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11/5/2004 Example A Small Signal Analysis of a MOSFET Amp.doc 1/4 Jim Stiles The Univ. of Kansas Dept. of EECS Example: A Small-Signal Analysis of a MOSFET Amplifier Let’s again consider this simple NMOS Amplifier: We can perform a small-signal analysis to determine the small-signal open-circuit voltage gain vo A : () () o vo i vt A vt = 15.0 V 5 D R K = () () D D d i t I i t = + + . 40V () i v t () () O DS o v t V v t = + 2 0.25 mA/V 2.0 V t K V = =

Example a Small Signal Analysis of a MOSFET Amp

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Page 1: Example a Small Signal Analysis of a MOSFET Amp

11/5/2004 Example A Small Signal Analysis of a MOSFET Amp.doc 1/4

Jim Stiles The Univ. of Kansas Dept. of EECS

Example: A Small-Signal Analysis of a MOSFET

Amplifier Let’s again consider this simple NMOS Amplifier:

We can perform a small-signal analysis to determine the small-signal open-circuit voltage gain voA :

( )( )

ovo

i

v tAv t

=

15.0 V

5DR K=

( ) ( )D D di t I i t= +

+

.4 0V

( )iv t

( ) ( )O DS ov t V v t= +

20.25 mA/V

2.0 Vt

K

V

=

=

Page 2: Example a Small Signal Analysis of a MOSFET Amp

11/5/2004 Example A Small Signal Analysis of a MOSFET Amp.doc 2/4

Jim Stiles The Univ. of Kansas Dept. of EECS

Step 1: DC Analysis Turning off the small signal source leaves a DC circuit of: We ASSUME saturation, so that we ENFORCE:

( )2tGSDI K V V= −

It is evident that:

4.0 VGSV =

Therefore the DC drain current is:

( )220.25(4 2)

1.0 mA

tGSDI K V V= −

= −

=

Thus, the DC voltage DSV can be determined from KVL as:

15.015.0 1(5)10.0 V

DS D DV I R= −

= −

=

We CHECK our results and find:

4.0 2.0tGSV V= > =

15.0 V

5DR K= DI

.4 0V

DSV

Page 3: Example a Small Signal Analysis of a MOSFET Amp

11/5/2004 Example A Small Signal Analysis of a MOSFET Amp.doc 3/4

Jim Stiles The Univ. of Kansas Dept. of EECS

and: 10.0 2.0tGSDSV V V= > − =

Step 2: Determine the small-signal parameters We find that the transconductance is:

( )22(0.25)(4.0 2.0)

mA1 V

m tGSg K V V= −

= −

=

Note that no value of λ was given, so we will assume 0λ = , and thus output resistance or = ∞ . Steps 3 and 4: Determine the small-signal circuit We now turn off the two DC voltage source, and replace the MOSFET with its small signal model. The result is our small-signal circuit:

+ vgs

-

m gsg v

0gi =di

di

G D

S

5K

( )ov t

+

( )iv t

Page 4: Example a Small Signal Analysis of a MOSFET Amp

11/5/2004 Example A Small Signal Analysis of a MOSFET Amp.doc 4/4

Jim Stiles The Univ. of Kansas Dept. of EECS

Step 5: Analyze the small-signal circuit The analysis of this small-signal circuit is fairly straightforward. First, we note that:

gs iv v=

and that:

1.0m gsd

gs

gs

i g vv

v

=

=

=

and that:

5o dv i= −

Combing these equations, we find that:

5o iv v= −

And thus the small-signal open-circuit voltage gain of this amplifier is:

( ) 5.0( )

ovo

i

v tAv t

= = −