Upload
johnny-jany
View
223
Download
0
Embed Size (px)
Citation preview
8/13/2019 Exam Review Word Sph4u1
1/60
EXAM REVIEW - D. O'Hara - SPH4U1
Multiple Choie
Identify the letter of the choice that best completes the statement or answers the question.
____ 1. A football player successfully kicks a field goal through the uprights situated at the south end of the stadium.What are the directions of the instantaneous velocity and acceleration, respectively, of the football at the peak
of its trajectory?
a. south, south d. south, up
b. up, south e. down, down
c. south, down
____ . A race car completes e!actly 1" laps around an oval track. Which of the following pairs of #uantities
concerning its motion would both have values of $ero?
a. displacement, average velocity
b. average speed, average acceleration
c. distance, average speed
d. average speed, average velocity
e. displacement, average speed____ %. A bus drives &"." km '() from town A to town *, then another %"." km '+) to town in a total time of 1.""
h. What are the values of its average speed and average velocity, respectively?a. -"." kmh, -"." kmh '%-/ + of () d. 0"." kmh, -"." kmh '%-/ + of ()
b. -"." kmh, 0"." kmh '%-/ + of () e. 0"." kmh '%-/ + of (), -"." kmh
c. 0"." kmh, 0"." kmh '%-/ + of ()
____ &. Which of the following graphs does 23 depict uniform motion?
a. A and * d. * and 4
b. only e. A and (
c. 4 and (
____ 0. Which of the following graphs depicts uniform motion?
a. A and * d. * and 4
b. and 4 e. ( onlyc. A and
____ 5. Which of the following statements concerning motion graphs is 23 correct?
a. 3he slope of a position6time graph gives velocity.b. 3he area under a velocity6time graph gives displacement.
8/13/2019 Exam Review Word Sph4u1
2/60
c. 3he slope of a velocity6time graph gives acceleration.
d. 3he area under an acceleration6time graph gives velocity.
e. 3he slope of the tangent in a position6time graph gives instantaneous velocity.
____ -. Which of the following statements concerning motion graphs is correct?
a. 3he slope of a position6time graph gives acceleration.
b. 3he area under an acceleration6time graph gives instantaneous velocity.
c. 3he slope of a velocity6time graph gives displacement.
d. 3he area under a position6time graph gives velocity.e. 3he area under a velocity6time graph gives displacement.
____ 7. Which of the following descriptions best represents the acceleration6time graph of a car that pulls away from
a corner when the light turns green, reaches and maintains a constant velocity, then slows down until it stops?Assume that all accelerations are uniform.
a. All three sections of the graph are comprised of hori$ontal lines.
b. 3wo sections of the graph are diagonal lines and one is hori$ontal.
c. 3wo sections of the graph are hori$ontal lines and one is diagonal.
d. All three sections of the graph are comprised of diagonal lines.
e. All three sections of the graph are comprised of curved lines.
____ 8. An object is thrown vertically upward with a speed of 0 ms. 9ow much time passes before it comes backdown at 10 ms? :Air resistance is negligible.;
a. 1." s d. 17 s
b. &.1 s e. - s
c. 8.7 s
____ 1". ?
a. an object, initially at rest, dropped out of a window
b. an object thrown vertically downward from a window
c. an object projected vertically upward from a window
d. an object thrown hori$ontally from a window
e. all of the above
____ 11. 3hree identical objects are thrown from the same height through a window at the same time. 2bject A is
thrown hori$ontally at &." ms, object * is thrown hori$ontally at 7." ms, and object is simply dropped.
8/13/2019 Exam Review Word Sph4u1
3/60
____ 1&. 3hree identical boats set out to cross a river that has a current. *oat A points directly across the river, boat *
points "/ downstream from a point straight across the river, and boat points "/ upstream from a point
straight across the river. Which boat will arrive on the opposite shore first?
a. boat A
b. boat *c. boat
d. it is impossible to tell with the information givene. all three boats will arrive at the same time
____ 10. 3he free6body diagram of a block being pushed up a rough ramp is best represented by
a. A d. 4
b. * e. (
c. ____ 15. 3he free6body diagram of a car in a skid with its brakes locked up is best represented by
a. A d. 4
b. * e. (
c.
____ 1-. An object sits at rest on a ramp. Which of the following free6body diagrams best represents the forces actingon the object?
a. A d. 4
b. * e. (
c.
____ 17. An elevator moves downward at a constant speed. What is the relationship between the gravitational force
acting on the elevator and the tension in the cable?
a. d.
b. e.
c.
8/13/2019 Exam Review Word Sph4u1
4/60
____ 18. According to ewton@s third law, when you walk across a floor, the force that propels you forward is
a. the force applied by your feet on the floor
b. the force of friction of your feet on the floor
c. the force of the floor applied against your feet
d. e!erted upward by the floor on your feet :i.e., the normal force;e. the force acting on you working against gravity
____ ". A &."6kg object, A, and a ."6kg object, *, are connected with a rope. A force is applied to another rope
attached to the ."6kg object that pulls both A and * along a hori$ontal surface. Which of the followingstatements is true?
a. 3he force that * e!erts on A is greater than the force that A e!erts on *.
b. 3he force that A e!erts on * is greater than the force that * e!erts on A.
c. 3he force that * e!erts on A is e#ual to the force that A e!erts on * provided that the
system slides with uniform motion.
d. 3he force that * e!erts on A is e#ual to the force that A e!erts on * regardless of the
motion of the system.
e. 3he sum of the applied force and the force that * e!erts on A is e#ual to the force that A
e!erts on *.
____ 1. 3hree masses are suspended vertically as shown in the diagram below. 3he system is accelerating upward.
What is the relationship among the forces of tension?
a. d.
b. e.
c.
____ . or an object travelling with =uniform circular motion,> its acceleration is
a. $ero because the speed is constant
b. directed tangent to the circle
c. directed toward the centre of the circle
d. changing in magnitude depending on its position in the circle
e. directed outward from the centre of the circle
____ %. A child whirls a ball around in circles on the end of a &7 cm long string at a fre#uency of .0 9$. What is the
ball@s centripetal acceleration?
a. 1. 1"&ms d. %7 ms
b. 1. 1"ms e. %." ms
c. &- ms
____ &. A rock is tied to the end of a %0 cm long string and whirled around in a circle that describes a vertical plane.
3he tension in the string becomes $ero when the speed of the rock is
8/13/2019 Exam Review Word Sph4u1
5/60
a. 8.7 1"cms d. 8.7 cmsb. 1.8 1"cms e. 1.8 cmsc. 18 cms
____ 0. 3he acceleration due to gravity on the surface of a planet having twice the (arth@s mass and twice its radius
would be
a. %8. ms
d. &.8 ms
b. 18.5 ms e. .&0 ms
c. 8.7 ms
____ 5. lanet B has a radius & times that of (arth and the acceleration due to gravity at the surface of planet B is &.8
ms. 3he mass of lanet B compared to (arth@s mass is
a. 15 times d. timesb. 7 times e. the same
c. & times
____ -. 3he force of gravity acting on a 1"6kg object at an altitude e#uivalent to the (arth@s radius isa. &8 d. 0."
b. & e. .&
c. 8.7
____ 7. 3he orbital speed of a satellite at an altitude e#uivalent to (arth@s radius :r(C 5.%7 1"5m; is :m(C 0.87 1"&kg, GC 5.5- 1"D11Emkg;a. 8.7 1"%ms d. &.8 1"%msb. -.8 1"%ms e. .0 1"%msc. 0.5 1"%ms
____ 8. Astronauts on board an orbiting space station appear to be =floating> because
a. they are in the vacuum of space
b. they are outside (arth@s gravitational influence
c. the force of gravity acting on them has been reduced to an insignificant level
d. they have become truly =weightless>
e. they are in free fall along with the space station itself
____ %". Which of the following graphs best illustrates the relationship between a satellite@s orbital radiusroand itsorbital speed vo?
a. A d. 4
b. * e. (
c.
____ %1. A ripple tank is used to generate water waves. 3hese waves are refracted as they travel from deep to shallow
water. Which of the following factors, when changed, will not affect the amount of bending observed?
a. the angle between the boundary and the incident wave front
b. the difference in depth between the shallow and deep regions
c. the wavelength of the incident wave
d. the amplitude of the incident wave
e. the fre#uency of the incident wave
8/13/2019 Exam Review Word Sph4u1
6/60
____ %. A two6point source interference pattern is generated in a ripple tank. oint , on the second nodal line, is
located 7 cm from one source and %- cm from the other. 3he wavelength of the waves is
a. 17 cm d. 5." cm
b. 1& cm e. &.0 cm
c. 8." cm
____ %%.
8/13/2019 Exam Review Word Sph4u1
7/60
c. %" cm
____ %-. A student counts a total of eight nodal lines on each side of a two6point source interference pattern and
measures the sources to be 10 cm apart. What is the appro!imate wavelength of the waves?
a. ".0" cm d. 10 cm
b. ." cm e. none of the above
c. -.0 cm
____ %7. A two6point source interference pattern is generated in a ripple tank by identical sources vibrating in phaseand located 1." cm apart. 3here are seven nodal lines observed on each side of the centre line.
8/13/2019 Exam Review Word Sph4u1
8/60
____ &&. A student performs a double6slit e!periment using a monochromatic light source, two slits spaced ".1" mm
apart, and a screen located 10" cm away. 3he bright fringes are located ".%" cm apart.
8/13/2019 Exam Review Word Sph4u1
9/60
____ 0%. 3he e#uationEC mcillustrates that
a. travelling at the speed of light converts matter into energy
b. rest mass and energy are e#uivalent
c. energy can be converted into mass
d. matter can be converted into energye. both b and d
____ 0&. 3he total energy of a particle
a. can never increase or decreaseb. will increase due to the speed of light
c. will decrease due to the speed of light
d. will reach a limit before the speed of light
e. none of the above
____ 00. 3he total energy, in joules, of a "."16kg object moving at ".00cis
a. -.%7 1"1&K d. &.1% 1"10Kb. 1."7 1"10K e. 5.07 1"D%Kc. &.%& 1"1&K
____ 05. 3he energy, in joules, of light with a fre#uency of 0.5 1"159$ is
a. 0.5 1"15K d. 1. 1"D0"Kb. 7.& 1"&8K e. 5.5% 1"D%& Kc. %.- 1"D1-K
____ 0-.
8/13/2019 Exam Review Word Sph4u1
10/60
b.times
e. none of the above
c. & times
____ 5%. A net force of 1 changes the momentum of a 0"6g ball by %.- kgms. 3he force acts fora. ".%1 s d. %. s
b. ".71 s e. && sc. 1. s
____ 5&. A car with a mass of 17"" kg slows from & kmh '() to 7 kmh '(). 3he impulse from the brakes is
a. .0 1"&s '() d. .1 1"&s 'W)b. .0 1"&s 'W) e. -." 1"%s 'W)c. .1 1"&s '()
____ 50. A 1.06kg bird is flying at a velocity of 17 ms '/ above the hori$ontal). 3he vertical component of its
momentum is
a. 1" ms 'up) : significant digits; d. 1- ms 'up)
b. 5.- kgms 'up) e. none of the abovec. 0 kgms 'up)
____ 55. A bullet with a mass of 7 g is fired from a .76kg gun that is stationary, but free to recoil. After the bullet isfired, the gun is observed to be moving at 1.& ms 'left). 3he velocity of the bullet is
a. 1&" ms 'left) d. -1 ms 'left)
b. 1&" ms 'right) e. -1 msc. -1 ms 'right)
____ 5-. An arrow slows down from &% ms to 7 ms as it passes through an apple.
8/13/2019 Exam Review Word Sph4u1
11/60
Which vector below most closely represents the new velocity of ?
a. A d. 4
b. * e. (
c.
____ -1. 3wo objects of e#ual mass with the speeds indicated by the vectors below, collide and stick together.
Which vector below best represents the velocity of the combined objects after the collision?
a. A d. 4
b. * e. (
c.
____ -. A -6kg satellite is in circular orbit -%7" km above the surface of (arth :M(C 0.87 1"&
kg;. 3hegravitational force acting on the satellite is
a. 1.0 1"% d. -.%% b. 0.8 1"8 e. -."7 1"%c. 0.8 1"%
____ -%. 3he +un has a mass of 1.88 1"%"kg. Kupiter has a mass of 1.8" 1"-kg and a mean radius of orbit aroundthe +un of -.-7 1"7km. 3he speed that Kupiter travels in its orbit around the +un isa. 1.%1 1"&kms d. &."& 1"ms
8/13/2019 Exam Review Word Sph4u1
12/60
b. &.-" 1"&kmh e. 1.7 1"&msc. &.1% 1"0ms
____ -&.
8/13/2019 Exam Review Word Sph4u1
13/60
7-. A ".06kg snowball moving at 10 ms '() collides and sticks with a 1.86kg toy truck travelling at .7 ms 'W).
eglecting friction, calculate the velocity of the snowballDtruck system after the collision.
77. A 06kg bag of cement thrown at .0 ms '() is caught by a person sliding 1.7 ms '() on a frictionless
surface.
8/13/2019 Exam Review Word Sph4u1
14/60
:d;
8/13/2019 Exam Review Word Sph4u1
15/60
:c;
8/13/2019 Exam Review Word Sph4u1
16/60
:a; 4raw a free6body diagram of the ice as it is sliding along the roof.
:b; With what speed does it leave the roof?
:c; 9ow far away from the foot of the building does the ice land?
1"1. 3wo blocks are connected by a =massless> string over a =frictionless> pulley as shown in the diagram.
:a; 4etermine the acceleration of the blocks.
:b; alculate the tension in the string .:c; rope over a =frictionless> pulley as pictured in
the diagram. 3he ramp is inclined at %"."/ and the coefficient of kinetic friction on the ramp is ".17.
8/13/2019 Exam Review Word Sph4u1
17/60
:a; 4raw free6body diagrams of both masses.
:b; 4etermine the acceleration of the system once it begins to slide.
:c; 4etermine the tension in the rope.
:d;
8/13/2019 Exam Review Word Sph4u1
18/60
111. A two6point source interference pattern is generated by sources operating in phase at 1." 9$. 3he sources are
." m apart and the wavelength of the waves is ".5" m. At what angles, measured from the centre line of the
pattern, are the nodal lines produced located?
11. A student creates a two6point source interference pattern in a ripple tank with two sources operating in phase
and records the following informationF nC &, C %-.0 mm,LC 1.0 m, dC & cm. alculatex&.
11%. A student creates a two6point source interference pattern in a ripple tank with two sources operating in phase.
A point on the eighth nodal line is 1.0 m from the centre of the two sources and &7." cm from the
perpendicular bisector of the two sources.
8/13/2019 Exam Review Word Sph4u1
19/60
18. A spring with a force constant of 78 m is compressed 7.- cm and placed between two stationary dynamics
carts of mass 1." kg and 1.0 kg.
8/13/2019 Exam Review Word Sph4u1
20/60
EXAM REVIEW - D. O'Hara - SPH4U1
A!"#er Setio!
MU&IP&E CHOICE
1. A+F P(F OM 2*KF 1.& I2F J1."%. A+F A P(F OM 2*KF 1.1 I2F J1."1
%. A+F * P(F OM 2*KF 1.1 I2F J1."
&. A+F P(F OM 2*KF 1.1 I2F J1."
0. A+F ( P(F OM 2*KF 1.1 I2F J1."
5. A+F 4 P(F OM 2*KF 1.1 I2F J1."1
-. A+F ( P(F OM 2*KF 1.1 I2F J1."
7. A+F A P(F OM 2*KF 1. I2F J1."1
8. A+F * P(F OM 2*KF 1.% I2F J1."
1". A+F ( P(F OM 2*KF 1.& I2F J1."
11. A+F ( P(F OM 2*KF 1.& I2F J1."%
1. A+F A P(F OM 2*KF 1.& I2F J1."%1%. A+F P(F OM 2*KF 1.0 I2F J1."
1&. A+F A P(F OM 2*KF 1.0 I2F J1."
10. A+F ( P(F OM 2*KF .1 I2F J1."1
15. A+F A P(F OM 2*KF .1 I2F J1."1
1-. A+F P(F OM 2*KF .1 I2F J1."1
17. A+F A P(F OM 2*KF . I2F J1."1
18. A+F P(F OM 2*KF . I2F J1."1
". A+F 4 P(F OM 2*KF .% I2F J1."1
1. A+F * P(F OM 2*KF .% I2F J1."1
. A+F P(F OM 2*KF %.1 I2F J1."&
%. A+F * P(F OM 2*KF %.1 I2F J1."&&. A+F * P(F OM 2*KF %. I2F J1."&
0. A+F 4 P(F OM 2*KF %.% I2F J1."5
5. A+F * P(F OM 2*KF %.% I2F J1."5
-. A+F * P(F OM 2*KF %.% I2F J1."5
7. A+F P(F OM 2*KF %.& I2F J1."5
8. A+F ( P(F OM 2*KF %.& I2F J1."5
%". A+F A P(F OM, < 2*KF %.& I2F J1."5
%1. A+F 4 P(F OM 2*KF 8.1 I2F WA1."1
%. A+F 4 P(F OM 2*KF 8.% I2F WA1."%
%%. A+F P(F OM, 2*KF 8.% I2F WA1."%
%&. A+F * P(F OM 2*KF 8.% I2F WA."1%0. A+F A P(F OM 2*KF 8.% I2F WA."1
%5. A+F ( P(F J 2*KF 8.% I2F WA."&
%-. A+F * P(F < 2*KF 8.% I2F WA."1
%7. A+F 4 P(F < 2*KF 8.% I2F WA."1
%8. A+F 4 P(F OM 2*KF 8.& I2F WA1."0
&". A+F P(F J 2*KF 8.& I2F WA%."
&1. A+F ( P(F OM 2*KF 8.& I2F WA1."0
8/13/2019 Exam Review Word Sph4u1
21/60
&. A+F 4 P(F < 2*KF 8.0 I2F WA."%
&%. A+F P(F OM, 2*KF 8.0 I2F WA."
&&. A+F A P(F OM 2*KF 8.0 I2F WA."
&0. A+F ( P(F OM, 2*KF 8.0 I2F WA."
&5. A+F A P(F OM 2*KF 11.1 I2F J(1."1
&-. A+F P(F OM 2*KF 11. I2F J(1."0&7. A+F * P(F OM 2*KF 11. I2F J(1."0
&8. A+F A P(F OM 2*KF 11. I2F J(1."0
0". A+F P(F J 2*KF 11. I2F J(."
01. A+F 4 P(F < 2*KF 11. I2F J(."
0. A+F A P(F < 2*KF 11. I2F J(."
0%. A+F ( P(F OM 2*KF 11.% I2F J(1."5
0&. A+F * P(F OM 2*KF 11.% I2F J(1."5
00. A+F * P(F < 2*KF 11.% I2F J(1."5
05. A+F P(F < 2*KF 1.1 I2F J(1."1
0-. A+F A P(F OM 2*KF 1.1 I2F J(1."%
07. A+F A P(F OM 2*KF 1.1 I2F J(1."%08. A+F * P(F < 2*KF 1.1 I2F J(1."%
5". A+F P(F
8/13/2019 Exam Review Word Sph4u1
22/60
3herefore, .
An object will travel 5.1 times higher on the moon than on (arth when projected vertically upward from the
two surfaces with the same initial velocity.
P(F 2*KF 1.% I2F J1."0
-5. A+F
3he central point is located e#uidistant from each of the two slits. +ince the light through each slit originates
from a single source, it is coherent :in phase; when it leaves the slits and reaches the centre of the screen in
phase. 3his creates constructive interference, or in the case of light, a bright band.
P(F 2*KF 8.0 I2F WA1."&
--. A+F3he medical supplies would travel in a parabolic arch down and to the right relative to an observer on the
ground.
P(F J 2*KF 11.1 I2F J(1."1
-7. A+F
8/13/2019 Exam Review Word Sph4u1
23/60
71. A+F
*oth the driver and the pedestrian would see the light moving at c, the speed of light.
P(F J 2*KF 11. I2F J(1."0
7. A+F
3he ship would appear to be =longer> but no change in height would occur.
P(F OM 2*KF 11. I2F J(."
7%. A+F
We can neglect the force of gravity because it is so small.
3he average force acting on the ball is 5.0 1".
P(F OM 2*KF 0.1 I2F (J1."1
7&. A+F
We can neglect the force of gravity because it is so small.
3he average force acting on the ball is 08 .
P(F OM 2*KF 0.1 I2F (J1."1
70. A+F
6 3he ball does not reach its original height after the bounce. :some loss of energy;
6 +ound is produced. :sound energy must come from original kinetic energy;
P(F OM 2*KF 0.% I2F (J1."&
75. A+F
3he energy is stored as elastic potential energy in the deformed shape of the ball.
P(F OM 2*KF 0.% I2F (J1."&
8/13/2019 Exam Review Word Sph4u1
24/60
7-. A+F
hoose east as the Qxdirection.
3he final velocity is ".-% ms 'W).
P(F OM 2*KF 0. I2F (J1."
77. A+F
hoose east as the Qxdirection.
3he mass of the person is 5 kg.
P(F OM 2*KF 0. I2F (J1."
78. A+F
3he 8"/ angle means we can use the ythagorean theorem.
3he initial speed of the billiard ball was 0." ms.
P(F OM 2*KF 0.& I2F (J1."%
8/13/2019 Exam Review Word Sph4u1
25/60
PRO)&EM
8". A+F
:a;
v1C "." msaC 0." ms
d C 7"." cm C ".7"" mvC ?
he "pee* o+ the o$,et upo! reahi! the rouh "etio! i" ./ %0".
:b;
v1C .7% ms
vC "." ms
t C .0 saC ?
he o$,et" aeleratio! i" 1.1 %0"a!* "lo#i!.
:c;
4uring the period of accelerationF
dC ".7"" m
4uring the period of uniform motionF
v C .7% ms
tC &." sd C vtC .7% ms:&." s; C 11.% m
4uring the period of decelerationF
v1 C .7% ms
vC "." ms
tC .0 s
8/13/2019 Exam Review Word Sph4u1
26/60
3otal distance the object slidesF ".7"" m Q 11.% m Q %.0& m C 15 m
he o$,et "li*e" a total *i"ta!e o+ 12 %.
P(F OM 2*KF 1. I2F J1."
81. A+F
:a;
Msing the sign convention that =up> is :D; and =down> is :Q;F
v1C D0 ms
vC "." ms
aC 8.7 ms
dC ?
3he arrow travels %1.8 m upward to its highest point. 3he halfway position is 10.8 m.
3he time to travel the last half of its flightF
dC D10.8 mvC "." ms
a C 8.7 ms
tC ?
or the second arrowF
dC 6%1.8 maC 8.7 ms
t C 1.7" sv1C ?
8/13/2019 Exam Review Word Sph4u1
27/60
he "pee* o+ the "eo!* arro# at lau!h i" 3 %0" up#ar*5.
:b;inding the ma!imum height of the second arrowF
v1C D5.0 ms
vC "." ms
a C 8.7 ms
d C ?
he "eo!* arro# reahe" a %a6i%u% heiht o+ 72 % up#ar*5.
P(F OM 2*KF 1.% I2F J1."
8. A+F:a;
arF v1C "." ms, aC .5 ms
3ruckF v3 C 7." ms
arF
3ruckF d3C v3td3C 7." t
d3C dQ 1. 1"
m7." tC 1.%:t;Q 1. 1"solving the #uadraticF tC 0.8 s, 15 she tru8 pa""e" the ar a+ter 9.: ".
:b;v1C "." ms
aC .5 ms
8/13/2019 Exam Review Word Sph4u1
28/60
t C 0.8 sdC ?
he ar tra;el" 49 % $< the ti%e the tru8 pa""e" it.
:c;
v1C "." ms
aC .5 ms
t = 15.6 s (the other root of the quadratic)v C v1Q at
C .5 ms:10.5 s;
v C &1 ms
he ar #ill $e tra;elli! at 41 %0" #he! it pa""e" the tru8 i+ it %ai!tai!" it" aeleratio!.
P(F OM 2*KF 1. I2F J1."
8%. A+F
anoeist *F
Msing sine lawF .
3he component of across the river isF .&sin:05Q 15; C .7 ms.3he time for * to cross to point BF
8/13/2019 Exam Review Word Sph4u1
29/60
anoeist AF
3he time for A to reach point BF
Ca!oe A %u"t #ait 171.2 " = 19 " > 2.2 ".
P(F OM 2*KF 1.0 I2F J1."0
8&. A+F
:a; displacement C area under graph
C %.-0 m '+) Q 17.-0 m ')
displacement C 0." m '+)
:b;
he o$,et" a;erae ;eloit< *uri! the +ir"t 2.? " i" ?./7 %0" S5.
:c;
he o$,et" a;erae "pee* *uri! the +ir"t 2.? " i" 3.1 %0".
:d; 3he object is at its starting location % times throughout the motion.
8/13/2019 Exam Review Word Sph4u1
30/60
:e; 3he object@s acceleration is greatest betweentC 5.0 s and -." s. :the greatest slope; acceleration C slope of
graph C %" ms')
:f;
:g;
P(F OM 2*KF 1. I2F J1."
80. A+F:a;
3ime of flightF let =up> be :D; and =down> be :Q;
v1C D5 ms:sin 5"/; C D.0 ms
aC 8.7 ms
dC ." mtC ?
8/13/2019 Exam Review Word Sph4u1
31/60
." C :D.0;tQ &.8:t;
+olving the #uadraticF t C &.57 she ti%e o+ +liht i" 4.3 ".
:b;
9ori$ontal rangeF dC vtC 5 ms:cos 5";:&.57 s; C 5".7 m3he receiver must runF 5".7 m D %." m C 0-.7 m.3he time the receiver has to reach the footballF &.57 s Q ." s C 5.57 s.
3he average speed of the receiverF
he reei;er %u"t ru! #ith a! a;erae "pee* o+ /.3 %0".
P(F OM 2*KF 1.& I2F J1."%
85. A+F
:a; 3rigonometric Jethod
Iooking at the vector triangleF C ".
Msing cosine lawF C 1.%
Msing sine lawF C 17.
As a resultF .
:b; omponent Jethod
1BC %.0 :cos %"; '() C %."% '()BC .7 :sin &"; 'W) C 1.7" 'W)BC %."% '() Q 1.7" 'W) C 1.% '()
8/13/2019 Exam Review Word Sph4u1
32/60
1HC %.0 :sin %"; ') C 1.-0 ')HC .7 :cos &"; '+) C .1& '+)HC 1.-0 ') Q .1& '+) C ".%8 '+)
Msing ythagorasF
Msing a trigonometric ratioF C tanD1 C 17.
As a resultF .
3he two methods give e#uivalent results.
P(F 2*KF .% I2F J1."1
8-. A+F
:a;
ree6body diagramF acting up
gacting down
Aacting as illustrated
Oacting to the right
=Mp> and =to the right> are the positive directions.
9ori$ontallyF
he aeleratio! o+ the o$,et i" 1.? %0".
:b;
GerticallyF
8/13/2019 Exam Review Word Sph4u1
33/60
he !or%al +ore i" 1.7 1?(up5.
:c;
ree6body diagramF acting up
gacting down
Aacting to the left
Oacting to the right=Mp> and =to the right> are the positive directions.
he aeleratio! o+ the t#o %a""e" i" ?.9: %0".
:d;
ree6body diagramF acting up
gacting down
Aacting to the left
Oacting to the right
acting to the right :force of &." kg object on 1." kg object;
=Mp> and =to the right> are the positive directions.
he 4.?-8 o$,et e6ert" a +ore o+ 9.7 ( o! the 1.?-8 o$,et.
8/13/2019 Exam Review Word Sph4u1
34/60
P(F OM 2*KF .% I2F J1."
87. A+F
:a;
or the 0."6kg massF
ree6body diagramF acting perpendicular to ramp and up
gacting down
3acting up along the ramp :this is the positive direction;Oacting down along the ramp :this is the negative direction;
0." kg:a; C3Dmg:cos ; D mg:sin ;
0." kg:a; C3D %0.0
or the "."6kg massF
ree6body diagramF 3acting up :this is the negative direction;
gacting down :this is the positive direction;
"." kg:a; D 185 D3
+olving the system of e#uationsF
aC 5.& ms
he aeleratio! o+ the 9.?-8 %a"" alo! the ra%p i" 2.4 %0".
:b;
he te!"io! i! the a$le i" 2/ (.
:c;
3he speed of projection of the mass off the top of the ramp is -. ms.
:d;
GerticallyF Iet =up> be :D; and =down> be :Q;.
aC 8.7 ms
dC 5." m
8/13/2019 Exam Review Word Sph4u1
35/60
9ori$ontal rangeF
he hori@o!tal ra!e +or the pro,ete* %a"" i" :.9 %.
P(F OM 2*KF .% I2F J1."1
88. A+F
:a;ree6body diagram of the crateF 3acting up
gacting down
Iet =up> be :D; and =down> be :Q;.
C D5"" Q 0"." kg:8.7 kg;C D11"
8/13/2019 Exam Review Word Sph4u1
36/60
It #ill ta8e .3 " to li+t the rate.
:b;
or the 0"."6kg massF
ree6body diagramF 3acting up :this is the negative direction;
gacting down :this is the positive direction;
0"." kg:a; C 0"." kg:8.7 kg; D3
or the &0."6kg massF
ree6body diagramF 3acting up :this is the positive direction;
gacting down :this the negative direction;
&0." kg:a; C &0." kg:8.7 kg; D3
+olving the system of e#uationsF
aC ".0 ms
he aeleratio! o+ the rate #ill $e ?.9 %0".
:c;
3C &0." kg:a; Q &0." kg :8.7 kg;
C &0." kg:".0 ms; Q &0." kg:8.7 kg;
3C &.5 1"he te!"io! i! the a$le #oul* $e 4.2 1?(.
P(F OM 2*KF .% I2F J1."1
1"". A+F
:a;
ree6body diagramF acting perpendicular to the roof :upward;gacting down
Oacting up along the roof :this is the negative direction;
:b;
arallel to the roofF
8/13/2019 Exam Review Word Sph4u1
37/60
maCmg:sin; Dmg:cos ;
aC 8.7 kg:sin 0"/; D :".1&;:8.7 kg;:cos 0"/;
aC 5.5 ms
he ie lea;e" the roo+ at 1.? 1?1%0".
:c;
When the ice leaves the roof it becomes a projectileF
GerticallyF
+olving the #uadraticF tC ".&"5 s
9ori$ontallyF
dC v:cos )tC 1".% ms:cos 0";:".&"5 s;d C .- mhe ie la!*" .3 % +ro% the $a"e o+ the $uil*i!.
P(F OM 2*KF .% I2F J1."1
1"1. A+F:a;
or the ".7"6kg massF
ree6body diagramF acting up
gacting down
3acting to the right :this is the positive direction;
Oacting to the left :this is the negative direction;
".7" kg:a; C3DO
".7" kg:a; C3D ".1&:".7" kg;:8.7 kg;
".7" kg:a; C3D 1.1"
or the ."6kg massF
ree6body diagramF acting perpendicular to the ramp :upward;
gacting down
3acting up along the ramp :this is the negative direction;
Oacting up along the ramp
8/13/2019 Exam Review Word Sph4u1
38/60
." kg:a; C ." kg:8.7 kg;:sin %"/; D3D ".1&:." kg;:8.7 kg;:cos %"/;
." kg:a; C D3Q -.&
+olving the system of e#uationsF aC .% ms
he "
8/13/2019 Exam Review Word Sph4u1
39/60
:c;
3C &." kg:a; Q1%.0
C &." kg:&.0% ms; Q 1%.0
3C %
he te!"io! i! the a$le i" 7 (.
:d;
or the block sliding down the rampF
ree6body diagramF acting perpendicular to the ramp :upward;
gacting down
Oacting up along the ramp :this is the negative direction;
maC mg:sin ; Dmg:cos ;
a C 8.7 kg:sin %"/; D :".17;:8.7 kg;:cos%"/;
a C %.%- ms
It #oul* ta8e 1.7 " to reah the $otto% o+ the ra%p.
P(F OM 2*KF .% I2F J1."1
1"%. A+F
:a;
or the engineF
ree6body diagramF acting upgacting down
Oacting to the left
Aacting as indicated
3acting to the left :force of caboose on engine;
or the cabooseF
ree6body diagramF acting up
gacting down
Oacting to the left
3acting to the right :force of engine on caboose;
Iet =to the right> and =upward> be :Q;.
:b;
8/13/2019 Exam Review Word Sph4u1
40/60
onsidering the entire trainF
he trai! #ill aelerate at .1 %0".
:c;
onsidering the cabooseF
C ".1"" kg:.1 ms; D :D".&" ;
C ".51
he te!"io! i! the "tri! ,oi!i! the e!i!e a!* a$oo"e i" ?.21 (.
P(F OM 2*KF .% I2F J1."1
1"&. A+F
:a;
3he minimum fre#uency occurs when the tension becomes $ero.
he %i!i%u% +reue!< i" ?.7: H@.
8/13/2019 Exam Review Word Sph4u1
41/60
:b;
3he ma!imum tension occurs at the bottom of the circle.
Iet =up> be negative and =down> be positiveF
he %a6i%u% te!"io! i" 7.: ( up5.
P(F OM 2*KF %. I2F J1."&
1"0. A+F
3he free body diagram of the pilot at the bottom of the arcF
8/13/2019 Exam Review Word Sph4u1
42/60
C force of seat e!erted upward on the pilot :the normal force;
C &mg
he ra*iu" o+ the ar i" 9: %.
P(F OM 2*KF %. I2F J1."&
1"5. A+F
3he weight of a 5"."6kg person at (arth@s surfaceF
gC mg
C 5"." kg:8.7 kg;gC 077
+ince , the two planets can be compared.
(arthF(C 077 lanetFC ?
m1C 5"." kg m1C 5"." kg
mC m( mC .0 m(rC r( rC 1.r(
8/13/2019 Exam Review Word Sph4u1
43/60
he per"o! #oul* #eih 1.? 1?7( at the pla!et" "ur+ae.
P(F OM 2*KF %.% I2F J1."51"-. A+F
3he orbital radius is 5.%7 1"5m Q %.0 1"0m C 5.-"0 1"5m3he centripetal force acting on the satellite is supplied by gravity.
Cg
he or$ital perio* i" :1.? %i!.
P(F OM 2*KF %.& I2F J1."51"7. A+F
8/13/2019 Exam Review Word Sph4u1
44/60
:a;
he relati;e i!*e6 o+ re+ratio! +ro% "hallo# to *eep #ater i" ?.4.
:b;
he "pee* o+ the #a;e i! the *eep #ater i" 1 %0".
P(F OM 2*KF 8.1 I2F WA1."1
1"8. A+F
:a;
8/13/2019 Exam Review Word Sph4u1
45/60
he i!*e6 o+ re+ratio! $et#ee! the t#o reio!" i" ?.49.
:b;
he #a;ele!th i" 17 %.
P(F OM 2*KF 8.1 I2F WA."%
11". A+F
8/13/2019 Exam Review Word Sph4u1
46/60
he "pee* i" 1/ %0"B the #a;ele!th i" 9.7 %B a!* the +reue!< i" 7.7 H@.
P(F OM 2*KF 8.% I2F WA1."1
111. A+F
8/13/2019 Exam Review Word Sph4u1
47/60
he three !o*al li!e" appear at a!le" o+ /.2oB 3oB a!* 4:o+ro% the e!tre li!e.
P(F OM 2*KF 8.% I2F WA1."111. A+F
he ;alue +or x4i" 2/ %.
P(F OM, 2*KF 8.% I2F WA1."1
11%. A+F
8/13/2019 Exam Review Word Sph4u1
48/60
he #a;ele!th i" 1.41 %%.
P(F OM, 2*KF 8.% I2F WA1."1
11&. A+F
8/13/2019 Exam Review Word Sph4u1
49/60
he #a;ele!th o+ liht u"e* #a" 4.9 1?=3%.
P(F OM, 2*KF 8.0 I2F WA."
110. A+F
he +reue!< o+ the "tatio! i" :9 MH@.
P(F J 2*KF 8.0 I2F WA%."
115. A+F
vC ".80c
C 11 a
8/13/2019 Exam Review Word Sph4u1
50/60
he ti%e that ha* pa""e* o! Earth #a" 79
8/13/2019 Exam Review Word Sph4u1
51/60
P(F < 2*KF 11. I2F J(."
118. A+F
mC 0"" g :".0 kg;
vC ".0c
he $o%$'" relati;i"ti %o%e!tu% i" :.1 1?38%0".
P(F < 2*KF 11. I2F J(."
1". A+F
1.5" 1"D18K =1 eGm=1.5- 1"D-kgv=".-0"c
he total e!er< o+ the proto! i" 14 MeV.
P(F < 2*KF 11.% I2F J(1."5
11. A+F
8/13/2019 Exam Review Word Sph4u1
52/60
he eletro! ha" a 8i!eti e!er< o+ ?.42/ MeV.
P(F < 2*KF 11.% I2F J(1."5
1. A+F
(oB a! eletro! #oul* !ot $e e,ete* $eau"e the 8i!eti e!er< i" !ot a po"iti;e ;alue.
P(F < 2*KF 1.1 I2F J(1."%
1%. A+F
v C ?
8/13/2019 Exam Review Word Sph4u1
53/60
he eletro! #oul* $e e,ete* +ro% the "o*iu% #ith a "pee* o+ 7.:/1?9%0".
P(F
8/13/2019 Exam Review Word Sph4u1
54/60
P(F < 2*KF 1. I2F J(1."&
15. A+F
he #a;ele!th o+ liht that #oul* $e e%itte* #oul* $e 14? !%.
P(F
8/13/2019 Exam Review Word Sph4u1
55/60
P(F < 2*KF 1.0 I2F J(."1
17. A+F
*efore the collisionF
After the collisionF
ow using the kinematics e#uationsF
he pair oa"t a total o+ 1.4 % a+ter the olli"io!.
P(F OM 2*KF 0. I2F (J1."
18. A+F
Msing conservation of momentumF
8/13/2019 Exam Review Word Sph4u1
56/60
ow use conservation of energyF
he +i!al "pee* o+ the %ore %a""i;e art i" ?.4 %0".
P(F OM 2*KF 0.% I2F (J1."
1%". A+F
Jomentum is conserved during the collision.
onserved energy for the spring compressionF
8/13/2019 Exam Review Word Sph4u1
57/60
ow sub in to calculate the mass of the wooden block
he %a"" o+ the #oo*e! $lo8 i" 1 8.
P(F OM 2*KF 0.% I2F (J1."
1%1. A+F
3he momentum of the ""6g piece,p, is "." 1.& C ".7 kgms.3he momentum of the %""6g piece,p%, is ".%" ".8" C ".- kgms.3he momentum of the unknown piece,pm, is m1.7 C 1.7mkgms.
hoose the Qxdirection to be the direction of the ""6g piece.is the angle between the unknown momentum vector and opposite to the ""6g momentum vector.
8/13/2019 Exam Review Word Sph4u1
58/60
ow divide (#uation 1 by (#uation F
+ubstitute this value into (#uation 1F
3he angle measured from the ""6g piece is 17"/ D %8/ C 1&1/.
he %a"" o+ the thir* piee i" ?.7 8 a!* it i" %o;i! 141 +ro% the ??- piee. It i" 17: +ro% the
7??- piee.F
P(F OM 2*KF 0.& I2F (J1."%
1%. A+F
irst use conservation of energy after the collision until the ma!imum compressionF
ow use conservation of momentum for the collisionF
8/13/2019 Exam Review Word Sph4u1
59/60
8/13/2019 Exam Review Word Sph4u1
60/60
he lau!h "pee* #oul* !ee* to $e /.7/ 1?7%0".
P(F OM 2*KF 5.% I2F (J1."-