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End Show © Copyright Pearson Prentice Hall Slide 1 of 40 Empirical Formulas formaldehyde CH 2 O (toxic preservative) acetic acid C 2 H 4 O 2 (vinegar) glucose C 6 H 12 O 6 (simple sugar) all have the same basic or “empirical ” formula

End Show © Copyright Pearson Prentice Hall Slide 1 of 40 Empirical Formulas formaldehyde CH 2 O (toxic preservative) acetic acid C 2 H 4 O 2 (vinegar)

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Page 1: End Show © Copyright Pearson Prentice Hall Slide 1 of 40 Empirical Formulas formaldehyde CH 2 O (toxic preservative) acetic acid C 2 H 4 O 2 (vinegar)

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Empirical Formulas

formaldehyde CH2O(toxic preservative)

acetic acid C2H4O2

(vinegar)

glucose C6H12O6

(simple sugar)

all have the same basic or “empirical” formula

CH2O

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Percent Composition and Chemical Formulas

>empirical formula:

the smallest whole-number ratio of the atoms in a compound.

Examples:

CH3 HO PbO2 C2H6N

Non-Examples:

C2H6 H2O2 Pb2O4 C6H18N3

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Percent Composition and Chemical Formulas

>

Acetylene (C2H2) is a gas used in welder’s torches.

These two compounds of carbon both have the same empirical formula (CH) but different molecular formulas.

Styrene (C8H8) is used in making polystyrene.

Page 4: End Show © Copyright Pearson Prentice Hall Slide 1 of 40 Empirical Formulas formaldehyde CH 2 O (toxic preservative) acetic acid C 2 H 4 O 2 (vinegar)

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SAMPLE PROBLEM

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Percent to Mass

Mass to Mole

Divide by Small

Times ‘till Whole

What is the empirical formula of a compound that is analyzed and found to contain 25.9% N and 74.1% O?

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SAMPLE PROBLEM

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What is the empirical formula of a compound that is analyzed and found to contain 25.9% N and 74.1% O?

Percent to Mass

Mass to Mole

Divide by Small

Times ‘till Whole

25.9 g N

74.1 g O

x 1 mol N 14.01 g N

x 1 mol O 16.00 g O

= 1.85 mol N

= 4.63 mol O

________ 1.85

________ 1.85

= 1 N

= 2.5 O

x 2 = 2 N

x 2 = 5 O

N2O5

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Practice Problems

62.1 g C

13.8 g H

24.1 g N

x 1 mol C 12.01 g C

x 1 mol H 1.01 g H

x 1 mol N 14.01 g N

= 5.17 mol C

= 13.66 mol H

= 1.72 mol N

________ 1.72

_________ 1.72

________ 1.72

= 3 C

= 8 H

= 1 N

C3H8N

1,6-diaminohexane is used to make nylon. What is the empirical formula if it is 62.1% C, 13.8% H, and 24.1% N?

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Slide 7 of 40

Percent Composition and Chemical Formulas

>molecular formula:

a whole-number multiple of the empirical formula of a compound

formaldehyde CH2O

acetic acid C2H4O2

glucose C6H12O6

all have the same empirical formula

CH2O

Page 8: End Show © Copyright Pearson Prentice Hall Slide 1 of 40 Empirical Formulas formaldehyde CH 2 O (toxic preservative) acetic acid C 2 H 4 O 2 (vinegar)

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SAMPLE PROBLEM

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Calculate the molecular formula of a compound with the empirical formula CH4N and a molar mass of 60.0 g/mol.

molecular mass = multiple of emp. form.empirical mass

empirical mass1(C) + 4(H) + 1(N) =

12.01 + 4(1.01) + 14.01 = 30.06 g/mol

60.0 =30.06

1.996 ≈ 2 2 (CH4N) =

C2H8N2

Page 9: End Show © Copyright Pearson Prentice Hall Slide 1 of 40 Empirical Formulas formaldehyde CH 2 O (toxic preservative) acetic acid C 2 H 4 O 2 (vinegar)

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SAMPLE PROBLEM

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Calculate the molecular formula of benzene with the empirical formula CH and a molar mass of 78 g/mol.

molecular mass = multiple of emp. form.empirical mass

empirical mass1(C) + 1(H) =

12.01 + 1.01 = 13.02 g/mol

78 =13.02

5.991 ≈ 6 6 (CH) = C6H6

Page 10: End Show © Copyright Pearson Prentice Hall Slide 1 of 40 Empirical Formulas formaldehyde CH 2 O (toxic preservative) acetic acid C 2 H 4 O 2 (vinegar)

1. An empirical formula shows the __________ of atoms in a compound.

A. lowest common number

B. highest whole ratio

C. lowest whole number ratio

D. average ratio

Quick Quiz!

Page 11: End Show © Copyright Pearson Prentice Hall Slide 1 of 40 Empirical Formulas formaldehyde CH 2 O (toxic preservative) acetic acid C 2 H 4 O 2 (vinegar)

2. Which of the following is NOT an empirical formula?

A. CH3

B. H2N

C. CH

D. C3H6

Quick Quiz.

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3. True or False:

A molecular formula can be the same as an empirical formula.

True False

Example:

Formaldehyde has theempirical formula CH2O,which is its molecular formula as well.

Quick Quiz.

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Quick Quiz.

4. Determine the molecular formula of a compound that contains 40.0 % C, 6.71 % H, and 53.29 % O by mass and has a molar mass of 60.05 g/mol.

A. C2H4O2

B. CH2O

C. C2H3O

D. C2H4O