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EP101 Sen Lnt 003 Alkene May11
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5/25/2018 EP101 Sen Lnt 003 Alkene May11
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AlkenesJully Tan
School of Engineering
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WK 3 EP101 / EG101 2School of Engineering
Alkenes: Names and Structures Alkenes- hydrocarbons that have one or more double bonds between carbon atoms
CnH2n
Monounsaturated- one double bond
DieneAlkenes that have two double bonds.
Polyunsaturated- two or more double bonds
Double bonds (alkenes) is shorter than single bond (alkanes).
Each pi bond (and each ring) decreases the number of Hs by two.
Each of these is an element of unsaturation.
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Nomenclatureof Alkenes
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Nomenclature: One double bonding Alkenes are named using the IUPAC system
Rules:Step 1: Find the longest chain that includes bothcarbons of the double or triple
bond. Indicate the length of the parent chain by using a prefix that tell the
number of carbon atoms and the suffix, -ene(dropane)
Step 2: Number the chain from the end that gives the lower set of numbers to the
carbons of the double bond. Designate the position of the double bond by
the number of its 1st carbon.
Step 3: Branched Alkenes are named in a manner similar to alkanes; substituent
groups are located and named.
In naming cycloalkenes, we number the carbon atoms of the ring double bond 1and 2 in the direction that gives the substituent encountered first the lower
number.
CH3 - CH = CH - CH2 - CH(CH3) - CH3 is called 5-methylhex-2-ene
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Common Names Usually used for small molecules. Examples:
CH2 CH2
ethylene
CH2 CH CH3
propylene
CH2 C CH3
CH3
isobutylene
IUPAC: ethene propene 2-methylpropene
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The root name is based on the longest chain containingboth endsof allthe alkenes units.
The chain is numbered so as to give the one of the alkenes units the lowest possible number (i.e.
first point of difference).
The location for the lowest numbered carbon of each alkenes is used in the name.
The appropriate multiplier (i.e.di- for two, tri for three) is inserted before the -ene suffix.
In order make the name pronounceable, -a- is inserted after the root.
Nomenclature: Dienes, Trienes, and Polyenes
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1,4-pentadiene
2-methyl-1,3-butadiene
1,3-cyclopentadiene
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Alkenes as Substituents In some cases, a group containing an alkenes may need to be treated as a substituent.
In these cases the substituent is named in a similar fashion to simple alkyl substituents.
The method is required when the alkenes is not the priority group. The substituent is named in a similar way to the parent alkenes.
It is named based on the number of carbon atoms in the branch plus the suffix-yl. i.e. alkenyl
There are two common names that are widely used:
Example CH3CH=CHCH(CH=CH2)2
1. Functional group is a alkenes, therefore suffix = -ene
2. The longest continuous chain with 2 C=C is C6 therefore root plus "a" =hexa
3. There are two alkenes in the parent chain, so insert the multiplierdi
4. Number from the right as drawn to give the C=C the lowest locants : therefore1- and 4-
5. The substituent is a C2 alkenyl group i.e. an ethenylgroup
6. The substituent is on C3
3-ethenylhexa-1,4-diene
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Cis- and Trans- Terminology All terminal alkenes those with a C=CH2 unit do notexist as cis-and trans-isomers.
All 1,1-symmetrically disubstituted alkenes i.e. those with a C=CR2 unit do notexist as cis-and
trans-isomers.
Alkenes with the R-CH=CH-R unit canexist as cis-and trans-isomers.
If we consider the general alkenes unit shown below, then the alkenescan only exist as cisand trans
isomersif R1is not equal to R2ANDR3is not equal to R4.
If 2 identical groups attached to any one of the double bonded C, geometric isomerism is not possible.
33
3
CHCH
CH HCC
2-methyl-2-butene 1,1-dichloro-2-methyl-propene
Cl
ClCC
CH
CH
3
3
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Name these:C C
CH3
H
H
CH3CH2
C C Br
H
Br
H
trans-2-pentene cis-1,2-dibromoethene
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E- and Z-Nomenclature of Alkenes The cis- / trans- style is based on the longest chain whereas the E/Z style is based
on a set of priority rules.
For alkenes with 4 different substituents, we use E/Z nomenclature.
The E- and Z- style is more reliable and particularly suited to highly substituted
alkenes, especially when the substituents are not alkyl groups.
The Cahn-Ingold-Prelog priority rulesare used for naming geometric isomers(e.g. E- or Z-alkenes).
These rules are based on atomic number, and the first point of difference.
http://www.chem.ucalgary.ca/courses/350/orgnom/main/difference.htmlhttp://www.chem.ucalgary.ca/courses/350/orgnom/main/difference.html5/25/2018 EP101 Sen Lnt 003 Alkene May11
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Cahn-Ingold-Prelog Priority Rules Imagine each alkenes as two pieces, each piece containing one of the sp2 C
Assign the priority (high = 1, low = 2) to each group on each sp2 C based on atomic
number Determine the relative position of the two higher priority groups
If they are on the same side then it is a (Z)-alkenes (German; zusammen= together)
If they are on opposite sides then it is an (E)-alkenes (German; entgegen= opposite)
If there is more than one C=C that can be E/Z, then the location needs to be included
with the location, e.g.(2E,4Z)
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Ranking Priorities: Cahn-Ingold-Prelog Rules Must rank atoms that are connected at comparison point Higher atomic number gets higher priority
Br > Cl > F > O > N > C > H
In this case,The higher prioritygroups are opposite:
(E )-1-bromo-1-chloro-propene
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Example, -Z
C C
H3C
H
Cl
CH2C C
H
H
CH CH3
Cl1
2
1
2
2Z
2
1
1
2
5E
(2Z, 5E)-3,7-dichloro-2,5-octadiene
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Boiling point - trends are similar to those shown in alkanes
- increases as they get more carbon atoms in their formula
more atoms = greater intermolecular Van der Waals forces
greater intermolecular force = more energy to separate molecules
greater energy required = higher boiling point
- for isomers, greater branching = lower boiling point
C2H4 (- 104 C) C3H6(- 48C) ....... C6H10(83C)
Melting point general increase with molecular mass
the trend is not as regular as that for boiling point.
Solubility alkenes are non-polarso are immiscible (dont mix with) with water
miscible with most organic solvents.
1. Physical Properties Of Alkenes
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Geometry of C-C Double Bond AlkenesC bonded to 3 atoms, used sp2hybridized orbital.
In generally, double bond is shorter than single bond.
High electron density: pair of electrons inbond able to explain the reactivity of alkenes.
Rotation of C=C does not happen: any rotation of 1 C with respect of the other requires bond be
broken.
The rotation of C=C requires 2 C and 4 others atoms attached in the same plane, planar geometry.
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Polarity alkenes is slightly polar than alkanes due to the electrons inbonds are more polarized. Alkyl
substituent donate a electron to C=C bond which increase polarization of vinylic bond.
Polarity is key in determining relative boiling pointas it causes increased intermolecular forces,
thereby raising the boiling point. In the same manner, symmetryis key in determining relative
melting pointas it allows for better packing in the solid state. Thus, trans-alkenes which are less
polar and more symmetrical have lower boiling points and higher melting points and cis-alkenes,
which are generally more polar and less symmetrical have higher boiling points and lower melting
points.
= 0.33 D = 0
cis-2-butene, bp 4C
C C
H
H3C
H
CH3
trans-2-butene, bp 1C
C C
H
H
H3C
CH3
Melting pt
Boiling pt Melting pt
Boiling pt
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Comparing Stabilities of Alkenes Evaluate heat given off when C=C is converted to C-C.
This is partly due to their shape, the straighter shape of the trans isomer leads to hydrogenintermolecular forces that make the isomer more stable
Stability: cis < trans isomer
Less stable isomer is higher in energy, has a more exothermic heat of hydrogenation.
More stable alkenes gives off less heat
Trans butene generates 5 kJ less heat than cis-butene.
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Substituent Effects More substituted alkeness are more stable.
H2C=CH2 < R-CH=CH2< R-CH=CH-R < R-CH=CR2< R2C=CR2
unsub. < monosub. < disub. < trisub. < tetra sub.
Alkyl group stabilizes the double bond.
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Heats of hydrogenation of three butene isomers:
Overall Relative Stabilities of Alkenes
The greater the number of attached alkyl groups (i.e. the more highly substituted the
carbon atoms of the double bond), the greater the alkenes stability
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2 Chemical Properties Of AlkenesELECTROPHILIC ADDITION MECHANISM
The main reaction of alkenes is addition
Because of the extra electron density in a C=C double
bond, alkenes are attacked by species which like
electrons.
These species are called electrophiles; they possess
a positive or partial positive charge somewhere in
their structure.
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ELECTROPHILIC ADDITION MECHANISM
The electrophile, having some positive
character is attracted to the alkenes.
The electrons in the pi bond come out to
form a bond to the positive end.
Because hydrogen can only have two
electrons in its orbital, its other bondbreaks heterolytically. The H attaches to
one of the carbon atoms.
A carbocationis formed. The species thatleft now has a lone pair.
It acts as nucleophile and attacks the
carbocation using its lone pair to form a
covalent bond. Overall, there is ADDITION
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Reaction of AlkenesSynthesis of Alkenes
Addition reaction
Oxidation reaction
Synthesis
Dehydration of alcohol
Hydrogenation of Al kyne
Dehydrohalogenation of alkyl
halides
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Alkenes Synthesis:I: Dehydration of Alcohol It is one of the best method to synthesize of alkenes.
Dehydration=> removal of water, H2O.
This reaction is reversible.
Reagent involved:
Concentrated H2SO4/ H3PO4(as acidic catalyst & dehydrating agent) at
200C or
Al2O3 at high T
General equation:
C CC C
H OH
acid+ HOH
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Example
Saytzeff Rule: The major product of alkenes is the comp. with the highest no. of alkyl
substitution on C atom of the double bond.
(c) H2SO4
OH
R2C=CR2> R2C=CHR > RHC=CHR and R2C=CH2> RHC=CH2
2-butanolCH3CH2CH(OH)CH3
H+
H+
2-butene (major product)
1-butene (minor product)
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Mechanism of Dehydration Involved formation of carbocation: +ve charged intermediate which is very reactive &
unstable.
+
slow
++ H2O
CH3C CH
3
CH3
OH2
CH3C CH
3
CH3
Step 2: Carbocation formation: The electronegative O atom attract the electron from C, which cause
breaking of a bond. 1 molecule of water released and a carbocation form.
Step 1: Protonation of alcohol: Proton of acid act as catalyst which protonates the OH group into H2O.
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+
+ H+
CH3C CH
3
CH3
C CH2
CH3
CH3
Step 3: Removal of 1 proton of carbocation to regenerate the
acid catalyst and form alkenes
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There are 3 type of carbocation: Primary, secondary & tertiary
- The stability & easiest for carbocation forming is 3> 2 > 1
- The tertiary alcohol undergo dehydration easier compared secondary & primary evenin low acidic catalyst.
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R C C R'
NH3 or RNH2
R
C C
R'
R
C C
R'
H2 Ni
Li or Na
H2C C
LindlarCatalyst H
C C
H
Alkenes Synthesis:II: Hydrogenation of Alkynes
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Syn-Hydrogenation of Alkynes: cis-Alkenes
.
Theselective catalytic hydrogenation of alkynes with a "poisoned"catalyst is a syn-additionthat yields cis-alkenes. A second way to carry
out this transformation is with a nickel boride catalyst(Ni2B) sold
commercially as P-2
3-hexyne+ H2CH3CH2C CCH2CH3 Ni2B
(Z)-3-hexene (97%)
C CH
H3CH2C
H
CH2CH3
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.
Alkynes are reduced to trans-alkenes by alkali metals (Li or Na) in
liquid ammonia (-33o
C) or ethylamine (BP 16.6o
C) at lowtemperatures. Because these metals dissolve as they react, these and
other similar reductions are called dissolving metal reductions
3-hexyne
(i) Li, C2H5NH2, -78oC
(ii) NH4Cl (workup)
(E)-3-hexene
CH3
CH2
C CCH2
CH3 C C
H3CH2C
H
H
CH2CH3
Anti-Hydrogenation of Alkynes: trans-Alkenes
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examples:
Saytzev rule: to form a highly substituted alkenes
1. Involved removal of H and X from C atom
2. Rxn is in basic condition
3. Alkyl halide is heated in KOH in alcohol to give alkenes.
Alkenes Synthesis:III: Dehydrohalogenation of Alkyl Halide
2OHKX+ ++ KOH
X
Alcohol
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Reaction of AlkenesOxidation
i. cleavage
Addition
i. Hydrogenation
ii. Halogenation (Cl / Br)
iii. Electrophilic (H-A)
iv. H2SO4
v. H20
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Addition Reaction onto C=C
C C C C
A
+ A-B
B
alkenes reagent Additional product
Addition Reaction: (i) H (Hydrogenation)
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Addition Reaction: (ii) Halogenation (Cl / Br)CCl4
halogen
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Addition Reaction: (iii) Electrophilic (HCl / HBr / HI) Hydrogen halide is a polar compound that consist of H+
H+ less of electron is named as electrophilic.
Double bond, in C=C is with electron.
H+ will attack the electrons in bond.
Carbocation intermediate forms.
Nucleophile adds to the carbocation.
Net result is addition to the double bond. H-AH+ + A-
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It is a rxn of cold concentrated sulfuric acid to alkenes and stirred to products alkyl hydrogen
sulfate.
Addition Reaction: (iv) H2SO4
C C+ H
+C
H
C +
C
H
C+ + X:_
C
H
C
X
HOSO3-
HOSO3
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Addition Reaction: (v) H2O
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Both the pi and sigma bonds break.
C=C becomes C=O.
Two methods:
Warm or concentrated or acidic KMnO4.
Ozonolysis
Used to determine the position of a double bond in an unknown.
Oxidation of alkenes: (i) Cleavage
Permanganate is a strong oxidizing agent.
Glycol initially formed is further oxidized.
Disubstituted carbons become ketones. Monosubstituted carbons become carboxylic acids.
Terminal =CH2becomes CO2.
a) Cleavage with MnO4-
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Cleavage by KMnO4
CCCH3 CH3
H CH3 KMnO4
(warm, conc.)C C
CH3
CH3
OHOH
H3C
H
C
O
H3C
H
C
CH3
CH3
O
C
O
H3COH
+
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C
C
CH2CH3
H CH2CH3
C
C
CH2CH3
CH2CH3
OH
OH
H
HH2O2
H
(2)
(1)OsO4
cis-3-hexene meso-3,4-hexanedi
Cleavage by Osmium tetroxide (OsO4)
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b) Ozonolysis Reaction with ozone forms an ozonide. Ozonides are not isolated, but are treated with a mild reducing agent like Zn or dimethyl
sulfide.
Milder oxidation than permanganate.
Products formed are ketones or aldehydes.
CCCH3 CH3
H CH3 O3C
H3C
H
O O
CCH3
CH3
O
Ozonide
+
(CH3)2SC
H3C
HO C
CH3
CH3
O CH3 S
O
CH3
DMSO
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Test for Presence of Alkenes1. Decoloration Test
2. Permanganate Test
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alkanesname contains
CnH(2n+2)
undergo cracking to produce
-ane
petroleum
aqueous
bromine
are
alcohols
substitution
reactions
CO2and H2O
fuels
areusedas
saturated
- CH2-
unsaturated
C=C
CnH2n
-ene
additional
reactions
alcohols alkanes
dibromoalkanes
react with hydrogen to produce
reactwithsteam
toproduce
name contains
are
decolourises
withbrominetoproduce
each member ofhomologous series
differs by
alkenes