25
www.sakshieducation.com www.sakshieducation.com FUNCTIONS OBJECTIVE PROBLEMS 1. Let A be a set of n distinct elements. Then the total number of distinct functions from A to A is a) n 2 b) n n c) 2n d) n! 2. Set A has 3 elements and set B has 4 elements. The number of injections that can be defined from A into B is a) 144 b) 12 c) 24 c) 64 3. Let n(A) = 4 and n(B) = K. The number of all possible injections from A to B is 120 then k = a) 9 b) 24 c) 5 d) 6 4. Let n(A) = 4 and n(b) = 5. The number of all possible many-one functions from A to B is a) 625 b) 20 c) 120 d) 505 5. Set A contains 3 elements and set B contains 2 elements. The number of onto functions from A onto B is a) 3 b) 6 c) 8 d) 9 6. Let A = {1, 2, 3, ….., n} and B = {a, b, c}, the number of functions from A to B that are onto is a) 3 n – 2 n b) 3 n – 2 n = 1 c) 3(2 n – 1) d) 3 n – 3(2 n – 1) 7. Set A has 3 elements, Set B has 4 elements. The number of surjections that can be defined from A to B is a) 144 b) 12 c) 0 d) 64

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    FUNCTIONS

    OBJECTIVE PROBLEMS

    1. Let A be a set of n distinct elements. Then the total number of distinct functions from A

    to A is

    a) n2 b) nn c) 2n d) n!

    2. Set A has 3 elements and set B has 4 elements. The number of injections that can be defined from A into B is

    a) 144 b) 12 c) 24 c) 64

    3. Let n(A) = 4 and n(B) = K. The number of all possible injections from A to B is 120 then k =

    a) 9 b) 24 c) 5 d) 6

    4. Let n(A) = 4 and n(b) = 5. The number of all possible many-one functions from A to B is

    a) 625 b) 20 c) 120 d) 505

    5. Set A contains 3 elements and set B contains 2 elements. The number of onto functions from A onto B is

    a) 3 b) 6 c) 8 d) 9

    6. Let A = {1, 2, 3, .., n} and B = {a, b, c}, the number of functions from A to B that are onto is

    a) 3n 2n b) 3n 2n = 1 c) 3(2n 1) d) 3n 3(2n 1)

    7. Set A has 3 elements, Set B has 4 elements. The number of surjections that can be defined from A to B is

    a) 144 b) 12 c) 0 d) 64

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    8. Let A, B are two sets each with 10 elements, then the number of all possible bijections from A to B is

    a) 20 b) 10! C) 100 d) 1000

    9. The number of one-one onto functions that can be defined from (1, 2, 3, 4) onto set B is 24 then n(B) =

    a) 4 b) 2 c) 3 d) 6

    10. A = {1, 2, 3, 4), B = {a, b, c, d, e}, then the number of all possible constant functions from A to B is

    a) 9 b) 4 c) 5 d) 16

    11. If ( ) cos(log )f x x= , then 1( ) ( ) [ ( / ) ( )]2

    f x f y f x y f xy + =

    (a) 1 (b) 21

    (c) 2 (d)None of these

    12. If ( ) sin logf x x= , then the value of ( ) 2 ( ).cos logxf xy f f x yy

    +

    is equal to

    (a)1 (b) 0 (c)1 (d) sin log .cos logx y

    13. If ( ) cos(log )f x x= , then 2 2

    2 22

    1( ) ( )2 2

    x xf x f y f fy

    +

    has the value

    (a)2 (b) 1 (c)1/2 (d)None of these

    14. If ( ) cos(log )f x x= , then the value of 1( ). (4) (4 )2 4

    xf x f f f x +

    (a)1 (b) 1 (c)0 (d) 1

    15. Given the function ( ) , ( 2)2

    x xa af x a+

    = > . Then ( ) ( )f x y f x y+ + =

    (a) )().(2 yfxf (b) )().( yfxf

    (c) )()(

    yfxf

    (d)None of these

    16. Let :f R R be defined by ( ) 2 | |f x x x= + , then (2 ) ( ) ( )f x f x f x+ = (a) x2 (b) ||2 x

    (c) x2 (d) ||2 x

    17. If ( ) 10 , ( 10,10)10

    f x xe xx

    +=

    and 2200( )

    100xf x kfx

    = +

    , then k =

    (a) 0.5 (b) 0.6 (c) 0.7 (d)0.8

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    18. If 1( ) log1

    xf xx

    + =

    , then 2

    21

    xfx

    +

    is equal to

    (a) 2)]([ xf (b) 3)]([ xf

    (c) )(2 xf (d) )(3 xf 19. If 2 2( ) cos[ ] cos[ ]f x x xpi pi= + , then

    (a) 24

    =

    pif (b) 2)( =pif

    (c) 1)( =pif (d) 12

    =

    pif

    20. If ( ) ax by f xcx a

    += =

    , then x is equal to

    (a) )(/1 xf (b) )(/1 yf

    (c) )(xyf (d) )(yf 21. The function equivalent to 2log x is

    (a) xlog2 (b) ||log2 x

    (c) |log| 2x (d) 2)(log x 22. The graph of the function ( )y f x= is symmetrical about the line 2x = , then (a) )()( xfxf = (b) )2()2( xfxf =+

    (c) )()( xfxf = (d) )2()2( =+ xfxf

    23. If 1 1( )2 2 4 2 2 4

    f xx x x x

    = ++

    for 2x > , then (11)f =

    (a) 7/6 (b) 5/6 (c) 6/7 (d)5/7 24. If :f IR IR is defined by ( ) 3 4f x x= , then 1 :f IR IR is

    (a) x34 (b) 3

    4+x

    (c)43

    1x

    (d)4

    3+x

    25. Which of the following function is invertible?

    (a) ( ) 2xf x = (b) 3( )f x x x=

    (c) 2)( xxf = (d)None of these

    26. The inverse of the function 10 1010 10

    x x

    x x

    + is

    (a) 101 1log2 1x

    x

    +

    (b) 101 1log2 1

    x

    x

    +

    (c) 101 2log4 2x

    x

    (d)None of these

    27. If x

    xxf

    +=

    1)( , then )(1 xf is equal to

    (a) x

    x)1( + (b) )1(

    1x+

    (c) )1()1(

    x

    x

    + (d) )1( x

    x

    28. If 2

    ( )1

    xf xx

    =

    +, then =))(( xfofof

    (a) 21

    3

    x

    x

    + (b)

    231 x

    x

    + (c)

    21

    3

    x

    x

    + (d)None of these

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    29. If ( ) logaf x x= and xaxF =)( , then )]([ xfF is (a) )]([ xFf (b) )]2([ xFf (c) |)2(| xfF (d) )][(xF

    30. Let f and g be functions defined by ( ) ,1

    xf xx

    =

    +( )

    1xg x

    x=

    , then ))(( xfog is

    (a) x

    1 (b)

    11x

    (c) 1x (d)x

    31. If ( ) , 11

    xf x xx

    =

    +. Then, for what value of is xxff =))((

    (a) 2 (b) 2 (c) 1 (d)1

    32. If 1/( ) ( ) ,n nf x a x= where 0>a and n is a positive integer, then =)]([ xff (a) 3x (b) 2x

    (c) x (d)None of these

    33. If 1 21 21 2

    ( ) ( )1x xf x f x f

    x x

    =

    for 1 2, [ 1,1]x x , then )(xf is

    (a) )1()1(log

    x

    x

    +

    (b) )1()1(

    tan 1x

    x

    +

    (c) )1()1(log

    x

    x

    + (d) all the above

    34. If , when is rational( )0, when is irrationalx xf x

    x

    =

    ; 0, when is rational( )

    , when is irrationalx

    g xx x

    =

    then ( )f g is

    (a) One-one onto (b)One-one not onto (c) Not one-one but onto (d)Not one-one not onto 35. If 21xe y y= + + , then y =

    (a) 2

    x xe e+ (b)

    2

    x xe e

    (c) x xe e+ (d) x xe e

    36. If ||||)(

    x

    xxxf = , then = )1(f

    (a) 1 (b) 2 (c) 0 (d) +2 37. If ( , )f x ay x ay axy+ = , then ),( yxf is equal to

    (a) xy (b) 222 yax

    (c)4

    22 yx (d) 2

    22

    a

    yx

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    38. Let

    1 1, 0

    2 2( )1 1

    , 13 2

    if xf x

    if x

    = <

    , then f is

    (a) A rational function (b)A trigonometric function (c) A step function (d)An exponential function

    39. Let : (2,3) (0,1)f be defined by ][)( xxxf = then )(1 xf equals (a) 2x (b) 1+x

    (c) 1x (d) 2+x

    40. The domain of

    3logsin 3

    1 x is

    (a) [1, 9] (b) [1, 9] (c) [9, 1] (d) [9, 1] 41. The domain of the function 1 2( ) sin [log ( / 2)]f x x= is

    (a) [1, 4] (b) [4, 1] (c) [1, 4] (d) None of these

    42. The domain of the function ( ) log( 4 6 )f x x x= + is (a) ),4[ (b) ]6,(

    (c) ]6,4[ (d) None of these

    43. Domain of the function 1/22

    105( ) log

    4x xf x =

    is

    (a)

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    47. Domain of the function 2

    23 2( )

    6x xf xx x

    +=

    + is

    (a) }3,:{ xRxx (b) }2,:{ xRxx

    (c) }:{ Rxx (d) }3,2,:{ xxRxx

    48. The domain of the function 1| |y x x= is

    (a) )0,( (b) ]0,(

    (c)

    )1,(

    (d)

    ),(

    49. Function x1sin is defined in the interval (a) (1, 1) (b) [0, 1] (c) [1, 0] (d) (1, 2)

    50. The domain of the function 1sin (3 )( )

    ln(| | 2)xf x

    x

    =

    is

    (a) [2, 4] (b) (2, 3) (3, 4] (c) [2, ) (d)

    ),2[)3,(

    51. The domain of 22log ( 3)( )

    3 2xf x

    x x

    +=

    + + is

    (a) }2,1{ R (b) ),2( +

    (c)

    }3,2,1{ R (d)

    }2,1{),3( +

    52. The domain of the function 23( ) log ( 1)xf x x+= is (a) ),1()1,3(

    (b)

    ),1[)1,3[

    (c) ),1()1,2()2,3( (d)

    ),1[)1,2()2,3[

    53. Domain of definition of the function )(log4

    3)( 3102 xxx

    xf +

    = , is

    (a) (1, 2) (b) )2,1()0,1(

    (c) ),2()2,1( (d)

    ),2()2,1()0,1(

    54. Domain of the function { }2log (5 ) / 6x x is (a) (2, 3) (b) [2, 3] (c) [1, 2] (d) [1, 3]

    55. The domain of the function 2log( 6 6)x x + is

    (a) ),( (b) ),33()33,( +

    (c) ),5[]1,( (d) ),0[

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    56. The domain of the function 2( ) exp( 5 3 2 )f x x x= is

    (a)

    23

    ,1 (b)

    ,

    23

    (c) ]1,[ (d)

    23

    ,1

    57. The domain of the function 1

    2

    sin ( 3)( )9

    xf xx

    =

    is

    (a) [1, 2) (b) [2, 3) (c) [1, 2] (d) [2, 3] 58. The domain of the function 1 1( ) sin {(1 ) }xf x e = + is

    (a)

    31

    ,

    41

    (b) [1, 0] (c) [0, 1] (d) [1, 1]

    59. Domain of the function 29

    12x

    x

    is

    (a) (3, 1) (b) [3, 1] (c) (3, 2] (d) [3, 1)

    60. Domain of the function 2

    3( )( 1) 4

    xf xx x

    =

    is

    (a) (1, 2) (b) ),2()2,( (c) ),1()2,( (d) }2,1{),(

    61. The domain of the function 1( ) log | sin |f x x= is

    (a) },2{ InnR pi (b) },{ InnR pi (c) },{ pipiR (d) ),(

    62. The function ,][

    sec)(1

    xx

    xxf

    =

    where [.] denotes the greatest integer less than or equal to x is

    defined for all x belonging to

    (a) R (b) )}|()1,1{( ZnnR (c) )1,0(+R

    (d)

    }|{ NnnR +

    63. Domain of |log|log)( xxf = is

    (a) ),0( (b) ),1(

    (c) ),1()1,0( (d) )1,( 64. Domain of function xxf 5sin)( 1= is

    (a)

    51

    ,

    51

    (b)

    51

    ,

    51

    (c) R (d)

    51

    ,0

    65. The domain of the function ( ) log( 4 6 )f x x x= + is (a) ),4[ (b) ]6,(

    (c) ]6,4[ (d)None of these

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    66. Domain of the function )231(sin)( 21 xxxf ++= is

    (a) ),( (b) )1,1(

    (c)

    0,

    23

    (d) ),2(21

    ,

    67. The range of the function 2( ) | 2 |xf xx

    +=

    + is

    (a) {0, 1} (b) {1, 1} (c) R (d) }2{R 68. Range of the function

    x3sin21

    is

    (a) [1, 3] (b)

    1,31

    (c) (1, 3) (d)

    1,31

    69. If x is real, then value of the expression 32914

    2

    2

    ++

    ++

    xx

    xx lies between

    (a) 5 and 4 (b) 5 and 4 (c) 5 and 4 (d) None of these 70. If the function :[1, ) [1, )f is defined by ( 1)( ) 2 ,x xf x = then 1f (x) is

    (a) )1(

    21

    xx

    (b) )log411(21

    2 x++

    (c) )log411(21

    2 x+ (d) Not defined

    71. The range of function The range of function 76)( 2 += xxxf is

    (a) ),( (b) ),2[

    (c) )3,2( (d) )2,(

    72. Range of the function 2

    22( ) ;1

    x xf x x Rx x

    + +=

    + + is

    (a) ),1( (b) ]7/11,1(

    (c) ]3/7,1( (d) ]5/7,1( 73. The function RRf : is defined by xxxf 42 sincos)( += for Rx , then =)(Rf

    (a)

    1,43

    (b)

    1,43

    (c)

    1,43

    (d)

    1,43

    74. If RRf : , then the range of the function 1

    )( 22

    +=

    x

    xxf is

    (a) R (b) +R

    (c) R (d) RR 75. Range of the function ( ) 9 7sinf x x= is (a) (2, 16) (b) [2, 16] (c) [1, 1] (d) (2, 16] 76. The range of

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    77. If dcbxaxf ++= )cos()( , then range of )(xf is

    (a) ]2,[ adad ++ (b) ],[ dada +

    (c) ],[ daad + (d) ],[ adad +

    78. Range of the function 1

    )(2

    2

    +=

    x

    xxf is

    (a) (1, 0) (b) (1, 1) (c) [0, 1) (d) (1, 1)

    79. The domain of )(logsin 31 x is

    (a) [1, 1] (b) [0, 1] (c) [0, ] (d) R 80. For

    3pi > , the value of 22 cossec)( +=f always lies in the interval

    (a) (0, 2) (b) [0, 1] (c) (1, 2) (d) ),2[ 81. The Domain of function ])[(log)( xxxf e = is

    (a) R (b) R-Z (c) ),0( + (d) Z 82. If 1)( 2 += xxf , then )17(1f and )3(1 f will be

    (a) 4, 1 (b) 4, 0 (c) 3, 2 (d) None of these

    83. If |cos|)( xxf =

    and ][)( xxg = , then )(xgof is equal to

    (a) |][cos| x (b) |cos| x

    (c) |]cos[| x (d) |][cos| x

    84. Let ][1)( xxxg += and

    >

    =

    =

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    88. If RRf : , then ||)( xxf = is

    (a) One-one but not onto (b) Onto but not one-one (c) One-one and onto (d) None of these

    89. Which one of the following is a bijective function on the set of real numbers

    (a) 52 x (b) || x

    (c) 2x (d) 12 +x

    90. If Ryx ),( and 0, yx ; yxyxf ),( , then this function is a/an

    (a) Surjection (b) Bijection (c) One-one (d) None of these 91. The function ( )2( ) sin log( 1)f x x x= + + is (a) Even function (b) Odd function (c) Neither even nor odd (d) Periodic function 92. If xxf 2sin)( = and the composite function |sin|)}({ xxfg = , then the function )(xg is equal to

    (a) 1x (b) x (c) 1+x (d) x

    93. If 246 432)( xxxxf ++= then )(' xf is

    (a) Even function (b) An odd function (c) Neither even nor odd (d) None of these

    94. The function )1log()( 2 ++= xxxf , is

    (a) An even function (b) An odd function (c) A Periodic function (d) Neither an even nor odd function 95. The period of ( ) [ ]f x x x= , if it is periodic, is

    (a) )(xf is not periodic (b) 21

    (c) 1 (d)2

    96. A function f from the set of natural numbers to integers defined by

    =

    even is when,2

    oddiswhen,2

    1

    )(n

    n

    nn

    nf , is

    (a) One-one but not onto (b) Onto but not one-one (c) One-one and onto both (d) Neither one-one nor onto

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    97. Let NNf : defined by 1)( 2 ++= xxxf , Nx , then f is (a) One-one onto (b) Many one onto

    (c) One-one but not onto (d) None of these 98. The function RRf : defined by )1()( = xxf )3)(2( xx is

    (a) One-one but not onto (b) Onto but not one-one (c) Both one-one and onto (d) Neither one-one nor onto

    99. If :[0, ) [0, )f and ( ) ,1

    xf xx

    =

    +then f is

    (a) One-one and onto (b) One-one but not onto (c) Onto but not one-one (d) Neither one-one nor onto

    100. Let the function RRf : be defined by ( ) 2 sin ,f x x x x R= + . Then f is (a) One-to-one and onto (b)One-to-one but not onto

    (c) Onto but not one-to-one (d) Neither one-to-one nor onto

    101. 2)( xxxf += is a function from R R , then )(xf is

    (a) Injective (b) Surjective (c) Bijective (d) None of these

    102. Range of 2

    234 71( )2 7

    x xf xx x

    + =

    + is

    (a) [5, 9] (b) ),9[]5,(

    (c) (5, 9) (d) None of these 103. Which of the following functions is inverse of itself

    (a) x

    xxf

    +

    =

    11)( (b) xxf log5)( =

    (c) )1(2)( = xxxf (d) None of these

    104. If 53)( = xxf , then )(1 xf

    (a) Is given by 53

    1x

    (b) Is given by 3

    5+x

    (c) Does not exist because f is not one-one (d) Does not exist because f is not onto 105. If SRf : defined by ( ) sin 3 cos 1f x x x= + is onto, then the interval of S is (a) [1, 3] (b) [1, 1] (c) [0, 1] (d) [0, 1] 106. Let RRf : be a function defined by

    nx

    mxxf

    =)( , where nm . Then

    (a) f is one-one onto (b) f is one-one into (c) f is many one onto (d) f is many one into

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    107. Let 44)( 2

    2

    +

    =

    x

    xxf for 2|| >x , then the function : ( , 2] [2, ) ( 1,1)f is

    (a) One-one into (b) One-one onto (c) Many one into (d) Many one onto

    108. Let X and Y be subsets of R, the set of all real numbers. The function YXf : defined by 2)( xxf = for Xx is one-one but not onto if (Here +R is the set of all positive real numbers)

    (a) +== RYX (b)

    +== RYRX ,

    (c) RYRX == + , (d)

    RYX ==

    109. Function xxxfRRf += 2)(,: is

    (a) One-one onto (b) One-one into (c) Many-one onto (d) Many-one into

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    FUNCTIONS

    HINTS AND SOLUTIONS

    1. (b).

    ( ) ( )( ) ( ). n A

    n A n B n

    and no functions n B= =

    =

    2. (c) Synopsis 3. (c) Synopsis 4. (d) Synopsis 5. (b) Synopsis 6. (d) 7. (c) 8. (b) 9. (a) 10. (c) Synopsis 11. (d) )(logcos)()(logcos)( yyfxxf ==

    +

    )(

    21)().( xyf

    yxfyfxf

    +

    = )(logcoslogcos

    21)(logcos)(logcos xy

    yxyx

    )](logcos)(logcos2[21)(logcos)(logcos yxyx = = 0.

    12. (b) )log(logsinlogsin)( yxxyxyf +== .....(i)

    )log(logsin)/log(sin)/( yxyxyxf == .....(ii)

    yxyxfxyf logcoslogsin2)/()( =+

    0logcoslogsin2logcoslogsin2 = yxyx .

    13. (d) 14. (c) 15. (a) )()( yxfyxf ++

    12

    x y x y x y x ya a a a+ + = + + +

    1 ( ) ( )2

    x y y x y ya a a a a a = + + +

    1 ( ) ( ) 2 ( ) ( )2

    x x y ya a a a f x f y = + + = .

    16. (b) (2 ) 2(2 ) | 2 | 4 2 | |f x x x x x= + = + ,

    2 1y x= + ,

    ||2)( xxxf += )()()2( xfxfxf +

    4 2 | | | | 2 2 | |x x x x x x= + + ||2 x= .

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    17. (a) ( ) 1010

    f x xex

    +=

    +=

    x

    xxf

    1010log)(

    2

    2

    2

    2 )10(10)10(10log

    10020010

    10020010

    log100

    200

    +=

    +

    ++

    =

    + x

    x

    x

    xx

    x

    x

    xf

    )(21010log2 xf

    x

    x=

    +=

    .5.021

    100200

    21)( 2 ==

    += k

    x

    xfxf

    18. (c)

    2( ) log( 1)f x x x= + +

    +

    ++=

    +

    ++

    =

    +

    xx

    xx

    x

    x

    x

    x

    x

    xf2121log

    121

    121

    log1

    22

    2

    2

    2

    2

    )(211log2

    11log

    2

    xfx

    x

    x

    x=

    +=

    += .

    19. (d)

    xxxf ][cos][cos)( 22 pipi +=

    )10cos()9cos()( xxxf += )10cos()9cos( xx +=

    =

    2cos

    219

    cos2 xx

    =

    4cos

    419

    cos22

    pipipif ; 12

    1212

    2=

    =

    pif .

    20. (d) acx

    baxy

    +=

    aybacyx += )( )(yfacybay

    x =

    += .

    21. (b) domain of 2log x is R-{0} and the domain of ||log x is also R-{0}.

    2log x and ||log2 x are identical functions.

    22. (b) )0()0()()( xfxfxfxf =+= is symmetrical about 0=x . )2()2( xfxf =+ is symmetrical about 2=x .

    23. (c) 422

    1

    422

    1)(

    ++

    =

    xxxx

    xf

    18211

    1

    18211

    1)11(

    ++

    =f

    76

    723

    723

    231

    231

    =

    ++

    =

    ++

    = .

    24. (b) 43)( = xxf . let xyfxfy == )()(1

    4343 +== xyxy

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    34)(

    34 1 +

    =+

    = x

    xfxy .

    25. (a) A function is invertible if it is bijection.

    26. (a)

    +=

    +

    =

    yy

    xyxx

    xx

    11log

    21

    10101010

    10

    Let )(xfy = )(1 yfx =

    +=

    yyyf

    11log

    21)( 101

    +=

    x

    xxf

    11log

    21)( 101

    27. (d) x

    xxf

    +=

    1)( . Let )()( 1 yfxxfy ==

    xyxyx

    xy =++

    =

    1

    yy

    x

    =

    1

    y

    yyf

    =

    1)(1

    x

    xxf

    =

    1)(1 .

    28. (b)

    +==

    21)())(()()()(

    x

    xfofxffofxfofof

    ++

    +=

    ++

    +=

    22

    2

    2

    2

    2

    211

    1

    11

    1

    xx

    xxf

    x

    x

    x

    x

    f

    .

    3121

    1

    2121 2

    2

    2

    2

    2x

    x

    x

    x

    x

    x

    x

    xf+

    =

    ++

    +=

    +=

    29. (a) xaxFxfF xa a === log)(log)]([ xaxaafxFf axax ==== loglog)()]([ .

    30. (d) xxx

    x

    x

    x

    x

    x

    x

    xfxgfxfog =+

    =

    +

    =

    ==

    111

    11

    ))(())(( .

    31. (d)

    1.

    11

    11)()())((

    2

    ++=

    +

    +

    +=

    +=

    xx

    x

    x

    x

    x

    x

    xfxf

    xff

    1)1(

    .

    2

    ++=

    x

    xx

    or 0)1)1(( 2 =++ xx

    Or 0)1()1( 22 =++ xx .

    01,01 2 ==+ , 1= .

    32. (c) { } xxaaxfaxff nnnn === /1/1 )]([])([)]([ .

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    33. (d) When 11 =x and 12 =x , then

    0)1()1()1(1111)1()1( ==

    +

    = fffff

    Which is satisfied when

    +

    =

    x

    xxf

    11

    tan)( 1

    When 021 == xx , then

    0)0()0(0100)0()0( ==

    = fffff

    When 11 =x and 02 =x then

    0)0()1(0101)0()1( ==

    = fffff

    Which is satisfied when

    +

    =

    x

    xxf

    11log)( and

    +=

    x

    xxf

    11log)( .

    34. (a)

    = QxxQxx

    xgf,

    ,))((

    35. (b)

    21 yye x ++=

    21 yye x +=

    )1()( 22 yye x +=

    xxxx yeeyyeye 2112 2222 =+=+

    xxx

    x

    eeye

    ey == 2122

    2

    xx eey

    = .

    36. (b)

    21

    11|1|

    |1|1)1( ==

    =f .

    37. (c) axyayxayxf =+ ),( ..(i) Let uayx =+ and vayx =

    Then 2

    vux

    +=

    and a

    vuy2

    =

    Substituting the value of x and y in (i), we obtain

    4),(

    22 vuvuf =

    4),(

    22 yxyxf = .

    38. (c)

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    39. (d) ][)( xxxf =, here [x]=2

    2)( == xyxf 2)()(2 11 +==+= xxfyfyx .

    40. (a)

    =

    3logsin 3

    1 xy 1

    3log1 3

    x

    333

    1 x 91 x ]9,1[x .

    41. (a) )]2/([logsin)( 21 xxf = , Domain of x1sin is ]1,1[x

    1)2/(log1 2 x 2221 x

    41 x

    ]4,1[x .

    42. (c)

    )64log()( xxxf +=

    04 x and 06 x 4x and 6x

    Domain of )(xf = ]6,4[ .

    43. (b) We have 2/1

    2

    10 45log)(

    =

    xxxf ..(i)

    From (i), clearly )(xf is defined for those values of x for which 04

    5log2

    10

    xx

    14

    5104

    5 202

    xxxx

    0452 + xx 0)4)(1( xx

    44. (b) 22 2 0x x 1 3 1 3.x + 45. (d) 101 + xx ; 0,101 xxx

    Domain is }0{]1,1[ .

    46. (d)

    1011 >> xx

    . Also, 0x .

    Required interval ),1()0,( =

    47. (d)

    ( 2) ( 3) 0x x + Domain is { }3,2,: xxRxx . 48. (a) 0|| >xx

    xx >|| but xx =|| for x positive and xx >|| for x negative. Domain is )0,( .

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    49. (b) Let yxxy sinsin 1 == 10,sin 2 = xyx

    50. (b) [ ]2||log)3(sin)(

    1

    =

    x

    xxf

    Let )3(sin)( 1 xxg = 131 x

    Domain of )(xg is [2, 4] And let [ ]2||log)( = xxh 02|| >x 2|| >x 2x ),2()2,(

    We know that

    =))(/( xgf { }0)(:)()(

    21 = xgRxDDxxgxf

    Domain of }3{]4,2()( =xf ]4,3()3,2( = .

    51. (d) Here 03 >+x and 0232 ++ xx 3>x and ,0)2)(1( ++ xx i.e. 2,1 x

    Domain }2,1{),3( =

    52. (c)

    012 >x

    ,12 >x 1or 1 >< xx and 03 >+ x

    3>x and 2x

    ),1()1,2()2,3( =fD .

    53. (d) )(log4

    3)( 3102 xxxxf +

    = . 04 2 x 4x

    0)1(0 23 >> xxxx 1,0 >> xx

    54. (b) 16

    506

    5log22

    xxxx or 0652 + xx or 0)3()2( xx . Hence .32 x

    55. (c) 0)66log( 2 + xx 1662 + xx 0)1)(5( xx

    1x or 5x . Domain is ),5[]1,( .

    56. (d) 0235 2 xx 023)1(

    xx

    Domain is [1,3 / 2] .

    + +

    1 0 1

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    57. (b) 3339 2

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    023 x

    0,

    23

    x

    Domain of function =

    0,23

    .

    67. (b) |2|2)(

    +

    +=

    x

    xxf

    22

    ,1,1)(

    >

    yyy

    0)1293(4)1449(4 22 >++ yyyy

    0483612561964 22 >++ yyyy

    016088 2

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    72. (c)

    43

    2111)( 2

    +

    +

    +=

    x

    xf Range ]3/7,1(= .

    73. (c) xxxfy 42 sincos)( +== )cos1(sincos)( 222 xxxxfy +==

    xxxxy 2222 cossinsincos +=

    xxy 22 cossin1 = xy 2sin.411 2=

    1)(43 xf , )12sin0( 2 x

    ]1,4/3[)( Rf .

    74. (b)

    +R {as y is always positive }Rx .

    75. (b)

    .sin79)( xxfy == Range ].16,2[=

    76. (a)

    = xxf 2cos

    4sec)( pi

    1cos0 2 x at ,0cos =x 1)( =xf and at ,1cos =x 2)( =xf ; 21 x ]2,1[x .

    77. (d)

    dcbxaxf ++= )cos()( ..(i) For minimum 1)cos( =+ cbx

    )()( addaxf =+=

    For maximum 1)cos( =+ cbx

    )()( addaxf +=+=

    Range of ],[)( adadxf += .

    78. (c) Let 12

    2

    +=

    x

    xy

    1,10)1( 2 =++ yyxxy For real values of x,

    We have )1,0[0)1(0)1(40 yyyyyD

    11

    0 22

    , 2sec

    4sec 2 . Required interval ),2[ =

    81. (a) The domain of { }log [ ]e x x is R, because [x] 0

    82. (d) Let 12 += xy 1= yx

    1)(1 = yyf 1)(1 = xxf

    4117)17(1 ==f and 413)3(1 ==f , which is not possible

    83. (c) |].cos[|)}({)( xxfgxgof == 84. (b) Here Znxnnxg ==+= ,11)(

    knkn +=++ 11 , knx += (where 10,

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    ( ) ( ) 0f x f x + =

    )(xf is odd function.

    92. (b) ( )( ) | sin |gof x x= and xxf 2sin)( = 2(sin ) | sin |g x x= ; ( )g x x= . 93. (b) 6 4 2( ) 2 3 4f x x x x= + +

    6 4 2( ) 2( ) 3( ) 4( ) ( )f x x x x f x = + + =

    )(xf is an even function and derivative of an even function is always odd.

    94. (b) )1log()( 2 ++= xxxf and )1log()( 2 ++= xxxf )(xf=

    )(xf is odd function.

    95. (c) 96. (c) (1) 0, (2) 1, (3) 1, (4) 2, (5) 2f f f f f= = = = =

    And 3)6( =f so on.

    No two elements of domain have same image. And range of the function is set of all integers. Hence f is one-one and onto function.

    97. (a) Let Nyx , such that )()( yfxf = Then 11)()( 22 ++=++= yyxxyfxf

    ( )( 1) 0x y x y x y + + = = Or Nyx = )1(

    f is one-one. Again, since for each Ny , there exist Nx

    f is onto. 98. (b) )3)(2)(1()( = xxxxf

    0)3()2()1( === fff )(xf is not one-one.

    For each Ry , there exists Rx such that yxf =)( . Therefore f is onto. Hence RRf : is onto but not one-one.

    99. (b) ),0[,0)1(1)( 2 >+=

    xx

    xf and range )1,0[

    Function is one-one but not onto

    100. (a)

    0cos2)( >+= xxf . So, )(xf is strictly monotonic increasing so, )(xf is one-to-one and onto.

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    101. (d) ||)( 2 xxxxxf +=+= Clearly f is not one-one as 0)2()1( == ff f is not one-one

    ,,0)( Rxxf Range of Rf = ),0( . f is not onto.

    102. (b) Let yxx

    xx=

    +

    +

    727134

    2

    2

    0)717()17(2)1(2 =++ yxyyx

    0

    5,9045142 + yyyy .

    103. (a) 111 1( ) ( ( ) ) ,11 11

    x

    x xfof x f f x f x xxx

    x

    += = = =

    + ++

    fIfof = is the inverse of itself.

    104. (b) f is one-one and onto, so 1f exists and is 3

    5)(1 += xxf .

    105. (a) 22 )3(1)cos3(sin)3(1 ++ xx 2)cos3(sin2 xx

    12)1cos3(sin12 +++ xx

    3)1cos3(sin1 + xx i.e., range ]3,1[=

    For f to be onto ]3,1[=S 106. (b) For any ,, Ryx we have

    yxnymy

    nx

    mxyfxf =

    =

    = )()(

    f is one-one.

    Let R such that =

    =nx

    mxxf )(

    =

    1nm

    x

    Clearly Rx for 1= . So, f is not onto.

    107. (c) Let )()( yfxf = 44

    44

    2

    2

    2

    2

    +

    =

    +

    yy

    x

    x

    441441

    44 22

    2

    2

    2

    2+=+

    +

    =

    +

    yxyy

    x

    x

    yx = , )(xf is many-one.

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    Now for each ),1,1(y there does not exist Xx such that yxf =)( . Hence f is into. 108. (c) 21222121 )()( xxxxxfxf === , [if ]+= RX

    f is one-one. Since YRRR f == + ; f is not onto.

    109. (d) 0)1()0( == ff hence )(xf is many one. But there is no pre-image of 1 . Hence )(xf is into function. So function is many-one into.