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EQUATIONS OF A LINE
By: Mr. Xandro Alexi A. Nieto, M.Ed.Math UST Faculty of Pharmacy
run = 2
Review of Terms Before proceeding to our lesson, please recall the
following terms: Slope (m) rise / run from any point in the line. x-intercept (a) point of the x-axis where the line pass through.
To illustrate,
x-int (a) - 2
y-int (b) 1 rise = 1
y-intercept (b) point of the y-axis where the line pass through.
FORMS OF A LINE
The three forms of a line that we are going to discuss in this presentation are, as follows:
1by
a
x
slope-intercept form
point slope form two-point form
Some Analytic Geometry books would include the intercept form, . But since equations in those forms may be derived using the two-point form, it wont be discussed anymore in this presentation.
bm xy 11 xxmyy
112
121 xx
xx
yyyy
SLOPE-INTERCEPT FORM
SLOPE-INTERCEPT FORM
The slope-intercept form is used when the given are slope (m) and y-intercept (b) of the line. Do not use the slope-intercept form if the given are slope (m) and x-intercept (a).
Any equation in standard form, is already in slope-intercept form.
bm xyslope y-intercept
SLOPE-INTERCEPT FORM
EXAMPLES:
bm xy
Find the equation of the line with slope of and y-intercept of 3. 3
4
To graph the given, m = and b = - 3. 34
run = 3
rise = 4
y-int = -3
To find the equation of the line, use .
Since m = and b = -3, then 34
334 xy , then express in general form
0934943
394
yxxy
xy
is the equation of the line.
SLOPE-INTERCEPT FORM
EXAMPLES:
bm xy
Find the equation of the line with slope of and y-intercept of .
32
To graph the given, m = and b = .
run = 3
rise = -2
y-int = 1/2
To find the equation of the line, use .
Since m = and b = , then
21
32 xy , then express in general form
0364346
634
yxxy
xy
is the equation of the line.
32
32
21
21
21
TRY THIS! 41
SLOPE-INTERCEPT FORM
Find the equation of the line with slope of and y-intercept of .
32
ANSWER: 3x + 12y - 8 = 0
POINT-SLOPE FORM
Let (x,y) be the unknown point and (x1,y1) be the given point.
By definition of slope ,
and since the (x,y) is an unknown point, then .
By cross-multiplication, .
POINT-SLOPE FORM The point-slope form is used when the given are slope
(m) and a point passing through the line (x1,y1). Suppose you want to find the slope of the line, in which theres only
one given point (x1,y1).
1
1
xx
yym
11 yyxxm
Thus, the formula were going to use is , where m is the given slope and (x1,y1) is the given point.
11 xxmyy
12
12
xx
yym
To find the equation, it is given that
m = - 3 and (x1,y1)=(1, 2).
Find the equation of the line with slope of - 3 and passing through (1, 2).
POINT-SLOPE FORM
11 xxmyy
EXAMPLES:
(1,2) rise = - 3
run = 1
Substitute the given to
132 xy332 xy
053 yx is the equation of the line.
To graph the given, note that the slope is -3 or -3/1. Thus, giving a rise of -3 and run of 1.
To find the equation, it is given that
m = and (x1,y1)=(-3,1).
Find the equation of the line with slope of and passing through (-3, 1).
POINT-SLOPE FORM
32
32
11 xxmyy
EXAMPLES:
(-3,1)
run = 3
rise = 2
Substitute the given to )3(
321 xy 3
321 xy
3213 xy6233 xy0932 yx is the equation of the line.
Find the equation of the line with slope of and passing through (-3, -2).
POINT-SLOPE FORM
41
TRY THIS!
ANSWER: x + 4y + 11 = 0
TWO-POINT FORM
TWO-POINT FORM
The two-point form is used when the given are two points ((x1,y1) & (x2,y2)) passing through the line.
11 xxmyy Weve learned in the point-slope form that and from the definition of slope that .
12
12
xx
yym
112
121 xx
xx
yyyy
Thus, by making m as , in the point-slope form, we have
12
12
xx
yy
where ((x1,y1) & (x2,y2)) are the two points passing through the line.
TWO-POINT FORM
EXAMPLES: Find the equation of the line passing through (1,2) and (4,3).
To graph, simply plot the two points then connect by drawing a line.
(4,3) (1,2)
To find the equation of the line, substitute (1,2) and (4,3) to (x1,y1) and (x2,y2)) respectively.
112
121 xx
xx
yyyy
114232
xy
1312 xy
1123 xy
163 xy053 yx is the equation of the line.
TWO-POINT FORM
EXAMPLES: Find the equation of the line passing through and .
(3,-0.5)
(-0.25,-2)
112
121 xx
xx
yyyy
41
413
221
2 xy
41
41323
2 xy
41
1362 xy
416213 xy
2362613 xy
is the equation of the line.
2,41
21
,3
0249136 yx
0492612 yx
TWO-POINT FORM
TRY THIS! Find the equation of the line passing through and (1,-2).
41
,3
ANSWER: 9x + 16y + 23 = 0
REVIEW
So far, we have discussed the three forms of equations and we derived equations by direct substitution of the given.
slope-intercept form
point slope form two-point form
bm xy 11 xxmyy
112
121 xx
xx
yyyy
WHAT IFs?
What if the given are the slope and the x-intercept of the line?
What if the given are a point passing through the line and x or y-intercept?
What if the given are the lines x and y-intercepts?
Lets answer these questions one by one.
What if the given are the slope and the x-intercept of the line?
Do not use the slope-intercept form because the slope-intercept form is used if the given are the slope and the y-intercept (NOT THE X-INTERCEPT!).
What if the given are the slope and the x-intercept of the line?
Instead, recall that any x-intercept (a) may be expressed as ordered pair (a,0). Thus, you may use point-slope form.
What if the given are the slope and the x-intercept of the line? EXAMPLE:
Find the equation of the line with slope of 3 and has an x-intercept of 2.
run = 1
rise = 3
Since the x-intercept is 2, then its ordered pair is (2,0). Considering the slope of 3, then we have to use the point-slope form.
06363
23011
yxxy
xyxxmyy
is the equation of the line.
x-intercept = 2
What if the given are a point passing through the line and x or y-intercept? Recall that any x-intercept (a) may be expressed in
ordered pair (a,0).
Likewise, any y-intercept (b) may be expressed in ordered pair (0,b).
Thus, the two-point form may be used in cases like this.
What if the given are a point passing through the line and x or y-intercept? EXAMPLE:
Find the equation of the line passing through (3,-1) and having a y-intercept of -2.
(3,-1) Y-intercept = - 2
Since the y-intercept is -2, then its ordered pair is (0,-2). Considering the other given, (3,-1), then we can make use of the two-point form.
063
6323
312
003
212
112
121
yxxy
xy
xy
xy
xxxx
yyyy
is the equation of the line.
What if the given are the lines x and y-intercepts?
Again, recall that any x-intercept (a) may be expressed in ordered pair (a,0).
Likewise, any y-intercept (b) may be expressed in ordered pair (0,b).
Thus, the two-point form may be used in cases like this.
What if the given are the lines x and y-intercepts?
EXAMPLE: Find the equation of the line having an x-intercept of 3 and a y-intercept of 2?
y-intercept = 2
x-intercept = 3
Since the x-intercept is 3, then its ordered pair is (3,0). Likewise, since the y-intercept is 2, then its ordered pair is (0,2). Thus, we can now make use of the two-point form.
0632623
33
2
330020
112
121
yxxy
xy
xy
xxxx
yyyy
is the equation of the line.
Were done with the topic.
You may now answer the 10-point online assignment,
linear equations in two variables.