EX 306- Electrical Workshop · 2014-11-08 · MARRIED JOINT-: For a wire having one strand only the joint made is called twisted joint but for wires having no. of strands the joint

Name of Laboratory : Electrical Workshop Lab Subject Code : EX 306 Name of Department : Electrical Engineering

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LIST OF EXPERIMENT

S.No. NAME OF EXPERIMENT 1. STUDY & PERFORMANCE OF DIFFERENT TYPES OF WIRE JOINTS

2. STUDY AND PERFORMANCE OF STAIRCASE WIRING

3. STUDY AND PERFORMANCE OF SERIES AND PARALLEL CONNECTION OF FLOURESCENT TUBE LIGHT

4. STUDY AND PERFORMANCE OF GODOWN WIRING

5. SERIES AND PARALLEL CONNECTION OF BULBS AND POWER SOCKETS BY SINGLE SWITCH AND MULTI SWITCHES.

6. Project

7. LAB QUIZ


EXPERIMENT NO. 1

OBJECT -: Study & performance of different types of wire joints

APPARATUS REQUIRED-: S. No Description Wire size Quantity 1. Single core standard wire 3.20 Sq. mm 13 pcs 2. Single core standard wire 7.20 Sq. mm 13 pcs 3. Pocket knife ------- 1 no. 4. Wire cutter ------- 1 no. 5. Side cutting plier ------- 1 no.

THEORY-: In all jobs of wiring, splicing (jointing) and termination is a necessity. The jointing is required

since the wires are manufactured in 100 meters lengths and the total length of wire used for house wiring may be more than 100 meter. The termination of wire is needed as the wires are to be connected to switches , holders, receptacles etc. It is important to note that all joints made must be mechanically and electrically sound. The jointing conductors and wires should always be carried out at outlets, i.e. in switches, ceiling roses using the looping in system or in junction boxes used specially for this purpose. Splicing should never be done in conduit runs . but sometimes when repairing old works jointing becomes a necessity.

PROCEDURE-: 6 types of wiring joints are should be mentioned here:-

1. Western union splice or twist splice

The western union splice can be completed in two steps which are A. Removing insulation :

For jointing two conductors together, first their insulation is removed B. Mechanically joints the conductors:

For making the joints cross the two bare wires at ends at a distance of about 2 cm from insulation of either of the wire , the wire are crossed or neek turned as shown in figure 1(a). the crossing or neek turn of the conductors prevents the two wire being separated out under a pressure. Now with the help of the forefinger and thumb or with plier make five to eight turns, as shown. The remaining excess of the conductors could be cut away with the plier and the turns should be tightened with it. Now a similar process is repeated with the other conductor and is finished off in a similar manner. The finished joint is shown in figure 1(c).


2. MARRIED JOINT-: For a wire having one strand only the joint made is called twisted joint but for wires having no. of strands the joint made is called as married joint . the following points show how the joint is made: A. Remove the insulation about 10 cm , on each wire with the help of knife in a tapered fashion

as explained in twist splice. B. Remove braid for about 2-5 cm, on each wire. C. Separate the strands of each wire by twisting the stranded conductors in opposite direction

to that of winding. D. Clean each of the strand gently with sand paper. E. Retwist the strands for a length of about 5 cm. F. Bind the twisted wire with a binding wire. G. Cut of the middle strand. H. Spread the individual strand as shown in figure2 (a). I. Bring the two wires end to end with all the strands intersecting as shown in figure 2(b). J. Hold the one of the wires in the left and wrap one of the strands of the wire around the

twisted conductor in opposite direction as shown as in figure 2(c). Repeat the process with the other strand and so on.

K. Round off the ends with mallet or pliers. L. Repeat the process with the other side of the wire.

3. Single branch splice or a tap joint-: Sometimes it is necessary to tap the electrical energy from a running line. In that case only one free end of the wire is available and thus the twist joint or western union joint is not possible which necessarily requires two free ends. So in such circumstances a T joint is necessarily made. The following step explains the process of joining-: A. Remove the insulation of the running wire as shown in figure 3(a) for a length of about 2.5

cm, with care & precautions as explained earlier. B. Remove the insulation of the branch wire for a length of about 7.5 cm as shown in figure

3(b). C. Gently clean the conductors with the help of a double zero sand paper. D. Now keeping the branch wire at 90 degree to the running wire & with insulation of both

wires near to each other make a neck turn as shown in figure 3(c) Which grounds against the slipping of the joints under pressure

E. With the branch wire mow give 5 to 8 turns as in the case of western union splice.


F. Cut of the excess of the conductor. G. Now round off the conductor end with the help of a plier or mallet. The finished joint is

shown in figure 3(d).

4. DOUBLE BRANCH SPLICE-: The double branch splice is used when the electrical energy is required to be tapped in two directions at right angles to each other. Such a splice is nothing more than that of two single branch splices in opposite direction. So the method of obtaining such a joint is the same as that of a single branch splice figure 4 it represents double branch splice.

5. TAP JOINT FOR STANDERED WIRES

For standard wires the single branch splice or the tap joint is made as explained in steps indicated in figure 5(a, b & c) A. Remove insulation of the running wire of the length of about 5 cm. B. Similarly remove insulation of the tapping wire for a length of about 7.5 cm. C. Clean the conductors gently with sand paper. D. Separate strands of the running wire into two groups as shown in figure 5 (a). E. Insert the tap wire into the opening made in the running wire. F. Divide the strands of the tap wire into two groups shown in the figure 5(b). G. Wrap on of the strands around the running wire than wrap the second strand & so on. H. Wrap one of the strands around the running wire in the opposite direction to the previous

one as shown in figure 5 (c). I. Round of the ends of the conductor with a plier or mallet.

6. PIGTAIL JOINT-: The pigtail joint is most important joint, since it is often required for termination of the wires in switches, Holders etc. Moreover it can easily be made & unmade. For making such a joint. A. Remove insulation from the two wires as shown earlier for a length of about 5 cm. B. Gently clean both the conductors. C. Keep the two wires with their insulation parallel. D. With a plier make a number of twists as shown in figure 6. E. Keep the length of the twists about 2.5 cm & cut off the excess conductor. F. Round off the corners with a mallet.


Now soldier the splice & provide a tape. Similarly more than two wires can also be spliced together to form a pigtail joint.

PRECAUTION-: It is Important to note that all joints made be mechanically & electrically sound take care not to injure the copper conductor.


EXPERIMENT NO. 2

OBJECT-: Study and performance of STAIRCASE WIRING

APPARATUS REQUIRED-: S .No. DESCRIPTION CAPACITY QUANTITY 1. Single core stranded wire 3.20sq. mm. 230 volts 3 meter 2. Incandescent lamp (Bulb) 60watt. 230 volts 01 no. 3. Tumbler switch (Two way) 5 ampere 230 volts 02 no. 4. 3 pin socket outlet 5 ampere 230 volts 01 no. 5. Wooden board 4.5 sq. feet 01 no. 6. Bulb holder (Batten type) ----- 04 no. 7. Drill machine ----- 01 no. 8. Neon tester ----- 01 no. 9. Screw driver ----- 01 no. 10 Cutting plier ----- 01 no.

THEORY-: In this wiring, a single lamp is controlled from two places. For this purpose two numbers of two way switches are used . it is that wiring which makes use of 2 switches to operate bulb at the beginning of the stair lights and the bulb gives off by pushing the button in the end. One of the terminals of the bulb is connected to the main line whose power line is connected to middle slot of two-way switch. Remaining first of these slots is connected in parallel as in crossed node.

PROCEDURE-: A. Collect the materials required for this experiment. B. Draw the layout of the given circuit diagram in the circuit board. C. Fix the necessary materials, by using drilling machine in the layout board. D. One end (B1-2) of the lamp holder (B1) is connected to neutral point and another point

(B1- 1) is connected at the center of the two-way switch (S2-2) E. The center of the switch (S1-2) is connected to the phase line. F. The connection of the other two ends of two-way switch is connected as follows. The point 1 of

switch S1 is connected to point 1 of switch S2 and point 3 of S1 is connected to point 3 of S2. G. The given lamp is fixed on the lamp holders. H. Controlling the switches, the circuit is checked and results are tabulated.


CIRCUIT DIAGRAM-:

CALCULATION-: FUSE RATING CALCULATIONS: Power drawn by the circuit = 60 watts Voltage of the circuit = 230 volts P = V I COS Ø Assuming COS Ø = 1 P = V x I x 1 Current in the circuit (I) = power (P) / Voltage (V) = 60 W / 230 V = .260 AMP. Fuse rating of the circuit= rounding off the current to the nearest 5 = 5A ( Normally fuses are available in the ratings of 5A, 10A and etc.)

RESULT-: Thus the STAIRCASE WIRING has been constructed, tested and the results are tabulated.

PRECAUTION-:

1. Tools should be used carefully 2. Fitting should be tightly fitted. 3. Connection should be tight. 4. Wire should be on the conduit, power gripped properly.


EXPERIMENT NO. 3

OBJECT-: study and performance of series and parallel connection of FLOURESCENT TUBE LIGHT.

APPARATUS REQUIRED-: S. No. DESCRIPTION CAPACITY QUANTITY

1. Fluorescent Tube light 40 Watts 1 NO. 2. Fluorescent Tube light 20 Watts 2 NO. 3. Polyester ballast (Choke) 40 Watts 1 NO. 4. Electronic ballast (Choke) 40 Watts 1 NO. 5. Flexible wire 2 core 0.5 mm square 10 Meters 6. Starter ----- 2 NO. 7. Tube light base with holder ----- 2 NO. 8. Plier ----- 1 NO. 9. Knife ----- 1 NO. 10 Side cutter ----- 1 NO. 11. Screw driver ----- 1 NO. 12 Neon tester ----- 1 NO.

THEORY-: Fluorescent tube is a low pressure mercury vapour lamp. The lamp is in the form of long glass tube. The fluorescent tubes are available in lengths of 0.61m (20 watts) and 1.22m (40 watts). The tubes are coated from inside with phosphorous, which is used to convert ultra violet radiations into visible light and to give the required color sensation. When the temperature increases mercury changes into vapour form. Tungsten filaments coated with barium oxide are placed at each side of the tube. At each end of the tube, electrode in spiral form is made of tungsten coated with electrons emitting barium. The tube contains small amount of mercury with small quantity of argon gas at low pressure. A choke is used to give a transient high voltage so as to initiate the electron movement. With the switch closed, the circuit gets closed. The current flows through the choke and the starter. The starter suddenly breaks thereby breaking the circuit. Due to high inductive property of the choke, a transient high voltage is available across the filaments. Hence electrons are emitted and travel through the tube. Such a continuous flow of electrons produces the sensation of light to human eyes.

PROCEDURE-: A. Collect the materials required for this experiment. B. Draw the layout of the given diagram in the plane paper. C. Fix the tube holder and the polyester ballast on the tube base. D. Phase wire is connected in the polyester ballast and neutral direct to the tube light.


E. Fix the fluorescent tube between the tube holders. F. Finally connect the starter in series with the tube light.

CIRCUIT DIAGRAM-:


RESULT-: Thus the fluorescent tube wiring has been constructed and the working is tested.

PRECAUTION-: 1. Check all the accessories as per the circuit. 2. Tools should be used carefully. 3. Fitting should be tightly fitted. 4. Connection should be tight.


EXPERIMENT NO. 4 OBJECT-: Study and performance of GODOWN WIRING


1. Single core stranded wire 3.20Sq. mm 230volts 5 meter 2. Incandescent lamp (Bulb) 60 watt. 230 Volts 4 No. 3. Tumbler switch (one way) 5AMP 230 Volts 01 no. 4. Tumbler switch (two way) 5AMP 230 Volts 03 no. 5. 3 pin socket outlet 5AMP 230 Volts 01 no. 6. Wooden board 4.5 Sq. feet 01 no. 7. Bulb holder ----- 4 No.

THEORY-: In this wiring , we have control to 4 bulbs by 1 single way and 3 two way switches. Suppose that ,we have four rooms in our home and every room have 1 bulb with one switch. In starting position, bulbs B1, B2, B3 and B4 is off(dark) when switches S1, S2,S3, and S4 is switched off position. Hence, terminal 1 and 2 are short circuited of switch S2 when the switch is off position. And terminal 1 and 2 are open circuited of switch S1, when the switch is off position. Firstly, when we turn on the switch S1 for the illuminate the bulb B1. So , that the terminal 1 and 2 of switch S1 is short circuited and the bulb B1 is illuminate. After that, we are entered to second room. Operate the switch S2, the bulb B2 is automatically turn-on and bulb B1 is automatically turn off. After that we are entered to third room. Operate the switch S3, the bulb B2 is automatically turn off and bulb B3 is Automatically turn on. And when we entered in the last fourth room, if we operate the switch S4, Bulb B4 is turn on and Bulb B3 is automatically turn off. After some time we will come back, the same process is reversly repeat ones again from room no. 4 to room no. 1.


CIRCUIT DIAGRAM-:

PROCEDURE-: A. Collect the materials required for this experiment. B. Draw the layout of the given circuit diagram in the circuit board. C. Fix the necessary materials, by using drilling machine in the layout board. D. Terminal 2 of the bulb B1 is connected to neutral point (N) and another terminal 1 is connected

to terminal 1 of switch S2. E. Terminal 1 of the switch S1 is connected to the phase line (P). F. Now, The terminal 2 of switch S1 is connected with terminal 2 of switch S2. G. The terminal 3 of switch S2 is connected with terminal 2 of switch S3. H. And terminal 3 of Switch S3 is connected with terminal 2 of switch S4. I. After that, the terminal 3 of switch S4 is connected with terminal 1 of Bulb B4.


J. Terminal 1 of switch S3 is connected to terminal 1 of bulb B2. K. Terminal 1 of switch S4 is connected to terminal 1 of Bulb B3. L. Terminal 2 of Bulb B1 , B2, B3 and B4 are internally connected with respect to neutral(N). M. After this all process , give the 1 phase , 230 volts, 5oHz AC supply to the main input P and N

terminals. N. The given lamp is fixed on the lamp holders. O. Controlling the switches, the circuit is checked and results are tabulated.

CALCULATION-: FUSE RATING CALCULATIONS:

Power drawn by the circuit = 240 watts Voltage of the circuit = 230 volts P = V I COS Ø Assuming COS Ø = 1 P = V x I x 1 Current in the circuit (I) = power (P) / Voltage (V) = 240 W / 230 V = 1.043 AMP. Fuse rating of the circuit= rounding off the current to the nearest 5 = 5A ( Normally fuses are available in the ratings of 5A, 10A and etc.)

RESULT-: Thus the GODOWN WIRING has been constructed, tested and the results are tabulated.

PRECAUTION-:



EXPERIMENT NO. 5 OBJECT-: Series and parallel connection of bulbs and power sockets by single switch and multi

switches.


1. Single core stranded wire 3.20 sq. mm. 230 volts 5 meter 2. Incandescent lamp (bulb) 60 watt. 230 volts 04 no. 3. 3 pin socket outlet 5 ampere 230 volts 03 no. 4. Bulb holder (Batten type) ----- 02 no. 5. Bulb holder (pendent type) ----- 02 no. 6. Single way switch 5 ampere 04 no. 7. Wooden board 4.5 sq. feet 01 no. 8. Drill machine ----- 01 no. 9. Neon tester ----- 01 no.

10. Screw driver ----- 01 no. 11. Cutting plier ----- 01 no.

THEORY-: Wiring having two types of connection. First type of connection is parallel and second one is series. In parallel connection, we are connecting all electrical accessories and appliances in parallel connections, means phase and neutral wires both are supply provided to electrical accessories like as bulb, fan and power sockets etc. in parallel connection phase wire is provided to current flow and neutral wire is used for complete the circuit as well as return path conductor for closed circuit. In this type of connection, same voltage rating capacity are provided to all electrical accessories with same frequency but current is distributed to all electrical accessories according to its resistance of each electrical accessories. In this type of wiring, No any kind of disturbance to operate any other electrical accessories except faulty circuit. If any electrical accessories are fused or damaged. Very important thing is for improving the power factor of supply, parallel wiring connection is most important. In series connection, we are connecting all electrical accessories and appliances in series connection, means all electrical accessories are connected together with only single phase wire such like as shown in figure of series wiring connection diagram. In this type of connection, current rating capacity having will be little bit different with same frequency but voltage is distributed to all electrical accessories according to its power dissipation capacity. Whole supply of electrical accessories of appliances is cut-off, if any electrical accessories are fused or damaged. So, that’s why we are connected to all electrical appliances or accessories in parallel connection to provide continue flow continue flow of supply.


PROCEDURE-: for parallel connection

1. Neutral wire (Black) of 1 phase 230 volt 50Hz incoming supply is connected to terminal 2 of main

socket MS 1. 2. Phase wire (Red) of 1 phase 230 volt 50Hz incoming supply is connected to terminal 3 of main

socket MS 1. 3. Earth wire (Green) of 1 phase 230 volt 50Hz incoming supply is connected to terminal 1 of main

socket MS 1. 4. Earth terminal 1 of main socket MS 1 is connected to terminal 1 of socket SO 1 and socket SO 2. 5. Neutral terminal 2 of main socket MS 1 is connected to terminal 2 of socket SO 1 and socket So 2

and also connected to bulb B1 and B2. 6. Phase terminal 3 of main socket MS1 is connected to terminal 2 of single way switch S1, S2, S3 and

S4. 7. Phase terminal 1 of switch S1 is connected to terminal 3 of Socket SO 1. 8. Phase terminal 1 of switch S2 is connected to terminal 3 of Socket SO 2. 9. Phase terminal 1 of switch S3 is connected to Bulb B1. 10. Phase terminal 1 of switch S4 is connected to Bulb B2.

For series connection-: A. Neutral wire (Black) of 1 phase 230 volt 50Hz incoming supply is connected to terminal 2 of main

socket MS 1. B. Phase wire (Red) of 1 phase 230 volt 50Hz incoming supply is connected to terminal 3 of main

socket MS 1. C. Earth wire (Green) of 1 phase 230 volt 50Hz incoming supply is connected to terminal 1 of main

socket MS 1. D. Earth terminal 1 of main socket MS 1 is connected to terminal 1 of socket SO 1 and socket SO 2. E. Phase terminal 3 of main Socket MS is connected to terminal 2 of single way switch S1. F. Terminal 1 of switch S1 is connected to one terminal of Bulb B2 G. Second terminal of Bulb B2 is connected to first terminal of Bulb B1. H. Second terminal of Bulb B1 is connected to terminal 2 of socket SO 1. I. Terminal 3 of socket SO 1 is connected to terminal 2 of socket SO 2. J. Terminal 3 of socket SO 2 is connected to terminal 2 of main socket MS 1.


CIRCUIT DIAGRAM-:


CALCULATION-: For parallel circuit -:

Suppose that, 2 Bulbs X 60 watts = 120 watts + 1 CFL = 40 watts + 1 Electric iron = 800 watts Power drawn by the circuit = 960 watts Voltage of circuit = 230 volts

Power(p) = VICos Ø [Assuming Cos Ø = 1] P = V x I x 1 P = V x I watts Current in the circuit I = P / V = 960 / 230 = 4.174 Amp. Total voltage of the circuit V = 230 Volts Total current of 60 watt Bulb I 1 = 60 / 230 = 0.260 x 2 = 0.52 Amp. (I 2) Total current of 40 watt CFL I 3 = 40 / 230 = 0.174 Amp. Total current of 800 watt Electric iron I 4 = 800 / 230 = 3.478 Amp.


Total current in the circuit = 0.52 + 0.174 + 3.478 = 4.174 Amp. Total power consumption of the circuit p = V x I = 230 x 4.174 = 960 watts Total resistance of the circuit R = V / I = 230/4.174 55.10 ohms ( acc. To ohms law) Total current in the circuit I = V / R = 230/55.10 = 4.174 Amp. Total voltage of the circuit V = I. R = 4.174 x 55.10 = 230 Volts Fuse rating of the circuit = rounding off the current to the nearest 5 = 5 Amp. (normally fuses are available in the ratings of 5A, 10A and etc..)

for series circuit-: suppose that, 2 Bulbs X 60 watts = 120 watts

+ 1 CFl = 40 watts + 1 Electric iron = 800 watts Current rating of the 60 watt Bulb B2 I 1 = P1 / V = 60/230 = 0.260 Amp Voltage rating of the 60 watt Bulb B2 V 1 = P1 / I1 = 60/ 0.260 = 230 Volts Current rating of the 60 watt Bulb B1 I 2 = P1 + P2 / V = 60+60/230 = 0.521 Amp. Voltage rating of the 60 watt Bulb B1 V2 = P2 / I2 = 60/ 0.521 = 115.163 volts Current rating of the 40 watt CFL C1 I3 = P1+P2+P3/V =60+60+40/230 =0.695Amp Voltage rating of the 40 watt CFL C1 V3= P3 / I3 = 40/0.695 = 57.553Volts Current rating of the 800 watt Electric Iron E1 I4 = P1+P2+P3+P4/V = 60+60+40+800/230 = 4.173 Amp Voltage rating of the 800 watt Electric Iron E1 V4= P4/I4 = 800/4.173 = 191.708 Volts V1, V2, V3, and V4 is different in series wiring.

If all loads having same wattage are connected in series connection, then the current flows in the each load are to be equal but the voltage is distributed to all electrical accessories according to its power dissipation capacity. But all load are having different-different wattage capacity, so the every equipment drawn the different current and different voltage.

RESULT-: Thus the series wiring has been constructed, tested and the results are tabulated.

PRECAUTION-:



LAB QUIZ/ANSWERS Q1. What is the abbreviation of kwa? ANS-: Kilo Watt Amperes Q2. Name the standard of the wires according to their gauges? ANS-: 1/18, 3/20, 7/20, 7/22 Q3.What is the use of lamp holder? ANS-: Hold in particular position Q4. What is the symbol of the ceiling fan? ANS-: Q5. What is the function of hawk saw? ANS-: To cut pipes, metal sheet & wooden pieces Q6. How many types of pliers we used? ANS-: Flat nose, long nose, cutting & combination Q7. What do you meant by RPM? ANS-: Revolutions per minute Q8. What is the function of chisel? ANS-: Cutting metal pieces Q9. What is the function of screwdriver? ANS-: According to length of a bit Q10. Why we use flexible wires? ANS-: Increasing the length of the supply cable Q11. Why we make a T joint? ANS-: To tap the supply Q12. What does you meant by 3/22 SWG? ANS-: 3 wires &22 is the diameter of the wire Q13. What is the application of straight joint? ANS-: Increase the length of the wire Q14. What is the main precaution to make the joints? ANS-: Tight and properly Insulated


Q15. Which joint we use for tap connection from T-joint horizontal line? Q16. Which tool is used for twisting the wires? ANS-: Plier Q17. Which joint is used for Fan connection? ANS-: T-joint Q18. What is swg. Of earthing wire? ANS-: 1/18 SWG Q19. How we increase the length of conductor? ANS-: Straight joint Q20. What is the function of a cutter? ANS-: Cutting cables

Q21. Which type of switch we use in stair case wiring? ANS-: Two way switch Q22 What do you meant by CTS? ANS-: Tough Sheath Q23. Where we use two-way switches? ANS-: Staircase wiring & long godown Q24. Which tools are used for wiring? ANS-: Plier, cutter, screwdriver, hammer. Q25. What is TW batten? ANS-: Teak Wood Batten Q26. What is the main precaution for staircase wiring? ANS-: No connection should be naked Q26. What is the function of saw? ANS-: Cutting sheet, wood & pipes Q27. What is the link clips? ANS-: Holding wires


Q28. Where we use three pin plugs? ANS-: Connecting the load Q29. What is the function of megger? ANS-: Measure insulation of cable Q30. What do you meant by 3/22 ? ANS-: 3 wires & 22gauge of wire Q31. How much voltage in a single-phase supply? ANS-: AC 230 volt Q32. What do you meant by DPIC? ANS-: Double pole iron clad Q33. What is the bus bar? ANS-: To take many connections Q34. How we represent the lamp? ANS-: Q35. Why we use regulator? ANS-: To regulate supply voltage Q36. What is the max. Load on a switchboard? ANS-: 10 switches or 1000W Q37. What is full form of MCB? ANS-: Miniature circuit breaker Q38. What is cleat wiring? ANS-: Used for moist wiring Q39. What is the colour code of wiring? ANS-: R-Y-B phase Q40. What is the full form of PVC? ANS-: Polyvinyl chloride

Q41. What is the standard dia. of the tube light?


ANS-: 25 mm Q42. Which material is used for coating the tube? ANS-: Argon gas or neon Q43. Which gas is used in tube light? ANS-: Zinc silicate cadmium silicate. Q44. What are the standard lengths of tube light? ANS-: 6m, 1.2m and 1.5m. Q45. What is the function of starter? ANS-: Yes, by shorting the two wires temporarily. Q46. Why we use choke in tube light? ANS-: To supply high voltage during starting Q47. Name any two types of the starter? ANS-: Glow type, thermal type. Q48. How much power consumed by the tube light? ANS-: 40 watt approximately. Q49. At which supply the tube is operated? ANS-: 230 volt ac Q50. Can we start the tube light with out a starter? ANS-: To complete the circuit initially

Documents

EX 306- Electrical Workshop · 2014-11-08 · MARRIED JOINT-: For a wire having one strand only the joint made is called twisted joint but for wires having no. of strands the joint