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Entry AerodynamicsENAE 791 - Launch and Entry Vehicle Design
U N I V E R S I T Y O FMARYLAND
Entry Aerodynamics• Atmospheric Regimes on Entry• Basic fluid parameters• Definition of Mean Free Path• Rarified gas Newtonian flow• Continuum Newtonian flow (hypersonics)
1
© 2014 David L. Akin - All rights reservedhttp://spacecraft.ssl.umd.edu
Entry AerodynamicsENAE 791 - Launch and Entry Vehicle Design
U N I V E R S I T Y O FMARYLAND
Basic Fluids Parameters
2
M ⌘ Mach Number =v
a
a ⌘ speed of sound =
p�RT
ordered energy
random energy
=
12mv2
12mv2g
=
v2
3RT=
�
3
v2
a2=
�
3
M2
✓R =
<m
◆
Re ⌘ Reynold’s number =
inertial force
viscous force
Re =mv
⌧A=
⇢Av2
µ vLA
=⇢vL
µ
Entry AerodynamicsENAE 791 - Launch and Entry Vehicle Design
U N I V E R S I T Y O FMARYLAND
Random vs. Ordered Energy
3
Entry AerodynamicsENAE 791 - Launch and Entry Vehicle Design
U N I V E R S I T Y O FMARYLAND
More Fluid Parameters
4
K =
number of collisions with body
number of collisions with other molecules
K ⌘ Knudsen number
K =�
L
� ⌘ mean free path
L ⌘ vehicle characteristic length
Entry AerodynamicsENAE 791 - Launch and Entry Vehicle Design
U N I V E R S I T Y O FMARYLAND
Estimating Mean Free PathAssume:• All molecules are perfect rigid spheres• Each has diameter σ, mass m, and velocity• Consider a cube with side length L containing N
molecules• N/6 molecules are traveling in each direction
– ±X– ±Y– ±Z
5
v
Entry AerodynamicsENAE 791 - Launch and Entry Vehicle Design
U N I V E R S I T Y O FMARYLAND
Consider Collisions in +Z Direction
6
v
v2v
()
Area = ⇡�2
number of potential +Z collisions
n(+Z) =1
6N
⇡�2L
L3=
1
6N
⇡�2
L2
frequency of +Z collisions
f(+Z) =n(+Z)
�t=
⇡6N
�2
L2
L2v
f(+Z) =⇡⇢�2v
3m
Entry AerodynamicsENAE 791 - Launch and Entry Vehicle Design
U N I V E R S I T Y O FMARYLAND
Consider Collisions in +X Direction
7
v
v
2v
()frequency of +X collisions
f(�X) = f(+Y ) = f(�Y ) = f(+X) f(�Z) = 0
Total frequency of collisions
f =⇡
3(1 + 2
p2)
⇢�2v
m
f(+X) =n(+X)
�t=
p2⇡⇢�2v
6m
Entry AerodynamicsENAE 791 - Launch and Entry Vehicle Design
U N I V E R S I T Y O FMARYLAND
Mean Free Path
8
� =v
f=
m/�2
⇡3 (1 + 2
p2)⇢
✓/ 1
⇢
◆
at sea level: � = 6.7⇥ 10�8 m
at 100 km: � = 0.3 m ⇠ 1 ft
Entry AerodynamicsENAE 791 - Launch and Entry Vehicle Design
U N I V E R S I T Y O FMARYLAND
Five Basic Flow Regimes• Free molecular regime• Near-free molecular regime• Transition regime• Viscous merged boundary layer• Continuous regime
9
Entry AerodynamicsENAE 791 - Launch and Entry Vehicle Design
U N I V E R S I T Y O FMARYLAND
Entry Flow Regimes
ref: Frank J. Regan, Reentry Vehicle Dynamics AIAA Education Series, NY, NY 1984
10
Entry AerodynamicsENAE 791 - Launch and Entry Vehicle Design
U N I V E R S I T Y O FMARYLAND
Flow Regime Definitions
11
K =�
RN
Mean free path after collision
Knudsen number in rarified flow
�c =4
p⇡�
✓Tw
T1
◆ 12 �1M1
If Tw ⇠ T1
�c⇠= 1.9
�1M1
Entry AerodynamicsENAE 791 - Launch and Entry Vehicle Design
U N I V E R S I T Y O FMARYLAND
Free Molecular Regime• Orbital flight• • Molecule encountering a boundary (e.g., surface of
vehicle) attains the state of the boundary aer a single collision
•
12
� � `
Kc � 10 or K1 > 5.24M1
Entry AerodynamicsENAE 791 - Launch and Entry Vehicle Design
U N I V E R S I T Y O FMARYLAND
Newtonian Flow• Mean free path of
particles much larger than spacecra --> no appreciable interaction of air molecules
• Model vehicle/ atmosphere interactions as independent perfectly elastic collisions
α
αV
V
13
Entry AerodynamicsENAE 791 - Launch and Entry Vehicle Design
U N I V E R S I T Y O FMARYLAND
Newtonian Analysis
α
AA sin(α)
ρ
Vmass flux = (density)(swept area)(velocity)
dm
dt= (!)(A sin")(V )
14
Entry AerodynamicsENAE 791 - Launch and Entry Vehicle Design
U N I V E R S I T Y O FMARYLAND
Momentum Transfer
• Momentum perpendicular to wall is reversed at impact
• “Bounce” momentum is transferred to vehicle
• Momentum parallel to wall is unchanged
Vsin(α)
V
F
V
F =dm
dt!V = !V A sin"(2V sin") = 2!V 2A sin2 "
15
Entry AerodynamicsENAE 791 - Launch and Entry Vehicle Design
U N I V E R S I T Y O FMARYLAND
Lift and Drag
F
VD
L
α
cD =D
1
2!V 2A
= 4 sin3 "
cL =L
1
2!V 2A
= 4 sin2 " cos "
D = F sin! = 2"V 2A sin3 !
L = F cos ! = 2"V 2A sin2 ! cos !
L
D=
cos !
sin!= cot !
16
Entry AerodynamicsENAE 791 - Launch and Entry Vehicle Design
U N I V E R S I T Y O FMARYLAND
Flat Plate Newtonian Aerodynamics
0
0.5
1
1.5
2
2.5
3
3.5
4
4.5
0 20 40 60 80 100
Angle of Attack (deg)
Lift coeff. Drag coeff. L/D
17
Entry AerodynamicsENAE 791 - Launch and Entry Vehicle Design
U N I V E R S I T Y O FMARYLAND
Example of Newtonian Flow Calculations
Consider a cylinder of length l, enteringatmosphere transverse to flow
dF
dDdLV
r!dm = !dA cos "V = !V cos "rd"d#
dF = dm!V = 2!V 2cos
2 "rd"d#
dA = rd!dl
dD = dF cos ! = 2"V 2cos
3 !rd!d#
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dL = dF sin ✓ = 2⇢V 2cos
2 ✓ sin ✓rd✓d`
Entry AerodynamicsENAE 791 - Launch and Entry Vehicle Design
U N I V E R S I T Y O FMARYLAND
Integration to Find Drag Coefficient
Integrate from
By definition, and, for a cylinder
D =
! + !
2
!
!
2
! !
0
dD = 2!V 2r
! + !
2
!
!
2
! !
0
cos3 "d"d#
D =1
2!V 2AcD A = 2r!
! = !
"
2"
"
2
19
= 2⇢V 2r`
Z +⇡2
�⇡2
cos
3 ✓d✓ =
8
3
⇢V 2r`
⇢V 2r`cD =8
3⇢V 2r` =) cD =
8
3
Entry AerodynamicsENAE 791 - Launch and Entry Vehicle Design
U N I V E R S I T Y O FMARYLAND
Near Free Molecular Flow Regime• Also known as “slip region”• Gas molecule only attains state of moving boundary
aer several collisions• Molecules near the wall will have a different velocity
from the wall• Temperature will be nearly discontinuous function
of separation from wall•
20
10 Kc 1
3
or 5.4M1 K1 0.175M1
Entry AerodynamicsENAE 791 - Launch and Entry Vehicle Design
U N I V E R S I T Y O FMARYLAND
Transition Region• Very difficult to treat analytically• For engineering purposes, usually treated as
interpolation between slip and viscous flow•
21
0.175M1 K1 1
Entry AerodynamicsENAE 791 - Launch and Entry Vehicle Design
U N I V E R S I T Y O FMARYLAND
Viscous Merged Layer Regime• Viscous effects in forming shock and boundary layer
must be treated in a unified manner– Boundary layer on the wall alters the conditions for the
forming shock wave– Large pressure gradients across the shock wave
significantly alter the boundary layer• Neither shocks nor boundary layers can be treated as
discontinuities•
22
1 K1 0.1
⇢s/⇢1
Entry AerodynamicsENAE 791 - Launch and Entry Vehicle Design
U N I V E R S I T Y O FMARYLAND
Continuous Regime• Classical fluid mechanics of high Reynolds number• Shock waves and boundary layer treated as
discontinuities• • Subdivided based on Mach number
– Incompressible (subsonic)– Transonic– Supersonic– Hypersonic
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(M ⇠ 0.8)
(⇠ 0.8 M ⇠ 1.3)
(⇠ 1.3 M ⇠ 5)
(⇠ 5 M)
K1 >0.1
⇢s/⇢1
Entry AerodynamicsENAE 791 - Launch and Entry Vehicle Design
U N I V E R S I T Y O FMARYLAND
Continuum Newtonian Flow (Hypersonics)
• Air molecules predominately interact with shock waves
• Effect of shock wave passage is to decelerate flow and turn it parallel to vehicle surface
αV
Shock wave
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Entry AerodynamicsENAE 791 - Launch and Entry Vehicle Design
U N I V E R S I T Y O FMARYLAND
Continuum Newtonian Flow (Hypersonics)
• Treat hypersonic aerodynamics in manner similar to previous Newtonian flow analysis
• All momentum perpendicular to wall is absorbed by the wall
αV
25
Entry AerodynamicsENAE 791 - Launch and Entry Vehicle Design
U N I V E R S I T Y O FMARYLAND
Mass Flux (unchanged)
α
AA sin(α)
ρ
Vmass flux = (density)(swept area)(velocity)
dm
dt= (!)(A sin")(V )
26
Entry AerodynamicsENAE 791 - Launch and Entry Vehicle Design
U N I V E R S I T Y O FMARYLAND
Momentum Transfer• Momentum
perpendicular to wall is absorbed at impact and transferred to vehicle
• Momentum parallel to wall is unchanged
Vsin(α)
V
F
Vcos(α)
F =dm
dt!V = !V A sin "(V sin") = !V 2A sin2 "
27
Entry AerodynamicsENAE 791 - Launch and Entry Vehicle Design
U N I V E R S I T Y O FMARYLAND
Lift and Drag
F
VD
L
α
L
D=
cos !
sin!= cot !
L = F cos ! = "V 2A sin2 ! cos !
D = F sin! = "V 2A sin3 !
cL =L
1
2!V 2A
= 2 sin2 " cos "
cD =D
1
2!V 2A
= 2 sin3 "
28
Entry AerodynamicsENAE 791 - Launch and Entry Vehicle Design
U N I V E R S I T Y O FMARYLAND
Modified Newtonian Flow• Coefficient of pressure in “classical” Newtonian flow
• Coefficient of pressure in modified Newtonian flow
• Cp(max) is the pressure coefficient behind a normal shock at flight conditions
29
cp = cpmax
sin2 (↵)
cp = 2 sin2 (↵)
cp
max
=Pshock
� P112⇢1v21
Entry AerodynamicsENAE 791 - Launch and Entry Vehicle Design
U N I V E R S I T Y O FMARYLAND
Maximum Coefficient of Pressure
30
cpmax
=2
�M21
((� + 1)2M2
14�M2
1 � 2(� � 1)
� �
��11� � + 2�M2
1� + 1
�� 1
)
cpmax
�!(� + 1)2
4�
� �
��1
4
� + 1
�
cpmax
�! 1.839 for � = 1.4
cpmax
�! 2 for � = 1
as M �! 1