15
G-L’s LAW – Pressure vs. Temperature

G-L’s LAW – Pressure vs. Temperature. Pressure (kPa) Volume (mL) BOYLE’S LAW – Pressure vs. Volume = P1V1P1V1 P2V2P2V2

Embed Size (px)

Citation preview

Page 1: G-L’s LAW – Pressure vs. Temperature. Pressure (kPa) Volume (mL) BOYLE’S LAW – Pressure vs. Volume = P1V1P1V1 P2V2P2V2

G-L’s LAW – Pressure vs. Temperature

Page 2: G-L’s LAW – Pressure vs. Temperature. Pressure (kPa) Volume (mL) BOYLE’S LAW – Pressure vs. Volume = P1V1P1V1 P2V2P2V2

Pre

ssur

e (k

Pa)

Volume (mL)

BOYLE’S LAW – Pressure vs. Volume

=

P1V1 P2V2

Page 3: G-L’s LAW – Pressure vs. Temperature. Pressure (kPa) Volume (mL) BOYLE’S LAW – Pressure vs. Volume = P1V1P1V1 P2V2P2V2

Temperature (K)

Vol

ume

(mL

)

CHARLES’S LAW – Temp vs. Volume

=

V1 V2

T2

T1

Page 4: G-L’s LAW – Pressure vs. Temperature. Pressure (kPa) Volume (mL) BOYLE’S LAW – Pressure vs. Volume = P1V1P1V1 P2V2P2V2

•Describe the relationship between the temperature of a gas and its pressure.

•Solve problems involving temperature-pressure relationships.

•Describe some practical applications of Gay-Lussac’s Law.

Page 5: G-L’s LAW – Pressure vs. Temperature. Pressure (kPa) Volume (mL) BOYLE’S LAW – Pressure vs. Volume = P1V1P1V1 P2V2P2V2

Joseph Gay-Lussac (1778-1850)

Determined that temperature and pressure of a gas is a direct relationship (volume and amount of gas are held constant)

Page 6: G-L’s LAW – Pressure vs. Temperature. Pressure (kPa) Volume (mL) BOYLE’S LAW – Pressure vs. Volume = P1V1P1V1 P2V2P2V2

=

P1 P2

T2

T1

**As with Charles’ Law, temperature in Kelvin.

Page 7: G-L’s LAW – Pressure vs. Temperature. Pressure (kPa) Volume (mL) BOYLE’S LAW – Pressure vs. Volume = P1V1P1V1 P2V2P2V2

If a 12.0 L sample of gas is found to have a pressure of 101.3 kPa at 0.0°C, calculate the new pressure at 128°C if the volume is held constant.

0.0°C + 273 = 273 K128°C +273 = 401 K

=

P1 P2

T2

T1

=

101.3 P2 (401) 273

149 kPa

Page 8: G-L’s LAW – Pressure vs. Temperature. Pressure (kPa) Volume (mL) BOYLE’S LAW – Pressure vs. Volume = P1V1P1V1 P2V2P2V2

Boyle’s Law: Pressure α ___1___

volume

Charles’ Law: Volume α temperature

Gay-Lussac’s Law: Pressure α temperature

=

P1 P2

T2

T1

V1 V2

combined gas law

Page 9: G-L’s LAW – Pressure vs. Temperature. Pressure (kPa) Volume (mL) BOYLE’S LAW – Pressure vs. Volume = P1V1P1V1 P2V2P2V2

If a gas occupies a volume of 25.0 L at 25.0°C and 1.25 atm, calculate the volume at 128°C and 0.750 atm.

=

P1 P2

T2

T1

V1 V2

=

(1.25)(401) 298 (0.750)

25 V2

25°C + 273 = 298 K128°C +273 = 401 K

56.1 L

Page 10: G-L’s LAW – Pressure vs. Temperature. Pressure (kPa) Volume (mL) BOYLE’S LAW – Pressure vs. Volume = P1V1P1V1 P2V2P2V2

A gas has a volume of 125 L at 325 kPa and 58.0°C, calculate the temperature in Celsius to produce a volume of 22.4 L at 101.3 kPa

=

P1 P2

T2

T1

V1 V2

=

(101.3) (331) 325 (125)

22.4T2

58°C + 273 = 331 K

18.5 K

18.5 K - 273 = -254°C

Page 11: G-L’s LAW – Pressure vs. Temperature. Pressure (kPa) Volume (mL) BOYLE’S LAW – Pressure vs. Volume = P1V1P1V1 P2V2P2V2

A bag contains 145 L of air at the bottom of a lake, at a temperature of 5.20°C and a pressure of 6.00 atm. When the bag is released, it ascends to the surface where the pressure is 1.00 atm and 16.0°C.

Given:P1 = 6.00 atm

V1 = 145L

T1 = 5.20°C

P2 = 1.00 atm

T2 = 16.0°C

Find: V2

If the maximum volume of the lift bag is 750 L, will the bag burst at the surface?

Page 12: G-L’s LAW – Pressure vs. Temperature. Pressure (kPa) Volume (mL) BOYLE’S LAW – Pressure vs. Volume = P1V1P1V1 P2V2P2V2

Avogadro’s Hypothesis - any sample of any gas at the same temperature and pressure will contain the same number of particles.

Page 13: G-L’s LAW – Pressure vs. Temperature. Pressure (kPa) Volume (mL) BOYLE’S LAW – Pressure vs. Volume = P1V1P1V1 P2V2P2V2

Dalton’s Law of Partial Pressure:

Each gas in a mixture exerts pressure independently.

Total pressure = sum of the pressures of each gas (partial

pressures)

Partial pressure depends on the number of gas particles present (moles), the temperature and volume of container.

Ptotal = P1 + P2 + P3 + P4 …

Page 14: G-L’s LAW – Pressure vs. Temperature. Pressure (kPa) Volume (mL) BOYLE’S LAW – Pressure vs. Volume = P1V1P1V1 P2V2P2V2

1.0 mol H2 2.0 mol He 1.0 mol H2

2.0 mol He3.0 mol gas

Page 15: G-L’s LAW – Pressure vs. Temperature. Pressure (kPa) Volume (mL) BOYLE’S LAW – Pressure vs. Volume = P1V1P1V1 P2V2P2V2