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Factor.
64x144x81 2
8-6 Perfect Squares and Factoring
Algebra 1 Glencoe McGraw-Hill Linda Stamper
In the previous lesson you worked with the difference of two squares (sum and difference pattern). Today the focus is on perfect square trinomials (square of a binomial pattern).
For a trinomial to be factorable as a perfect square, three conditions must be satisfied.
25x20x4 2
The first term must be a
perfect square.
The middle term must be twice the
product of the square roots of the first and last terms.
The last term must be a
perfect square.
2x4 x225 5
x105x2 x202x10
25x2
2x
x +
2Remember the square of a binomial is a SQUARE ?
4x4x2x 22
3x x +
3
9x6x3x 22
4x x +
4
16x8x4x 22
To find the product…
16x8x4x
9x6x3x
4x4x2x
22
22
22
25x
Square first term.
Multiply the terms and then
double it.
Square last term.
25x10x2 26x 36x12x2
22x2 4x8x4 2 23x2 9x12x4 2 25x3 25x30x9 2 26x4 36x48x16 2
Factoring is working backwards from multiplying!
Think – What is the square of the
first term and what is the
square of the second term.
22x2 Can you
factor out a greatest monomial
factor?
Square of a Binomial Pattern
16x8x4x
9x6x3x
4x4x2x
22
22
22
25x 25x10x2
26x 36x12x2
4x8x4 2 23x2 9x12x4 2
25x3 25x30x9 2
26x4 36x48x16 2
Which answer/s are not factored
completely?
21x4
1x2 1x22x2 2x2
23x24
3x22 3x226x4 6x4
21x4
1x2 1x22x2 2x2
Could you use the X-Factor method to
factor these problems?
Factor.
64x144x81 2 28x9
8x98x9
Do you recognize this Square of a Binomial Pattern?
16x8x4x
9x6x3x
4x4x2x
22
22
22
Square first term.
Multiply the terms and then double it. Note: middle
term is negative!
Square last term.
2x x –
2The middle term is always negative?
4x4x2x 22
Square of a Binomial Pattern
16x8x4x
9x6x3x
4x4x2x
22
22
22
25x 25x10x2 26x 36x12x2
22x2 4x8x4 2 24x3 16x24x9 2
25x4 25x40x16 2
Which answer/s are not factored
completely?
21x4
1x2 1x2
2x2 2x2
Example 1 100y60y9 2
210y3
Check using FOIL!
Determine whether each trinomial is a perfect square trinomial. If so, factor it.
Example 2 81m144m64 2 29m8
Example 3
4m12m9 2 22m3
Example 4 64y32y16 2
.T.S.Panot
Example 5 25y40y16 2 25y4
Example 6 x6036x25 2
26x5
Example 7 9n24n16 2
23n4
Example 8 81y9y2
.T.S.Panot
Example 9 9x30x25 2
23x5
When solving equations involving repeated factors, it is only necessary to set one of the repeated factors equal to zero.
2516
x58
x2
02516
x58
x2
054
x2
054
x
54
x
or054
x
58
54
2
Double
root!
Use factoring to solve the equation. Remember if it is a perfect square, it is only necessary to set one of the repeated factors equal to zero
036a12a2
Example 10 Example 11
094
y34
y2
x3681x4 2
Example 12 Example 13 16d24d9 2
x9x12x4 23
Example 14 Example 15
41
xx2
036a12a2
Example 10 Example 11
094
y34
y2
6a
32
y
06a 2 06a 0
32
y2
032
y
x3681x4 2
Example 12 Example 13 16d24d9 2
29
x
34
d
081x36x4 2
09x2 2 09x2
9x2
016d24d9 2
04d3 2 04d3
4d3
x9x12x4 23
Example 14 Example 14
23
x
0x9x12x4 3
09x12x4x 2
03x2x 2
3x2 03x2or0x
41
xx2
041
xx2
021
x2
021
x
21
x
HOW TO APPROACH FACTORING PROBLEMS
When factoring it is important to approach the problem in the following order. Look at the problem carefully and ask yourself:1. Can I pull out a greatest common factor? If you can, do it, but then look at what is left to check for opportunities to factor again.2. Is this the DIFFERENCE of Two Squares?
22 ba Remember that these never have a middle (x) term. If so, factor it into the ( + )( – ) pattern.
3. Is this a Perfect Square Trinomial? 22
22
bab2a
or bab2a
If so, it will factor into two parentheses that are exactly the same and can be written as a square. 22 3x or 3x
Check by doing FOIL. Remember that factoring is working backwards from multiplying.
Always look at what remains and check for opportunities to factor further.
4. If you examined the problem closely and answered the above
questions each with a NO, then you must factor using the X figure. Use the X-Factor method if the leading coefficient does not equal 1.
HOW TO APPROACH FACTORING PROBLEMS
5. If there are four or more terms look to factor by grouping. Group terms with common factors and then factor out the GCF from each grouping. Then use the distributive property a second time to factor a common binomial factor.
8-A12 Pages 458-460 #12–30,57–60.