5
1 Solution of a System of ODEs with POLYMATH and Excel, Parametric Studies with Excel ( ) ( ) ( ) x y y y f dx dy x y y y f dx dy x y y y f dx dy n n n n n , , , , , , , , , 2 1 2 1 2 2 2 1 1 1 K M K K = = = 0 , 0 0 , 2 0 2 0 , 1 0 1 ) ( ) ( ) ( n n y x y y x y y x y = = = M The canonical form of a system of n simultaneous first-order ordinary differential equations ODE with specified initial values (initial value problem) is: where x is the independent variable and y 1 , y 2 , . . . y n are dependent variables Adiabatic Operation of a Tubular Reactor for Cracking of Acetone The irreversible, vapor-phase cracking of acetone (A) to ketene (B) and methane (C) that is given by the reaction: CH 3 COCH 3 CH 2 CO + CH 4 is carried out adiabatically in a tubular reactor. The reaction is first order with respect to acetone and the specific reaction rate can be expressed by T k 34222 34 . 34 ln - = The acetone feed flow rate to the reactor is F A mol/s, the inlet temperature is T = 1150 K and the reactor operates at the constant pressure of P = 162 kPa (1.6 atm). The volume of the reactor is V = 4 m 3 . Inert gas (nitrogen) is fed at the rate of F N mol/s.

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Page 1: f ( )y y y yn x - TAU

1

Solution of a System of ODEs with POLYMATH and Excel,

Parametric Studies with Excel

( )

( )

( )xyyyfdx

dy

xyyyfdx

dy

xyyyfdx

dy

nn

n

n

n

,,,

,,,

,,,

21

2122

211

1

K

M

K

K

=

=

=

0,0

0,202

0,101

)(

)(

)(

nn yxy

yxy

yxy

=

=

=

M

The canonical form of a system of n simultaneous first-order

ordinary differential equations ODE with specified initial values

(initial value problem) is:

where x is the independent variable and y1, y2, . . . yn are

dependent variables

Adiabatic Operation of a Tubular Reactor for Cracking of

Acetone

The irreversible, vapor-phase cracking of acetone (A) to ketene

(B) and methane (C) that is given by the reaction:

CH3COCH3→CH2CO + CH4

is carried out adiabatically in a tubular reactor. The reaction is

first order with respect to acetone and the specific reaction rate

can be expressed by

Tk

3422234.34ln −=

The acetone feed flow rate to the reactor is FA mol/s, the inlet

temperature is T = 1150 K and the reactor operates at the constant

pressure of P = 162 kPa (1.6 atm). The volume of the reactor is V

= 4 m3. Inert gas (nitrogen) is fed at the rate of FN mol/s.

Page 2: f ( )y y y yn x - TAU

2

Adiabatic Operation of a Tubular Reactor for Cracking of

Acetone - Assignments

(a) Calculate the flow-rates (in mol/s) and the mole fractions of

acetone, ketene and methane along the reactor for the case where

pure toluene is being fed at the rate of FA = 38.3 g-mol/s. Use

Polymath to calculate and plot the conversion and reactor

temperature (in K) versus volume.

(b) The conversion in the reactor in part (a) is very low in

adiabatic operation because the reactor content cools down very

quickly. It is suggested that feeding nitrogen along with the

acetone might be beneficial in maintaining a higher temperature.

Compare the final conversions and temperatures for the cases

where 28.3, 18.3, 8.3, 3.3 and 0.0 mol/s nitrogen is fed into the

reactor (the total molar feed rate is 38.3 mol/s in all the cases).

Adiabatic Operation of a Tubular Reactor for Cracking of

Acetone – Model Equations

The POLYMATH code provides

complete and clear documentation

Export to Excel

Page 3: f ( )y y y yn x - TAU

3

Adiabatic Operation of a Tubular Reactor for Cracking of

Acetone – Solution for FA

= 38.3 mol/s

Drop of ~120 K in the

temperature reduces the reaction

rate by two orders of magnitude

Low conversion of the reactant

Adiabatic Operation of a Tubular Reactor – Exporting to

Excel and Adding the ODE Solver

Solver Add-In

should be removed

Separate Worksheets are

Prepared for the Various Cases

Page 4: f ( )y y y yn x - TAU

4

Adiabatic Operation of a Tubular Reactor – ODE Solver Add

In Communication Box

Adiabatic Operation of a Tubular Reactor – Comparison of

results for FN

= 0 and FN

= 28.3

Value

0.257272258

-0.437213285

38.3

0

162

12.68958732

0.590745352

0.204627324

0.204627324

0.034454492

79773.92861

154.9084155

80.3112995

67.86057679

14.2009238

28.44647253

9.853527468

9.853527468

907.5421516

-0.437213285

0.437213285

0.437213285

-5.945205114

4

No significant change in the

temperature profile and the

conversion occurs because of the

addition of the inert gas.

Page 5: f ( )y y y yn x - TAU

5

Adiabatic Operation of a Tubular Reactor – Comparison of

results for FN

= 0 and FN

= 28.3

900

920

940

960

980

1000

1020

1040

1060

0 1 2 3 4

Volume (m^3)

Te

mp

era

ture

(K

)

T (FN=0) T(FN=28.3)

Adiabatic Operation of a Tubular Reactor – Comparison of

results for FN

= 0 and FN

= 28.3

0

0.05

0.1

0.15

0.2

0.25

0.3

0.35

0 1 2 3 4

Volume (m^3)

Co

nvers

ion

of

A

X ((FN=0) X5(FN=28.3)