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Exam 1 Stats. Average 51.8 ± 22.1 High 92.5 (2 of you) Low 14. Chapter 8 Activity. The “true” nature of ionic species in solution. Ions are charged molecules As a result, they tend to attract polar solvent molecules (like water, for instance) and other ions Hydrated radius - PowerPoint PPT Presentation
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Exam 1 Stats
• Average 51.8 ± 22.1• High 92.5 (2 of you)• Low 14
A 100-83 4
B 82-64 11
C 63-41 15
D 40-22 8
F 21-0 6
Chapter 8Activity
The “true” nature of ionic species in solution
• Ions are charged molecules• As a result, they tend to attract polar
solvent molecules (like water, for instance) and other ions– Hydrated radius– Ionic atmosphere
• The thickness of the ionic atmosphere is a function of the ionic strength of the solution “the concentration of charge”
_
+
Hydrated radius
_ +
water Chloride Sodium ion
+
Ionic Atmosphere and Shielding
_
Sulfateion
Sodium ion
-+ +
++
+++
+
++ +
+
++-
+ +++
+++
+
+
+
+- -
--
---
+- -
--
---
--- -
----
- --
--
-
-+
Calcium ion
Chloride ion
Low ionic strength High ionic strength
Activity
• All ionic species in any equilibrium expression are more accurately expressed as activities.
A Ca2+ = [Ca2+]Ca2+
or
A + H2O ↔ A- + H3O+
Ka = A A- A H3O+ / [A] = [A-]A-[H3O+]H3O+ / [A]where is the activity coefficient and is a
function of the ionic radius of the ion and the ionic strength of the solution.
Activity - continued
• The higher the ionic strength of the solution, the larger the smaller the activity coefficient.
• Rationalization: At higher ionic strengths the ion cloud around any ion is thicker, which weakens the attractive forces between the ion and its counterpart, inhibiting recombination.
Ionic strength• A measure of the concentration of ions in
solution
= ½ ∑ cizi2
0.010 M Ca(NO3)2
= ½ ([NO3-](-1)2 + [Ca2+](2+)2) =
½ {(0.02)(-1)2 + (0.01)(2)2 } = 0.03 M
Ca2+@=0.03 = ?
Use extended Debye-Huckle eq or Table 8.1 and extrapolation
Take home message
• At high ionic strengths, solubility increases slightly (by a factor of 2-10).
• pH is influenced by ionic strength
• Weak acid and base dissociation is influenced a little by ionic strength
• Significant figures?
Example 8-12
• Solubility of Hg2Br2
– in pure water
– in 0.00100 M KNO3
– in 0.0100 M KNO3
– in 0.100 M KNO3
In pure water
Hg2Br2 Hg22+ + 2Br-
Ksp = [Hg22+]Hg22+ [Br-]2Br-
2
2[Hg22+] = [Br-] and let [Hg2
2+] = x Ionic strength is very low.
Hg22+ and Br- are close to 1.00so,
Ksp = 4 [x]3 = 5.6E-23x = 2.4E-8 M
Activity coefficient as a function of ionic strength Table 8 -1
= 0.001 = 0.01 = 0.1
Hg22+ 0.867 0.660 0.335
Br- 0.964 0.898 0.75
in 0.00100 M KNO3
= ½ ((.001)(+1)2 + (0.001)(-1)2 = 0.001 M
Hg22+ @ = 0.001 = 0.867
Br-2
@ = 0.001 = 0.964
Ksp = 4 Hg22+ Br-2 [x]3 = 5.6E-23
x = 2.6E-8M
in 0.0100 M KNO3
= ½ ((.01)(+1)2 + (0.01)(-1)2 = 0.01 M
Hg22+ @ = 0.001 = 0.660
Br-2
@ = 0.001 = 0.898
Ksp = 4 Hg22+ Br-2 [x]3 = 5.6E-23
x = 3.0E-8M
in 0.100 M KNO3
= ½ ((0.1)(+1)2 + (0.1)(-1)2 = 0.1 M
Hg22+ @ = 0.001 = 0.335
Br-2
@ = 0.001 = 0.75
Ksp = 4 Hg22+ Br-2 [x]3 = 5.6E-23
x = 4.2E-8M
solubility vs log()
2.2E-08
2.7E-08
3.2E-08
3.7E-08
4.2E-08
4.7E-08
-8 -6 -4 -2 0
log()
solu
bili
ty o
f H
g 2B
r 2
pH and ionic strength
• True definition of pH• pH = -logAH+ = -log {[H+]H+}• pH of a 0.00100 M HCl solution
– Ionic strength, , = 0.001; H+ = 0.967– pH = -log(.001*.967) = 3.01
• pH of a 0.100 M HCl solution– Ionic strength, , = 0.1; H+ = 0.83– pH = -log(0.1*0.83) = 1.08
• pH of a 0.00100 M HCl/0.100 M NaCl solution – Ionic strength, , = 0.1; H+ = 0.83– pH = -log(0.001*0.83) = 3.08
What is the concentration H+ an OH- in a 0.100 M NaCl solution?
Kw = [OH-]OH-[H+]H+ = 1.01E-14
At = 0.100, OH- = 0.76 and H+ = 0.83
H2O is the only source of H+ and OH- so let x = [H+] = [OH-]
Kw = (0.76)(0.83) x2
x = 1.27E-7 M
EDTA Prob 12-31
• A 50 mL sample containing Ni2+ is treated with 25.00 mL of 0.0500 M EDTA to complex all of the Ni2+. The excess EDTA is back-titrated, requiring 5.00 mL of 0.0500 M Zn2+. What is the concentration of Ni2+ IN THE ORIGINAL SAMPLE?