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8/13/2019 Example Relation
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Example 1.What is the relative closure of the relationR= {(a, b) | a < b }
on the set of integers?
Solutions:The reflexive closure ofRis
R = {(a, b) | a < b } {(a, a) | a Z} = {(a, b) | a b}.
Example 2.What is the symmetric closure of the relationR = {(a, b) | a >
b}on the set of positive integers?
Solutions:The symmetric closure of R is the relation
R R-1= {(a, b) | a > b} {(b, a) | a > b} ={(a, b) | a b}
Example 3. LetRbe the relation on the set of all subway stops in New
York City that contains (a, b)if it is possible to travel from stop ato stop
bwithout changing trains What isRnwhen nis a positive integer? What
isR*?
Solution:The relationRncontains (a, b)if it is possible to travel from
stop ato stop bby making at most n 1changes of trains. The relation R*
consists of ordered pairs (a, b)where it is possible to travel from stop ato
stop bmaking as many changes of trains as necessary. (The reader should
verify these statements.)
Example 4. Show that the greatest than or equal relation ()is a partial
ordering on the set of integers.
Solutions:Since a a for every integer a, is reflexive. If a band b
a,then a = b. Hence, is antisymmetric. Finally, is transitive sincea
band bcimply that a c. It follows that is a partial ordering on theset of integers and (Z, )is a poset
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Example 5. The divisibility relation | is a partial ordering on the set of
positive integers, since it is reflexive, antisymmetric, and transitive, as
was shown in Section 6.1 We see that (Z+, |)is a poset (Z
+denotes the set
of positive integers.)
Example 6. Show that the inclusion relation is a partial ordering on the
power set of a set S.
Solutions:SinceA AwheneverAis a subnet of S, is reflexive. It is
antisymmetric sinceA BandB Aimply thatA = B. Finally is
transitive, sinceA BandB Cimply thatA C. Hence, is a partial
ordering onP(S), and (P(S), )is a poset
Example 7. In the poset (Z+, |),are the integers 3 and 9 comparable? Are
5 and 7 comparable?
Solutions: The integers 3 and 9 are comparable, since 3 | 9. The integers
5 and 7 are in comparable, because 5 is not divisible by 7 and 7 is not
divisible by 5
Example 8. The poset (Z, )is totally ordered, since a bor b a
whenever aand bare integers.
Example 9. The poset (Z+, |)is not totally ordered since is contains
elements that are in comparable, such as 5 and 7.
Example 10.Let Sbe a set. Determine whether there is a greatest
element and a least element in the poset (P(S), ).
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