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EXAMPLE 1 Write an exponential function Write an exponential function y = ab whose graph passes through (1, 12) and (3, 108). x SOLUTION STEP 1 Substitute the coordinates of the two given points into y = ab . x 12 = ab 1 108 = ab 3 Substitute 12 for y and 1 for x. Substitute 108 for y and 3 for x. STEP 2 Solve for a in the first equation to obtain a = , and substitute this expression for a in the second equation. 12 b

EXAMPLE 1 Write an exponential function Write an exponential function y = ab whose graph passes through (1, 12) and (3, 108). x SOLUTION STEP 1 Substitute

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EXAMPLE 1 Write an exponential function

Write an exponential function y = ab whose graph passes through (1, 12) and (3, 108).

x

SOLUTION

STEP 1 Substitute the coordinates of the two given points into y = ab .

x

12 = ab1

108 = ab3

Substitute 12 for y and 1 for x.

Substitute 108 for y and 3 for x.

STEP 2 Solve for a in the first equation to obtain

a = , and substitute this expression for

a in the second equation.

12 b

EXAMPLE 1 Write an exponential function

108 = b312 b

108 = 12b2

29 = b

3 = b

Substitute for a in second equation.

12 b

Simplify.

Divide each side by 12.

Take the positive square root because b > 0.

STEP 3 Determine that a = 12 b = 12

3 = 4. so, y = 4 3 .x

EXAMPLE 2 Find an exponential model

• Draw a scatter plot of the data pairs (x, ln y). Is an exponential model a good fit for the original data pairs (x, y)?

• Find an exponential model for the original data.

A store sells motor scooters. The table shows the number y of scooters sold during the xth year that the store has been open.

Scooters

EXAMPLE 2 Find an exponential model

SOLUTION

Use a calculator to create a table of data pairs (x, ln y).

STEP 1

Plot the new points as shown. The points lie close to a line, so an exponential model should be a good fit for the original data.

STEP 2

x 1 2 3 4 5 6 7

ln y 2.48 2.77 3.22 3.58 3.91 4.29 4.56

EXAMPLE 2 Find an exponential model

STEP 3

Find an exponential model y = ab by choosing two points on the line, such as (1, 2.48) and (7, 4.56). Use these points to write an equation of the line. Then solve for y.

x

ln y – 2.48 = 0.35(x – 1)

ln y = 0.35x + 2.13

y = e0.35x + 2.13

y = e (e )2.13 0.35 x

y = 8.41(1.42) x

Equation of line

Simplify.

Exponentiate each side using base e.

Use properties of exponents.

Exponential model

EXAMPLE 3 Use exponential regression

SOLUTION

Use a graphing calculator to find an exponential model for the data in Example 2. Predict the number of scooters sold in the eighth year.

Scooters

Enter the original data into a graphing calculator and perform an exponential regression. The model is y = 8.46(1.42) .x

Substituting x = 8 (for year 8) into the model gives y = 8.46(1.42) 140 scooters sold.

8

GUIDED PRACTICE for Examples 1, 2 and 3

Write an exponential function y = ab whose graph passes through the given points.

x

1. (1, 6), (3, 24)

SOLUTION

STEP 1 Substitute the coordinates of the two given points into y = ab .

x

6 = ab1

24 = ab3

Substitute 6 for y and 1 for x.

Substitute 24 for y and 3 for x.

GUIDED PRACTICE for Examples 1, 2 and 3

STEP 2 Solve for a in the first equation to obtain

a = , and substitute this expression for

a in the second equation.

6 b

24 =b3

6 b

24 = 6b2

24 = b

2 = b

Substitute for a in second equation.

6 b

Simplify.

Divide each side by 6.

Take the positive square root because b > 0.

STEP 3 Determine that a = 6 b = 6

2 = 3. so, y = 3 2 .x

GUIDED PRACTICE for Examples 1, 2 and 3

Write an exponential function y = ab whose graph passes through the given points.

x

2. (2, 8), (3, 32)

STEP 1 Substitute the coordinates of the two given points into y = ab .

x

8 = ab1

32 = ab3

Substitute 8 for y and 2 for x.

Substitute 32 for y and 3 for x.

SOLUTION

GUIDED PRACTICE for Examples 1, 2 and 3

STEP 2

32 = 8b

4 = b

Divide each side by 4.

Take the positive square root because b > 0.

STEP 3

Solve for a in the first equation to obtain

a = , and substitute this expression for

a in the second equation.

8 b2

32 =b3

8 b2

Substitute for a in second equation.

8 b2

Determine that a = = 8 b2

8 42

816

1 2== .

1 2So, y = 4x

GUIDED PRACTICE for Examples 1, 2 and 3

Write an exponential function y = ab whose graph passes through the given points.

x

3. (3, 8), (6, 64)

STEP 1 Substitute the coordinates of the two given points into y = ab .

x

8 = ab3

64 = ab6

Substitute 8 for y and 3 for x.

Substitute 64 for y and 6 for x.

SOLUTION

GUIDED PRACTICE for Examples 1, 2 and 3

STEP 2

b = 2

Divide each side by 8.

Take the positive square root because b > 0.

Solve for a in the first equation to obtain

a = , and substitute this expression for

a in the second equation.

8 b3

64 =b6

8 b3

Substitute for a in second equation.

8 b3

64= 8b3

b = = 83 64 8 Simplify.

GUIDED PRACTICE for Examples 1, 2 and 3

STEP 3 8 b3Determine that a = = 8

23 8 8 == .1

So, b = 2, a = 1, y = 1 2 = 2 .x x

GUIDED PRACTICE for Examples 1, 2 and 3

SOLUTION

4. WHAT IF? In Examples 2 and 3, how would the exponential models change if the scooter sales were as shown in the table below?

The initial amount would change to 11.39 and the growth rate to 1.45.