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page.1
Game Theory
Extensive Form Games: Applications
Levent Kockesen
Koc University
Levent Kockesen (Koc University) Extensive Form Games: Applications 1 / 23
page.2
A Simple Game
You have 10 TL to share
A makes an offer◮ x for me and 10− x for you
If B accepts◮ A’s offer is implemented
If B rejects◮ Both get zero
Half the class will play A (proposer) and half B (responder)◮ Proposers should write how much they offer to give responders◮ I will distribute them randomly to responders
⋆ They should write Yes or No
Click here for the EXCEL file
Levent Kockesen (Koc University) Extensive Form Games: Applications 2 / 23
page.3
Ultimatum Bargaining
Two players, A and B, bargainover a cake of size 1
Player A makes an offerx ∈ [0, 1] to player B
If player B accepts the offer(Y ), agreement is reached
◮ A receives x◮ B receives 1− x
If player B rejects the offer (N)both receive zero
A
B
x, 1− x 0, 0
x
Y N
Levent Kockesen (Koc University) Extensive Form Games: Applications 3 / 23
page.4
Subgame Perfect Equilibrium of Ultimatum BargainingWe can use backward induction
B’s optimal action◮ x < 1 → accept◮ x = 1 → accept or reject
1. Suppose in equilibrium B accepts any offer x ∈ [0, 1]◮ What is the optimal offer by A? x = 1◮ The following is a SPE
x∗ = 1
s∗B(x) = Y for all x ∈ [0, 1]
2. Now suppose that B accepts if and only if x < 1◮ What is A’s optimal offer?
⋆ x = 1?⋆ x < 1?
Unique SPE
x∗ = 1, s∗B(x) = Y for all x ∈ [0, 1]
Levent Kockesen (Koc University) Extensive Form Games: Applications 4 / 23
page.5
Bargaining
Bargaining outcomes depend on many factors◮ Social, historical, political, psychological, etc.
Early economists thought the outcome to be indeterminate
John Nash introduced a brilliant alternative approach◮ Axiomatic approach: A solution to a bargaining problem must satisfy
certain “reasonable” conditions⋆ These are the axioms
◮ How would such a solution look like?◮ This approach is also known as cooperative game theory
Later non-cooperative game theory helped us identify critical strategicconsiderations
Levent Kockesen (Koc University) Extensive Form Games: Applications 5 / 23
page.6
Bargaining
Two individuals, A and B, are trying to share a cake of size 1If A gets x and B gets y,utilities are uA(x) and uB(y)If they do not agree, A gets utility dA and B gets dBWhat is the most likely outcome?
uA
uB
1
1
dA
dB
Levent Kockesen (Koc University) Extensive Form Games: Applications 6 / 23
page.7
BargainingLet’s simplify the problem
uA(x) = x, and uB(x) = x
dA = dB = 0A and B are the same in every other respectWhat is the most likely outcome?
uA
uB
1
1
(dA, dB)
45◦
0.5
0.5
Levent Kockesen (Koc University) Extensive Form Games: Applications 7 / 23
page.8
BargainingHow about now? dA = 0.3, dB = 0.4
uA
uB
1
1
0.3
0.4
45◦
0.45
0.55
Let x be A’s share. Then
Slope = 1 =1− x− 0.4
x− 0.3
or x = 0.45
So A gets 0.45 and B gets 0.55
Levent Kockesen (Koc University) Extensive Form Games: Applications 8 / 23
page.9
Bargaining
In general A gets
dA +1
2(1− dA − dB)
B gets
dB +1
2(1− dA − dB)
But why is this reasonable?
Two answers:
1. Axiomatic: Nash Bargaining Solution2. Non-cooperative: Alternating offers bargaining game
Levent Kockesen (Koc University) Extensive Form Games: Applications 9 / 23
page.10
Bargaining: Axiomatic Approach
John Nash (1950): The Bargaining Problem, Econometrica1. Efficiency
⋆ No waste
2. Symmetry⋆ If bargaining problem is symmetric, shares must be equal
3. Scale Invariance⋆ Outcome is invariant to linear changes in the payoff scale
4. Independence of Irrelevant Alternatives⋆ If you remove alternatives that would not have been chosen, the
solution does not change
Levent Kockesen (Koc University) Extensive Form Games: Applications 10 / 23
page.11
Nash Bargaining Solution
What if parties have different bargaining powers?
Remove symmetry axiom
Then A gets
xA = dA + α(1− dA − dB)
B gets
xB = dB + β(1− dA − dB)
α, β > 0 and α+ β = 1 represent bargaining powers
If dA = dB = 0
xA = α and xB = β
Levent Kockesen (Koc University) Extensive Form Games: Applications 11 / 23
page.12
Alternating Offers Bargaining
Two players, A and B, bargain over a cake of size 1
At time 0, A makes an offer xA ∈ [0, 1] to B◮ If B accepts, A receives xA and B receives 1− xA
◮ If B rejects, then
at time 1, B makes a counteroffer xB ∈ [0, 1]◮ If A accepts, B receives xB and A receives 1− xB
◮ If A rejects, he makes another offer at time 2
This process continues indefinitely until a player accepts an offer
If agreement is reached at time t on a partition that gives player i ashare xi
◮ player i’s payoff is δtixi
◮ δi ∈ (0, 1) is player i’s discount factor
If players never reach an agreement, then each player’s payoff is zero
Levent Kockesen (Koc University) Extensive Form Games: Applications 12 / 23
page.13 A
B
xA, 1− xA
B
xA
Y N
A
δA(1− xB), δBxB
A
xB
Y N
B
δ2AxA, δ2
B(1− xA)
A
xA
Y N
Levent Kockesen (Koc University) Extensive Form Games: Applications 13 / 23
page.14
Alternating Offers Bargaining
Stationary No-delay Equilibrium
1. No Delay: All equilibrium offers are accepted
2. Stationarity: Equilibrium offers do not depend on time
Let equilibrium offers be (x∗A, x∗
B)
What does B expect to get if she rejects x∗A?◮ δBx
∗
B
Therefore, we must have
1− x∗A = δBx∗
B
Similarly1− x∗B = δAx
∗
A
A
B
xA, 1− xA
B
xA
Y N
A
δA(1 − xB), δBxB
A
xB
Y N
B
δ2AxA, δ2
B(1− xA)
A
xA
Y N
Levent Kockesen (Koc University) Extensive Form Games: Applications 14 / 23
page.15
Alternating Offers Bargaining
There is a unique solution
x∗A =1− δB
1− δAδB
x∗B =1− δA
1− δAδB
There is at most one stationary no-delay SPE
Still have to verify there exists such an equilibrium
The following strategy profile is a SPE
Player A: Always offer x∗A, accept any xB with 1− xB ≥ δAx∗
A
Player B: Always offer x∗B, accept any xA with 1− xA ≥ δBx∗
B
Levent Kockesen (Koc University) Extensive Form Games: Applications 15 / 23
page.16
Properties of the Equilibrium
Bargaining Power
Player A’s share
πA = x∗A =1− δB
1− δAδB
Player B’s share
πB = 1− x∗A =δB(1− δA)
1− δAδB
Share of player i is increasing in δi and decreasing in δj
Bargaining power comes from patience
Example
δA = 0.9, δB = 0.95 ⇒ πA = 0.35, πB = 0.65
Levent Kockesen (Koc University) Extensive Form Games: Applications 16 / 23
page.17
Properties of the Equilibrium
First mover advantage
If players are equally patient: δA = δB = δ
πA =1
1 + δ>
δ
1 + δ= πB
First mover advantage disappears as δ → 1
limδ→1
πi = limδ→1
πB =1
2
Levent Kockesen (Koc University) Extensive Form Games: Applications 17 / 23
page.18
Capacity Commitment: Stackelberg Duopoly
Remember Cournot Duopoly model?◮ Two firms simultaneously choose output (or capacity) levels◮ What happens if one of them moves first?
⋆ or can commit to a capacity level?
The resulting model is known as Stackelberg oligopoly◮ After the German economist Heinrich von Stackelberg in Marktform
und Gleichgewicht (1934)
The model is the same except that, now, Firm 1 moves first
Profit function of each firm is given by
ui(Q1, Q2) = (a− b(Q1 +Q2))Qi − cQi
Levent Kockesen (Koc University) Extensive Form Games: Applications 18 / 23
page.19
Nash Equilibrium of Cournot Duopoly
Best response correspondences:
Q1 =a− c− bQ2
2b
Q2 =a− c− bQ1
2b
Nash equilibrium:
(Qc1, Q
c2) =
(
a− c
3b,a− c
3b
)
In equilibrium each firm’s profit is
πc1 = πc
2 =(a− c)2
9b
Levent Kockesen (Koc University) Extensive Form Games: Applications 19 / 23
page.20
Cournot Best Response Functions
Q1
Q2
a−cb
a−cb
ab
ab
a−c2b
a−c2b
b
a−c3b
a−c3b
B1
B2
Levent Kockesen (Koc University) Extensive Form Games: Applications 20 / 23
page.21
Stackelberg ModelThe game has two stages:
1. Firm 1 chooses a capacity level Q1 ≥ 0
2. Firm 2 observes Firm 1’s choice and chooses a capacity Q2 ≥ 0
1
2
u1, u2
Q1
Q2
ui(Q1, Q2) = (a− b(Q1 +Q2))Qi − cQi
Levent Kockesen (Koc University) Extensive Form Games: Applications 21 / 23
page.22
Backward Induction Equilibrium of Stackelberg Game
Sequential rationality of Firm 2 implies that for any Q1 it must play abest response:
Q2(Q1) =a− c− bQ1
2b
Firms 1’s problem is to choose Q1 to maximize:
[a− b(Q1 +Q2(Q1))]Q1 − cQ1
given that Firm 2 will best respond.
Therefore, Firm 1 will choose Q1 to maximize
[a− b(Q1 +a− c− bQ1
2b)]Q1 − cQ1
This is solved as
Q1 =a− c
2b
Levent Kockesen (Koc University) Extensive Form Games: Applications 22 / 23
page.23
Backward Induction Equilibrium of Stackelberg GameBackward Induction Equilibrium
Qs1 =
a− c
2b
Qs2(Q1) =
a− c− bQ1
2b
Backward Induction Outcome
Qs1 =
a− c
2b>
a− c
3b= Qc
1
Qs2 =
a− c
4b<
a− c
3b= Qc
2
Firm 1 commits to an aggressivestrategy
Equilibrium Profits
πs1 =
(a− c)2
8b>
(a− c)2
9b= πc
1
πs2 =
(a− c)2
16b<
(a− c)2
9b= πc
2
There is first mover advantage
Levent Kockesen (Koc University) Extensive Form Games: Applications 23 / 23