Electrostatic Formula

Electric Force

F = 1 q1q2 = k q1q2

4 eo r2 r2

k = 9.0x10 9 N m2 = 1 = -------1------------

C2 4 eo 4 8.85x10-12 C2

N m2

Electric Force

F = 1 q1q2 = k q1q2

4 eo r2 r2

k = 9.0x10 9 N m2 = 1 = -------1------------

C2 4 eo 4 8.85x10-12 C2

N m2

Electric Force

F = 1 q1q2 = k q1q2

4 eo r2 r2

k = 9.0x10 9 N m2 = 1 = -------1------------

C2 4 eo 4 8.85x10-12 C2

N m2

Electric Force

F = 1 q1q2 = k q1q2

4 eo r2 r2

k = 9.0x10 9 N m2 = 1 = -------1------------

C2 4 eo 4 8.85x10-12 C2

N m2

Electric Force

F = 1 q1q2 = k q1q2

4 eo r2 r2

k = 9.0x10 9 N m2 = 1 = -------1------------

C2 4 eo 4 8.85x10-12 C2

N m2Vector sum – x components, y components, sum of x components, sum of y components, pythagorean theorem, and inv tan of (sum of y )/(sum of x )

Electric Force

F = 1 q1q2 = k q1q2

4 eo r2 r2

k = 9.0x10 9 N m2 = 1 = -------1------------

C2 4 eo 4 8.85x10-12 C2

N m2Vector sum – x components, y components, sum of x components, sum of y components, pythagorean theorem, and inv tan of (sum of y )/(sum of x )

Electric Field associated with point charges

E = F q

F = kqq therefore E = Kqq therefore E =kq r2 r2q r2

Vector sum – x components, y components, sum of x components, sum of y components, pythagorean theorem, and inv tan of (sum of y )/(sum of x )

Electric Field associated with point charges

E = F q

F = kqq therefore E = Kqq therefore E =kq r2 r2q r2

Vector sum – x components, y components, sum of x components, sum of y components, pythagorean theorem, and inv tan of (sum of y )/(sum of x )

Electric Field associated with point charges

E = F q

F = kqq therefore E = Kqq therefore E =kq r2 r2q r2

Vector sum – x components, y components, sum of x components, sum of y components, pythagorean theorem, and inv tan of (sum of y )/(sum of x )

Electric Field associated with point charges

E = F q

F = kqq therefore E = Kqq therefore E =kq r2 r2q r2

Vector sum – x components, y components, sum of x components, sum of y components, pythagorean theorem, and inv tan of (sum of y )/(sum of x )

Electric Field associated with point charges

E = F q

F = kqq therefore E = Kqq therefore E =kq r2 r2q r2

Vector sum – x components, y components, sum of x components, sum of y components, pythagorean theorem, and inv tan of (sum of y )/(sum of x )

Electric Field associated with point charges

E = F q

F = kqq therefore E = Kqq therefore E =kq r2 r2q r2

Vector sum – x components, y components, sum of x components, sum of y components, pythagorean theorem, and inv tan of (sum of y )/(sum of x )

Electric Field Associated with Parallel Plates

The electric field is uniform between plates

Work is required to move +q from the – to +W=Fd W=qEd W=qKqd W=Kqq W = Kq W =V=Joules= Electric Potential d2 d q d q Coulomb W=qEd W = Ed V = Ed V = E q d

Electric Field Associated with Parallel Plates

The electric field is uniform between plates

Work is required to move +q from the – to +W=Fd W=qEd W=qKqd W=Kqq W = Kq W =V=Joules= Electric Potential d2 d q d q Coulomb W=qEd W = Ed V = Ed V = E q d

Electric Field Associated with Parallel Plates

The electric field is uniform between plates

Work is required to move +q from the – to +W=Fd W=qEd W=qKqd W=Kqq W = Kq W =V=Joules= Electric Potential d2 d q d q Coulomb W=qEd W = Ed V = Ed V = E q d

Electric Field Associated with Parallel Plates

The electric field is uniform between plates

Work is required to move +q from the – to +W=Fd W=qEd W=qKqd W=Kqq W = Kq W =V=Joules= Electric Potential d2 d q d q Coulomb W=qEd W = Ed V = Ed V = E q d

Electric Field Associated with Parallel Plates

The electric field is uniform between plates

Work is required to move +q from the – to +W=Fd W=qEd W=qKqd W=Kqq W = Kq W =V=Joules= Electric Potential d2 d q d q Coulomb W=qEd W = Ed V = Ed V = E q d

Electric Field Associated with Parallel Plates

The electric field is uniform between plates

Work is required to move +q from the – to +W=Fd W=qEd W=qKqd W=Kqq W = Kq W =V=Joules= Electric Potential d2 d q d q Coulomb W=qEd W = Ed V = Ed V = E q d

Electric Field Associated with Parallel Plates

The electric field is uniform between plates

Work is required to move +q from the – to +W=Fd W=qEd W=qKqd W=Kqq W = Kq W =V=Joules= Electric Potential d2 d q d q Coulomb W=qEd W = Ed V = Ed V = E q d

Electric Field Associated with Parallel Plates

The electric field is uniform between plates

Work is required to move +q from the – to +W=Fd W=qEd W=qKqd W=Kqq W = Kq W =V=Joules= Electric Potential d2 d q d q Coulomb W=qEd W = Ed V = Ed V = E q d

Electric Field Associated with Parallel Plates

The electric field is uniform between plates

Work is required to move +q from the – to +W=Fd W=qEd W=qKqd W=Kqq W = Kq W =V=Joules= Electric Potential d2 d q d q Coulomb W=qEd W = Ed V = Ed V = E q d

Electric Field Associated with Parallel Plates

The electric field is uniform between plates

Work is required to move +q from the – to +W=Fd W=qEd W=qKqd W=Kqq W = Kq W =V=Joules= Electric Potential d2 d q d q Coulomb W=qEd W = Ed V = Ed V = E q d

Electric Field Associated with Parallel Plates

The electric field is uniform between plates

Work is required to move +q from the – to +W=Fd W=qEd W=qKqd W=Kqq W = Kq W =V=Joules= Electric Potential d2 d q d q Coulomb W=qEd W = Ed V = Ed V = E q d

Electric Field Associated with Parallel Plates

The electric field is uniform between plates

Work is required to move +q from the – to +W=Fd W=qEd W=qKqd W=Kqq W = Kq W =V=Joules= Electric Potential d2 d q d q Coulomb W=qEd W = Ed V = Ed V = E q d

Electric Field Associated with Parallel Plates

The electric field is uniform between plates

Work is required to move +q from the – to +W=Fd W=qEd W=qKqd W=Kqq W = Kq W =V=Joules= Electric Potential d2 d q d q Coulomb W=qEd W = Ed V = Ed V = E q d

Electric Field Associated with Parallel Plates

The electric field is uniform between plates

Work is required to move +q from the – to +W=Fd W=qEd W=qKqd W=Kqq W = Kq W =V=Joules= Electric Potential d2 d q d q Coulomb W=qEd W = Ed V = Ed V = E q d

Electric Field Associated with Parallel Plates

The electric field is uniform between plates

Work is required to move +q from the – to +W=Fd W=qEd W=qKqd W=Kqq W = Kq W =V=Joules= Electric Potential d2 d q d q Coulomb W=qEd W = Ed V = Ed V = E q d

Electric Field Associated with Parallel Plates

The electric field is uniform between plates

Work is required to move +q from the – to +W=Fd W=qEd W=qKqd W=Kqq W = Kq W =V=Joules= Electric Potential d2 d q d q Coulomb W=qEd W = Ed V = Ed V = E q d

Electric Field Associated with Parallel Plates

The electric field is uniform between plates

Work is required to move +q from the – to +W=Fd W=qEd W=qKqd W=Kqq W = Kq W =V=Joules= Electric Potential d2 d q d q Coulomb W=qEd W = Ed V = Ed V = E q d

Electric Field Associated with Parallel Plates

The electric field is uniform between plates

Work is required to move +q from the – to +W=Fd W=qEd W=qKqd W=Kqq W = Kq W =V=Joules= Electric Potential d2 d q d q Coulomb W=qEd W = Ed V = Ed V = E q d

Electric Field Associated with Parallel Plates

The electric field is uniform between plates

Work is required to move +q from the – to +W=Fd W=qEd W=qKqd W=Kqq W = Kq W =V=Joules= Electric Potential d2 d q d q Coulomb W=qEd W = Ed V = Ed V = E q d

Electric Field Associated with Parallel Plates

The electric field is uniform between plates

Work is required to move +q from the – to +W=Fd W=qEd W=qKqd W=Kqq W = Kq W =V=Joules= Electric Potential d2 d q d q Coulomb W=qEd W = Ed V = Ed V = E = Volts q d meter

Capacitance

C = Q V

C = KAo

d K= dielectric constant A = area in m2

x10-12 C2

N m2

d = distance between plates in m

Capacitance

C = Q V

C = KAo

d K= dielectric constant A = area in m2

x10-12 C2

N m2

d = distance between plates in m

Capacitance

C = Q V

C = KAo

d K= dielectric constant A = area in m2

x10-12 C2

N m2

d = distance between plates in m

Capacitance

C = Q V

C = KAo

d K= dielectric constant A = area in m2

x10-12 C2

N m2

d = distance between plates in m

Capacitance

C = Q V

C = KAo

d K= dielectric constant A = area in m2

x10-12 C2

N m2

d = distance between plates in m

Capacitance

C = Q V

C = KAo

d K= dielectric constant A = area in m2

x10-12 C2

N m2

d = distance between plates in m

Capacitance

C = Q V

C = KAo

d K= dielectric constant A = area in m2

x10-12 C2

N m2

d = distance between plates in m

Capacitance

W = QV = U ( Potential energy stored ) For a capacitor U = ½ QV since it is easier to add charge at first and

progressively gets more difficult C = Q CV = Q therefore U =1/2 QV= ½ CV2

V C = Q V = Q therefore U = ½ QV = ½ Q2

V C C

Capacitance

W = QV = U ( Potential energy stored ) For a capacitor U = ½ QV since it is easier to add charge at first and

progressively gets more difficult C = Q CV = Q therefore U =1/2 QV= ½ CV2

V C = Q V = Q therefore U = ½ QV = ½ Q2

V C C

Capacitance

W = QV = U ( Potential energy stored ) For a capacitor U = ½ QV since it is easier to add charge at first and

progressively gets more difficult C = Q CV = Q therefore U =1/2 QV= ½ CV2

V C = Q V = Q therefore U = ½ QV = ½ Q2

V C C

Capacitance

W = QV = U ( Potential energy stored ) For a capacitor U = ½ QV since it is easier to add charge at first and

progressively gets more difficult C = Q CV = Q therefore U =1/2 QV= ½ CV2

V C = Q V = Q therefore U = ½ QV = ½ Q2

V C C

Capacitance

W = QV = U ( Potential energy stored ) For a capacitor U = ½ QV since it is easier to add charge at first and

progressively gets more difficult C = Q CV = Q therefore U =1/2 QV= ½ CV2

V C = Q V = Q therefore U = ½ QV = ½ Q2

V C C

Capacitance

W = QV = U ( Potential energy stored ) For a capacitor U = ½ QV since it is easier to add charge at first and

progressively gets more difficult C = Q CV = Q therefore U =1/2 QV= ½ CV2

V C = Q V = Q therefore U = ½ QV = ½ Q2

V C C

Capacitance

W = QV = U ( Potential energy stored ) For a capacitor U = ½ QV since it is easier to add charge at first and

progressively gets more difficult C = Q CV = Q therefore U =1/2 QV= ½ CV2

V C = Q V = Q therefore U = ½ QV = ½ Q2

V C C

Capacitance

W = QV = U ( Potential energy stored ) For a capacitor U = ½ QV since it is easier to add charge at first and

progressively gets more difficult C = Q CV = Q therefore U =1/2 QV= ½ CV2

V C = Q V = Q therefore U = ½ QV = ½ Q2

V C C

Capacitance

W = QV = U ( Potential energy stored ) For a capacitor U = ½ QV since it is easier to add charge at first and

progressively gets more difficult C = Q CV = Q therefore U =1/2 QV= ½ CV2

V C = Q V = Q therefore U = ½ QV = ½ Q2

V C C

Capacitance

W = QV = U ( Potential energy stored ) For a capacitor U = ½ QV since it is easier to add charge at first and

progressively gets more difficult C = Q CV = Q therefore U =1/2 QV= ½ CV2

V C = Q V = Q therefore U = ½ QV = ½ Q2

V C C

Capacitance

W = QV = U ( Potential energy stored ) For a capacitor U = ½ QV since it is easier to add charge at first and

progressively gets more difficult C = Q CV = Q therefore U =1/2 QV= ½ CV2

V C = Q V = Q therefore U = ½ QV = ½ Q2

V C C

Capacitance

W = QV = U ( Potential energy stored ) For a capacitor U = ½ QV since it is easier to add charge at first and

progressively gets more difficult C = Q CV = Q therefore U =1/2 QV= ½ CV2

V C = Q V = Q therefore U = ½ QV = ½ Q2

V C C

Capacitance

Cparallel = C1+C2+C3

2F

4F

6F

12F

3 V

What is the total charge stored in the system? C = Q VCV = Q = 12x10-6F (3V) = 36x10-6C or 3.6x10-5Q

What is the energy stored in the system?U=1/2 QV U = ½ CV2 U= ½ 12x10-6F(3V)2 =U=1.08x10-4 J

What is the charged stored on each of the capacitors?CV=Q= 2x10-6F (3V) = 6x10-6C

CV=Q= 4x10-6F (3V) = 12x10-6C or 1.2x10-5Q

CV=Q= 2x10-6F (3V) = 18x10-6C or 1.8x10-5Q

Capacitance

Cparallel = C1+C2+C3

2F

4F

6F

12F

3 V

What is the total charge stored in the system? C = Q VCV = Q = 12x10-6F (3V) = 36x10-6C or 3.6x10-5Q

What is the energy stored in the system?U=1/2 QV U = ½ CV2 U= ½ 12x10-6F(3V)2 =U=1.08x10-4 J

What is the charged stored on each of the capacitors?CV=Q= 2x10-6F (3V) = 6x10-6C

CV=Q= 4x10-6F (3V) = 12x10-6C or 1.2x10-5Q

CV=Q= 2x10-6F (3V) = 18x10-6C or 1.8x10-5Q

Capacitance

Cparallel = C1+C2+C3

2F

4F

6F

12F

3 V

What is the total charge stored in the system? C = Q VCV = Q = 12x10-6F (3V) = 36x10-6C or 3.6x10-5Q

What is the energy stored in the system?U=1/2 QV U = ½ CV2 U= ½ 12x10-6F(3V)2 =U=1.08x10-4 J

What is the charged stored on each of the capacitors?CV=Q= 2x10-6F (3V) = 6x10-6C

CV=Q= 4x10-6F (3V) = 12x10-6C or 1.2x10-5Q

CV=Q= 2x10-6F (3V) = 18x10-6C or 1.8x10-5Q

Capacitance

Cparallel = C1+C2+C3

2F

4F

6F

12F

3 V

What is the total charge stored in the system? C = Q VCV = Q = 12x10-6F (3V) = 36x10-6C or 3.6x10-5Q

What is the energy stored in the system?U=1/2 QV U = ½ CV2 U= ½ 12x10-6F(3V)2 =U=1.08x10-4 J

What is the charged stored on each of the capacitors?CV=Q= 2x10-6F (3V) = 6x10-6C

CV=Q= 4x10-6F (3V) = 12x10-6C or 1.2x10-5Q

CV=Q= 2x10-6F (3V) = 18x10-6C or 1.8x10-5Q

Capacitance

Cparallel = C1+C2+C3

2F

4F

6F

12F

3 V

What is the total charge stored in the system? C = Q VCV = Q = 12x10-6F (3V) = 36x10-6C or 3.6x10-5Q

What is the energy stored in the system?U=1/2 QV U = ½ CV2 U= ½ 12x10-6F(3V)2 =U=1.08x10-4 J

What is the charged stored on each of the capacitors?CV=Q= 2x10-6F (3V) = 6x10-6C

CV=Q= 4x10-6F (3V) = 12x10-6C or 1.2x10-5Q

CV=Q= 2x10-6F (3V) = 18x10-6C or 1.8x10-5Q

Capacitance

Cparallel = C1+C2+C3

2F

4F

6F

12F

3 V

What is the total charge stored in the system? C = Q VCV = Q = 12x10-6F (3V) = 36x10-6C or 3.6x10-5Q

What is the energy stored in the system?U=1/2 QV U = ½ CV2 U= ½ 12x10-6F(3V)2 =U=1.08x10-4 J

What is the charged stored on each of the capacitors?CV=Q= 2x10-6F (3V) = 6x10-6C

CV=Q= 4x10-6F (3V) = 12x10-6C or 1.2x10-5Q

CV=Q= 2x10-6F (3V) = 18x10-6C or 1.8x10-5Q

Capacitance

Cparallel = C1+C2+C3

2F

4F

6F

12F

3 V

What is the total charge stored in the system? C = Q VCV = Q = 12x10-6F (3V) = 36x10-6C or 3.6x10-5Q

What is the energy stored in the system?U=1/2 QV U = ½ CV2 U= ½ 12x10-6F(3V)2 =U=1.08x10-4 J

What is the charged stored on each of the capacitors?CV=Q= 2x10-6F (3V) = 6x10-6C

CV=Q= 4x10-6F (3V) = 12x10-6C or 1.2x10-5Q

CV=Q= 2x10-6F (3V) = 18x10-6C or 1.8x10-5Q

Capacitance

Cparallel = C1+C2+C3

2F

4F

6F

12F

3 V

What is the total charge stored in the system? C = Q VCV = Q = 12x10-6F (3V) = 36x10-6C or 3.6x10-5Q

What is the energy stored in the system?U=1/2 QV U = ½ CV2 U= ½ 12x10-6F(3V)2 =U=1.08x10-4 J

What is the charged stored on each of the capacitors?CV=Q= 2x10-6F (3V) = 6x10-6C

CV=Q= 4x10-6F (3V) = 12x10-6C or 1.2x10-5Q

CV=Q= 2x10-6F (3V) = 18x10-6C or 1.8x10-5Q

Capacitance

Cparallel = C1+C2+C3

2F

4F

6F

12F

3 V

What is the total charge stored in the system? C = Q VCV = Q = 12x10-6F (3V) = 36x10-6C or 3.6x10-5Q

What is the energy stored in the system?U=1/2 QV U = ½ CV2 U= ½ 12x10-6F(3V)2 =U=1.08x10-4 J

What is the charged stored on each of the capacitors?CV=Q= 2x10-6F (3V) = 6x10-6C

CV=Q= 4x10-6F (3V) = 12x10-6C or 1.2x10-5Q

CV=Q= 2x10-6F (3V) = 18x10-6C or 1.8x10-5Q

Capacitance

Cparallel = C1+C2+C3

2F

4F

6F

12F

3 V

What is the total charge stored in the system? C = Q VCV = Q = 12x10-6F (3V) = 36x10-6C or 3.6x10-5Q

What is the energy stored in the system?U=1/2 QV U = ½ CV2 U= ½ 12x10-6F(3V)2 =U=1.08x10-4 J

What is the charged stored on each of the capacitors?CV=Q= 2x10-6F (3V) = 6x10-6C

CV=Q= 4x10-6F (3V) = 12x10-6C or 1.2x10-5Q

CV=Q= 2x10-6F (3V) = 18x10-6C or 1.8x10-5Q

Capacitance

Cparallel = C1+C2+C3

2F

4F

6F

12F

3 V

What is the total charge stored in the system? C = Q VCV = Q = 12x10-6F (3V) = 36x10-6C or 3.6x10-5Q

What is the energy stored in the system?U=1/2 QV U = ½ CV2 U= ½ 12x10-6F(3V)2 =U=1.08x10-4 J

What is the charged stored on each of the capacitors?CV=Q= 2x10-6F (3V) = 6x10-6C

CV=Q= 4x10-6F (3V) = 12x10-6C or 1.2x10-5Q

CV=Q= 2x10-6F (3V) = 18x10-6C or 1.8x10-5Q

Capacitance

Cparallel = C1+C2+C3

2F

4F

6F

12F

3 V

What is the total charge stored in the system? C = Q VCV = Q = 12x10-6F (3V) = 36x10-6C or 3.6x10-5Q

What is the energy stored in the system?U=1/2 QV U = ½ CV2 U= ½ 12x10-6F(3V)2 =U=1.08x10-4 J

What is the charged stored on each of the capacitors?CV=Q= 2x10-6F (3V) = 6x10-6C

CV=Q= 4x10-6F (3V) = 12x10-6C or 1.2x10-5Q

CV=Q= 2x10-6F (3V) = 18x10-6C or 1.8x10-5Q

Capacitance

Cparallel = C1+C2+C3

2F

4F

6F

12F

3 V

What is the total charge stored in the system? C = Q VCV = Q = 12x10-6F (3V) = 36x10-6C or 3.6x10-5Q

What is the energy stored in the system?U=1/2 QV U = ½ CV2 U= ½ 12x10-6F(3V)2 =U=1.08x10-4 J

What is the charged stored on each of the capacitors?CV=Q= 2x10-6F (3V) = 6x10-6C

CV=Q= 4x10-6F (3V) = 12x10-6C or 1.2x10-5Q

CV=Q= 2x10-6F (3V) = 18x10-6C or 1.8x10-5Q

Capacitance

Cparallel = C1+C2+C3

2F

4F

6F

12F

3 V

What is the total charge stored in the system? C = Q VCV = Q = 12x10-6F (3V) = 36x10-6C or 3.6x10-5Q

What is the energy stored in the system?U=1/2 QV U = ½ CV2 U= ½ 12x10-6F(3V)2 =U=1.08x10-4 J

What is the charged stored on each of the capacitors?CV=Q= 2x10-6F (3V) = 6x10-6C

CV=Q= 4x10-6F (3V) = 12x10-6C or 1.2x10-5Q

CV=Q= 2x10-6F (3V) = 18x10-6C or 1.8x10-5Q

Capacitance

Cparallel = C1+C2+C3

2F

4F

6F

12F

3 V

What is the total charge stored in the system? C = Q VCV = Q = 12x10-6F (3V) = 36x10-6C or 3.6x10-5Q

What is the energy stored in the system?U=1/2 QV U = ½ CV2 U= ½ 12x10-6F(3V)2 =U=1.08x10-4 J

What is the charged stored on each of the capacitors?CV=Q= 2x10-6F (3V) = 6x10-6C

CV=Q= 4x10-6F (3V) = 12x10-6C or 1.2x10-5Q

CV=Q= 2x10-6F (3V) = 18x10-6C or 1.8x10-5Q

Capacitance

1 = 1 + 1 + 1 Cseries C1 C2 C3

2F 4F 6F

1/C = 1/2F 1/4F + 1/6F

1/C = 11/12F = 12F/11=1.09 F

3 V

What is the total charge stored in the system? C = Q VCV = Q = 1.09x10-6F (3V) = 3.27x10-6C

What is the energy stored in the system?U=1/2 QV U = ½ CV2 U= ½ 3.27x10-6F(3V)2 =U=1.47x10-5 J

Capacitance

1 = 1 + 1 + 1 Cseries C1 C2 C3

2F 4F 6F

1/C = 1/2F 1/4F + 1/6F

1/C = 11/12F = 12F/11=1.09 F

3 V

What is the total charge stored in the system? C = Q VCV = Q = 1.09x10-6F (3V) = 3.27x10-6C

What is the energy stored in the system?U=1/2 QV U = ½ CV2 U= ½ 3.27x10-6F(3V)2 =U=1.47x10-5 J

Capacitance

1 = 1 + 1 + 1 Cseries C1 C2 C3

2F 4F 6F

1/C = 1/2F 1/4F + 1/6F

1/C = 11/12F = 12F/11=1.09 F

3 V

What is the total charge stored in the system? C = Q VCV = Q = 1.09x10-6F (3V) = 3.27x10-6C

What is the energy stored in the system?U=1/2 QV U = ½ CV2 U= ½ 3.27x10-6F(3V)2 =U=1.47x10-5 J

Capacitance

1 = 1 + 1 + 1 Cseries C1 C2 C3

2F 4F 6F

1/C = 1/2F 1/4F + 1/6F

1/C = 11/12F = 12F/11=1.09 F

3 V

What is the total charge stored in the system? C = Q VCV = Q = 1.09x10-6F (3V) = 3.27x10-6C

What is the energy stored in the system?U=1/2 QV U = ½ CV2 U= ½ 3.27x10-6F(3V)2 =U=1.47x10-5 J

Capacitance

1 = 1 + 1 + 1 Cseries C1 C2 C3

2F 4F 6F

1/C = 1/2F 1/4F + 1/6F

1/C = 11/12F = 12F/11= 1.09 F

3 V

What is the total charge stored in the system? C = Q VCV = Q = 1.09x10-6F (3V) = 3.27x10-6C

What is the energy stored in the system?U=1/2 QV U = ½ CV2 U= ½ 3.27x10-6F(3V)2 =U=1.47x10-5 J

Capacitance

1 = 1 + 1 + 1 Cseries C1 C2 C3

2F 4F 6F

1/C = 1/2F 1/4F + 1/6F

1/C = 11/12F = 12F/11= 1.09 F

3 V

What is the total charge stored in the system? C = Q VCV = Q = 1.09x10-6F (3V) = 3.27x10-6C

What is the energy stored in the system?U=1/2 QV U = ½ CV2 U= ½ 3.27x10-6F(3V)2 =U=1.47x10-5 J

Capacitance

1 = 1 + 1 + 1 Cseries C1 C2 C3

2F 4F 6F

1/C = 1/2F 1/4F + 1/6F

1/C = 11/12F = 12F/11= 1.09 F

3 V

What is the total charge stored in the system? C = Q VCV = Q = 1.09x10-6F (3V) = 3.27x10-6C

What is the energy stored in the system?U=1/2 QV U = ½ CV2 U= ½ 3.27x10-6F(3V)2 =U=1.47x10-5 J

Capacitance

1 = 1 + 1 + 1 Cseries C1 C2 C3

2F 4F 6F

1/C = 1/2F 1/4F + 1/6F

1/C = 11/12F = 12F/11= 1.09 F

3 V

What is the total charge stored in the system? C = Q VCV = Q = 1.09x10-6F (3V) = 3.27x10-6C

What is the energy stored in the system?U=1/2 QV U = ½ CV2 U= ½ 3.27x10-6F(3V)2 =U=1.47x10-5 J

Capacitance

1 = 1 + 1 + 1 Cseries C1 C2 C3

2F 4F 6F

1/C = 1/2F 1/4F + 1/6F

1/C = 11/12F = 12F/11= 1.09 F

3 V

What is the total charge stored in the system? C = Q VCV = Q = 1.09x10-6F (3V) = 3.27x10-6C

What is the energy stored in the system?U=1/2 QV U = ½ CV2 U= ½ 3.27x10-6F(3V)2 =U=1.47x10-5 J

Capacitance

1 = 1 + 1 + 1 Cseries C1 C2 C3

2F 4F 6F

1/C = 1/2F 1/4F + 1/6F

1/C = 11/12F = 12F/11= 1.09 F

3 V

What is the total charge stored in the system? C = Q VCV = Q = 1.09x10-6F (3V) = 3.27x10-6C

What is the energy stored in the system?U=1/2 QV U = ½ CV2 U= ½ 3.27x10-6F(3V)2 =U=1.47x10-5 J