without spontaneous polarization and for not too strong E, P E.

P = 0E

Not net charge

No net charge in the interior.Two sheet charges at surfaces.

d

(sPA)d = P(Ad)

sP = P

The polarization charge, or “internal” charge, density

The polarization (or “internal”) charge leads to a polarization (or “internal”) field

0EP = P

EP = sP/0

EP = P/0

(external, applied)

EP

Notice that the polarization (internal) filed is always in opposite direction to the external, applied field Eext.

0EP = P

Eext

(total field)

(external, applied)

EP

Now consider a parallel capacitor filled with this dielectric between the two plates.External surface charge density s

induces external field

Eext = s/0

The polarization (or internal) field

EP = sP/0 = P/0

The total field

E = Eext + EP

E = Eext EP = s/0 P/0 Recall thatP = 0EE = s/0 E

Notice this is the total field

(1+)E = s/0

Define r = 1+, and we have: rE = s/0

r0E = s

Define = 0r = 0(1+), and we have: E = s

We often write as e, thus re 00 )1(

We lump the polarization effect of a dielectric material into a parameter ,and substitute 0 (for free space) with (for the dielectric) in equations.

(total field)Eext

Not net charge

d

On both surfaces of a dielectric slabsP = P (ignoring sign)

Recall that the field of a parallel-plate capacitor is the consequenceof Gauss’s law applied to the surface charge densities:

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… …

PP sP = P

Notice the sign

By analogy:

Generalize to other geometries:

EP 0e

PP

PE0

DE)( 00 e ,

where re 00 )1( ,

EED r0

E 0

total0

)(11

P

E P00

1

Gauss’s law in dielectrics

We lump the polarization effect of a dielectric material into a parameter ,and substitute 0 (for free space) with (for the dielectric) in equations.

Gauss’s law in dielectrics

Take-home message:

Limitations of our discussion:• No spontaneous polarization (or piezoelectric effect): whenever

E = 0, P = 0 • Linearity: P = 0E, D = E• Isotropy: The proportional constants are the same in all

directions, thus P // E, D // E

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The discontinuity is due to the polarization charge on the surface. If you plot D(r), there is no discontinuity. The D field is due to "external" charge only.