Experiment One - Measurement (Final) Lab Report yolo

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  • 7/29/2019 Experiment One - Measurement (Final) Lab Report yolo

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    Cesar Avila 1/23/13

    Results:

    Part A (measurements of samples to find density):

    Mass (measured with electronic balance):

    Dimensions of Plastic Sample (measured with Vernier calipers):

    Volume (using measurements obtained from Vernier calipers):

    Sample Equation for Plastic Sample 1:

    V=l*w*h

    2.00*1.70*1.45=4.93 cm3

    V=4.93 cm3

    Sample Volume (cm3)

    1 4.932 7.39

    3 9.86

    4 12.33

    Density (using measurements obtained from Vernier caliper):

    Sample Equation for Plastic Sample 1:

    =m/v6.671/4.93=1.3 g/cm3

    =0.883g/cm3

    Sample (g/cm3)1 1.33

    2 1.37

    3 1.38

    4 1.37

    Average Density (using measurements from Vernier calipers):

    =1+2+3+4/4= 1.36 g/cm3

    Sample Mass (g)

    1 6.571

    2 10.119

    3 13.609

    4 16.882

    Sample Length (cm) Width (cm) Height (cm)

    1 2.00 cm 1.70 cm 1.45 cm

    2 3.00 cm 1.70 cm 1.45 cm

    3 4.00 cm 1.70 cm 1.45 cm

    4 5.00 cm 1.70 cm 1.45 cm

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    Volume (using measurements obtained from graduated cylinder)

    Sample Equation for Plastic Sample 1:

    Vfinal Vinitial = Vplastic

    74.3 mL-70.0 mL=4.30 mL

    Sample Vinitial (mL) Vfinal (mL) Vplastic (mL)

    1 70.0 74.3 4.30

    2 70.0 77.2 7.20

    3 70.0 79.9 9.90

    4 70.0 82.0 12.00

    Density (using measurements obtained from graduated cylinder):

    Sample (g/mL)1 1.50

    2 1.41

    3 1.37

    4 1.41

    Average Density (using measurements from graduated cylinder):

    =1+2+3+4/4= 1.42 g/mL

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    Mass (g)

    Volume (cm3)

    Density (Vernier Caliper Measurements)

    Density (Vernier Caliper Measurem

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    Part B (use of density to identify unknown plastic):

    Dimensions of Plastic 1 (cylinder):

    Height 3.50 cmRadius (Diameter/2) 0.50 cm

    Volume of Plastic 1 (cylinder):

    V=r2hV=(.502)(3.50)V=2.75 cm3

    Mass of Plastic 1 (cylinder): 2.298 g

    Density of Plastic 1 (cylinder):

    =m/v=2.298/2.75=0.836 g/cm3

    Identity of Plastic 1 (cylinder): LDPE

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    Mass (g)

    Volume (mL)

    Density (Graduated Cylinder Measurements)

    Serie

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    Discussion Questions:

    1. Explain why significant figures are important to measurement and what theysignify.

    As one of the most heavily scrutinized components of any calculation or setof data, significant figures have proved to be one of the most important

    features in any numerical value given in a lab report. This importance stems

    from the fact that significant figures, for the most part, determine the

    accuracy of ones findings. If one were to rely primarily on calculations doneby a calculator without taking in to account of significant figures, then they

    would ultimately be left with data more accurate than any of the instruments

    that they used to take measurements or find certain values. Since garnering

    results several degrees more accurate than measuring instruments are

    capable of producing is impossible, significant figures show the correct result

    to the closest known degree of accuracy. That being said, by controlling the

    amount of decimal places that one can include in their results, significantfigures signify to the reader how accurately one could measure the data.

    2. Of the measurements you made, which were more precise: the massmeasurements or the volume measurements?

    After having completed all of the measurements necessary to determine the

    density of the plastic sample it was clear that the measurements for volume

    were more precise than those for mass. Since precision is defined as the

    degree to which repeated measurements under unchanged circumstances

    show the same results, it is impossible to measure true precision since the

    samples all vary in terms of dimension and thus both volume and weight. Inorder to determine which was more relatively precise I studied the

    increment of increase between sample variations:

    As evidenced by the charts and the calculations for differences between

    samples, the measurements for volume are more precise because they all increase in

    a linear model of 2.47 cm3 per sample.

    Sample Mass (g)

    1 6.571

    2 10.119

    3 13.609

    4 16.882

    Sample Volume (cm3)

    1 4.93

    2 7.39

    3 9.86

    4 12.33

    Difference: 2.47 cm3

    Difference: 2.47 cm3

    Difference: 2.47 cm3

    Difference: 3.548 g

    Difference: 3.490 g

    Difference: 3.273 g

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    3. Is it practical to use density to separate plastics? Explain.Although density is one of the most readily measurable properties of plastic,

    it is not a very practical means of separating plastics. Since there are several

    plastics that are denser than water then one could put all of the samples in a

    pool of water. By doing this, one could ascertain that the plastics that havesunk have a density of over 1.0 g/mL, which would narrow the possible

    plastics to very few, but not any one in particular. In order to further

    separate the remaining plastics one would need to repeat the process several

    times with liquids of varying densities in order to identify the plastics.

    Perhaps if this were done on a small scale with readily available liquids of

    varying densities then it might be pragmatic but generally speaking, it is not.

    4. Propose another way to separate plastics making use of a different propertyother than density.

    Since melting is one of the most integral steps in recycling, I believe that themost effective way to separate plastics would be to heat the plastics to

    different temperatures to take advantage of their varying melting points. In

    doing so, one would need a large-scale source of heat as well as a chart with

    the melting point values for the various plastics. In order to increase

    accuracy of separation, the samples would start at the lowest possible heat

    and then increase according to the various melting points provided. At each

    level, a different plastic will be identified until you are left with a single one.

    While there are many different means of separating plastics, I believe that

    this is an entirely practical way of doing so.

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    Experiment One: Measurement

    Observations:

    Plastic samples all cut in same shape (rectangular prism) but differ indimensions.

    Plastic samples are all proportional to one another. Exhibit a dark gray color, completely opaque. From sample to sample, the only dimension that changes is the length. This

    means that there are constant values for both height and width.

    Procedure:

    Part A (measurements of sample to obtain density):

    Linear Measurements (Vernier calipers):

    1. Using the electronic balance, record the mass of each of the four samples. Record

    this data.2. Using the Vernier calipers, measure the length, width, and height of each of the

    four samples. Record this data.

    3. Calculate the volume for each sample by inserting the measured values into the

    formula V=lxwxh.

    4. For each sample, divide its mass by its measured volume to obtain the density.

    Graduated Cylinder:

    1. Using the electronic balance, record the mass of each of the four samples. Record

    this data.

    2. Fill a graduated cylinder to a certain volume. Record this volume as the initial

    volume or Vinitial.3. Place the plastic sample inside of the filled graduated cylinder. Record the new

    volume of the water as the final volume or Vfinal.

    4. Subtract the initial volume from the final volume in order to determine the

    displacement of the plastic sample. This displacement will equal the volume.

    5. Repeat for each sample.

    6. For each sample, divide its mass by its measured volume to obtain the density.

    Part B (use of density to identify unknown plastic):

    1. Using the Vernier calipers, measure the height and diameter of the cylinder.

    Divide the diameter in half to obtain the radius.

    2. Calculate the volume of the cylinder using the formula V=r2h.3. Obtain the mass of the cylinder using the electronic balance.

    4. Divide the mass by the calculated volume in order to find the density of the

    sample.

    5. Compare the calculated density with the literature values to determine the

    identity of the sample.