1.what is the relation between RXLEV [0 to 63] and rxlev [- 110 to -47]?

Ans. Rx level 0 to 63 is GSM unit. While -110 to -47 is dbm Rxlevel unit of GSM. When we will add 110 to Rxlevel[dbm],it will get convert into GSM unit 0 to 63.

This relation is define on the bassis of TA report If the value of TA is less Then Rx lev is also near by -47 dBm and the the last stage of getting signal in idea state 34.2Km apart we will get -110 dBm

0 to 63 is the total Pool in a network in which we can use Carrier frequencies and etc And -110 to -47 is power level of in which MS sensitivity work

2. How the E1 speed is calculated as2.048mbps.write the full procedure.

Ans. E1 has 32 channels(timeslots) and data rate of each channelis 64kbps . so multiply 32*16 becomes 2048kbps or2.048Mbps.I hope you got the answer.

We need to calculate why a Time Slot occupies 64 bits.Lets Start-Audible Voice Frequency is of range 3.5Khz to 4Khz. As per sampleing theorm, rate of sampling should be twice the max. freq. i.e. 4X2=8Khz which means you require 8000samples per second to quantize the analog voice signal.As a fact, one sample requires 8-bits.Therefore, 8000 samples would require - 8000X8=64000bitsi.e. 1 voice sample will need at least 64kbps to travel.Now, E1 is designed as such to have 32 time slots, each with a BW of 64kbps.

Thus, E1=32X64=2048 Kbit i.e. 2Mbps

Hope this clarifies.