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• Geology deals with physical, chemical and mineralogical characteristics of rocks.
• Engineering deals with the mechanics of rocks and other earth materials.
• Eg. The response of materials to applied load
ENGINEERING PROPERTIES OF ROCKS
Illustrated By Sabariah 2009
Rocks as Earth Materials
• Solid and aggregates of mineral grain
• Igneous: Interlocking minerals from crystallization of magma
• Metamorphic: Re-crystallization of an existing rock
• The strength depends on the degree of interlocking
• Sedimentary:
~Chemical precipitation (interlocking aggregate of minerals)
~Clastic (particle from pre-existing rocks), cemented
Illustrated By Sabariah 2009
Porosity and Void Ratio
Illustrated By Sabariah 2009
Illustrated By Sabariah 2009
Properties of Porous Rock
for Fluid to Flow
1. Permeability: Indicates degree of
interconnection of voids
2. Intrinsic permeability, k : measured in
darcys or cm2
3. Hydraulic conductivity, K, (m/s) :
K = kρ g
µ
Illustrated By Sabariah 2009
~Handouts~
1. Range of Values of Intrinsic
Permeability and Hydraulic
Conductivity
2. Mechanical Properties of Rock
and Other Materials
Illustrated By Sabariah 2009
• The vertical stress acting on shallow horizontal planes in the earth is the sum of the unit weight of the material times the depth (h) and the atmospheric pressure (Pa)
Illustrated By Sabariah 2009
• Vertical stress beneath a sequence of layers is the sum of the unit weight of each layer times its thickness
• Atmospheric pressure is neglected.
Illustrated By Sabariah 2009
Question
• Calculate the vertical stress at a
depth of 8m at a location where a
5m bed of sandstone with a unit
weight of 25 kN/m3 overlies a
thick shale unit with a unit
weight of 27.5 kN/m3
Illustrated By Sabariah 2009
Solution
Illustrated By Sabariah 2009
Shear Stress
• To calculate shear stress use Oho Mohr (1835-
1918) graphical method.
σ1
σ3σ3
σ1
θ
Principal
Stress
Minimum
Stress
Below ground,
Min σ = Intermediate σ
Illustrated By Sabariah 2009
Mohr’s Circle
Illustrated By Sabariah 2009
To Plot Mohr’s Circle:
1. σ1 and σ3 are plotted on horizontal axis.
These two points represent normal
stress
2. Note: ~the circle of radius is
~shear stress on any plane is
represented by the circle at
angle θ from the principle
plane measured from σ3
σ1 - σ2
2
Illustrated By Sabariah 2009
• General equations for shear and normal
stress derived from Mohr’s circle
Illustrated By Sabariah 2009
Question
• Determine the normal and shear
stresses on a plane incline at 45º
to the principal plane if the
vertical and horizontal principal
stresses are 144 kN/m2 and 36
kN/m2 respectively.
Illustrated By Sabariah 2009
Illustrated By Sabariah 2009
Behavior of Rocks under
Stress
• Rock may deform under stress
• The amount of deformation is called strain
• In strain depends on σ , T
• How much rocks can deform under the loads of applied engineering structures?
Illustrated By Sabariah 2009
Review on Important
Definition
• Rocks my behave
~Brittle or Ductile
Str
ess
Str
ess
Strain Strain
BrittleDuctile
Illustrated By Sabariah 2009
Testing a Rock Sample
• E is called modulus of elasticity
• E is measured by the slope of segment 2
1
2
3
Point of Failure
Slope, E =
Stress σ
Strain ε
Illustrated By Sabariah 2009
Rock Properties
Important properties for
engineering material
1. Density
2. Strength
3. Compressibility
4. Durability
Illustrated By Sabariah 2009
Determination of Specific
Gravity
1. Weigh in air (A) after drying for 24
hours in oven
2. Weigh in air, saturated surface
dried (B)
3. Weigh in water (C)
Illustrated By Sabariah 2009
SG x % Adsorption
SpG = Mass of Rock in air
Mass of Equal Volume
of Water
= Wa
Wa - Wb
% adsorption = B – A X 100
A
Illustrated By Sabariah 2009
Rock Strength
• Rock can be subjected to three type
of stress:
~compressive, shear and tensile
Shear
Stress
Illustrated By Sabariah 2009
Compressive Strength
• The compressive strength is the
compressive stress required to break the
rock specimen
• It ranges 1000 kPa to 280,000 kPa
• The unit is psi or N/m2 ,
1psi=6.895 kN/m2 = 6.895 kPa
• Rock’s strength
σ = ρ/A
ρ=failure load, A=cross-sectional area
Illustrated By Sabariah 2009
Question
• A rock core of limestone is 3 in. in
diameter and 6 in. long. It was loaded
to failure in a confine testing
machine. If the failure load was 62150
lb, what is the unconfined
compression strength σ of the
sample?