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Chapter 11 Fluids

Fluid 1

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Page 1: Fluid 1

Chapter 11

Fluids

Page 2: Fluid 1

11.1 Mass Density

DEFINITION OF MASS DENSITY

The mass density of a substance is the mass of a substance divided by its volume:

V

m

SI Unit of Mass Density: kg/m3

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11.1 Mass Density

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11.1 Mass Density

Example 1 Blood as a Fraction of Body Weight

The body of a man whose weight is 690 N contains about5.2x10-3 m3 of blood.

(a) Find the blood’s weight and (b) express it as a percentage of the body weight.

kg 5.5mkg1060m102.5 333 Vm

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11.1 Mass Density

N 54sm80.9kg 5.5 2 mgW(a)

(b) %8.7%100N 690

N 54Percentage

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11.2 Pressure

A

FP

SI Unit of Pressure: 1 N/m2 = 1Pa

Pascal

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11.2 Pressure

Example 2 The Force on a Swimmer

Suppose the pressure acting on the backof a swimmer’s hand is 1.2x105 Pa. Thesurface area of the back of the hand is 8.4x10-3m2.

(a)Determine the magnitude of the forcethat acts on it.(b) Discuss the direction of the force.

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11.2 Pressure

A

FP

N 100.1

m104.8mN102.13

2325

PAF

Since the water pushes perpendicularly against the back of the hand, the forceis directed downward in the drawing.

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11.2 Pressure

Atmospheric Pressure at Sea Level: 1.013x105 Pa = 1 atmosphere

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11.3 Pressure and Depth in a Static Fluid

012 mgAPAPFy

mgAPAP 12

Vm

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11.3 Pressure and Depth in a Static Fluid

VgAPAP 12

AhV

AhgAPAP 12

hgPP 12

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11.3 Pressure and Depth in a Static Fluid

Conceptual Example 3 The Hoover Dam

Lake Mead is the largest wholly artificial reservoir in the United States. The waterin the reservoir backs up behind the damfor a considerable distance (120 miles).

Suppose that all the water in Lake Meadwere removed except a relatively narrowvertical column.

Would the Hoover Same still be neededto contain the water, or could a much lessmassive structure do the job?

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11.3 Pressure and Depth in a Static Fluid

Example 4 The Swimming Hole

Points A and B are located a distance of 5.50 m beneath the surface of the water. Find the pressure at each of these two locations.

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11.3 Pressure and Depth in a Static Fluid

Pa 1055.1

m 50.5sm80.9mkg1000.1Pa 1001.15

233

pressure catmospheri

52

P

ghPP 12

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11.4 Pressure Gauges

ghPP 12

ghPatm

mm 760m 760.0

sm80.9mkg1013.6

Pa 1001.1233

5

g

Ph atm

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11.4 Pressure Gauges

AB PPP 2

ghPPA 1

ghPP atm pressure gauge

2

absolute pressure

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11.4 Pressure Gauges

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11.5 Pascal’s Principle

PASCAL’S PRINCIPLE

Any change in the pressure applied to a completely enclosed fluid is transmitted undiminished to all parts of the fluid and enclosing walls.

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11.5 Pascal’s Principle

m 012 gPP

1

1

2

2

A

F

A

F

1

212 A

AFF

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11.5 Pascal’s Principle

Example 7 A Car Lift

The input piston has a radius of 0.0120 mand the output plunger has a radius of 0.150 m.

The combined weight of the car and the plunger is 20500 N. Suppose that the inputpiston has a negligible weight and the bottomsurfaces of the piston and plunger are atthe same level. What is the required inputforce?

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11.5 Pascal’s Principle

N

m

m N F 131

150.0

0120.020500 2

2

1

1

212 A

AFF

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11.6 Archimedes’ Principle

APPAPAPFB 1212

ghPP 12

ghAFB

hAV

gVFB

fluiddisplaced

of mass

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11.6 Archimedes’ Principle

ARCHIMEDES’ PRINCIPLE

Any fluid applies a buoyant force to an object that is partiallyor completely immersed in it; the magnitude of the buoyantforce equals the weight of the fluid that the object displaces:

fluid displaced

ofWeight

fluid

forcebuoyant of Magnitude

WFB

Page 24: Fluid 1

11.6 Archimedes’ Principle

If the object is floating then the magnitude of the buoyant forceis equal to the magnitude of itsweight.

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11.6 Archimedes’ Principle

Example 9 A Swimming Raft

The raft is made of solid squarepinewood. Determine whetherthe raft floats in water and ifso, how much of the raft is beneaththe surface.

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11.6 Archimedes’ Principle

N 47000

sm80.9m8.4mkg1000 233

max

gVVgF waterwaterB

m m m m Vraft 8.430.00.40.4

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11.6 Archimedes’ Principle

N 47000N

smmmkg

gVgmW

233

raftpineraftraft

26000

80.98.4550

The raft floats!

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11.6 Archimedes’ Principle

gVwaterwaterN 26000

Braft FW

If the raft is floating:

23 sm80.9m 0.4m 0.4mkg1000N 26000 h

m 17.0sm80.9m 0.4m 0.4mkg1000

N 2600023

h

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11.6 Archimedes’ Principle

Conceptual Example 10 How Much Water is Neededto Float a Ship?

A ship floating in the ocean is a familiar sight. But is allthat water really necessary? Can an ocean vessel floatin the amount of water than a swimming pool contains?

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11.6 Archimedes’ Principle

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11.7 Fluids in Motion

In steady flow the velocity of the fluid particles at any point is constant as time passes.

Unsteady flow exists whenever the velocity of the fluid particles at a point changes as time passes.

Turbulent flow is an extreme kind of unsteady flow in which the velocity of the fluid particles at a point change erratically in both magnitude and direction.

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11.7 Fluids in Motion

Fluid flow can be compressible or incompressible. Most liquids are nearly incompressible.

Fluid flow can be viscous or nonviscous.

An incompressible, nonviscous fluid is called an ideal fluid.

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11.7 Fluids in Motion

When the flow is steady, streamlines are often used to representthe trajectories of the fluid particles.

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11.7 Fluids in Motion

Making streamlines with dyeand smoke.

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11.8 The Equation of Continuity

The mass of fluid per second that flows through a tube is calledthe mass flow rate.

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11.8 The Equation of Continuity

2222 vA

t

m

111

1 vAt

m

distance

tvAVm

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11.8 The Equation of Continuity

222111 vAvA

EQUATION OF CONTINUITY

The mass flow rate has the same value at every position along a tube that has a single entry and a single exit for fluid flow.

SI Unit of Mass Flow Rate: kg/s

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11.8 The Equation of Continuity

Incompressible fluid: 2211 vAvA

Volume flow rate Q: AvQ

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11.8 The Equation of Continuity

Example 12 A Garden Hose

A garden hose has an unobstructed openingwith a cross sectional area of 2.85x10-4m2. It fills a bucket with a volume of 8.00x10-3m3

in 30 seconds.

Find the speed of the water that leaves the hosethrough (a) the unobstructed opening and (b) an obstructedopening with half as much area.

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11.8 The Equation of Continuity

AvQ

sm936.0

m102.85

s 30.0m1000.824-

33

A

Qv

(a)

(b) 2211 vAvA

sm87.1sm936.0212

12 v

A

Av

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11.9 Bernoulli’s Equation

The fluid accelerates toward the lower pressure regions.

According to the pressure-depthrelationship, the pressure is lowerat higher levels, provided the areaof the pipe does not change.

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11.9 Bernoulli’s Equation

2222

11

212

1nc mgymvmgymvW

VPPAsPsFsFW 12

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11.9 Bernoulli’s Equation

2222

11

212

112 mgymvmgymvVPP

2222

11

212

112 gyvgyvPP

BERNOULLI’S EQUATION

In steady flow of a nonviscous, incompressible fluid, the pressure, the fluid speed, and the elevation at two points are related by:

2222

121

212

11 gyvPgyvP

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11.10 Applications of Bernoulli’s Equation

Conceptual Example 14 Tarpaulins and Bernoulli’s Equation

When the truck is stationary, the tarpaulin lies flat, but it bulges outwardwhen the truck is speeding downthe highway.

Account for this behavior.

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11.10 Applications of Bernoulli’s Equation

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11.10 Applications of Bernoulli’s Equation

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11.10 Applications of Bernoulli’s Equation

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11.10 Applications of Bernoulli’s Equation

Example 16 Efflux Speed

The tank is open to the atmosphere atthe top. Find and expression for the speed of the liquid leaving the pipe atthe bottom.

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11.10 Applications of Bernoulli’s Equation

2222

121

212

11 gyvPgyvP

atmPPP 2102 v

hyy 12

ghv 212

1

ghv 21

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11.11 Viscous Flow

Flow of an ideal fluid.

Flow of a viscous fluid.

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11.11 Viscous Flow

FORCE NEEDED TO MOVE A LAYER OF VISCOUS FLUID WITHCONSTANT VELOCITY

The magnitude of the tangential force required to move a fluid layer at a constant speed is given by:

y

AvF

coefficient of viscosity

SI Unit of Viscosity: Pa·s

Common Unit of Viscosity: poise (P)

1 poise (P) = 0.1 Pa·s

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11.11 Viscous Flow

POISEUILLE’S LAW

The volume flow rate is given by:

L

PPRQ

812

4

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11.11 Viscous Flow

Example 17 Giving and Injection

A syringe is filled with a solution whose viscosity is 1.5x10-3 Pa·s. The internalradius of the needle is 4.0x10-4m.

The gauge pressure in the vein is 1900 Pa.What force must be applied to the plunger,so that 1.0x10-6m3 of fluid can be injected in 3.0 s?

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11.11 Viscous Flow

Pa 1200

m104.0

s 0.3m100.1m 025.0sPa105.18

8

44-

363

42

R

LQPP

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11.11 Viscous Flow

Pa 120012 PP

Pa 19001 P

Pa 31002 P

N25.0m100.8Pa 3100 252 APF