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Structural Analysis 6 Engineering Mechanics: Statics in SI Units, 12e 2011/5/17 1

Engineering Mechanics: Statics in SI Units, 12eeportfolio.lib.ksu.edu.tw/user/T/H/T093000099-20110525073914.pdf · Free-Body Diagram • Decide the section of the truss • Determine

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  • Structural Analysis6

    Engineering Mechanics: Statics in SI Units, 12e

    2011/5/17 1

  • Chapter Objectives

    • Determine the forces in the members of a truss using the method of joints and the method of sections

    • Analyze forces acting on the members of frames and machines composed of pin-connected members

    2011/5/17 2

  • Chapter Outline

    • Simple Trusses• The Method of Joints• Zero-Force Members• The Method of Sections• Space Trusses• Frames and Machines

    2011/5/17 3

    WIN64X矩形

  • 6.4 The Method of Sections

    • Consider the truss and section a-a as shown• Member forces are equal and opposite to those acting on the

    other part – Newton’s Law

    2011/5/17 27

  • 6.4 The Method of Sections

    Procedure for AnalysisFree-Body Diagram• Decide the section of the truss • Determine the truss’s external reactions• Use equilibrium equations to solve member forces at the cut

    session• Draw FBD of the sectioned truss which has the least

    number of forces acting on it• Find the sense of an unknown member force

    2011/5/17 28

  • 6.4 The Method of Sections

    Procedure for AnalysisEquations of Equilibrium• Summed moments about a point • Find the 3rd unknown force from moment equation

    2011/5/17 29

  • Example 6.5

    Determine the force in members GE, GC, and BC of the truss. Indicate whether the members are in tension or compression.

    2011/5/17 30

  • Solution

    • Choose section a-a since it cuts through the three members• Draw FBD of the entire truss

    NANNAF

    NDmDmNmNMNAANF

    yyy

    yyA

    xxx

    30009001200 ;0

    9000)12()3(400)8(1200 ;04000400 ;0

    2011/5/17 31

  • Solution

    • Draw FBD for the section portion

    )(500053300 ;0

    )(8000)3()8(300 ;0)(8000)3()3(400)4(300 ;0

    TNFFNF

    CNFmFmNMTNFmFmNmNM

    GCGCy

    GEGEC

    BCBCG

    2011/5/17 32

  • 2011/5/17 33

  • 2011/5/17 34

  • 2011/5/17 35

  • 2011/5/17 36

  • 6.5 Space Trusses

    • Consists of members joined together at their ends to form 3D structure

    • The simplest space truss is a tetrahedron• Additional members would be redundant in supporting

    force P

    2011/5/17 37

  • 6.5 Space Trusses

    Assumptions for Design• Members of a space truss is treated as 2 force members

    provided the external loading is at the joints• When weight of the member is considered, apply it as a

    vertical force, half of its magnitude applied at each end of the member

    Method of Joints• Solve ∑Fx = 0, ∑Fy = 0, ∑Fz = 0 at each joint• Force analysis has at least 1 unknown force and 3 unknown

    forces2011/5/17 38

  • 6.5 Space Trusses

    Method of Sections• When imaginary section is passes through a truss it must

    satisfied∑Fx = 0, ∑Fy = 0, ∑Fz = 0∑Mx = 0, ∑My = 0, ∑Mz = 0

    • By proper selection, the unknown forces can be determined using a single equilibrium equation

    2011/5/17 39

  • Example 6.8

    Determine the forces acting in the members of the space truss. Indicate whether the members are in tension or compression.

    2011/5/17 40

  • Solution

    For Joint A,

    0577.0577.0577.04

    0;0

    )577.0577.0577.0(

    ,,}4{

    kFjFiFkFjFj

    FFFPF

    kjiF

    rrFF

    kFFjFFkNjP

    AEAEAEACAB

    AEACAB

    AE

    AE

    AEAEAE

    ACACABAB

    2011/5/17 41

  • Solution

    For Joint B,

    To show,0

    )(2)(66.5

    0707.02;0

    045sin4;0

    0707.045cos;0

    CEDCDE

    BD

    BEB

    BEBDz

    By

    BEBx

    FFF

    CkNFTkNFR

    FFF

    RF

    FRF

    2011/5/17 42