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7/27/2019 Energyband and Effective Mass
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CHAPTER 2ENERGY BANDS AND EFFECTIVE
MASS
Semiconductors, insulators and metals
Semiconductors
Insulators
Metals The concept of effective mass
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The electrical properties of metals andinsulators are well known to all of us.
Everyday experience has alreadytaught us a lot about the electricalproperties of metals and insulators.
But the same cannot be said aboutsemiconductors.
What happens when we connect abattery to a piece of a silicon;
would it conduct well ? or
would it act like an insulator ?
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Conductivity :
metals ~1010/-cm
insulators ~ 10-22 /-cm
The conductivity () of a
semiconductor (S/C) lies
between these two
extreme cases.
S/C
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The electronssurrounding a nucleushave certain well-definedenergy-levels.
Electrons dont like to
have the same energy inthe same potentialsystem.
The most we could gettogether in the sameenergy-level was two,provided thet they hadopposite spins. This iscalled Pauli ExclusionPrinciple.
1 2 4N
Number of atoms
Allowedband
Forbiddenband
Forbiddenband
Allowedband
Allowedband
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The difference in energy between each of these smallerlevels is so tiny that it is more reasonable to considereach of these sets of smaller energy-levels as beingcontinuous bands of energy, rather than considering theenormous number of discrete individual levels.
Each allowed band is seperated from another one by aforbidden band.
Electrons can be found in allowed bands but they can not
be found inforbidden bands.
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Consider 1 cm3 of Silicon. How many atoms does this contain ?
Solution:
The atomic mass of silicon is 28.1 g which contains Avagadros number of atoms.
Avagadros number N is 6.02 x 1023 atoms/mol .
The density of silicon: 2.3 x 103 kg/m3
so 1 cm3 of silicon weighs 2.3 gram and so contains
This means that in a piece of silicon just one cubic centimeter involume , each electron energy-level has split up into 4.93 x 1022
smaller levels !
23226.02 10 2.3 4.93 10
28.1atoms
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Both ful l and empty bands do not partake in electr ical conduction.
Fullband
All energy levels are
occupied by electrons
Empty band
All energy levels are empty
( no electrons)
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At low temperatures the valanceband is full, and the conductionband is empty.
Recall that a full band can notconduct, and neither can anempty band.
At low temperatures, s/cs do notconduct, they behave likeinsulators.
The thermal energy of the electronssitting at the top of the full bandis much lower than that of the Egat low temperatures.
Forbiddenenergy gap [Eg]
Emptyconductionband
Fullvalanceband
Electron
ener
gy
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Assume some kind of energy isprovided to the electron (valenceelectron) sitting at the top of thevalance band.
This electron gains energy from theapplied field and it would like to
move into higher energy states.
This electron contributes to theconductivity and this electron iscalled as a conduction electron.
At 00K, electron sits at the lowest
energy levels. The valance band isthe highest filled band at zerokelvin.
Forbiddenenergy gap [Eg]
Emptyconductionband
Fullvalanceband
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When enough energy is suppliedto the e- sitting at the top of thevalance band, e- can make atransition to the bottom of theconduction band.
When electron makes such atransition it leaves behind amissing electron state.
This missing electron state iscalled as a hole.
Hole behaves as a positive chargecarrier.
Magnitude of its charge is thesame with that of the electron butwith an opposite sign.
Forbiddenenergy gap [Eg]
Fullvalanceband
Emptyconductionband
+e- +e- +e- +e-energy
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Holes contribute to current in valance band (VB) as e-sare able to create current in conduction band (CB).
Hole is not a free particle. It can only exist within the
crystal. A hole is simply a vacant electron state.
A transition results an equal number of e- in CB andholes in VB. This is an important property of intrinsic,
or undoped s/cs. For extrinsic, or doped, semiconductorsthis is no longer true.
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After transition, thevalance band is now nolonger full, it is partly
filled and may conductelectric current.
The conductivity is due to
both electrons and holes,and this device is calleda bipolar conductor orbipolar device.
occupied
Valance Band(partly filledband)
Electron
energy
empty
After transition
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Thermal energy ? Electrical field ?
Electromagnetic radiation ?
Answer:
To have a partly field band configuration in a s/c ,
one must use one of these excitation mechanisms.
Eg
Partly filled
CB
Partly filled
VB
Energy band diagram of a
s/c at a finite temperature.
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Thermal energy= k x T= 1.38 x 10-23J/K x 300 K =25 meV
Excitation rate= constant x exp(-Eg / kT)
Although the thermal energy at room temperature, RT,is very small,i.e.25 meV, a few electrons can be promoted to the CB.
Electrons can be promoted to the CB by means of thermal energy.
This is due to the exponential increase of excitation rate with increasingtemperature.
Excitat ion rate is a strong func t ion o f temperature.
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For low fields, this mechanism doesnt promote electrons tothe CB in common s/cs such as Si and GaAs.
An electric field of 1018 V/m can provide an energy of the
order of 1 eV. This field is enormous.
So , the use of the electric field as an excitationmechanism is not useful way to promote electrons in
s/cs.
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1.24Silicon 1.1 ( ) 1.1
1.1gfor E eV m m
34 8 1.24(6.62 10 ) (3 10 / ) / ( ) ( )(in )
cE h h x J s x x m s m E eV
m
h = 6.62 x 10-34 J-s
c = 3 x 108 m/s1 eV=1.6x10-19 J
To promote electrons from VB to CB Silicon , the wavelength
of the photons must 1.1 m or less
Near
infrared
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+
The converse transition can alsohappen.
An electron in CB recombineswith a hole in VB and generate a
photon. The energy of the photon will be
in the order of Eg.
If this happens in a direct band-
gap s/c, it forms the basis ofLEDs and LASERS.
e-
photon
Valance Band
Conduction Band
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The magnitude of the band gapdetermines the differences betweeninsulators, s/cs and metals.
The excitation mechanism ofthermal is not a useful way topromote an electron to CB even themelting temperature is reached inan insulator.
Even very high electric fields is alsounable to promote electrons acrossthe band gap in an insulator.
Insulators :
CB (completely empty)
VB (completely full)
Eg~several electron volts
Wide band gaps between VB and CB
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Metals :
CB
VB
CB
VB
No gap between valance band and conduction band
Touching VB and CB Overlapping VB and CB
These two bands
looks like as if partly
filled bands and it is
known that partly
filled bands conducts
well.
This is the reason
why metals have high
conductivity.
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If the same magnitude of electric field isapplied to both electrons in vacuum and insidethe crystal, the electrons will accelerate at adifferent rate from each other due to theexistence of different potentials inside the
crystal.
The electron inside the crystal has to try tomake its own way.
So the electrons inside the crystal will have a
different mass than that of the electron invacuum.
This altered mass is called as an effective-mass.
ComparingFree e- in vacuum
An e- in a crystal
In an electric field
mo =9.1 x 10-31
Free electron mass
In an electric field
In a crystal
m = ?
m* effective mass
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Particles of electrons and holes behave as a wave under certain
conditions. So one has to consider the de Broglie wavelength tolink partical behaviour with wave behaviour.
Partical such as electrons and waves can be diffracted from thecrystal just as X-rays .
Certain electron momentum is not allowed by the crystal lattice.This is the origin of the energy band gaps.
sin2dn
n = the order of the diffraction
= the wavelength of the X-ray
d = the distance between planes = the incident angle of the X-ray beam
dn 2= (1)
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The energy of the free e-
is related to the k
free e- mass , m0
is the propogation constant
dn 2=
k
2=
The waves are standing waves
The momentum is
kP =
(1)
(2)
By means of equations (1) and (2)certain e- momenta are not allowedby the crystal. The velocity of theelectron at these momentum values
is zero.
The energy of the free electron
can be related to its momentum
mE
P
2
2
=
hP=
2
12 2 (2 )
22 2
2 2
2 2E
m
kh hEm m
k
2
h=
momentum
k
Energy
E versus k diagram is a parabola.
Energy is continuous with k, i,e, all
energy (momentum) values are allowed.
E versus k diagram
or
Energy versus momentum diagrams
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2
2 2
2
2 2
2*
dE k
dk m
d E
mdk
m
d E d k
We will take the derivative ofenergywith respect to k ;
Change m* instead of m
This formula is the effective mass of
an electron inside the crystal.
- m* is determined by the curvature of the E-k curve
- m* is inversely proportional to the curvature
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For a direct-band gap material, theminimum of the conduction band andmaximum of the valance band lies atthe same momentum, k, values.
When an electron sitting at the bottomof the CB recombines with a hole sittingat the top of the VB, there will be nochange in momentum values.
Energy is conserved by means ofemitting a photon, such transitions arecalled as radiative transitions.
Direct-band gaps/cs (e.g. GaAs, InP, AlGaAs)
+
e-
VB
CBE
k
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For an indirect-band gap material;the minimum of the CB andmaximum of the VB lie at differentk-values.
When an e- and hole recombine inan indirect-band gap s/c, phononsmust be involved to conservemomentum.
Indirect-band gaps/cs (e.g. Si and Ge)
+
VB
CB
E
k
e-
Phonon
Atoms vibrate about their meanposition at a finite temperature.These
vibrations produce vibrational waves
inside the crystal.
Phonons are the quanta of these
vibrational waves. Phonons travel with
a velocity of sound .
Their wavelength is determined by the
crystal lattice constant. Phonons can
only exist inside the crystal.
Eg
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The transition that involves phonons without producing photonsare called nonradiative (radiationless) transitions.
These transitions are observed in an indirect band gap s/c and
result in inefficient photon producing.
So in order to have efficient LEDs and LASERs, one shouldchoose materials having direct band gaps such as compound s/csof GaAs, AlGaAs, etc
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For GaAs, calculate a typical (band gap) photon energy and momentum , and compare
this with a typical phonon energy and momentum that might be expected with thismaterial.
.:: CALCULATION
photon phonon
E(photon) = Eg(GaAs) = 1.43 ev
E(photon) = h = hc /
c= 3x108 m/sec
P = h / h=6.63x10-34
J-sec
(photon)= 1.24/ 1.43 = 0.88 m
P(photon) = h / = 7.53 x 10-28 kg-m/sec
E(phonon) = h = hvs /
= hvs / a0
(phonon) ~a0 = lattice constant =5.65x10-10 m
Vs= 5x103
m/sec ( velocity of sound)
E(phonon) = hvs/ a0 =0.037 eV
P(phonon)= h / = h / a0 = 1.17x10-24 kg-m/sec
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Photon energy = 1.43 eV
Phonon energy = 37 meV
Photon momentum = 7.53 x 10-28 kg-m/sec
Phonon momentum = 1.17 x 10-24 kg-m/sec
Photons carry large energies but negligible amount of momentum.
On the other hand, phonons carry very little energy but significant
amount of momentum.
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The sign of the effective mass is determineddirectly from the sign of the curvature of the E-k curve.
The curvature of a graph at a minimum point isa positive quantity and the curvature of a graphat a maximum point is a negative quantity.
Particles(electrons) sitting near the minimum
have a positive effective mass.
Particles(holes) sitting near the valence bandmaximum have a negative effective mass.
A negative effective mass implies that a particle
will go the wrong way when an extrernalforce is applied.
2 2
2*md E d k
Direct-band gaps/cs (e.g. GaAs, InP, AlGaAs)
+
e-
VB
CBE
k
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-1
-2
0
2
3
1
4GaAs
Conduction
band
Valanceband
0
E=0.31
Eg
[111] [100] k
Ener
gy(eV)
-1
-2
0
2
3
1
4Si
Conduction
band
Valance
band
0
Eg
[111] [100] k
Ener
gy(eV)
Energy band structures of GaAs and Si
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-1
-2
0
2
3
1
4GaAs
Conduction
band
Valanceband
0
E=0.31
Eg
[111] [100] k
Ener
gy(eV)
Energy band structure of GaAs
Band gap is the smallest energy
separation between the valence
and conduction band edges.
The smallest energy difference
occurs at the same momentum
value
Direct band gap semiconductor
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-1
-2
0
2
3
1
4Si
Conduction
band
Valanceband
0
Eg
[111] [100] k
Ener
gy(eV)
Energy band structure ofSi
The smallest energy gap is
between the top of the VB at k=0
and one of the CB minima awayfrom k=0
Indirect band gap semiconductor
Band structure of AlGaAs?
Effective masses of CB satellites?
Heavy- and light-hole masses in
VB?
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Eg k
EEE
direct
transition
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Egk
EE
direct
transition
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Egk
E
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Egindirect
transitionk
E
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Egindirect
transitionk
E