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Enzyme regulation
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It is all in the enzymes • Enzymes can enhance the rates of
metabolic (or other) reactions by many orders of magnitude.
• A rate enhancement of 1017 means that what would occur in 1 second with an enzyme’s help, would otherwise require 31,710,000,000 years to take place.
• So essentially without enzymes such reactions don’t take place.
• Thus, regulation of enzymatic activity is in a sense, regulation of metabolism, or any other cellular process.
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Regulation and control of enzyme activity���1. Substrate level control.
• Most enzymes are highly tuned towards their substrates, having a very low Km.
• Since often [S] > Km, the change in substrate concentration does not change the reaction rate appreciably.
• Thus, controlling a metabolic flux is not normally achieved by varying substrate concentrations.
• A notable exception is glucokinase (Hexokinase IV) in the liver which has a very high KM which is roughly comparable to blood glucose concentration.
• This enzyme was thought to be the glucose sensor in the body.
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Regulation and control of enzyme activity���2. Cooperativity, the “2nd secret of life”
• Cooperativy is the change in the response of an enzyme to changes in substrate concentration. It can be both negative as well as positive according to the sequential model.
• Binding of the 1st substrate molecule differs from binding subsequent molecules.
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Cooperativity: not only for multiple sub-units (e.g. glucokinase): • When [S] is low, the low affinity form of the enzyme (E’) predominates. • When [S] is high, the high affinity form of the enzyme (E) predominates. • The enzyme interconverts between the two states slowly.
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Regulation and control of enzyme activity���3. Allosteric effectors.
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Regulation and control of enzyme activity���4. Substrate cycles.
• The flux S2 -> S1 is 100 units/sec. • The flux S1 -> S2 is 98 units/sec. • The overall flux S2 -> S1 is 2 units/sec. • If enzyme ES2->S1 is activated by 50% (150
units/sec), then the overall flux is now 52 units/sec, an enhancement of 26 fold.
• Although a substrate cycle is wasteful in terms of energy expenditure it does allow moderate enzymatic activations to result in dramatic flux increases.
ES2->S1
S2
S1 ES1->S2
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Regulation and control of enzyme activity���5. Covalent modification.
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Regulation and control of enzyme activity���6. Enzyme concentration.
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Looking for Traditional Metabolic Control Points:���1. Enzymes with low Vmax. • Any enzyme that is working slowly
is obviously a bottle-neck in the reaction.
• Therefore activation of a slow enzyme can increase the flux of the entire pathway.
• In heart muscle glycolysis the slowest enzymes are: • Hexokinase. • Phosphofructokinase. • Aldolase. • Enolase.
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2. Enzymes that catalyze reactions that are far from equilibrium.
• Any enzyme that is catalyzing a reaction that is essentially irreversible (i.e. far from equilibrium) can be viewed as a gate to a dam (any enzyme that isn’t, cannot be used for control).
• This is true for: – Hexokinase. – Phosphofructokinase. – Pyruvate kinase. – Glucose transport.
• While glucose transport is close to equilibrium, once inside the cell, glucose is rapidly phosphorylated.
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A B C D E F G H Unstimulated
Met
abol
ite���
Conc
entra
tion
Diff
eren
ce
Stimulated
3. Cross-over points points. • Upon stimulating a system, look at what happens to the
concentrations of every metabolite. • Any metabolite prior to the control point will be depleted
and any metabolite after will be accumulated.
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4. Control points at the start of a pathway and immediately after brach points.
• Any enzyme that catalyzes the 1st step in a pathway is a potential control point since it shows “commitment” to the pathway.
• Phosphofructokinase is the obvious point in glycolysis.
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• The relationship between the properties and characteristics of a metabolic pathway: – Flux. – Metabolite concentration. – Enzyme activity. – Enzyme concentration.
• The system studied should be in steady state. • The analysis defines several variables in the system.
Metabolic control analysis
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Enzyme flux control coefficient (C) • The fractional change in the pathway flux (J) due to a
fractional change in the enzyme’s concentration. • Flux control coefficient is a property of the pathway. • The sum of all the flux control coefficients in a pathway
should be equal to 1.
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CEiJ ≡
∂JJ
∂[Ei][Ei]
=∂J∂[Ei]
⋅[Ei]J
Flux
Ei concentration
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Elasticity coefficient (ε) • The fractional change in the enzyme’s activity in response
to a fractional change in the concentration of a substrate. • All other components are held in place. • The elasticity coefficient is a property of an individual
enzyme, not a pathway. • For substrates and activators ε > 0, and ε < 0 for products
and inhibitors.
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→ S1→V1S2 →
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εS1E1 ≡
∂ViVi
∂SiSi
=∂Vi
∂Si⋅SiVi
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Response coefficient (R) • The response of a system to external effectors, or
metabolites. • The response coefficient of metabolite X on the flux J
where X acts on enzyme I, is the product of the flux control coefficient and the elasticity coefficient with respect to X.
• A pathway flux will only respond to an effector if it acts on an enzyme with a relatively large flux control coefficient.
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RXJ ≡ Ci
JεXi
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Metabolic control analysis: advantages • Test the influence of an enzyme in regulating a
particular pathway. • Dispels simplistic notions regarding the control of
all enzyme that catalyze reaction which are far from equilibrium.
• Important application in biotechnology, where one wants to increase a particular pathway.
• Helps in pointing out enzymes with high flux control coefficient as potential drug targets.
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MCA example worked out:���1. Flux control coefficient
• Here are the results from an experiment in which the rate of ethanol production by brewers’ yeast was tested as a function of expression levels of the last enzyme of the pathway: alcohol dehydrogenase.
0
50
100
150
200
250
0 50 100 150 200 250
Concentration of alcohol dehydrogenase
Eth
an
ol p
rod
ucti
on[Alcohol
dehydrogenase]Ethanol
production12 10018 12024 140100 200200 200
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[Alcohol dehydrogenase]
Ethanol production
12 10018 12024 140100 200200 200
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CEiJ ≡
∂JJ
∂[Ei][Ei]
≅ΔJ
JΔ[Ei]
[Ei]
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Point 1⇒ CEiJ =
120 −100100
18 −1212
= 0.4
Point 2⇒ CEiJ =
140 −120120
24 −1818
= 0.5
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Point 3⇒ CEiJ =
200 −140140
100 − 2424
= 0.14
Point 4 ⇒ CEiJ =
200 − 200200
200 −100100
= 0
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MCA example worked out:���2. Elasticity coefficient
• When isolated alcohol dehydrogenase is incubated in ethanol concentrations which are 20% above normal, it is inhibited by 10%.
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εS1E1 ≡
∂ViVi
∂SiSi
≅
ΔViVi
ΔSiSi
=−10%20%
= −0.5
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MCA example worked out:���3. Response coefficient
• When isolated alcohol dehydrogenase is incubated in ethanol concentrations which are 20% above normal it is inhibited by 10%.
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RXJ ≡ Ci
JεXi = −0.5 ⋅ 0.45 = −0.2250
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Aspartate transcarbamoylase
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Another subunit
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ATP: purine vs pyrimidines More ATP ore RNA synthesis
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