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Lesson 13 Shunt Connected Dc Motor
ExamplesET 332a
Dc Motors, Generators and Energy Conversion Devices
1
2
Learning Objectives
Explain how changing field excitation of a shunt motor affects its performance
Explain how the internal feedback inherent in the shunt motor maintains a nearly constant shaft speed.
Use shunt motor equations and circuit model to compute motor operating conditions.
3Lesson 13 332a.pptx
Dynamic Response of Shunt Motors
TD = KT(Ia)
Time
TD
Ia
n
TL
Ea
Ea = Ke(n)
1.) Increasing TL causes motor to slow.
2.) Reduced armature
speed decreases Ea.
3. ) More Ia flows in armature circuit. More Ia means more TD.
4.) When TD matches TL system stabilizes at new operating point. Ia higher:
5.) Ea and n return to almost the same values
e
a
K
En
acir
aTa R
EVI
Lesson 13 332a.pptx4
Dc Shunt Motor Solution MethodsJust as in other machines studied up to now, the motor speed, developed torque and generated emf are all proportional. If an operating point and a percent increase/decease is known, the new operating point can be found using proportions.
Ea is proportional to speed
2
1
2a
1a
n
n
E
E
TD is proportional to armature Current
2a
1a
2D
1D
I
I
T
T
1p
2p
2a
1a
2
1
E
E
n
n
Speed is directly proportional to Ea and inversely proportional to field flux
Lesson 13 332a.pptx5
Example 13-1:Shunt Motor Speed Control Using Field Weakening
A 10 HP 240 volt 1200 rpm motor is operatingat rated conditions. Determine the percent change in shunt field flux required to lower the speed to 900 rpm. Assume that armature current remains the same.
Lesson 13 332a.pptx6
Example 13-1 Solution (1)
n1 = 1200 rpm n2 = 900 rpm
Define speeds for two cases
Set up proportions
G1p
acir1aT1 k
RIVn
G2p
acir2aT2 k
RIVn
acir2aT
G2p
G1p
acir1aT
G2p
acir2aT
G1p
acir1aT
2
1
RIV
k
k
RIV
kRIV
kRIV
n
n Since Ia1=Ia2 this simplifies
1p
2p
2
1
n
n Find the value of Fp2 assuming Fp1 = 1
33.11rpm 900
rpm 1200 2p
%33%1001
133.1%100
1p
1p2p
Answer
Lesson 13 332a.pptx7
Example 13-2A 200 volt shunt motor is rated a 5 HP and 1000 rpm.At rated output it draws 25 A of line current. The totalarmature circuit resistance is 0.5 ohms. The field resistance is 100 ohms a.) find the total rotational losses of the motor at
rated conditions b.) Find the no load speed of the motor at 200 volts
Lesson 13 332a.pptx8
Example 13-2 Solution (1)
200 V
IT = 25 A
Racir Rf
5 HP1000 rpm
If
Ia
Find Ia
Rotational losses are the differencebetween Pem and Pshaft
Find Ea
Lesson 13 332a.pptx9
Example 13-2 Solution (2)
Answer
Lesson 13 332a.pptx10
Example 13-2 Solution (3)b.) At no-load the only power absorbed is what is required to supply Prot.
Power balance on electric side of motor. Neglecting brushes
Put into standard form
Solve quadratic forIa
Lesson 13 332a.pptx11
Example 13-2 Solution (4)Torques is proportional to armature current Ia. Lower power requires lower torque and armature current
Speed is proportional to Ea
Lesson 13 332a.pptx12
Example 13-2 Solution (5)Solve the previous equation for n2
Answer
Lesson 13 332a.pptx13
Example 13-3: Effects of Changing Field ExcitationWeakening the field increases speed but reduces torque
Example 13-3: A 500 volt 125 HP 1150 rpm shunt motor operates at rated conditions, driving a constant-torque load. The line current at rated conditions is 204.3 amps. The total armature resistance is 0.0343 ohms the field resistance is 96 ohms. a) Determine the steady-state armature current if a 0.052
ohm resistor is connected in series with the armature and the field is weakened by 10% from its rated value.
b) b.) Determine the steady-state speed for conditions in part a.
Lesson 13 332a.pptx14
Example 13-3: Solution (1)
VT=500 V
Racir
0.0343 W
R1=0.052 W
Rf=96 WIT = 204.3 A
If
Find Ea at rated conditions
Lesson 13 332a.pptx15
Example 13-3: Solution (2)
Switch in additional resistance, R1, and weaken field
TD1 = TD2 Constant torque load
Lesson 13 332a.pptx16
Example 13-3: Solution (3)
Field weakened by 10% reduces the value of KT by 10% assuming no magnetic saturation
Lesson 13 332a.pptx17
Example 13-3: Solution (4)
Answer Part a
b.) Find speed under the above conditions
Lesson 13 332a.pptx18
Example 13-3: Solution (5)
Answer Part b
Lesson 13 332a.pptx
End Lesson 13ET 332aDc Motors, Generators and Energy Conversion Devices
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